If a wind instrument, such as a tuba, has a fundamental frequency of 56.0 Hz, what are its first three overtones (in Hz)? It is closed at one end. (The overtones of a real tuba are more complex than this example, because it is a tapered tube.)

Answer:

ac = 204 [m/s²]

Explanation:

To solve this problem we must use the following equation that relates the tangential velocity to the radius of rotation.

ac = v²/r

where:

v = tangential velocity = 15 [m/s]

r = radius = 1.1 [m]

Now replacing we have:

ac = (15)²/1.1

ac = 204 [m/s²]

Answer:

∝ = 28.92 rad/s²

Explanation:

Applying third equation of motion to the angular motion, we have:

2∝θ = ωf² - ωi²

where,

∝ = angular acceleration = ?

θ = angular displacement = (27 rev)(2π rad/1 rev) = 169.64 rad/s

ωf = final angular velocity = 99 rad/s

ωi = initial angular velocity = 0 rad/s

Therefore,

(2)∝(169.64 rad) = (99 rad/s)² - (0 rad/s²)

∝ = (9801 rad²/s²)/(38.8 rad)

∝ = 28.92 rad/s²

Answer:

D) 763 nm

Explanation:

Calculation for the wavelength of light

Using this formula

Wavelength of light=Delta Y*Distance / Length

Where,

Delta Y represent the 2nd order bright fringe

Length represent the distance between both the slits and the screen

Distance represent the Distance between the slits

Let note that cm to m = (4.2) x 10^-2 and mm to m= ( 0.0400x 10^-3)

Now Let plug in the formula

Wavelength of light=[(4.2 x 10^-2m)(0.0400 x 10^-3m) / 2(1.1m)]*10^-7 meters

Wavelength of light=[(0.042m) (0.0004m)/2.2m]*10^-7 meters

Wavelength of light =(0.0000168m/2.2m)*10^-7 meters

Wavelength of light =7.63 *10^-7 meters

Wavelength of light =763 nm

Therefore the Wavelength of light will be 763 nm

Answer:

E₀ = 9.5 eV

Explanation:

In the processes of absorption, excitation and shocks the energy must be conserved therefore the energy before the shock is

         E₀ = E_excitation + E_residual

         E₀ = 5.8 + 3.7

         E₀ = 9.5 eV

this is the energy of the electron before the collision

Answer:

First one,

Its because

Downward force must greater to uplift its weight.

From 3rd law of motion

Answer:

The downward force of the rocket exhaust is greater than the upward force on the rocket.

Explanation:

Your Welcome (;

Answer:

velocity = 44.98 m/s

Explanation:

given data

velocity = 45.0 m/s

angle = 30.0 degrees

solution

first we get here time that is

time = 2u × sin θ ÷ g   .............1

time = 2×45 × sin 30 ÷ 9.8

time = 4.59 sec

and

velocity = [tex]\sqrt{vx^2+vy^2}[/tex]   .....................2

here

vx = 45 cos30 = 38.97 m/s

vy = uy - gt

vy = 45 sin30 - 9.8 ×  4.59  = -22.48 m/s

so velocity will be

velocity = [tex]\sqrt{38.97^2+22.48^2}[/tex]

velocity = 44.98 m/s

Answer:

A.

Explanation:

If its at a height the Gratitude of it falling down with only Gravity if Any other Forces are acting on it so as Friction But Sideways.

Answer:

a = 2m/s^2

Explanation:

Force (F) = 100 N

Mass (m) = 50 kg

Here,

F = m×a

100 = 50 × a

a = 100÷50

a = 2m/s^2

Thus, the acceleration on the cart is a = 2m/s^2

-TheUnknownScientist

Answer:

When elements bond together or when bonds of compounds are broken and form a new substance

Explanation:

Assuming both forces act horizontally, the net force is in Kathryn's direction with a magnitude of 5 N.

If "towards Kathryn" is taken the be the positive direction, then the net force is

∑ F = 20 N - 15 N = 5 N

Answer:

when u learn something new it goes to ur short term memory

Answer: The height of its fourth bounce = 0.43m

Explanation:

The coefficient of restitution denoted by (e), is the ratio that shows the  final velocity to initial relative velocity between two objects after collision

IT is given by the formula in terms of height as

Coefficient of Restitution, e  = √(2gh))/√(2gH) = √(h/H)

Where

Coefficient of Restitution, e= 0.821

H = 2.07 m

At fourth bounce ,   we have that

Coefficient of Restitution, e⁴  =√(h₄/H)  

Putting the given values and solving , we have,

e⁴  =√(h₄/H)  

= 0.821⁴ = √(h₄/2.07)

 (0.821⁴ )² =h₄/2.07

0.2064 x 2.07 = 0.427 = 0.43

At  fourth bounce,  h₄ height = 0.43m

Given :

Object A is 71 degrees and object B is 75 degrees .

