If the graph of f(x) = x2, how will the graph be affected if it is changed to f(x) = 1/3x^2
A. The parabola will be wider.
B. The parabola will be translated up.
C. The parabola will be narrower
D. The parabola will be translated down

Use the general formula for decay substance

[tex]\\ \rm\Rrightarrow N=N_o(1-r)^t[/tex]

For our equation r=62%=0.62

So

function becomes

[tex]\\ \rm\Rrightarrow N=650(1-0.62)^t[/tex]

[tex]\\ \rm\Rrightarrow N=650(0.38)^t[/tex]

Change for a year

[tex]\\ \rm\Rrightarrow N=650(0.38)[/tex]

[tex]\\ \rm\Rrightarrow N=247g[/tex]

Amount decayed=650-247=403g

Daily decay

Percentage decay

[tex]\\ \rm\Rrightarrow \dfrac{1.1}{650}\times 100[/tex]

[tex]\\ \rm\Rrightarrow 0.169[/tex]

[tex]\\ \rm\Rrightarrow 16.9\%[/tex]

Answer:

D.

Step-by-step explanation:

-5.3 rounds up to -5

7.9 rounds up to 8

the sum of the two rounded is 3

her answer of 2.4 rounds to 2, not 3

so her answer is not reasonable

Answer:

3400

Step-by-step explanation:

1L=1000ml

½L=500ml price = 1700

2(500)=2(1700)

1000L= 3400

hence Joshua will pay R3400 for 1L of cooking oil

Answer:

The value of x = 22/3

Step-by-step explanation:

x + 5 - 1/3 = 12

=> x+5 = 12 + 1/3

=> x + 5 = (36 + 1) /3

=> x + 5 = 37 /3

=> (x+5) 3 = 37

=> 3x + 15 = 37

=> 3x = 37 -15

=> 3x = 22

=> x = 22/3

Answer to your question is given in the attachment

Hope this Helps :)

Answer:

can i please have somepoints

Step-by-step explanation:

i need to get an answer to a question and if i don't i might fail a really hard test

Answer:

19/29 probability of bieng an only child

Step-by-step explanation:

Answer:

f(x ) ----> Output

x     -----> Input

-5  -------> Slope

2  --------> y -intercept

Step-by-step explanation:

f(x)  = -5x + 2

Compare this with y = mx + b

m = slope =  co efficient of x

b =  y-intercept = constant term

f(x ) ----> Output

x     -----> Input

-5  -------> Slope

2  --------> y -intercept

Answer:

3xy+5z

Step-by-step explanation:

5(xy+z)-2xy

=5xy+5z-2xy

3xy+5z

Answer:

A

B

C

and

D

Step-by-step explanation:

A

B

C

and

D

Answer:

in 7hours and 30 mn the cost will be (7.5×d×e) cents

Step-by-step explanation:

[tex]\begin{matrix}\text{Time} &1h&7.5h\\ \text{number of dolls} &d&7.5\\ \text{Cost} &d\times e&7.5\times d\times e\end{matrix}[/tex]

The area of the composite figure in the given diagram is calculated as: 152 square inches.

The area of a composite figure is gotten by decomposing the figure into known shapes and finding the area of each of the shapes.

The area of the figure = area of bigger rectangle + area of smaller rectangle = lw + lw

The area of the figure = (20)(6) + (8)(4)

The area of the figure = 152 in.²

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Answer:

$160

Step-by-step explanation:

the difference between May 21, 2022 -- October 1, 2022 = 133 days. since u only get money every 8 days divide 133 by 8 and round down.

[tex]133/8=16.625[/tex]

[tex]\approx16[/tex]

multiply 16 by $10 to get $160

Answer:

1,064dm^2

Step-by-step explanation:

The formula for Area

—> A = lw

Plug our units into the formula

A = 38(28)

A= 1064dm^2

Answer: $86.65

Step-by-step explanation:

First, find how much Justine paid in tax. To do this, first convert 13% to a decimal by dividing by 100. This gets a tax rate of 0.13. Now, multiply the price of the boots by the tax rate. 76.68*0.13 = 9.9684. Round to the nearest cent to get $9.97.

Now, add the amount paid in tax to the price of the boots. 76.68+9.97 = $86.65.

