We can observe that the ball reaches the bottom with the highest speed when the ball is dropped.
What occurs when a ball is dropped?As you drop the ball, gravity pulls it downward and accelerates it.It squashes as soon as it collides with the earth at impact.The crushed ball pushes against the floor, which pushes back as the ball assumes its original shape.The power of the floor pressing against the ball causes it to rebound back into the air.When you drop a ball, where does the energy go?If you drop the basketball, gravity will pull it down and, as it does so, transform its potential energy into kinetic energy.The potential energy of the ball decreases as it gets closer to the earth.However, the ball also accelerates upward, increasing its kinetic energy.To learn more about dropping a ball visit:
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Metals corrode when left exposed to substances in the environment. State why aluminium quickly becomes protected from further corrosion.
Answer:
Explanation: because it develops a thin oxide layer on the surface when the metal comes in contact with oxygen. The oxide layer protect the aluminum against corrosion and if damaged it will immediately regenerate in presence of
a balloon is filled with helium gas how would the balloon volume change if it floated to a higher altitude (p decreases, assume n and t are constant)?
As we know, Pv= nRT where,
P : pressure
V : volume
n : number of moles
R : constant
T : temperature
According to question PV is constant therefore if balloon floats to a higher altitude where the outside pressure is lower than Volume will increase as a result of Boyle's Law. Therefore Figure C represents the final volume.
What is altitude?
A measurement of altitude or height is the distance between a location or item and a reference datum, often in the vertical or "up" direction. Depending on the circumstance, many definitions and reference points are appropriate.
Therefore,
a balloon is filled with helium gas how would the balloon volume change if it floated to a higher altitude (p decreases, assume n and t are constant)?
As we know, Pv= nRT where,
P : pressure
V : volume
n : number of moles
R : constant
T : temperature
According to question PV is constant therefore if balloon floats to a higher altitude where the outside pressure is lower than Volume will increase as a result of Boyle's Law. Therefore Figure C represents the final volume.
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A tray containing 0.20 kg of water at 20 °C is placed in a freezer temperature of the water drops to 0 °C in 10 minutes. (specific heat capacity of water = 4200 J /kg K Calculate
(i) the energy lost by the water as it cools to 0 °C,
(ii) the average rate at which the water is losing energy, in J/s.
Answer:i) Energy lost by the water to cool to a temperature of 0°C from 20°C is 16800 J ii) Average rate at which the water is losing energy = 28J/s when specific heat capacity of water = 4200 J/kg K
Explanation: i)The formula used to calculate the energy lost by the water is
Q=mcΔT where Q= heat or energy lost (or gained), m= mass of the water, c= specific heat capacity of the water, ΔT= [tex]T_{f}-T_{i}[/tex] where [tex]T_{f}[/tex] is the final temperature of the water and [tex]T_{i}[/tex] is the initial temperature of the water
Given, m=0.2kg , c= 4200 J/kg K , [tex]T_{f}=0[/tex]°C and [tex]T_{i}=20[/tex]°C
∴ΔT=[tex]T_{f}-T_{i}=(0-20)[/tex]°C= -20 K ∵Change of temperature in celsius = change of temperature in kelvin
∴[tex]Q=[/tex][tex]0.2*4200*(-20)= -16800 J[/tex] (minus denotes energy loss)
ANS:Energy lost by the water as it cools is Q=16800 joules = 16800J
ii) formula used to calculate average rate at which the water is losing energy is
average rate of losing energy [tex]=\frac{Energy Lost}{Time}[/tex][tex]= \frac{Q}{t}[/tex]
Energy Lost= Q = 16800 J (from answer (i))
Time taken for water to cool to 0°C = t= 10 min= 10*60 sec= 600 sec
∴Avg. rate of losing energy[tex]=\frac{Q}{t}=\frac{16800}{600}=28 J/s[/tex]
ANS: Average rate at which the water is losing energy is 28J/s
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What is Momentum ?
Ty :))
Answer:
Momentum can be well defined as the measure of the kinetic energy of the object. In simple words, the momentum is the product of mass and velocity.
a 40kg crate rests on a horizontal floor, and a 60kg person is standing on the crate. determine the magnitude of the normal force that the floor exerts on the crate.
The magnitude of the normal force that the floor exerts on the crate is 980 N.
What is normal force?The normal force of an object the perpendicular force of the object due to its weight. The weight of the force of the object due force of gravity.
According to Newton's third law of motion, the normal force of an object is equal and opposite to the weight of the object.
