If the output work is 500 J and the input work is 380 J, what is the machine efficiency?

Answers

Answer 1

If the output work is 500 J and the input work is 380 J, then the machine efficiency can be calculated as 130 % as per the efficiency formula.

How do you determine a machine’s efficiency?

Divide the output work by the input work to get a machine’s efficiency, then multiply the result by 100%.

Efficiency is equal to output times 100%.

How is energy efficiency calculated?

You may determine the efficiency by figuring out what proportion of the energy input results in the desired output: Efficiency is defined as EnergyOut/EnergyIn 100%.

What is an example of energy efficiency?

Utilizing less energy to deliver an energy service is referred to as energy efficiency. LED light bulbs, for instance, use between 75 and 80 percent less electricity to generate the same amount of light as incandescent bulbs.

According to efficiency formula we know

Efficiency = [tex]\frac{580}{380}[/tex] * 100 = 130%

But technically this is not possible as no engine has efficiency greater than Carnot engine i.e., 100%

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Related Questions

Identify the technologies as wireless technology or wired technology

Answers

Answer:

Headphones

Explanation:

There is some with wires and without

Answer:

headphones,phones,computers,robots,

Explanation:

some may have wires some may not but even if i did not answer correctly please give me a brainlyest

A cyclist with a mass of 55 kg coasts on level ground at 32,25 m·s -1 . He free wheels up an incline of 30° to the horizontal and grabs an overhanging tree branch. What is the velocity of the cyclist when he grabs the branch?

Answers

The velocity of the cyclist when he grabs the branch is 36.1 m/s.

What is the final velocity of the cyclist?

The final velocity of the cyclist is calculated as follows;

The final vertical velocity of the cyclist will be smaller than the initial vertical velocity due to opposing force of gravity.

Final vertical velocity of the cyclist, Vy = vi - vi sinθ

Vy = 32.25 - 32.25 sin(30)

Vy = 16.13 m/s

The final horizontal velocity will be constant.

Vx(final) = Vx(initial)

Vx = 32.25 m/s

Resultant final velocity = √Vx² + Vy²

Resultant final velocity = √(32.25² + 16.13²)

Resultant final velocity = 36.1 m/s

Thus, the final velocity of the cyclist will change when he grabs the overhanging tree branch.

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This is an A level/ Cape physics problem under the topic uncertainty, please do your best to answer, thank you.

Answers

The radius of the cylinder is 0.43 cm while the uncertainty is 0.04. This can likely be expressed as 0.43 +/- 0.04 cm

What is Absolute Uncertainty ?

Absolute uncertainty or error is the difference between measured value of a quantity and the actual value.

Given an expression for the volume of a cylinder to be

V = πr²h

Where

V = 12 +/- 0.5 cm³h = 21 +/- 0.1 cm

From the formula, make radius r the subject of the formula and calculate the radius

V = πr²h

r² = V/πh

r = √(V/πh)

r = √12/21π

r = √12/65.97

r = √0.18

r = 0.43 cm

The uncertainty Δr will be

Δr/r = (ΔV/V + Δh/h) × 2

Δr/0.43 = (0.5/12 + 0.1/21) × 2

Δr/0.43 = (0.0417 + 0.0048) × 2

Δr/0.43 = 0.093

Δr = 0.093 × 0.43

Δr = 0.0399

Δr = 0.04

Therefore, the radius of the cylinder is 0.43 +/- 0.04 cm

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Suppose that, while in a squatting position, you stand on your hands, and then you pull up on your feet with a great deal of force. You are applying a large force to the bottoms of your feet, but no matter how strong you are, you will never be able to lift yourself off the ground. Use your understanding of force and motion to explain why this is not possible.

Answers

Answer: The Earth's gravity is too strong.

Explanation: I don't have a full understanding, but probably the Earth is too strong. If you push yourself up, it'll feel difficult.

