Imagine that there is a small rocky body caught by Earth’s gravity. Draw a comic-strip cartoon

to illustrate its journey as it travels through space toward Earth, enters Earth’s atmosphere, and

lands on Earth. Describe your illustration with narration or speech/thought bubbles. Include the

use of these key terms: atmosphere, meteor, meteoroid, meteorite.

Answers

Answer 1

To create this comic strip you can use a narration describing each step and illustrate each one with one image or drawing.

Creating a comic strip involves using images and short texts to explain a specific idea or phenomenon. In the case of the process for a meteor to enter Earth you can use the following ideas.

A meteoroid approaches the Earth at high speed and draw a meteor traveling near to different planets and approaching Earth.What is that? and draw the Earth wondering who or what is approaching.The meteoroid enters the atmosphere of the Earth and becomes a meteor and draw the rocky body burningThe rocky body crashes with the surface becoming a meteorite and draw the zone where the meteorite crashed.

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Related Questions

The vertical and horizontal components of the velocity of a golf ball after being struck by a club are 4.0 m s1 and 5.0 m s respectively. Determine the magnitude and direction of the velocity of the golf ball. A 6.30 m s-1 B 6.35 m s-1 C 6.40 m s-1 D 6.45 m 5-1​

Answers

The magnitude and direction of the velocity of the  golf ball is 6.4 m/s at 38.7⁰.

The given parameters:

Vertical component of the velocity, [tex]v_y = 4 \ m/s[/tex]Horizontal component of the velocity, [tex]v_x = 5 \ m/s[/tex]

The magnitude of the resultant velocity of the golf ball is calculated as follows;

[tex]v= \sqrt{v_y^2 + v_x^2} \\\\v = \sqrt{4^2 + 5^2} \\\\v = 6.4 \ m/s[/tex]

The direction of the golf ball's velocity is calculated as follows;

[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{4}{5} )\\\\\theta = 38.7 \ ^0[/tex]

Thus, the magnitude and direction of the velocity of the  golf ball is 6.4 m/s at 38.7⁰.

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(a / xy=2x+a)does anyone can solve this??
Answer:??​

Answers

Answer:

Explanation:

a / xy = 2x + a

a = 2x²y + axy

a(1 - xy) = 2x²y

a = 2x²y / (1 - xy)

a / xy = 2x + a

a = 2x²y + axy

a = y(2x² + ax)

y = a / (2x² + ax)

a / xy = 2x + a

a = 2x²y + axy

a / xy = 2x + a

0 = 2yx² + ayx - a

x = (-ay ±√((ay)² - 4(2y)(-a))) / (2(2y))

x = (-ay ±√(a²y² + 8ay)) / 4y

During an experiment, your teacher gives you two objects: tissue paper and a balloon. You observe that the tissue paper repels the balloon. What does this most likely tell you about the charges of the two objects?

Both objects have negative charges.
The tissue has a positive charge, and the balloon has a negative charge.
The tissue has a negative charge, and the balloon has a positive charge.
The objects have no interactive with each other.

Answers

Answer:

i think your answer is this: the objects have no interactive with each other.

Explanation:

if you think about it tissue paper doesn't really have a static electrical charge if it does it is very weak so therefore cannot really attract or repel anything.

which of the following are ways in which energy can be transferred to or from a substance?
a.) heat and internal energy
b.) work and internal energy
c.) heat and work
d.) heat and kinetic energy ​

Answers

Answer:

a

Explanation:

the answer is a because it is feasible

the turns ratio for a transformer with 225 turns of wire in its primary winding and 675 turns in the secondary is: n

Answers

The ratio of the primary turns to the secondary turns is 1/3

The correct answer to the question is Option A. 1/3

From the question given above, the following data were obtained:

Primary turn (Nₚ) = 225 turnsSecondary turn (Nᵣ) = 675 turns Ratio of primary to secondary =?