Mathematically, the formula for normal force is given as;
W = Fn
mg = Fn
where;
m is the mass of the objectg is acceleration due to gravityFn is the magnitude of the normal forceSubstitute the given parameters and solve for normal force that the floor exerts on the crate.
Fn = (m1 + m2)g
where;
m1 is mass of the crate m2 is mass of the personFn = (40 + 60)9.8
Fn = (100)9.8
Fn = 980 N
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help me find intersect and slope
Answer:
58.01
Explanation:
because this is he answer to the question 019.10
A car travels downtown on the freeway with a constant speed of 10 miles/hour. if the car travels for .5 hours , how far away is downtown?
The downtown is 5 miles far away, if the car travels at 10 miles / hour for 0.5 hours.
v = d / t
v = Velocity
d = Distance
t = Time
v = 10 mi / hr
t = 0.5 hr
d = v * t
d = 10 * 0.5
d = 5 mi
Velocity of the car is the rate of change of position of the car. In simple words it can be said as velocity is used to calculate the distance covered in a given amount of time.
Therefore, the downtown is 5 miles far.
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PLEASE HELP PHYSICS
A miniature quadcopter is located at
xi = −2.25 m
and
yi = −4.70 m
at
t = 0
and moves with an average velocity having components
vav, x = 1.70 m/s
and
vav, y = −1.50 m/s.
What are the x-coordinate and y-coordinate (in m) of the quadcopter's position at
t = 2.60 s?
Answer:
Final coordinates in meters : (2.17, -8.6)
Explanation:
We have the equation
displacement Δd = average velocity x time
In this case there are two components of displacement corresponding to the two components of average velocity
[tex]v_{avg}(x) = 1.70 \; m/s[/tex]
[tex]v_{avg}(y) = -1.50 \; m/s[/tex]
Time traveled is t = 2.60s
So the x component is toward east (+x) axis and y component is due south(-y axis)
[tex]\sf{x \;displacement \;} \Delta_x = v_{avg}(x) x t= 1.70m/s \; \times \; 2.60 = 4.42 m\\\\[/tex]
Since the original x-coordinate was at -2.25m, the end x coordinate is
x = -2.25 + 4.2 = 2.17
The y-displacement
[tex]\sf{y \;displacement \;} \Delta_y = v_{avg}(y) x t\\\\ = - 1.50m/s \; \times \; 2.60 = - 3.9 m\\\\\\\\[/tex]
The starting y-coordinate was at y = -4.70m
So final y-coordinate = -4.7 - 3.9 = -8.6m
Final coordinates in meters : (2.17, -8.6)
Place a +3q point charge at the origin, and a -q point charge on the x-axis at D = 0.500 m. At what point on the x-axis will the net forces from the other two charges acting on a third charge, q°, be equal to zero?
The Point on the x-axis that the net forces from the other two charges acting on a third charge, q°, will be equal to zero is
x=1.72units
This is further explained below.
What are forces?Generally, The total amount of forces exerted on an item is referred to as its net force. The total of N forces exerted on an item is given in the equation below.
The total force operating on an item, which may include a number of different forces, is known as the net force acting on the object.
The n forces operating on an item are added up in this equation. According to this formula, the amount of net force exerted on an item is equal to the mass times the acceleration of the object.
+3q <------>+11q
[tex]&\frac{1}{4 \pi E v}\left(\frac{3 q}{x^2}-\frac{11 q}{(5-x)^2}\right)=0 \\\\&\frac{3}{x^2}=\frac{11 q}{(5-x)^2} \\&\frac{5-x}{x}=\sqrt{\frac{11}{3}}=1.91 \\\\[/tex]
5-x=1.91 x
=1.715
=1.72units
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Two students carried out an experiment to determine the speed of sound. This is the method used
Student A stands 100 m away from Student B.
1
2
3
4.
5.
Student A bangs two blocks of wood together making a loud sound.
Student B starts a stopclock when he sees the blocks of wood bang together.
Student B stops the stopclock when he hears the sound and records the time.
The students repeat steps 2-4 several times.
The students calculated the speed of sound from their results.
(e) Suggest the most likely source of error in the experiment.
The most likely source of error would be human error such as delay in stopping the stopwatch. The coordination error would be the source of error.
What is the speed of Sound?On Earth, the speed of sound as calculated experimentally at sea level assuming a default air temperature of 59 degrees Fahrenheit (15 degrees Celsius) is 761.2 mph (1,225 km/h). The speed of sound is slowed down because gas molecules move more slowly at lower temperatures.