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3. The diagram shows a child's mobile which is supported from the ceiling by a length of nylon thread of negligible weight. AB is a uniform horizontal rod supported at S.
c) A third fish of weight 0.30 N is suspended from the middle of the rod. The thread supporting the mobile is moved along the rod so that the rod remains horizontal. On which side of the center of the rod is the thread now attached, left or right? Explain how you arrived at your answer.​

Answers

Answer:

.12 * .12 = .0144        counterclockwise torque

.06 * .18 + W * .03 = .0108 + .03 W        clockwise torque

W = (.0144 - .0108) / .03 = .12 N     as requested

(.12 + .06 + .12) N = .30 N       total weight supported by thread

C) Suppose now rod supported at middle

.12 * .15 = .018 N      counterclockwise torque

.06 * .15 = .009 N     clockwise torque

Obviously the thread must be moved closer (left) to .12 weight to increase the clockwise torque (other weights are in the middle of the rod

A weightlifter lifts a 200 Kg barbell 4m using 800W of power. How long did this take?

Answers

Answer:

9.8 seconds

Explanation:

Power = work / time

work = F * d     =   200kg ( 9.81 m/s^2 ) * 4 m = 7818 J

800 W = 7818 J / t       t = ~ 9.8 seconds

Cliff divers at acapulco jump into the sea from a cliff 30.3 m high. at the level of the sea, a rock sticks out a horizontal distance of 7.94 m. the acceleration of gravity is 9.8 m/^2

Answers

If there isn't any beginning vertical velocity, figure out how long it will take to get to the water, then divide that number by the horizontal distance to get the necessary minimum horizontal speed.and for t=6.18 sec, we obtain v =1.28 m/s.

Velocity is the rate of change in direction of an object in motion as measured by a specific standard of time and observed from a specific point of reference (for example, 60 km/h northbound).  A key idea in kinematics, the area of classical mechanics that studies how bodies move, is velocity.

The definition of velocity requires both its magnitude and its direction because it is a physical vector quantity. Speed is a coherently derived unit that is measured in the SI (metric system) as metres per second (m/s or m/s1). Speed is the scalar absolute value (magnitude) of velocity. A scalar is a number, such as "5 meters per second," whereas a vector is "5 meters per second east." the case

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URGENT!! ILL GIVE
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What element is shown below?

Answers

Boron because the atomic number is 5 and that’s the number of electrons is 5

How do the masses of objects affect the strength of gravitational force?

Answers

Answer:

So as the mass of either object increases, the force of gravitational attraction between them also increases.

Explanation:

If the mass of one of the objects is doubled, then the force of gravity between them is doubled. If the mass of one of the objects is tripled, then the force of gravity between them is tripled.

What’s The difference between oxygen and water.

100 POINTS

Answers

Answer:

Oxygen gas is two oxygen atoms bonded together, O2. Water, is one oxygen atom bonded to two different hydrogen atoms, H2O

Explanation:

How many ohms is the resistance of the electric heater connected to 220 V voltage

Answers

Answer:

44 ohms.

Explanation:

R for V (according to Ohm's law). This second formula is more frequently used in practice to calculate resistive heating, whereas the first formula has other, more general applications. As we might infer from the equation, the units of watts also correspond to amperes2 x ohms (A2 x Ω).

Imagine that you are comparing three different ways of having a ball move down through the same height. In which case does the ball reach the bottom with the highest speed?.

Answers

When we are comparing three different ways of having a ball move down through the same height, dropping the ball reaches the bottom with the highest speed.

What happens when you drop a ball?Gravity drags the ball down and increases its speed as you drop it. At the instant of impact, it squashes when it meets the ground. The floor presses against the squished ball as it returns to its former shape, and the floor pushes back in response. The ball is sent back into the air by the force of the floor pushing on it.

Where does the energy leave after you drop a ball?If you drop the basketball, gravity will draw it down, converting its potential energy to kinetic energy as it does so. The ball's potential energy drops as it approaches the ground. But, the ball also accelerates up, thus its kinetic energy increases.

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Brooke kicks a soccer ball with an initial horizontal velocity of 15 m/s off a 40-meter-high cliff and the soccer ball lands 60 meters away from the edge cliff. determine the final vertical velocity of the soccer ball.

Answers

The final vertical velocity of the soccer ball is 20 m/s.