Ratio = Nₚ/Nᵣ

Nₚ/Nᵣ = 225 / 675

Nₚ/Nᵣ = 1/3

Therefore, the ratio of the primary turns to the secondary turns is 1/3

Complete question:

See attached photo

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In Newton's cannonball experiment, if the velocity is equal the orbital velocity the Cannon ball
will
O stay in orbit
O fall to the earth
O escape the earth
O none of the above

Answers

In Newton's cannonball experiment, if the velocity is equal to the orbital velocity then the cannonball will stay in Orbit.

Newtons cannonball experiment stated that the distance that a cannonball will travel, before being drawn into the Earth by the forces of gravity, is dependent on the initial velocity.

Therefore, if the cannonball is launched at a velocity that matches the orbital velocity, then it will not be able to be drawn in by gravity due to the Earth moving away from the cannonball at the same speed at which the cannonball itself is falling.

This means that the cannonball will continue to fall without reaching the Earth, therefore staying in orbit, much like that of the moon or planets around the sun.

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A 1.95 kg box sits on an incline of 24 ° with the horizontal. If the box accelerates down the incline at 0.245 m/s 2 , what is the coefficient of kinetic friction between the box and the inclined plane?

Answers

Answer:

Explanation:

                            F = ma

mgsinθ - μmgcosθ = ma

      gsinθ - μgcosθ = a

                   μgcosθ = gsinθ - a

                              μ = (gsinθ - a) / gcosθ

                              μ = (9.81sin24 - 0.245) / 9.81cos24

                              μ = 0.4178906...

                              μ = 0.418

The coefficient of kinetic friction will be equal to 0.418.

What is friction?

Friction is the force that prevents solid surfaces, fluid layers, and material elements from sliding against each other. There are various kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in-touch solid surfaces.

Given that a 1.95 kg box sits on an incline of 24 ° with the horizontal. If the box accelerates down the incline at 0.245 m/s 2

The coefficient of kinetic friction will be calculated as,

F = ma

mgsinθ - μmgcosθ = ma

gsinθ - μgcosθ = a

μgcosθ = gsinθ - a

Solve for the value of the coefficient of friction,

μ = (gsinθ - a) / gcosθ

μ = (9.81sin24 - 0.245) / 9.81cos24

μ = 0.4178906...

μ = 0.418

Therefore, the coefficient of kinetic friction will be equal to 0.418.

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2 examples of non fossil fuels ?

Answers

Answer:

-> Hydropower

-> Solar power

Explanation:

-> Hydropower

[] The power of water! It is the use of falling or fast-running water to produce electricity for power. Impoundments or da*ms are mainly used in this type of power source.

-> Solar power

[] The power of the sun! It is the use of sunlight, or solar energy, to produce electricity for power. You have probably heard of solar panels, and this is the main way to collect it.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

Wind energy and solar power

Explanation:

they do not use fossil fuels

For northern hemisphere observers, which celestial object would be above the horizon for the greatest
amount of time: one that is on the celestial equator, one that is 30° above the celestial equator, one that is
70° above the celestial equator, or one that is 40" below the celestial equator? Which one would be above
the horizon the greatest amount of time for southern hemisphere observers? Explain your answer.

Answers

Answer:

Explanation:

For a person at about 20° North latitude, an object 70° above the celestial equator would never set. It's arc path would touch the horizon be never sink below it. Observers north of 20° see it all night. Observers south of 20° an object 70° above the celestial equator would spend the greatest amount of time above the horizon.

For southern hemisphere observers, the object 40" below the celestial equator will spend the most time above the horizon. Nearly 12 hours per day. Did you mean 40°? 40 seconds is very close to the equator itself. However, the result is the same.

For northern hemisphere observers, the celestial object that is 70° above the celestial equator would be above the horizon for the greatest amount of time.

What is the equator?

The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.

For northern hemisphere observers, the celestial object that is 70° above the celestial equator would be above the horizon for the greatest amount of time.

One that is 40" below the celestial equator would be above the horizon for the greatest amount of time for southern hemisphere observers.

