3. The distance from a makeup mirror to C (the radius of curvature) is 70 cm. How far from the mirror
can a person be and still see an upright, magnified image?
The far point from the mirror can a person be and still see an upright, magnified image is focus i.e. 35cm from mirror.
What is radius of curvature?The mirror is made out of a sphere which has its radius called the radius of curvature.
The focal length f is half of the radius of curvature R of the lens.
Given the radius of curvature is 70cm, then focal length will be 70/2 = 35cm.
The makeup mirror is a concave mirror which forms real and upright images. The magnified images are obtained when the object is placed between focus and mirror.
Thus, the far point is focus i.e. 35cm from mirror.
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A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. Find its usual speed.
Answer:
Usual speed: [tex]500\; {\rm km \cdot h^{-1}}[/tex].
Explanation:
Let the usual duration of the trip be [tex]t[/tex] hours ([tex]t > 0[/tex].) The actual duration of this trip would be [tex](t - (1/2))[/tex] hours.
The usual speed would be:
[tex]\begin{aligned}\frac{1500}{t}\end{aligned}[/tex].
The actual speed would be:
[tex]\begin{aligned}\frac{1500}{t - (1/2)}\end{aligned}[/tex].
The actual speed is [tex]100\; {\rm km \cdot h^{-1}}[/tex] greater than the usual speed. In other words:
[tex]\begin{aligned}\frac{1500}{t - (1/2)} - \frac{1500}{t} = 100\end{aligned}[/tex].
Simplify this equation and solve for [tex]t[/tex] ([tex]t > 0[/tex]):
[tex]\begin{aligned}\frac{15}{t - (1/2)} - \frac{15}{t} = 1\end{aligned}[/tex].
[tex]\begin{aligned}15\, t - 15\, \left(t - \frac{1}{2}\right) = t^{2} - \frac{1}{2}\, t\end{aligned}[/tex].
[tex]\begin{aligned}t^{2} - \frac{1}{2}\, t - \frac{15}{2} = 0\end{aligned}[/tex].
[tex]2\, t^{2} - t - 15 = 0[/tex].
[tex](2\, t + 5)\, (t - 3) = 0[/tex].
Since [tex]t > 0[/tex], the only possible value for [tex]t[/tex] would be [tex]t = 3[/tex].
Thus, the usual duration of this trip would be [tex]3\; {\rm h}[/tex]. The usual speed of this trip would be:
[tex]\begin{aligned}v &= \frac{s}{t} = \frac{1500\; {\rm km}}{3\; {\rm h}} = 500\; {\rm km \cdot h^{-1}}\end{aligned}[/tex].
According to Einstein's equation, if 3 kg of mass "disappears" during a
reaction, then
A. 5.4 x 1018. J of energy is produced.
OB. the law of conservation of momentum is also violated.
OC. 9 x 108 J of energy is produced.
D. 2.7 x 1017 J of energy is produced.
HELP NOW
The 2.7 x 10^17 J of energy is produced when 3.0 kg mass disappears.
What is the energy produced when 3 kg of mass is converted to energy?According to Einstein's equation, the energy produced when mass is converted to energy is proportional to the mass of the substance.
The Einstein equation is given as:
[tex]E = mc^{2}[/tex]
Mass = 3 kg
c = 3.0 × 10^8
[tex]E = 3 × (3.0 × 10^{8})^{2} = 2.7 \times 10^{17}[/tex]
Therefore, 2.7 x 10^17 J of energy is produced when 3.0 kg mass disappears.
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50 points physics question (multiple choice) Will give brainliest!
There are two systems that contain only the fundamental frequency and they are the systems C and D.
What is fundamental frequency?The term fundamental frequency refers to the lowest frequency of a vibrating body. It does not include the overtones or the harmonics.
From the image shown in the question, there are two systems that contain only the fundamental frequency and they are the systems C and D.
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Question 1
A bus travels 5 km east. Then it travels 3 km west by the same path and stops.
What is the bus's displacement?
O 10 km
O2 km
O3km
O 8 km
What happens when a sound wave passes by the particles of a medium?
Answer:
Propagation of Sound Waves:
Sound waves move (propagate) through a medium by means of particle-to-particle interaction. The source disturbs the immediately surrounding particles, causing them to vibrate about their fixed position at the same frequency as the source.
Unguarded live parts operating at 30,000 volts located above a working space must be elevated at least _____ above the working space.