We need to know about the projectile motion to solve this problem. The projectile motion is known as parabolic motion and the velocity is divided by 2 axes.

vox = vo cosA

voy = vo sinA

where vox is initial velocity of x axis, voy is initial vertical velocity, vo is initial velocity and A is the angle.

From the question above, the given parameters are

vox = 15 m/s

h = 40 m

x = 60 m.

The time taken of horizontal motion will be

x = vox . t

60 = 15 . t

t = 4 s

By using the uniform motion, where vty = 0 m/s and time taken to reach the peak is half of total time. Hence

vty = voy - gt

0 = voy - 10.(1/2 . 4)

voy = 20 m/s

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a force of 40N stretches a wire through 3.0 cm what force will stretch it through 5.0cm and through what length will a force of 100N stretch it ?what assumption have you made

Answers

When the extension of the spring becomes 5 cm, the applied force is 66.67 N.

The length produced by a force of 100 N is 7.5 cm.

What is spring constant?

The spring constant of a spring is also known as force constant, is the ratio of force to the extension of a spring.

The force constant of a spring describes how stiff a spring is or how tough a spring is.

The force constant of the given spring is calculated as follows;

k = F/x

where;

F is the applied force on the springx is the extension of the springk is the spring constant

The extension of the spring = 3 cm = 0.03 m

The force is given as 40 N

K = 40 N / 0.03 m

K = 1,333.33 N/m

If the extension of the spring becomes 5 cm, the applied force is calculated as follows;

F = kx

F = 1,333.33 x 0.05

F = 66.67 N

The extension produced by a force of 100 N;

x = F/k

x = 100/1,333.33

x = 0.075 m = 7.5 cm

The assumption made is that the applied force is directly proportional to the extension of the spring.

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A 12100 kg railroad car is coasting on a level, frictionless track at a speed of 19. 0 m/s when a 4790 kg load is dropped onto it. If the load is initially at rest, find the new speed of the car and the % change of the kinetic energy.

Answers

The speed of the car when the load is dropped in it is 10.90 m/s.

Using the data given above:

Mass of the railroad car, m₁ =  12100kg

Mass of the load, m₂ =  4790kg

It can be assumed as the speed of the car, u₁ = 10 m/s

So, it is at rest, u₂ = 0

Here we assume the speed of the car be v

Using law of conservation of energy

Thus:

m1v1 + m2v2 = (m1v1)/ (m1 + m2)

= 12100*10 / 12100 + 4790

121000/16890

= 7.16 m/s

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block starts at the bottom of a ramp making an angle of θ with the horizontal, at initial speed v0 . as it slides up it slows due to gravity and kinetic friction, eventually coming to a stop. static friction is not large enough to hold it at res

Answers

The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort. Use Newton's second law to determine the friction force on the block.

The work-kinetic energy theorem can be used to provide a solution to this issue. Start by calculating how far the block will travel up the ramp. The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort.

You can use a free body diagram and Newton's second law to calculate the frictional force on the block. The frictional energy is calculated as the frictional force multiplied by the distance the block travels up the ramp.

The distance climbed up the ramp will also affect how much the gravitational potential energy changes. You can now generate kinetic energy.

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What's the Normal Force in Newtons for a 2,899 kg Warthog that Master Chief is driving while fighting off a horde of angry aliens? Assume the Halo installation the vehicle is on has an acceleration due to gravity of 10 m/s squared
(or same as Earth).

Answers

Answer:

-28990N

Explanation:

F = mass * acceleration = 2899kg * 10m/s^2 = -28990N (because it is a normal force applying pressure upward).

A person expended 600J of work to move a 95N move a full wheelbarrow. How far was the wheelbarrow moved?

Answers

Answer:

6.3 m

Explanation:

Work = force   X    distance

 600 = 95   x   d

d = 600/95 = 6.3 m

What will happen to acceleration of mass spring system if its mass is doubled?
explain mathematically and briefly

Answers

Answer:

If the mass is doubled, then acceleration will be halved.

Explanation:

That situation is described by Newton's Second Law of Motion. F is force, m is mass and a is acceleration. The math behind this is quite simple. If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.