Thus, sound tends to move faster in warmer air.
To explain what speed of sound is, the speed of sound can be described as the distance travelled per unit of time by any sound wave as it propagates through a completely elastic medium.
At 20 °C, temperature the speed of sound in air is about 343 meters per second, or one kilometer in 2.91 s or one mile in 4.69 s.
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A 10kg block of wood is pulled across a level ground by fore of 15N applied at an angle of 30 degree from the horizontal. How much work is done, if it is moved to a distance of 3m?
The amount of work done, given that the block moved to a distance of 3 m is 38.97 J
How to determine the work doneWork is defined as the product of force and distance moved in the direction of the force.
Work done (Wd) = force (F) × distance (d)
Wd = fd
Considering angle projection,
Wd = FdCosθ
With the above formula, we can detertmine the work done as follow:
Mass (m) = 10 KgForce (F) = 15 NAngle (θ) = 30°Distance (d) = 3 mWorkdone (Wd) =?Wd = FdCosθ
Wd = 15 × 3 × Cos 30
Wd = 45 × Cos 30
Wd = 38.97 J
Therefore, we can conclude that the work done is 38.97 J
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Two pulses are moving along a string. One pulse is moving to the right and the second is moving to the left. Both pulses reach point P at the same instant.
Since Two pulses are moving along a string, Mu response is Yes, there be an instance in which the wave interference is at the same level as point X because there will be an overlap in the way of the slope of the waves.
What happens when 2 pulses meet?When two pulses collide to produce a bigger pulse, this is called constructive interference. The two beginning pulses' amplitudes are added to create the size of the final pulse.
Note also that if two waves collide while moving across the same medium, wave interference is the result. The medium assumes a shape as a result of the net impact of the two distinct waves on the medium's particles due to wave interference.
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See full question below
Two pulses are moving along a string. One pulse is moving to the right and the second is moving to the left. Both pulses reach point X at the same instant.Will there be an instance in which the wave interference is at the same level as point X?
a boy wishes to cross a river in the shortest possible time, without necessarily landing directly across from his starting point. he can row at 2 m/s in still water and the river is flowing at 1 m/s. at what angle θ should he point the bow (front) of his boat?
He should bow his boat at 90° to cross the river.
While the water will push him in side ways, it will not affect the time it takes to actually cross the river.
Hence, the correct answer is 90°.
Factors that have an effect on the velocity of a river consist of the slope gradient, the roughness of the channel, and tides. Rivers generally tend to drift from a higher elevation to a lower elevation. The gradient is the drop of the elevation of a river.
Reverberation is the time taken for the sound to fall beneath the minimal audibility measured from the immediate whilst the supply stopped sounding. Therefore if the reverberation time will become too massive it produces an echo.
Due to velocity of water drift in river, a person either swimming or floating stationary within the river reports a pushing force alongside the flow direction.
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10.A fairground ride spins its occupants inside a large teacup. If the radius of the
circular path is 10m and the acceleration is 1.5g, what is the speed of the riders?
Radial acceleration is inversely related to the radius of the curved pathway and directly proportional to the square of the linear speed. The ratio of the square of the angular speed to the radius of the curved pathway is directly proportional to the radial acceleration.
Explain about the radius and acceleration?This is the acceleration of an object moving at speed v within a circle of radius r. Therefore, as you may have experienced while driving a car, centripetal acceleration is greater at high speeds and in acute curves (smaller radii). y.
We can argue that as the radius increases, the centripetal acceleration of the item moving in a circle falls exponentially. Along the radius, the centripetal acceleration's magnitude diminishes.
The centripetal acceleration would be decreased if the radius were decreased while all other factors remained constant, but it would be increased if the speed were increased while all other factors remained constant.
The radius of the circular path is 10m and the acceleration is 1.5g the speed of the rider is 1.82 m/s/s.
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What layer of the mantle moves with the convection current?
Magma is the layer of the mantle that moves with the convection current.
How does the mantle layer move with convection current?Magma is the molten rock that is present in the mantle below the earth's crust. The high amount of heat and pressure inside the earth leads to hot magma that flows in convection currents. These currents cause the movement of the tectonic plates that formed the earth's crust. Mantle convection is defined as the movement of the mantle that transfers heat from one layer to another. The mantle is heated from the lower side but it is cooled from the upper side so the temperature decreases over long periods.
So we can conclude that the layer of the mantle that moves with the convection current is the magma layer.
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A family drove 2,275 miles from los angeles to atlanta in a time span of 35 hours. calculate their average speed in miles per hour. what is the avarge speed
The average speed in miles per hour is 65 mph.