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Draw the graphs for exothermic and endothermic reactions Label: axes, reactants, products, Energy of reaction, heat energy change​

Answers

Answer:

axes, reactants, products, Energy of reaction, heat energy

Explanation:

axes, reactants, products, Energy of reaction, heat energyaxes, reactants, products, Energy of reaction,grreactantsaphs heat energy

You are in Paris, 50. m up on an Eiffel Tower support leg observation deck. If you throw a euro downward at a velocity of -1.0 m/s, how long would it take the coin to hit the ground?​

Answers

Here’s my work to your question. I used kinematic equations to solve. :)

Would you please help me with this? I can't figure it out, please! I need to know what the E means!

Answers

Answer:

Without the full content of your question, I will have to GUESS at the context and assume

E = Energy

released when glucose is broken down.

A disgruntled physics student, frustrated with
finals, releases his tensions by bombarding the
adjacent building, 13.5 m away, with water
balloons. He fires one at 38◦
from the horizontal with an initial speed of 23.6 m/s.
The acceleration of gravity is 9.8 m/s
2
.
For how long is the balloon in the air?

Answers

Answer:

Explanation:

The balloon would require a time of

t = d/v = 13.5/ (23.6cos38) = 0.7259...s

to travel the horizontal distance.

the vertical position relative to the throw point at that time is

h = 0 + (23.6sin38)(0.7259) + ½(-9.8)(0.7259²)

h = 7.9652...

so as long as the adjacent building is at least 8.0 m higher than the student position, the balloon is in the air for 0.726 s.

If the building is shorter than 8.0 m above the student, the balloon will land on the building roof and will be in the air for a longer period of time

Which of these is a push or a pull? Acceleration Force Mass Inertia

Answers

Answer:

the answer is force . force is applied as a push or pull

A 21 newton force keeps a 3 kg object in uniform circular motion. The speed of the object is 9 m/s. The magnitude of the centripetal acceleration is


3 m/s^2
7 m/s^2
27 m/s^2
30 m/s^2

Answers

Answer:

Explanation:

F = ma

a = F/m = 21/3 = 7 m/s²

Two rocks with different masses fall side by side, pulled downward by gravity. Why are they able to experience the same motion?(1 point)

The rock with more mass will also have more force pulling it down. Even though the accelerations are different, the rocks will have the same speed.
The rock with more mass will also have more force pulling it down. Even though the accelerations are different, the rocks will have the same speed.

The rock with more mass will also have more force pulling it down, so the accelerations can be the same.
The rock with more mass will also have more force pulling it down, so the accelerations can be the same.

Gravity will pull the rocks down equally, so the accelerations can be the same.
Gravity will pull the rocks down equally, so the accelerations can be the same.

Gravity will pull the rocks down equally. Even though the accelerations are different, the rocks will have the same speed.

Answers

Answer:

The rock with more mass will also have more force pulling it down, so the accelerations can be the same.

Explanation:

A person sitting in a chair with wheels stands up, causing the chair to roll backward across the floor. The momentum of the chair

a. was zero while stationary and increased when the person stood.

b. was greatest while the person sat in the chair.

c. remained the same.

d. was zero when the person got out of the chair and increased while the person sat.​

Answers

Answer:

a. was zero while stationary and increased when the person stood.

Explanation:

momentum is mass times velocity.

initial velocity was zero

final velocity was NOT zero.

A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 38 m/s when it reaches ground level. What was its speed when its height was half that of its starting point

Answers

Explanation:

look !

speed= 38m/s

start from rest= 0

What is an ellipse?

a plane that slices between orbits

an oval-shaped orbit

a circular orbit

the center of gravity between orbiting objects​

Answers

Answer:

i think it's C thx correct me if wrong

Which of the following is most likely to be a secondary source

Answers

Answer:

analyze, assess or interpret an historical event, era, or phenomenon,.