Answer:

See below

Step-by-step explanation:

[tex]\displaystyle \frac{\sec x\sin x}{\tan x+\cot x}\\\\=\frac{\frac{1}{\cos x} \sin x}{\frac{\sin x}{\cos x} + \frac{\cos x}{\sin x}}\\ \\=\frac{\frac{\sin x}{\cos x} }{\frac{\sin x \sin x}{\cos x \sin x} + \frac{\cos x \cos x}{\cos x \sin x}}\\\\=\frac{\frac{\sin x}{\cos x} }{\frac{\sin^2 x}{\cos x \sin x} + \frac{\cos^2 x}{\cos x \sin x}}\\\\=\frac{\frac{\sin x}{\cos x}}{\frac{\sin^2 x+\cos^2 x}{\cos x \sin x} }\\ \\=\frac{\frac{\sin x}{\cos x} }{\frac{1}{\cos x \sin x} }[/tex]

[tex]=\frac{\sin x}{\cos x}\cdot \sin x \cos x\\ \\=\frac{\sin x \sin x \cos x}{\cos x}\\ \\=\sin^2x[/tex]

Thus, the identity is proven. Match the options up accordingly to my step-by-step process.

Answer:

I think its c but not really sure but ill calculate it if I ever had the chance

Answer:

1. 1119.982

2. 315.266

3. 297.866

Answer:

1. 1119.982

2. 315.266

3. 297.866

Using the mean concept, it is found that the simulated average time to cross town is of 0.445.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.

In this problem, the 10 values of the simulation are given by:

0.21 0.53 0.05 0.89 0.15 0.73 0.06 0.28 0.81 0.74

Hence, the mean is given by:

M = (0.21 + 0.53 + 0.05 + 0.89 + 0.15 + 0.73 + 0.06 + 0.28 + 0.81 + 0.74)/10 = 0.445.

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Answer:

  k = 11  or  20

Step-by-step explanation:

The sum of terms of an arithmetic sequence is given by ...

  Sn = (a1 +an)(n/2)

We want to find the value of n for a particular series to have a particular sum.

__

The series of interest is defined by ...

  an = 48 -3n

so, the first term is ...

  a1 = 48 -3(1) = 45

The k-th term is ...

  ak = 48 -3k

__

Then the sum is ...

  Sk = (45 +(48 -3k))(k/2)

We want this value to be 330, so we have ...

  330 = (93 -3k)(k/2)

__

  220 = (31 -k)k . . . . . . . . multiply by 2/3

  k² -31k +220 = 0 . . . . . in standard form

We want factors of 220 that total 31.

  220 = (1)(220) = (2)(110) = (4)(55) = (5)(44) = (10)(22) = (11)(20)

The last of these pairs totals 31, so we have ...

  (k -11)(k -20) = 0 . . . . . factored form of the equation

  k = 11  or  k = 20 . . . . . values of k that make the factors zero

Possible values of k are 11 and 20.

Answer:

8

Step-by-step explanation:

The given monomial is :

The degree of the monomial is the highest power to which a variable is raised to in the monomial. The greatest power in this case belongs to b⁸, which has a power of 8.

Hence, the degree of the monomial is 8

Answer:

[tex]\frac{5}{6}[/tex]

Step-by-step explanation:

sin =opposite/hypotenuse

sinQ=5/6

The area of the composite figure = area of rectangle 1 + area of rectangle 2 + area of triangle = 56 km²

Find the area of each shape that make up the figure, then add up to get the area of the composite figure.

The area of the composite figure = area of rectangle 1 + area of rectangle 2 + area of triangle

Area of rectangle 1 = (length)(width) = (6)(3) = 18 km²

Area of rectangle 2 = (length)(width) = (7 + 3)(2) = 20 km²

Area of triangle = 1/2(base)(height) = 1/2(10 - 4)(6) = 18 km²

The area of the composite figure = 18 + 20 + 18 = 56 km²

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Answer:

Lateral surface area = [tex]18\sqrt{91}[/tex] units²

                                 = 171.71 units²

Step-by-step explanation:

Lateral area:  total surface area excluding its base

Find the radius (circumradius) of the regular hexagonal base.  Use this to find the slant edge of the pyramid, then use the slant edge to find the slant height and thus the area of each face.

