If I have 679 points out of 901 what grade will I get?​

Answers

Answer 1
Around a 75% divide 679 by 901
Answer 2

Answer:

you'll get a 75%

Step-by-step explanation:

all you have to do is

divide 679/901

and you get 0.75%


Related Questions

When I stand 20 feet away from my home, the angle of elevation from the ground to the top of my home is 46°. Approximately how tall is my home?

Answers

The height of the home is 20.71 feet and when stand 20 feet away from my home, the angle of elevation from the ground to the top of my home is 46°.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let h represent the height of the house, hence:

tan(46) = h/20

h = 20.71 feet

The height of the home is 20.71 feet and when stand 20 feet away from my home, the angle of elevation from the ground to the top of my home is 46°.

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This Diagram Shows a Regular Pentagon

Answers

A= 540


B.=108

Reasoning-540 degrees in a pentagon
540/5
=108

The sum of three number is 99. The second number is 9 more than the first the third number is 4 times the second. What are you numbers?

Answers

Answer:

First Number=9

Second number=18

Third Number=72

Step-by-step explanation:

let's take the first number as X

X+(9+X)+[4(9+X)]=99

X+9+X+36+4=99

6X=99-45

X=54/6

X=9

please answer this question​

Answers

Answer:

[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx = \boxed{ - \frac{\sqrt{x^4 + 1} (8x^8 - 4x^4 + 3)}{30x^{10}} + C }[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Methods: U-Substitution, U-Solve, Trigonometric Substitution

Step-by-step explanation:

*Note:

The problem is too big to fit all work. I will assume that you know how to do basic calculus.

Step 1: Define

Identify given.

[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx[/tex]

Step 2: Integrate Pt. 1

[Integrand] Rewrite:
[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx = \int {\frac{1}{x^{11}\sqrt{x^4 + 1}}} \, dx[/tex]

Step 3: Integrate Pt. 2

Identify variables for u-substitution/u-solve.

Set u:
[tex]\displaystyle u = x^2[/tex][u] Differentiate [Derivative Rule - Basic Power Rule]:
[tex]\displaystyle du = 2x \ dx[/tex][du] Rewrite [U-Solve]:
[tex]\displaystyle dx = \frac{1}{2x} \ du[/tex]

Step 4: Integrate Pt. 3

Start solving the integral using u-solve:

[tex]\displaystyle \begin{aligned}\int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx & = \int {\frac{1}{x^{11}\sqrt{x^4 + 1}}} \, dx \\& = \int {\frac{1}{2u^6 \sqrt{u^2 + 1}}} \, du \\& = \frac{1}{2} \int {\frac{1}{u^6 \sqrt{u^2 + 1}}} \, du \\\end{aligned}[/tex]

Step 5: Integrate Pt. 4

Identify variables for trigonometric substitution.

Set u:
[tex]\displaystyle\begin{aligned}u & = \tan v \\v & = \arctan u \\\end{aligned}[/tex][u] Differentiate [Triognometric Differentiation]:
[tex]\displaystyle du = \sec^2 v \ dv[/tex]

Step 6: Integrate Pt. 5

Let's focus on just the integral itself. Apply the Trigonometric Substitution Integration Method and other basic integration techniques listed under "Calculus":

[tex]\displaystyle \begin{aligned}\int {\frac{1}{u^6 \sqrt{u^2 + 1} }} \, du & = \int {\frac{\sec^2 v}{\tan^6 v \sqrt{\tan^2 v + 1} }} \, dv \\& = \int {\frac{\sec v}{\tan^6 v}} \, dv \\& = \int {\cot v \csc v (\csc^2 v - 1)^2} \, dv \\\end{aligned}[/tex]

Step 7: Integrate Pt. 6

Identify variables for u-substitution/u-solve again.

