if you double the magnitude of a vector, does it follow that the magnitude of the components double? Give example.

Answer:

true

Explanation:

Answer:

1.2703 km

Explanation:

The speed can be calculated using the formula;

Speed (m/s) = distance (m) ÷ time (s)

Based on the information in this question, it took 3.7 seconds for a sound with speed of 1236 km/h to reach John. The distance will be:

Distance = speed × time

However, we need to convert the time in seconds (s) to hour (hr).

1 second = 0.000277778 hour

3.7 seconds = 0.00102778 hours.

Hence,

distance = 1236 × 0.00102778

Distance = 1.2703 km

Answer:

approximately 13.77 m

Explanation:

We use the kinematic equations for the horizontal motion which is a uniform non-accelerated motion, and with initial velocity equal to 16 * cos(55). This is described by the equation:

[tex]x=16 * cos(55^o) * t = 9.177 * t[/tex]

then at t = 1.5 seconds, the covered distance becomes:

x = 9.177 * (1.5) = 13.7655  m

Round the answer to the number of decimals that the problem asks.

Complete Question

A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of [tex]1.20 \ \Omega[/tex]

Answer:

The current is   [tex]I = 0.0007 41 \ A[/tex]

Explanation:

From the question we are told that

   The  area is  [tex]A = 8.00 \ cm^2 = 8.0 *10^{-4} \ m^2[/tex]

   The initial magnetic field at [tex]t_o = 0 \ seconds[/tex]  is [tex]B_i = 0.500 \ T[/tex]

   The magnetic field at [tex]t_1 = 0.99 \ seconds[/tex] is  [tex]B_f = 1.60 \ T[/tex]

     The resistance is  [tex]R = 1.20 \ \Omega[/tex]

Generally the induced emf is mathematically represented as

      [tex]\epsilon = A * \frac{B_f - B_i }{ t_f - t_o }[/tex]

=>   [tex]\epsilon = 8.0 *10^{-4} * \frac{1.60 - 0.500 }{ 0.99- 0 }[/tex]

=>   [tex]\epsilon = 0.000889 \ V[/tex]

Generally the current induced is mathematically represented as

     [tex]I = \frac{\epsilon}{R }[/tex]

=>  [tex]I = \frac{0.000889}{ 1.20 }[/tex]  

=>  [tex]I = 0.0007 41 \ A[/tex]  

Answer:

The answer is A. The temperature remains the same.

Answer:

A

Explanation:

Answer: a or e

Explanation:

Answer:

12552 J or 3000 calories

Explanation:

Q = m × c × ∆T

Where;

Q = amount of heat energy (J)

m = mass of water (g)

c = specific heat capacity (4.184 J/g°C)

∆T = change in temperature

For 50mL of water, there are 50g, hence, m = 50g, c = 4.184 J/g°C, initial temperature = 0°C, final temperature = 60°C.

Q = m × c × ∆T

Q = 50 × 4.184 × (60 - 0)

Q = 209.2 × 60

Q = 12552 J

Hence, the amount of heat energy used to heat the water is 12552 J or 3000 calories

Answer:

Explanation:

given

initial velocity u = 4.45m/s

Height = 0.6m

g = 9.8m/s²

Required

final velocity v

Using the equation of motion;

v² = u²-2gH (upward motion of the fish makes g to be negative)

v² = 4.45²-2(9.8)(0.6)

v² = 19.8025-11.76

v² = 8.0425

v = 2.84 m/s

Hence the speed of the fish as it passes a point 0.6 m above the water is 2.84m/s

To get the time, we will use the formula

v = u - gt

2.84 = 4.45 - 9.8t

2.84-4.45 = -9.8t

-1.61 = -9.8t

t = 1.61/9.8

t = 0.164secs

Hence the time taken is 0.164secs

Heya!!

For calculate aceleration, lets applicate formula:

                                                   [tex]\boxed{a=\frac{V-V_o}{t} }[/tex]

                                                   Δ   Being   Δ

                                          V = Final Velocity = 5 m/s

                                         Vo = Initial Velocity = 2 m/s

                                          a = Aceleration = ? m/s²

                                                   t = Time = 7 s

⇒ Let's replace according the formula:

[tex]\boxed{a=\frac{5\ m/s - 2 \ m/s}{7\ s} }[/tex]

⇒ Resolving

[tex]\boxed{ a=0,428\ m/s^{2}}[/tex]

Result:

The aceleration of the object is 0,428 m/s²

Good Luck!!