Unguarded live parts operating at 30,000 volts located above a working space must be elevated at least 9.5' above the working space.
What is voltage?The voltage is the potential difference between the end of the conductor.
The place where electricity supply wires and power stations are present, the lives must protected. They must live far above the working space.
Thus, it must be 9.5' above the working space.
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An object moves 4 meters north, then 3 meters east. What is the displacement of the object?
Answer:
5 meters
Explanation:
4 and 3 are legs of a right triangle with the hypotenuse = displacement
Use Pythagorean theorem
4 ^2 + 3^2 = (displacement)^2
displacement = 5 m
The displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.
What is displacement?
Displacement is change in the position of an object. It can be described as the shortest distance between the initial and final position of an object.
The displacement of the object is calculated as follows;
d² = 4² + 3²
d² = 25
d = 5 m
Thus, the displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.
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The coefficient of dynamic friction between the grass and a 200 kg football blocking sled is 0.20. If a football player only pushes horizontally against the sled, how large must the horizontal force be to keep the sled moving at constant velocity
The horizontal force be to keep the sled moving at constant velocity is 392 N.
Horizontal force applied to the sled
The horizontal force applied to the sled to prevent it from moving is calculated from Newton's second law of motion.
F - Ff = ma
where;
a is acceleration of the sledat constant velocity, a = 0
F - μmg = m(0)
F - μmg = 0
F = μmg
F = 0.2 x 200 x 9.8
F = 392 N
Thus, the horizontal force be to keep the sled moving at constant velocity is 392 N.
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Question 12 A wave has a wavelength of 7.96 m and travels at 30.67 m/s. What is the frequency of the wave?
Answer:
0.2597hertz
Explanation:
first of all we have to calculate time.
time is given by speed/distance
hence=30.67/7.96
=3.85s
frequency is given by 1/time
=1/3.85
=0.2597hertz
Any sound with a frequency that is too low for humans to hear is called:
Answer:
infrasound
Explanation:
A car travels for 2 hours at a speed of 55 km/h. calculate the distance traveled
This is a uniform rectilinear motion (MRU) exercise.
We get the data:
d = ?, v = 55 km/h, t = 2 hr
To calculate the distance, multiply the speed by the time.
d = v * t
d = 55km/h * 2hr = 110kmThe distance traveled is 110 km.
Types of Forces Lab Report
Instructions: In the Types of Forces lab, you will experiment with the contact force friction. Use the following lab report to record your hypothesis, materials, procedures, observations, and conclusion. You will submit your completed report.
Name and Title
Name of Lab:
Student Name:
Instructor:
Date:
Objective
The purpose is to test whether the surface texture of the ground affects the distance an object can roll.
Hypothesis
If an object rolls over _______________ (type of material), then it will _____________ (describe the prediction of distance it will travel).
Materials
For this lab, I used the following items:
Procedure
Short summary of what I did:
I experienced the following errors while doing my experiment:
Test (independent) variable (What was different about my test groups?):
Outcome (dependent) variable (What was I measuring?):
Data
Record the distance traveled for each of the trials for the three floor surfaces in the table below.
Distance Object Traveled
Floor Surface Trial 1 Trial 2 Trial 3
Data Analysis
Calculate the average distance traveled for each floor surface. Use the following guidelines for calculating averages, and show your work.
Floor Covering Calculation of the Average Average Distance Traveled
Example (trial 1 measurement + trial 2 measurement + trial 3 measurement) / 3 (number of trials) Your answer from the calculation, showing the average distance the ball rolled for that floor covering.
Frictional force is reduced in smooth surfaces but is large in rough surfaces.
What is Force?Force is defined as an agent which causes a change in the motion or state of an object.
Forces are of two types:
Contact forces and Non-contact forcesContact forces include frictional force.
Frictional forces refers to the force which acts between two surfaces in contact by opposing the relative motion of one over the other
Frictional force depends on the nature of surfaces in contact where rough surfaces produce greater frictional force than smooth surfaces.
Therefore, frictional force is reduced in smooth surfaces but is large in rough surfaces.
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the amount of energy at the end of the system (output) is different from the starting energy (input). How does this not violate (break) the law of the conservation of energy. This question is based on solar and wind energy
Answer:
Because some of the energy escaped or was used.
Explanation:
When a ball rolls along the carpet, it slows down faster than when it is rolled on the floor. What transfer of energy explains this observation?
Answer:
D.) A carpet transfers more energy to heat than the floor.