Use another variable besides u to avoid confusion with earlier substitutions:

Set w:
[tex]\displaystyle w = \csc v[/tex][w] Differentiate [Triognometric Differentiation]:
[tex]\displaystyle dw = - \cot v \csc v \ dv[/tex][dw] Rewrite [U-Solve]:
[tex]\displaystyle dv = - \frac{1}{\cot v \csc v} \ dw[/tex]

Step 8: Integrate Pt. 7

Reduce the integral using the U-Solve Integration Method and other basic integration techniques listed under "Calculus":

[tex]\displaystyle \begin{aligned}\int {\frac{1}{u^6 \sqrt{u^2 + 1} }} \, du & = \int {\frac{\sec^2 v}{\tan^6 v \sqrt{\tan^2 v + 1} }} \, dv \\& = \int {\frac{\sec v}{\tan^6 v}} \, dv \\& = \int {\cot v \csc v (\csc^2 v - 1)^2} \, dv \\& = \int {-(w^2 - 1)^2} \, dw \\& = - \int {(w^2 - 1)^2} \, dw \\& = - \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw \\\end{aligned}[/tex]

Step 9: Integrate Pt. 8

Solve the integral using basic integration techniques listed under "Calculus":

[tex]\displaystyle\begin{aligned}- \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw & = - \Bigg[ \int {w^4} \, dx - \int {2w^2} \, dx + \int {} \, dx \Bigg] \\& = - \Bigg[ \int {w^4} \, dx - 2 \int {w^2} \, dx + \int {} \, dx \Bigg] \\& = - \Bigg[ \frac{w^5}{5} - \frac{2w^3}{3} + w + C \Bigg] \\& = - \frac{w^5}{5} + \frac{2w^3}{3} - w + C \\& = - \frac{\csc^5 v}{5} + \frac{2\csc^3 v}{3} - \csc v + C \\\end{aligned}[/tex]

[tex]\displaystyle\begin{aligned}- \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw & = - \frac{(u^2 + 1)^\Big{\frac{5}{2}}}{5u^5} + \frac{2(u^2 + 1)^\Big{\frac{3}{2}}}{3u^3} - \frac{\sqrt{u^2 + 1}}{u} + C \\\end{aligned}[/tex]

Step 10: Integrate Pt. 9

Let's substitute our integral value into our integral from "Step 4":

[tex]\displaystyle\begin{aligned}\frac{1}{2} \int {\frac{1}{u^6 \sqrt{u^2 + 1}}} \, du & = - \frac{(u^2 + 1)^\Big{\frac{5}{2}}}{10u^5} + \frac{(u^2 + 1)^\Big{\frac{3}{2}}}{3u^3} - \frac{\sqrt{u^2 + 1}}{2u} + C \\& = - \frac{(x^4 + 1)^\Big{\frac{5}{2}}}{10x^{10}} + \frac{(x^4 + 1)^\Big{\frac{3}{2}}}{3x^6} - \frac{\sqrt{x^4 + 1}}{2x^2} + C \\& = \boxed{ - \frac{\sqrt{x^4 + 1}(8x^8 - 4x^4 + 3)}{30x^{10}} + C } \\\end{aligned}[/tex]

∴ we have found the indefinite integral.

___

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Topic: Calculus

MULTIPLE CHOICE
A sphere has the same radius as a cylinder. In the cylinder, the radius equals the height. If
the cylinder has a volume of 150 cubic units, what is the volume of the sphere?
A
450 cubic units
B
200 cubic units
С
112.5 cubic units
D
50 cubic units

Answers

Answer:

B

Step-by-step explanation:

150 = πr² * r

r = 3.62783

V = 4/3 (π * 3.62783³)

V = 199.99 cubic units or 200

This figure represents an arrow painted on a walkway 12 times.

What is the area of the walkway that is painted with the 12 arrows?


70 cm²

90 cm²

840 cm²

1080 cm²

Answers

The area of the walkway that is painted with the 12 arrows will be 840 cm². Then the correct option is C.

What is Geometry?

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

This figure represents an arrow painted on a walkway 12 times.

The figure is given below.

The figure is the combination of a triangle and a rectangle. Then the area of the figure will be

Area = 1/2 x 8 x 5 + 10 x 5

Area = 20 + 50

Area = 70 cm²

Then the area of the walkway that is painted with the 12 arrows will be

Area of the walkway = 70 x 12

Area of the walkway = 840 cm²

More about the geometry link is given below.