Answer:

Ksasdasd

Explanation:

Answer:

Q = 12540  J

Explanation:

It is given that,

Mass of water, m = 50 mL = 50 g

It is heated from 0 degrees Celsius to 60 degrees Celsius.

We need to find the energy required to heat the water. The formula use to find it as follows :

[tex]Q=mc\Delta T[/tex]

Where c is the specific heat of water, c = 4.18 J/g°C

Put all the values,

[tex]Q=50\times 4.18\times (60-0)\\Q=12540\ J[/tex]

So, 12540 J of energy is used to heat the water.

Answer:

604m

Explanation:

30 * 20=600

600 + 4 = 604m

Answer:

Any situation that has a path that stops at the same position that it started from has a displacement of zero

Explanation:

hope it helps

Answer:

196.07 m, 2.85 m and 0.15 m

Explanation:

Frequency of AM radio signal, f₁ = 1530 kHz

Its wavelength can be given by :

[tex]\lambda_1=\dfrac{c}{f_1}\\\\=\dfrac{3\times 10^8}{1530\times 10^3}\\\\=196.07\ m[/tex]

Frequency of FM radio signal, f₂ = 105.1 MHz

Its wavelength can be given by :

[tex]\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{105.1\times 10^6}\\\\=2.85\ m[/tex]

Frequency of cell phone signal, f₃ = 1.9 GHz

Its wavelength can be given by :

[tex]\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{1.9\times 10^9}\\\\=0.15\ m[/tex]

Hence, the required wavelengths are 196.07 m, 2.85 m and 0.15 m respectively.

Answer:

Explanation:

Step one:

given

Mass m= 4kg

Force F= 12N

Required

Acceleration the relation between force, acceleration, and mass is Newton's first equation of motion, which says a body will continue to be at rest or uniform motion unless acted upon by an external force

F=ma

a=F/m

a=12/4

a=3 m/s^2

Answer:

Answer is D: D.Fp and Fg

Explanation:

I did the quiz some time ago and rember it hope it helps.

Answer:

i just finish its d

Explanation:

Answer:

equilibrium

Explanation:

bcoz forward reaction equals backward reaction

As the distance from the Sun increases the time to orbit the Sun  increases. (a)

Examples:

-- Nearest planet to the sun: Mercury.  Time to orbit the sun: 88 days

-- 3rd planet from the sun:  Earth.  Time to orbit the sun: 1 year

-- 5th planet from the sun:  Jupiter.  Time to orbit the sun: 12 years

-- 9th closest object to the sun:  Pluto.  Time to orbit the sun: 248 years

Another pair of examples:

-- Object in a near Earth orbit:  International Space Station

Time to orbit the Earth:  90 minutes

-- Object in a far Earth orbit:  the Moon

Time to orbit the Earth:  27.3 days

The reason for all of this is:  Two things about orbits.

1).  The larger the orbit is, the farther the object has to travel around it.

2).  The farther out the object is, the slower it travels in its orbit.

This is simply the way gravity works.

Answer:

the a.

Explanation:

because if you compute you can't know the distance

Answer:

So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3

Answer:

[tex]38.3\ \text{m/s}[/tex]

[tex]32.14\ \text{m/s}[/tex]

6.55 seconds

[tex]52.65\ \text{m}[/tex]

[tex]254.84\ \text{m}[/tex]

Explanation:

u = Initial velocity of rock = 50 m/s

[tex]\theta[/tex] = Angle of throw = [tex]40^{\circ}[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Horizontal component is given by

[tex]u_x=u\cos\theta\\\Rightarrow u_x=50\times \cos40^{\circ}\\\Rightarrow u_x=38.3\ \text{m/s}[/tex]

The horizontal component of the velocity is [tex]38.3\ \text{m/s}[/tex]

Vertical component is given by

[tex]u_y=u\sin\theta\\\Rightarrow u_y=50\times \sin40^{\circ}\\\Rightarrow u_y=32.14\ \text{m/s}[/tex]

The horizontal component of the velocity is [tex]32.14\ \text{m/s}[/tex]

Time of flight is given by

[tex]t=\dfrac{2u\sin\theta}{g}\\\Rightarrow t=\dfrac{2\times 50\sin40^{\circ}}{9.81}\\\Rightarrow t=6.55\ \text{s}[/tex]

The hang time of the rock is 6.55 seconds

Maximum height is given by

[tex]h=\dfrac{u^2\sin^2\theta}{2g}\\\Rightarrow h=\dfrac{50^2\sin^240^{\circ}}{2\times 9.81}\\\Rightarrow h=52.65\ \text{m}[/tex]