According to Newton's Second law of Motion, the acceleration of the mass spring system will be halved if the mass of the spring system is doubled.

What is Newton's Second law of Motion?

Newton's second law of motion states that when an external net force is applied on an object, the acceleration of the object is proportional to the net force which is applied on the object, and it also occurs in the same direction as the direction of applied force. The acceleration of an object is inversely proportional to the net force applied and acceleration is inversely proportional to the mass of the object.

This situation can be best described by Newton's Second Law of Motion. The second law of motion can be expressed by the equation:

F = m × a

where, F is force,

m is mass, and

a is acceleration

Mass of an object is inversely proportional to the acceleration of the body. If the mass of the spring system is doubled then the acceleration of the object will be reduced to half.

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an object has a mass of 10 kg and is pushed with a force of 2 N, how far did the object accelerate?

Answers

An object has a mass of 10 kg and is pushed with a force of 2 N the object acceleration is  0.2m/s².

Given;

m = 10 kg

F = 2N

by using Newton's second law of motion that is the formula of force

F = ma

a =  F/m

a = 2/10

a = 0.2m/s²

What is acceleration?

An object is said to accelerate when its velocity changes. A change in the speed of an object can be an increase or decrease in speed or a change in  direction of motion. Some examples of acceleration are a falling  apple, the moon orbiting  the Earth, or  a car stopping at a traffic light. Using these examples, we can understand that when  a moving object changes direction or increases or decreases speed, acceleration occurs.

The  unit of acceleration is  meter per second per second (m/s2).

There are 2 types of acceleration

Uniform Non-uniform acceleration

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In a closed system Mechanical Energy is constant

true or false

Answers

The answer is true!!!!!!!!!!!

help me on ixl describe ecosystem

Answers

Answer:

it is defined as the study of living things and their environment

a jet plane is cruising at 300 m/sm/s when suddenly the pilot turns the engines up to full throttle. after traveling 4.1 kmkm , the jet is moving with a speed of 400 m/sm/s.

Answers

The direction of the net force acting on an object defines the direction of its acceleration. The acceleration of the plane is 8.75 m/s².

What is meant by acceleration ?

Any procedure where the velocity varies exists directed to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This exists because velocity exists both a speed and a direction.

The initial speed of a plane is [tex]$v_{i s}[/tex] = 300 m/s

Distance covered by plane is s = 4 km = 4000m

The final speed of the plane is [tex]$$v_{f s}[/tex] = 400 m/s

The acceleration of the plane.

Using kinematical equation v²[tex]{ }_{f s}[/tex] = v²[tex]{ }_{\text {is }}[/tex] + 2as

Substitute known values in the above equation, we get

400² = 300² + 2 a(4000)

simplifying the above equation, we get

400² -300² = 8000 a

a = 70000/8000

= 8.75 m/s²

Therefore, the acceleration of the plane is 8.75 m/s².

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A spring gets 3.0cm longer when a 1.5N weight hangs from it. Calculate the extension with a 6.0N weight?

Answers

Answer:

The extension of an elastic object when a force is applied, such as a spring, is described by Hooke's law: force = spring constant × extension.


When an engine works, energy is transferred from one form to another form in four stages. The energy wasted in each stage is 10%. Calculate the efficiency of the engine.


(I WILL GIVE BRAINLIEST PLS HELP)

Answers

The efficiency of the engine is 60%.

What is the efficiency of engine?

The efficiency of a heat engine describes the amount of input energy converted into useful work.

It also entails the amount of useful work done by the engine. The greater the amount of useful work done by the engine, the greater the efficiency of the engine.

The efficiency of an engine ranges from 0 to 100%.

If there four stages in the energy conversion cycle, and 10% energy is wasted in each cycle, the total energy wasted in the four cycles is calculated as;

Total wasted energy = 4 x 10% = 40%

Efficiency of the engine = Useful energy = 100% - 40% = 60%

Thus, the efficiency of the engine is the useful work done by the engine.