Radius of a regular polygon: distance from its center to its vertices.

[tex]\textsf{Radius of a regular polygon}=\dfrac{s}{2 \sin \left(\dfrac{180^{\circ}}{n}\right)}[/tex]

where:

Given:

[tex]\implies \textsf{Radius}=\dfrac{6}{2 \sin \left(\dfrac{180^{\circ}}{6}\right)}=6\:\sf units[/tex]

Use Pythagoras' Theorem to find the slant edge:

[tex]\begin{aligned}\textsf{Slant edge} & =\sf \sqrt{r^2+h^2}\\& = \sqrt{6^2+8^2}\\ & = 10\:\sf units\end{aligned}[/tex]

Use Pythagoras' Theorem to find the slant height:

[tex]\begin{aligned}\textsf{Slant height} & = \sqrt{\textsf{slant edge}^2-\left(\dfrac{s}{2}\right)^2}\\& =\sqrt{10^2-3^2}\\ & =\sqrt{91}\: \sf units\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Area of one face} & = \dfrac{1}{2} \times s \times \textsf{slant height}\\\\ & = \dfrac{1}{2} \cdot 6 \cdot \sqrt{91}\\\\ & = 3\sqrt{91}\: \sf units^2\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Lateral Surface Area}& = 6 \times \textsf{area of one face}\\ & = 6 \cdot 3\sqrt{91}\\ & = 18\sqrt{91}\\ & =171.71\: \sf units^2\:(nearest\:hundredth)\end{aligned}[/tex]

There is only one row

3 columns

and 3 square tiles

Answer:

y = (3/4)x-9/2

Step-by-step explanation:

We've got two points, (-2, -6) and (2, -3). That's more than enough info to construct a line. The slope of the line is the ratio between the change in y (Δy) and the change in x (Δx). Here, Δy = -3 - (-6) = -3 +6 = 3, and Δx = 2 - (-2) = 2 + 2 = 4, so the slope is Δy/Δx = 3/4. From here, we can use the point-slope form of a line to get a general equation. With the slope m = 3/4 and choosing the point (2, -3), we have

[tex]y-y_1=m(x-x_1)\\y-(-3)=(3/4)(x-2)\\y+3=(3/4)x-3/2\\y=(3/4)x-3/2-3\\y=(3/4)x-3/2-6/2\\y=(3/4)x-9/2[/tex]

Answer:

A supplementary angle plus another angle = 180 degrees

Angle AOB is the supplementary angle

A straight line = 180 degrees so,

So angle AOD + angle AOB = 180 degrees

Angle AOB is the supplementary angle.

Step-by-step explanation:

Answer: Irvin wrote the point at the wrong coordinate

Step-by-step explanation: Irvin wrote it at (3,4) instead of (4,3)

[should have gone right four, up three instead]

Answer:

The coordinates have been mixed up.

Step-by-step explanation:

The given coordinates were (4, 3) where 4 is the x-coordinate and 3 is the y-coordinate. Here, Irvin has taken the point (3, 4) where 3 is the x-coordinate and 4 is the y-coordinate. Hence, he mixed up the coordinates of the point.

Answer:

Step-by-step explanation:

Let amount of Mix A is a, Mix B is b, Mix C is c.

With the given details, we get the following system

Find the value of c (the easiest one) for substitution

Substitute c into the first equation

Substitute c into the third equation

Double the equation (5) and subtract (6), find the value of a

Find b

Now find c

[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]

[tex] \large\underline{ \boxed{ \sf{✰\:Important\: point's }}}[/tex]

[tex]{ \rule{70mm}{2.9pt}}[/tex]

[tex] \underline{ \boxed{ \sf{✵\: let's\: solve\:✵}}}[/tex]

[tex] \sf ➛\angle \: 120 \degree + \angle \:t = 180\degree \\ \sf ➛\angle \:t = 180 \degree - \angle \:120 \degree \\ \sf ➛\angle \: t = \:60 \degree[/tex]

[tex]{ \rule{70mm}{2.9pt}}[/tex]

[tex] \boxed{✛\underline{ \boxed{ \sf{ \: \angle \: t = 60 \degree \: }}}✛}[/tex]

Hope it helps !

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https://riverside.rocks/index.php