Explanation:

Secondary sources are works that analyze, assess or interpret an historical event, era, or phenomenon, generally utilizing primary sources to do so. Secondary sources often offer a review or a critique. Secondary sources can include books, journal articles, speeches, reviews, research reports, and more.

Explain how the linear rate spring operates?

Answers

A linear spring has the same diameter along its entire length, and this uniform diameter gives it a constant spring rate.

Magma usually stays below the Earth's
under great pressure.
o mantle
Inner core
outer core
Crust

Answers

Answer:

In the inner vote part of the earth

A 0.75 kg model car is moving west at a speed of 9.0 m/s when it collides head-on with a 2.00 kg model truck that is traveling east at a speed of 10.0 m/s. After the collision, the 0.75 kg model car is now moving east at 11 m/s. What is the speed and direction of the model truck after the collision?

Answers

Answer:

  2.5 m/s east

Explanation:

Let east be the positive direction for velocity.

The change in momentum of the 0.75 kg model car is ...

  m1·v2 -m1·v1 = (0.75 kg)(11 m/s) -(0.75 kg)(-9 m/s)

  = (0.75 kg)(20 m/s) = 15 kg·m/s

The change in momentum of the 2.0 kg model car is the opposite of this, so the total change in momentum is zero.

  m2·v2 -m2·v1 = (2 kg)(v2 m/s) -(2 kg)(10 m/s) = 2(v2 -10) kg·m/s

The required relation is ...

  15 kg·m/s = -2(v2 -10) kg·m/s

  -7.5 = v2 -10 . . . . divide by -2

  2.5 = v2 . . . . . . . add 10

The velocity of the model truck after the collision is 2.5 m/s east.

As the amount of charge on either of two charged objects increases, the electric force between the objects decreases.

O True O False​

Answers

Answer:

False.

Explanation:

provided the distance between the forces remains the same, the force will increase with increased charge, whether attractive or repulsive.

How much power does it take to lift 30.0 N 10.0 m high in 10.00 s?

Answers

Answer:

60w

Explanation:

The power required is 30 Watt.

Let us recall that power is defined as the rate of doing work. Hence, we can write as follows;

Power = Work done/ time taken

Now;

work done =  Force × distance

Force = 30.0 N

Distance = 10.0 m

work done = 30.0 N × 10.0 m = 300 J

The power expended = 300 J/10.00 s = 30 Watt

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A 3.2 kg solid disk with a radius of 0.45 m has a tangential force of 420.4 N applied to it. What is the moment of inertia applied to the disk

Answers

Answer:

Explanation:

Your question makes no sense.

moment of inertia is a property of the disk and its geometry.

The moment of inertia of a uniform solid disk around an axis through its geometric center and perpendicular to its flat ends is

I = ½mR² = ½(3.2)0.45² = 0.324 kg•m²

the applied torque about the same axis would be

τ = FR = 420.4(0.45) = 189.18 N•m

and the angular acceleration about the same axis would be

α = τ/I = 189.18/0.324 = 583.9 rad/s²

True or False If the mass of the object increases, then the potential energy of the object decreases.​

Answers

False- the potential energy is force*distance and force is mass*acceleration so if there’s more mass, there’s more force, so there’s more potential energy
Hope that helps :)

What is the height of a building (in meters) if it takes a rock 8.2 seconds to drop from it's roof?

Answers

Answer:

d = 329.81m

Explanation:

V_f = V_0+a*t

V_f = Velocity final

V_0 = Velocity initial

a = acceleration

t = time

V_f = (0m/s)+(9.81m/s²)*(8.2s)

V_f = 80.442m/s

d = ((V_f-V_0)/2)*t

d = distance

d = ((80.442m/s-0m/s)/2)*(8.2s)

d = 329.81m

all pressure topics in physics​

Answers

Absolute, Atmospheric, Differential, and Gauge Pressure

at room tmeperature none of the metals are

Answers

What metal is not at room temperature?

Mercury is a metallic chemical element that is an only metal that is not a solid at room temperature.

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