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Ted wants to hang a wall clock on the wall by using a string. if the mass of the wall clock is 0.250 kilograms, what should be the tension of the string so that it can sustain the weight of the wall clock? a. 0.245 newtons b. 2.45 newtons c. 0 newtons d. 4.90 newtons e. 0.120 newtons

Answers

Answer:

B. 2.45 Newtons

Explanation:

This is a tension force problem with only tension and the weight force acting on the object. Using Newton's second law F=ma, and there being no acceleration in the system, T-w=0. Using this, T=w. w=mg, therefore (.250kg)(9.8m/s^2) = 2.45 Newtons

Answer:

See image

Explanation:

Plato

Guys if anyone knows how to answer, please help me with this question

Answers

Answer:

V = a t

t1 = 15 / 9.8 = 1.53 sec       time to reach 0 speed

t2 = t1 = 1.53 sec        time to reach point thrown

t3 = 5 - 2 * 1.53 = 1.94 sec    time to fall height of cliff

H = V0 t - 1/2 g t^2       time to fall height of cliff   (if V0 positive)

V0 = -15 m/s since it will return to thrown height with speed thrown up

Signs chosen must be consistent

H = -15 * 1.94 - 1/2 9.8 * 1.94^2 = -47.5 m where H is height of cliff

The

Which is the CORRECT description of the sequence of energy transformations occurring in this system?

Answers

Answer:

Explanation:

(I) Electrical energy into sound energy. (ii) Heat energy into kinetic energy (or mechanical energy). (iii) Chemical energy into kinetic energy (or mechanical energy). (iv) Chemical energy into heat energy

a 0.6 kg squirrel falling at 14 m/s hits in a pile of leaves and comes to rest in 2 s. find the normal force of the leaves on the squirrel as it comes to rest.

Answers

If a  0.6 kg squirrel falling at 14 m/s hits a pile of leaves and comes to rest in 2 s , the normal force of the leaves on the squirrel as it comes to rest would be 4.2 Newtons.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem a 0.6 kg squirrel falling at 14 m/s hits in a pile of leaves and comes to rest in 2 s.

The change in the moment of the squirrel = 0.6 × 14

                                                                      =8.4  Kg - m/s

The normal force = rate of the change of the momentum

                             = 8.4 / 2

                             = 4.2 Newtons

Thus,  the normal force of the leaves on the squirrel as it comes to rest would be 4.2 Newtons.

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a mIssile is moving 1810 m/s at a 20.0 angle. it needs to hit a target 19,500 m away iin a 32.0 direction in 9.20 s. what is the magnitude of the acceleration that the engine must produce

Answers

A missile is moving 1810 m/s at a 20.0 angle. it needs to hit a target 19,500 m away in a 32.0 direction in 9.20 s. The acceleration that the engine must deliver is 112 meters per second.

What is acceleration?

The term "acceleration" refers to the rate of change in the object's velocity in relation to time, and it is measured in meters per second (m/s). In most contexts, meters per second squared is the unit of measurement for acceleration.

Let us start by thinking about the component that is horizontal in the x direction.

The length of travel in a plane horizontal to the starting point.

x = 19,500 cos 32.0° m

Using the second equation of motion to determine acceleration along the horizontal axis in order to:

[tex]x = ut + 1/2at^2[/tex]

[tex]19,500 * (cos 32.0^0 = 0 + (1810* cos 20.0^o) *9.20+ 0.5*a *9.20^2[/tex]

a = 21.01 m/s²

The same may be said for the vertical direction.

The distance traveled in the upward and downward directions combined.

Y is the velocity in the vertical direction, and it is equal to 19,500 in 32.0° m.

u= 1810 sin 20.0° m/s

t = 9.20 s

For the purpose of determining acceleration along the vertical axis by using the second equation of motion, For the purpose of determining acceleration along the vertical axis by using the second equation of motion

[tex]y = ut +1/2at^2[/tex]

19,500 sin 32.0° = 0 + (1810 sin 20.0^o)* 9.20 + 0.5*a* 9.20^2

a = 109.6 m/s^2

The resultant acceleration

[tex]a^2 = (21.01)^2 + (109.6)^2[/tex]

a = 112 m/s²

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