The frictional force between carpet and ball is more due to the rough surface of the carpet as compared to the friction between floor and ball, so the ball on the carpet would come to rest first before a ball on the floor.
Explanation:
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A stone is thrown horizontally at 15 m/s from the top of a cliff. It takes it 2.4 s to hit the ground. How far from the base of the cliff does the stone hit the ground
Mr. Ramirez demonstrates that objects can exert forces on each other even when the objects
are not touching. He removes two long pleces of clear plastic tape from a tape dispenser. He
holds a piece of tape in each hand so that they are hanging down. As he moves his hands closer together, the pieces of tape repel each other. His students then plan an investigation to study the forces exerted by the pieces of tape. a. Identify two factors that may affect the forces exerted by the pieces of tape. Explain your
reasoning.
b. Describe how the effect of one of the factors you identified in part (a) could be tested. Be sure to include a description of how the effect would be measured and how the collected data would be analyzed.
The two factors that may affect the forces exerted by the pieces of tape are the charge on the tape and distance between them.
The effect of one of the factors could be tested by altering the distance and calculating the forces between them.
What is force?A force is the push or pull which make a body to move or stop it.
a. When two objects are kept apart. they are always attracted when uncharged kept at any distance.
When the objects are charged, the force will be attractive or repulsive.
The distance between those charged objects increase or decrease in strength depending on the distance between them.
Thus, the two factors that may affect the forces exerted by the pieces of tape are the magnitude of charge on the tape and distance between them.
b. By increasing the distance between the tapes, we can find the strength of forces.
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What happens when oxygen comes in contact with NOx and VOCs?
1. They combine to create ozone to replenish the ozone layer.
2. Oxygen neutralizes NOx and VOCs.
3. They combine to form low altitude ozone.
4. They combine to form smog.
When oxygen comes in contact with NOx and VOCs They combine to create ozone to replenish the ozone layer. Option A is correct.
What is an ozone layer?The layer form on the stratosphere region of the earth, which absorbs most of the ultraviolet rays.
The ultraviolet rays come from the sun are very harmful, increases global warming when enter inside the ozone layer due to its deplection.
When oxygen comes in contact with NOx and VOCs They combine to create ozone to replenish the ozone layer.
Hence, option A is correct.
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In a billiards game, one player hits the cue ball towards another ball. The cue ball has a mass of 0.1kg and hits the other ball with a velocity of 2m/s. If the collision is completely elastic and the cue ball travels with a velocity of 0.8m/s after the collision, what is the mass and velocity of the other ball?
Answer:
3/70 kg ≈ 0.04286 kg
2.8 m/s
Explanation:
In a perfectly elastic collision, the total momentum of the system is constant, and the difference in velocities changes sign.
We assume the other ball is at rest initially, and that the collision is "head-on." That is, final velocities are in the same direction as the initial velocity of the cue ball. We further assume no energy loss, and that the balls do not rotate.
__
initial momentumAssuming the ball being hit is initially at rest, it contributes no momentum to the system. The total momentum is ...
(0.1 kg)(2 m/s) = 0.2 kg·m/s
__
initial velocity differenceIf the cue ball has velocity v1 and the hit ball has velocity v2, the initial difference of velocities is ...
v1 -v2 = 2 m/s -0 m/s = 2 m/s
__
final velocity differenceAfter the collision, we must have ...
v1 -v2 = -2 m/s . . . . the velocity difference changes sign
v2 = v1 +2 m/s = 0.8 m/s +2 m/s
v2 = 2.8 m/s
The velocity of the other ball is 2.8 m/s after the collision.
__
mass of the other ballThe total momentum after the collision is the same as before, so we must have ...
m1·v1 +m2·v2 = initial momentum
(0.1 kg)(0.8 m/s) +(m2)(2.8 m/s) = 0.2 kg·m/s
m2 = (0.2 kg·m/s -0.08 kg·m/s)/(2.8 m/s) = (0.12/2.8) kg = 3/70 kg
The mass of the other ball is 3/70 ≈ 0.04286 kg.
Question 7.
When can a mouse have the same momentum as an elephant?
د ن ه ه
A. when the mouse has a large velocity and the elephant has a small velocity
when the mouse has a small velocity and the elephant has a large velocity
a mouse cannot have the same momentum as an elephant
D. when they both have the same velocity
A mouse have the same momentum as an elephant when the mouse has a large velocity and the elephant has a small velocity. The correct option is A.