Total distance d = 2275 miles
Total time t = 45 hours
To calculate average velocity
v = d/t
where v is velocity, d is distance and t is time.
v = 2275/45
v = 65 mph.
Thus, the average speed in miles per hour is 65 mph.
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A tennis player hits a ball vertically with a speed of 10 m/s. How high does it go?
Answer:
5.1 m
Explanation:
Assuming gravitational force is 9.8 m/s², the acceleration experience by the ball is -9.8 m/s²
The acceleration is negative because the ball is moving vertically upward and gravitational force acts vertically downward.
The velocity of the ball at maximum height is 0 m/s when it will start falling back to ground at a positive acceleration of 9.8 m/s²
We can use the following formula to calculate the height the ball reaches
v² = u² + 2 a d
where u is the initial velocity, v = final velocity, a = acceleration and d = displacement(in this case the vertical height from ground)
Final velocity is 0 since the ball has reached it maximum height and starts falling downward, Initial velocity u = 10 m/s
Plugging in values we get
0² = 10² - 2 x 9.8 x d
0 = 100 - 19.6d
Subtracting 100 from both sides
-100 = -4.9 d
Divide by -1 both sides
100 = 4.9d
d = 100/4.9 ≈ 5.1 m
So the ball will reach a height of 5.1m
A ball is seen at an initial position of 12m. It moves with an average velocity of 10m/s. How long will it take for the ball to reach the 98m mark?
The ball will take 8.6 sec to reach the 98m mark.
Given,
The initial position of the ball = 12m
The final position of the ball = 98m
The velocity of the ball = 10m/s
The displacement of the ball = (98-12)
= 86m
We know,
Average velocity = Displacement/time
Therefore,
Time = Displacement/velocity
= 86/10
= 8.6 sec
So, the ball will take 8.6 sec with average velocity of 10m/s to reach the mark of 98m from initial position of 12m.
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A battery-powered lawn mower has a mass of 49.0 kg. If the net external force
on the lawnmower, including both your push and any resistance, is 28.0 N (about
6.3 pounds), then what will be the magnitude of the mower’s acceleration?
is your interest equal to zero, meaning the line passes through the origin? if not then did we miss something when we said f in equation 5 was only due to spring force
When the angle between the force and the displacement is more than 90 degrees, work might be negative. It can also be zero; if = 90, this will occur.
The spring force, which defines the force applied to an object by the end of an ideal spring, is the most well-known illustration of a force whose value varies on position. An ideal spring will exert a force on the object attached to one end that is proportionate to how much it is stretched, and a force that is proportional to how much it is compressed on the object linked to the other end.
The force must function in order to accomplish its mission have a component that is parallel to the motion's direction or the opposite.
We must compute an integral (a sum) to determine the work done if the force acting on the object is not constant while it is moving.
Assume that an external force with the x component Fx(x) is acting on the object, causing it to travel in a straight line (let's say along the x axis, from xi to xf). (Or, we understand the force Fx to be a function of x.)
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q3. a v-tube with angle thetatheta contains some liquid of density ???????? inside and is open to atmosphere at point a. the height of the v-tube is HH. the v-tube can rotate along the axis ab at different speed. assume atmospheric pressure to be PP0. (1) what angular velocity ???????? can cause the pressure at b and c to be equal? (2) find the minimum pressure and its location along bc.
an angled v-tube Theta theta is open to the atmosphere at point a and contains some viscous liquid outside. The v-tube is HH in height. The speed at which the v-tube rotates along axis ab is variable. Assume that PP0 is the atmospheric pressure.
Atmosphere
An atmosphere is a subcaste of gas or layers of feasts that wrap an earth and are held in place by the gravity of the planetary body (from Ancient Greek: "atmós" "vapour," "brume," and "sphaîra" "sphere"). When the graveness is strong and the temperature of the atmosphere is low, the earth keeps its atmosphere. The outer portion of a star, known as its astral atmosphere, is made up of the layers above the opaque photosphere; low-temperature stars may have astral atmospheres that contain emulsion motes.
Nitrogen (78), oxygen (21), argon (0.9), carbon dioxide (0.04), and trace gases make up the Earth's atmosphere.
Most species utilize oxygen for respiration, while shops, algae, and cyanobacteria use carbon dioxide for photosynthesis. Lightning and bacteria use nitrogen obsession to manufacture ammonia, which is used to synthesize nucleotides and amino acids. The atmosphere's stratified structure reduces the dangers of the sun, UV radiation, solar wind, and cosmic shafts to protect species from irreparable harm. The biochemical modification of the pale atmosphere by living beings billions of times has led to the makeup of the Earth's atmosphere as it is now.