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Evaluate 0.2x for x = 5.
A. 0.1
B. 1
C. 10
D. 0

Answers

the answer is 1! think of it as 5x2 and move a decimal point between the 1 and 0 :)

find the equation (in terms of x) of the line through the point (-3,-3) and (2,-2)

Answers

Answer:

y = (1/5)x - 12/5

Step-by-step explanation:

First, you need to find the slope (m). This can be done by using the given points and the following equation.

y₁ - y₂ = m(x₁ - x₂)

-3 - (-2) = m(-3 - 2)

-1 = -5m

1/5 = m

Next, you need to find the y-intercept (b). You can do this by using the slope and the values of a point in the following equation.

y = mx + b

-2 = (1/5)(2) + b

-2 = 2/5 + b

-2.4 = b

-12/5 = b

Putting the information together, you are left with your final equation.

y = (1/5)x - 12/5

Find the area of the shaded figure.

Answers

Answer: 12

Step By Step Explanation:


precal—easy one question. please help!!

Answers

i believe it’s A- x=6+36k

What is the value of the expression?

Any help?

Answers

Answer:

32

Step-by-step explanation:

4 ÷ 1/8

make 4 into a fraction

4/1 ÷ 1/8

when dividing a fraction you change the divide into multiply and you flip the second fraction:

4/1 × 8/1 = 32

Answer:

32

Step-by-step explanation:

1/8 = 1 / 8 = 0.125        4 / 0.125 = 32

mad skillz gl cheating on your I-ready test

Help me please? I don’t understand.

Answers

Use a protractor
It can’t help measure your lines

Answer:

90°

Step-by-step explanation:

This is important to remember, the three interior angles will always have a sun of 180.


knowing this it’s pretty basic math

a + b + c = 180

33 + 57 + c = 180

90 + c = 180

[subtract 90 from each side (90 cancels out)]
c = 90°

Check
- > 33 + 57 + 90 = 180

33 + 147 + = 180

180 = 180

Check!

A cube has edge length of 12 in. Find its volume.

Answers

Answer:

1728 units^3

Step-by-step explanation:

The volume of a cube is given by the formula: a^3, where a is edge length.

a^3

(12)^3

1728

Answer: 1728 in^3

Step-by-Step Explanation:

Edge length (a) = 12 in
Volume = a^3

Therefore,
= a^3
= a * a * a
= 12 * 12 * 12
= 1728 in^3

Volume = 1728 in^3

Complete the sentence to describe the triangle shown.

GHI is _____ and _____.

Answers

GHI is GH and HI because of the congruency in the 180° triangle

Solve for x. Round to the nearest tenth.​

Answers

sin -1 = 11/35

Final Answer is 18.3

Given that A, O & B lie on a straight line segment, evaluate obtuse ∠AOC.

The diagram is not drawn to scale. < AOC=

Answers

Answer:

∠ AOC = 124°

Step-by-step explanation:

the 3 angles lie on a straight line and sum to 180°

sum the 3 angles and equate to 180

3x + 94 + x + 30 + 2x - 4 = 180

6x + 120 = 180 ( subtract 120 from both sides )

6x = 60 ( divide both sides by 6 )

x = 10

Then

∠ AOC = 3x + 94 = 3(10) + 94 = 30 + 94 = 124°

At the beach, Cody saw 4 times as many
seagulls as pelicans. If there were a total of 30
birds, how many birds were pelicans?

Answers

Answer:

6 pelicans

Step-by-step explanation:

Let x = number of pelicans

Cody saw 4 times as many seagulls as pelicans:

⇒ number of seagulls = 4x

Total of 30 birds:

⇒ seagulls + pelicans = 30

⇒ 4x + x = 30

⇒ 5x = 30

⇒ x = 6

Therefore, there were 6 pelicans (and 24 seagulls).

Pellicans be ySeagulls be 4y

ATQ

y+4y=305y=30y=6

Pellicans are 6

Anyone know the answer to 4 1/6 + 3/4? The final result should be a mixed number.​

Answers

Answer:

=59/12 or 4.92 or 4 11/12

Step-by-step explanation:

4 1/6 + 3/4

=25/6 + 3/4

=59/12 or 4.92 or 4 11/12


-
If f(x) = x3 - 2, find f(3).
O 25
O 24
O 26
O 20

Answers

Answer:

Option A, [tex]25[/tex]

Step-by-step explanation:

Step 1:  Plug in 3 for x and solve

[tex]f(x) = x^3 - 2[/tex]

[tex]f(3) = (3)^3 - 2[/tex]

[tex]f(3) = 27 - 2[/tex]

[tex]f(3) = 25[/tex]

Answer:  Option A, [tex]25[/tex]

* PLEASE HELP *

4
If f (x) = 3(x+5) +-, what is f(a+ 2)?
7
4
O A. 31a + 7) +
a +2
4
B. 347(a) + 5) +
f (a) + 2
C. 3(a + 2) + 2+2
-
a

Answers

Answer:

C is the only correct answer

When specific frequencies of______are absorbed by a material, it forms an absorption spectrum.
A. mass
B. light
C. lightyears
D. weight

Answers

Answer:

B. light

Step-by-step explanation:

When specific frequencies of light are absorbed by a material, it forms an absorption spectrum.