To Find :

How will thermal energy flow.

Solution :

We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.

So, in the given question energy will flow from object B from object A.

Hence, this is the required solution.

Answer:

16.67m/s

Explanation:

Given parameters:

Distance Pete drove  = 300m

Time taken  = 18s

Unknown:

Speed  = ?

Solution:

Speed is the distance traveled per unit of time.

It is mathematically expressed as;

   Speed  = [tex]\frac{distance}{time}[/tex]

Insert the parameters and solve;

  Speed  = [tex]\frac{300}{18}[/tex]  = 16.67m/s

Answer:

the effect is given by the energy that depends on the frequency, but not on the intensity

Explanation:

There are similarities and differences between mechanical waves and electromagnetic waves. The main difference is that mechanical waves depend on a material medium for their propagation, whereas electromagnetic waves are maintained by the oscillation of their electrical magnetoscope fields.

In the case of light (electromagnetic wave) the energy is given by the relation

          E = h f

where h is Planck's constant and f is the frequency.

Then the intensity is given by the number of waves or quasiparticles (photons) that are in the ray.

Consequently the effect is given by the energy that depends on the frequency, but not on the intensity

The energy in the given model depends on the frequency, but not on the intensity.

The given problem is based on the mechanical wave and electromagnetic waves. The mechanical waves depend on a material medium for their propagation, whereas electromagnetic waves are maintained by the oscillation of their electrical magneto scope fields.

In the case of light (electromagnetic wave) the energy is given by the relation,  

E = h f

Here,

h is Planck's constant.

And f is the frequency.

Then the intensity is given by the number of waves (photons) that are in the ray.  So, it is evident the effect is given by the energy that depends on the frequency, but not on the intensity.

Thus, we can conclude that the energy in the given model depends on the frequency, but not on the intensity.

Learn more about the intensity of wave here:

https://brainly.com/question/14697045

Answer:

The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).

Explanation:

The gravitational force is the force of mutual attraction that two objects with mass experience.

The Law of Universal Gravitation enunciated by Newton says that every material particle attracts any other material particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically this is expressed as:

[tex]F=G*\frac{m1*m2}{r^{2} }[/tex]

where m1 and m2 are the masses of the objects, r the distance between them and G a universal constant that receives  the name of constant of gravitation.

If the distance between two particles is reduced by half, then, where F' is the new value of the gravitational force:

[tex]F'=G*\frac{m1*m2}{(\frac{r}{2} )^{2} }[/tex]

[tex]F'=G*\frac{m1*m2}{\frac{(r )^{2} }{2^{2} } }[/tex]

[tex]F'=G*\frac{m1*m2}{\frac{(r )^{2} }{4} }[/tex]

[tex]F'=4*G*\frac{m1*m2}{r^{2} }[/tex]

F'=4*F

The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).

Answer:

It is Newton's first law of motion also referred  to as the law of inertia.

Explanation:

Answer:240 meters

Explanation:60×4

Answer:

A

Explanation:

heat transfer occurs between two objects that are not in thermal equilibrium (do not have the same temperature)(heat flows from hot to cold objects)

temp= measure of how hot/cold something is

internal E= total E of a closed system

The transfer of thermal energy between objects of different temperatures is called Heat.

Heat is the energy transferred from one object to another as a result of a temperature differential. When two bodies of different temperatures come into contact, energy is transferred—that is, heat flows— towards the colder body from the hotter.

As we know that when two bodies are not in thermal equillibrium then the heat starts to flow, from the higher temperature body towards the lower temperature body. Thus, The transfer of thermal energy between objects of different temperatures is called Heat.

Learn more about Heat:

https://brainly.com/question/1429452

Answer: 0.6cm

Explanation:

Strain is defined as  how much an object can be stretched or deformed  when force is applied to it .  it measures the  fractional change of the object’s length when the object faces  tensional stress. It is calculated  by using the formulae

Strain =  ΔL/ L

where strain = 6%

L= Original length

ΔL= change in length

 6% = ΔL/ 10 cm

ΔL= 10cm X 0.06

ΔL=0.6cm

Answer:

False

Explanation:

All the lanthanides are not radioactive in nature. Just one of the lanthanides are radioactive.