What is momentum?The momentum is the product of the mass of the object and its velocity.
Mouse has mass very less than the elephant. In order to make their momentum same, the velocity of the mouse must be greater than the elephant.
Mm x Vm = Me x Ve
A mouse have the same momentum as an elephant when the mouse has a large velocity and the elephant has a small velocity.
Thus, the correct option is A.
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Warren is a professional triathlete when doing an
Ironman, Warren swims 3.86km in 45 mins, then
bikes for 180.5 km in 5 hours and finishes by
running a marathon 42.2km in 2.75 hours. What is
Warren's average speed in Km/hr and m/s
Answer:26.7 and 7.4
Explanation:
So, first you add all the time up then the area travelled.
Firstly; 45 mins + 300 minutes(5 hours) + 165 minutes(2.75 minutes)= 510 minutes
Secondly; 42.2KM + 180.5KM + 3.86KM= 226.56KM
Finally: For hourly you would do: 510 divided by 60 to get 510 mins in terms of hours: so, 8.5 hours then you would do 226.56KM divided by 8.5 hours to get: 26.7Km/hr
For m/s: 7.4m/s
Inboard gasoline boats built after july 31st, 1981 must have what type of ventilation system?.
Inboard gasoline boats built after July 31st, 1981 must have a mechanical type of ventilation system.
What is a mechanical ventilation system?A mechanical ventilation system can be defined as a device in which circulates fresh/cold currents of air.
A mechanical ventilation system is based on the use of systems of ducts capable of ventilating the device.
In conclusion, inboard gasoline boats built after July 31st, 1981 must have a mechanical type of ventilation system.
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What type of waves do not require a medium to travel?.
Answer:
electromagnetic waves
how does this experiment help us understand their behavior? stanford prison experiment
This experiment help us understand their behavior as well as how the people will cop up with the rules and regulation the society wants to apply on them
What is Stanford prison experiment ?In a two-week simulation of a prison setting, the Stanford prison experiment was meant to look at the impact of situational factors on participants' responses and behaviors.
Hence, this experiment allows us to better understand their behavior, as well as how individuals will respond to the laws and regulations imposed by society.
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A car is travelled at 8m/s. The mass of the car is 750 kg.
Calculate the force required to stop the car in 8s
Answer:
F = 750N
Explanation:
We know that F(force) = mass(m) × acceleration(a)
And that Acceleration(a) = velocity(V) ÷ time(t)
So we'll first calculate the acceleration
a = V = 8m/s = 1m/s²
t 8
Next we'll calculate the force
F = ma = 750kg × 1m/s² = 750N
DOES THE SUN CONTAIN NUCLEAR ENERGY?
Answer: yes
Explanation: it's fueled by nuclear reactions that fuse hydrogen atoms together into helium and other heavier elements, releasing huge amounts of energy in the process.
What is the de Broglie wavelength of a 2.89 x 10-28 kg particle moving
at 3.00 x 108 m/s? (h = 6.626 x 10-34 J-s)
Explanation:
formula is given by
h/mv
where h is 6.626 × 10 ^-34
and c = 3 × 10^8
m = mass
by plugging in the values in the formula, the de Brogile wavelength is equal to 7.6424 × 10^(-15)
would appreciate a brainliest :)
Calculate the power if work is 9000 joules and time is 60 seconds
Answer:
150w
Explanation:
power = workdone/time
9000/60
150w
A metal artifact with a mass of 814.0 lbs and a length of 6.25 ft is recovered from the Queen Anne's Revenge wreckage site. It is believed to be a cannon. Unfortunately, the base of the cannon was not recovered, so it is a perfectly symmetrical metal tube. The outer circumference is 23.9 inches and the inner diameter of the bore is 11.5 cm. In order to care for it properly, it must be determined what type of metal it is composed of. What is the artifacts density in g/cm3
Answer:
discovered as obisdan
Explanation:
me ginus brooo
Transverse waves travel at in a string that is subjected to a tension of if the string is long, what is its mass?
The mass of the string is 0.515 kg.
Calculations and Parameters:Given that:
Tension= 60.5NLength of string= 15.9mv= 43.2 m/sm=?To solve for the mass of the string,
v=√(T/ρ) ,(v=43.2m/s , T=60.5N , L=15.9m )43.2= √(60.5/ρ)60.5/ρ= 1866.24ρ= 0.032418Therefore, the mass would be[tex]15.9*0.03242= 0.515448= 0.515[kg][/tex]
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