If you put $2,000 into an interest
bearing account, where interest is
compounded quarterly (4 times a year) at
6%, how long will it take for your money
to triple?
Use A = P(1+5)
Solve for t.
t = [?] years
Round your answer to the nearest tenth.

Answers

Answer:

18.4 years

Step-by-step explanation:

The compound interest formula:

[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

For this problem we have

[tex]P= 2000\\r= 0.06\\n= 4\\A= 2000(3)= 6000[/tex]

We plug our numbers...

[tex]6,000= 2,000(1+\frac{0.06}{4} )^{4t} \\[/tex]

Then divide

[tex]6,000/2,000=3[/tex]

[tex]3= (1.015)^{4t}[/tex]

Apply log both sides

[tex]3log=(1.015) 4tlog[/tex]

Solve for t

[tex]t= \frac{3log}{(4log(1.015))} =18.4 years[/tex]

Which transformations, when performed together, would carry graph A onto graph B? Choose all that apply.

A. A reflection over the x-axis

B. A translation of 4 units up

C. A vertical compression with a scale factor of 1/2

D. A vertical stretch with a scale factor of 2

Answers

Answer:

a and b I know for sure, im not sure about the others sorry

URGENT BRIANLIEST WILL BE GIVEN

Whats the volume of the barn?

Answers

Answer:

7840 ft^3

Step-by-step explanation:

give brainliest please!

(10*14*40) + (14*40*8)1/2

Solve for xxx.
Enter the solutions from least to greatest.
(-5x +4)(x -3)=0(−5x+4)(x−3)=0left parenthesis, minus, 5, x, plus, 4, right parenthesis, left parenthesis, x, minus, 3, right parenthesis, equals, 0
\text{lesser }x =lesser x=start text, l, e, s, s, e, r, space, end text, x, equals
\text{greater } x =greater x=start text, g, r, e, a, t, e, r, space, end text, x, equals

Answers

Then the two solutions of the quadratic equation are 4/5 and 3.

How to solve the equation?

Here we want to solve the quadratic equation:

(-5x + 4)*(x - 3) = 0

The two solutions are the values of x for which each parenthesis becomes equal to zero, so the two solutions are given by:

-5x + 4 = 0

x - 3 = 0

If we solve these two equations we get:

x = -4/-5 = 4/5

x = 3

Then the two solutions are 4/5 and 3.

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As part of a school project, Juanita was asked to draw an accurate sketch of her bedroom. using the dimensions and scale shown, determine the actual area of her room: 2.2in by 4.3in 1 inch is + to 5ft

Answers

Answer 11’ x 21.5’ and LxW for Area of room is 236.5 sq ft

Explained
Ratio is 1” to 5ft, for every inch it’s 5’ so
multiply ratio of 5’ by 2.2” and 4.3”

2.2” x 5’ = 11 ft

4.3” x 5’ = 21.5 ft


LxW for area if you need that
236.5 sq ft

Simplify: 4 - 5.2 + 6 + 7.9 - 8

Answers

3.9x+0.8y is the answer to your question.

what is the parent function

Answers

Using translation concepts, it is found that the parent function graphed in this problem is [tex]y = \sqrt{x}[/tex].

What is a translation?

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, we have only one graph, which has the format of the square root of x, hence the function is:

[tex]y = \sqrt{x}[/tex]

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8. f^7 • f^1 (1 point)
A. f^8
B. f^7
C. (2f)^8
D. (2f)^7

Answers

Answer:f^8

Step-by-step explanation:

F^7 multiplied by F^1 =f (7+6+1)= f^8F

look at the image and answer it for me please ​

Answers

Answers..
5-5,000
6-growth factor of 2
7-b=500^w
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