Maximum height is [tex]52.65\ \text{m}[/tex]

Range is given by

[tex]d=\dfrac{u^2\sin2\theta}{g}\\\Rightarrow d=\dfrac{50^2\sin(2\times40)^{\circ}}{9.81}\\\Rightarrow d=254.84\ \text{m}[/tex]

The range is [tex]254.84\ \text{m}[/tex]

Answer:

The work done on the air is 4.699 x 10⁶ Joules

Explanation:

Given;

increase in air volume, ΔV = 0.227 m³

net pressure of the air, P = 2.07 x 10⁷ Pa

The work done on the air is given by;

W = PΔV

Where;

W is the work done on the air

P is the net pressure

ΔV  is the increase in air volume

Substitute the given values and solve for work done;

W = (2.07 x 10⁷ Pa) (0.227 m³)

W = 4.699 x 10⁶ Joules

Therefore, the work done on the air is 4.699 x 10⁶ Joules

Answer:

Condenses on dust

Explanation:

Pls brainiest

Answer:

condenses on dust

Explanation:

Answer:

The pharyngeal tonsils are located near the opening of the nasal cavity into the pharynx. When these tonsils become enlarged they may interfere with breathing and are called adenoids.

Answer:

Photovoltaic Energy

Explanation:

There are other forms of energy that do not involve spinning of metals to generate electricity, one of many such is the Solar Photovoltaic Energy.

Photovoltaic is a form of energy in which sunlight Is directly into electricity. This type of energy is often used to power devices such as small wrist watches, rechargeable lamps, and others. They are connected together to panels that are joined together in arrays to power people or heavy power plants. Photovoltaic power plants are happening to be one of the fastest growing sources of electricity generation around the world.

Answer:

a) 2*10^9 J

b) 764.8 kg

Explanation:

Given that

Energy of charge, q = 20 C

Potential difference, ΔV = 1*10^2 MV = 1*10^2 * 10^6 V = 1*10^8 V

a)

To find the energy dissipated, we use the formula

ΔU = qΔV

ΔU = 20 * 1*10^8

ΔU = 2*10^9 J

b)

Change in temperature, ΔT = 100 - 15°

ΔT = 85° C

Change in energy, ΔU = 2*10^9 J

Specific heat of water, C = 4180 j./Kg.K

Latent heat of vaporization, L(v) = 2.26*10^6 J/Kg

Q1 = mcΔT

Q2 = mL(v)

Net energy needed, U = Q1 + Q2

U = mcΔT + mL(v)

U = m (cΔT + L(v))

m = U /[cΔT + L(v)]

Being that we have all the values, we then substitute

m = 2*10^9 / [(4180 * 85) + 2.26*10^6]

m = 2*10^9 / (3.553*10^5 + 2.26*10^6]

m = 2*10^9 / 2.615*10^6

m = 764.8 kg

c)

Having 765 kg of steam at the temperature would have extreme effect on the tree, damaging it permanently. Possibly even blowing it to pieces

Answer:D. schematic completion

Explanation:The rest are actual categoroes

Answer:

schematic completion

Explanation:

got it right on edge

Answer:

-2R

Explanation:

The focal length can be calculated using this formula

1/f = (n1/n2-1)(1/r1-1/r2)

1/f = (1/1.33-1)(1/r + 1/r)

= -0.133/1.33(2/R)

F = -2R

The focal length is this

Answer:

B. τ = 16 Nm

Explanation:

In order to find the torque exerted by the weight attached to the heel of man's foot, when his leg is stretched out. We use following formula:

τ = Fd

here,

τ = Torque = ?

F = Force exerted by the weight = Weight = mg

F = mg = (4 kg)(10 m/s²) = 40 N

d = distance from knee to weight = 40 cm = 0.4 m

Therefore,

τ = (40 N)(0.4 m)

B. τ = 16 Nm

The torque exerted by the weight about his knee, 40 cm away from the weight is: D. 1.6 Nm

Given the following data:

To determine the torque exerted by the weight about his knee, 40 cm away from the weight:

First of all, we would calculate the force being exerted by the weight on his heel.

[tex]Force = mg\\\\Force = 4 \times 10[/tex]

Force = 40 Newton

Mathematically, torque is given by the formula:

[tex]Torque = force \times distance[/tex]

Substituting the given parameters into the formula, we have;

[tex]Torque = 40 \times 0.04[/tex]

Torque = 1.6 Nm

Read more: https://brainly.com/question/14703849

Answer:

816m

Explanation:

70^2m/s=2(3m/ss)(x)

x=816