Answer:

A. 5.03 solar mass.

B. the masses of Star A and B are 1.01 solar mass and 4.02 solar mass respectively.

Explanation:

A. The sum of their two masses can be found using Kepler's third law:

[tex]\frac{P^{2}}{a^{3}} = \frac{4\pi^{2}}{G(m_{A} + m_{B})}[/tex]

Where:

P: is the period = 5 y = 1.58x10⁸ s

a: is the separation between the stars = 5 AU = 7.5x10¹¹ m

G: is the gravitational constant = 6.67x10⁻¹¹ m³kg⁻¹s⁻²

[tex]m_{A}[/tex] and [tex]m_{B}[/tex] are the masses of Star A and Star B respectively.    

[tex]m_{A} + m_{B} = \frac{4\pi^{2}a^{3}}{P^{2}G} = \frac{4\pi^{2}(5 AU*\frac{1.5\cdot 10^{11} m}{1 AU})^{3}}{(1.58 \cdot 10^{8} s)^{2}6.67 \cdot 10^{-11} m^{3}*kg^{-1}*s^{-2}} = 1.00 \cdot 10^{31} kg*\frac{1 M_{\bigodot}}{1.989\cdot 10^{30} kg} = 5.03 M_{\bigodot}[/tex]    

Hence, the sum of their two masses is 5.03 solar mass.  

B. Their individual masses can be found using the center of the mass equation:

[tex] a_{B} = (\frac{m_{A}}{m_{A} + m_{B}})a [/tex]

Where:

[tex]a_{B}[/tex] is the distance of Star B from the center of the mass

Since, [tex]a_{A}[/tex] is four times [tex]a_{B}[/tex] and a = 5 AU we have:

[tex] a_{A} = 4a_{B} [/tex]

[tex] a = a_{A} + a_{B} [/tex]

[tex] a_{B} = a - a_{A} = a - 4a_{B} \rightarrow a_{B} = \frac{a}{5} [/tex]      

Then, their individual masses are:

[tex]\frac{a}{5} = (\frac{m_{A}}{5.03 M_{\bigodot}})a[/tex]  

[tex]m_{A} = \frac{5.03 M_{\bigodot}}{5} = 1.01 M_{\bigodot}[/tex]

Now, the mass of Star B is:

[tex]m_{B} = m_{T} - m_{A} = 5.03 M_{\bigodot} - 1.01 M_{\bigodot} = 4.02 M_{\bigodot}[/tex]

Therefore, the masses of Star A and B are [tex]1.01 M_{\bigodot}[/tex] and [tex]4.02 M_{\bigodot}[/tex] respectively.

I hope it helps you!                              

Answer:

1) f= 8.6 GHz

2) t= 0.2 ms

Explanation:

1)

        [tex]v = \lambda * f (1)[/tex]

       [tex]f =\frac{c}{\lambda} =\frac{3e8m/s}{0.035m} = 8.57e9 Hz (2)[/tex]

⇒     f = 8.6 Ghz (with two significative figures)

2)

       [tex]v =\frac{d}{t} (3)[/tex]

       where v= c= speed of light in vacuum = 3*10⁸ m/s

       d= distance between mountaintops = 52 km = 52*10³ m

       [tex]t = \frac{d}{c} = \frac{52e3m}{3e8m/s} = 17.3e-5 sec = 0.173e-3 sec = 0.173 ms (4)[/tex]

       ⇒  t = 0.2 ms (with two significative figures)

Answer:

wave is in the y-direction, the wave is traveling in the

Explanation:

Answer:

no

Explanation:

This downward force and acceleration results in a downward displacement from the position that the object would be if there were no gravity. The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it.

Answer:

S = 40.8m

Explanation:

Given the following data;

Initial velocity, u = 2m/s

Acceleration, a = 1.6m/s²

Time, t = 6secs

Required to find the displacement

Displacement, S = ?

The displacement of an object is given by the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Where;

Substituting into the equation, we have;

[tex] S = 2*6 + \frac {1}{2}*(1.6)*6^{2}[/tex]

[tex] S = 12 + 0.8*36[/tex]

[tex] S = 12 + 28.8 [/tex]

S = 40.8m

Therefore, the displacement of the skateboarder during this game is 40.8 meters.