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4.
Both solenoids and electromagnets
produce magnetic fields using
A electric current and coiled wires
B
compasses and magnetic fields
C coiled wires and a ferromagnetic core
D electric current and a battery
Both solenoids and electromagnets produce magnetic fields using electric current and coiled wires. The correct option is A
What are electromagnets?An electromagnet can be defined as a type of magnet in which the magnetic field is produced by an electric current.
Electromagnets usually consist of wire wound into a coil.
Both solenoids and electromagnets produce magnetic fields using electric current and coiled wires.
The simple arrangement and construction of electromagnets requires an insulated copper wire, iron rod and battery.
Electromagnets has some advantages which includes :
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32. Use billiard balls to model the motion of particles in a gas. Use students in a crowded
hallway to model the motion of particles in a liquid. Use an audience in a movie theater to model the
motion of particles in a solid.
55
The particles of a solid are in fixed positions, the particles of a liquid do not translate to a large extent while the particles of a gas has extreme degree of freedom.
What are particles?We have to refer to the kinetic molecular theory at this point. We would recall from the theory that the particles that compose a substance are said to be in a constant random motion. As such, the molecules of a gas do have the greatest degree of freedom thus they move about freely. On the other hand, the molecules that compose a solid have the least degree of freedom as they remain in their fixed positions and can only vibrate.
Billiard balls are free to have about and they move at high speeds since they are spaced from each other. This is the nature of the interaction between the molecules of a gas.
Students in a hall way that is crowded can be used to approximate liquid particles because they do not posses a high degree of freedom but the molecules could move a few inches away from each other.
For a solid. an apt approximation is the audience in a movie theater. This is because, they can only remain on their seats just as the particles in a solid retain a fixed position and do not translate.
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3. Alice and Kai were playing air hockey, which is a game where players hit a puck with paddles so the puck slides across
a table. After the game, they were crashing the puck and two different paddles. The puck was the same in both crashes.
but the paddles were different: the red paddle had less mass, while the purple paddle had more mass. Use the
information in the diagram to answer.
In which crash did the puck experience a stronger force? Why?
Answer: Purple because it is greater than the red in mass and the more mass and the more mass it is the stronger it would be to have a change in velocity.
Explanation:
Answer:
Crash 2
Explanation:
The force on purple paddle was stronger, so the force on the puck has to be stronger
what is the total work wfric done on the block by the force of friction as the block moves a distance l up the incline? express the work done by friction in terms of any or all of the variables μ , m , g , θ , l , and f1 .
The work done by friction W = (F1 - mg sin θ) L, W = -μ mg cos θ L.
Use Newton's Second Law to find the force of friction. In these tasks, the X-axis will be parallel to the plane and the Y-axis will be perpendicular to the plane:
Y-Axis
N - =[tex]w_{y}[/tex]
N = W_{y}
X axis
F1 - fr - Wₓ = 0
fr = F1 - Wₓ
Let's use trigonometry to find the components of the weight
sin θ = Wₓ / W
cos θ = W_{y} / W
Wₓ = W sin θ
W_{y} = W cos θ
We substitute
fr = F1 - W sin θ
Work is defined by
W = F .dx
W = F dx cos θ
Since the friction force is in the negative direction parallel to the plane and the displacement along the plane is positive, the angle is 180° and cos θ = -1
W = -fr x
W = (F1 - mg sin θ) L
Another way to calculate is
fr = μ N
fr = μ W cos θ
the work is
W = -μ mg cos θ L.
Zero work can occur in any of the following situations When a single force is applied but no displacement. There are gaps but the power of the individual is not showing. A single force is applied in a direction perpendicular to the direction of displacement.
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6. If an object's velocity increases from 13.2 m/s to 15.1 m/s in 8.00 seconds, what
is the acceleration of the object?
A. 1.89 m/s²
B. -0.250 m/s²
C. -1.65 m/s²
D. 0.238 m/s²
Answer:
Acceleration 0.238 m/s²
Explanation:
Given:
V₀ = 13.2 m/s
V = 15.1 m/s
t = 8.00 s
__________
a - ?
Is the acceleration of the object:
a = (V - V₀) / t
a = (15.1 - 13.2) / 8.00 ≈ 0.238 m/s²
Acceleration of the object is 0.238 m/s²
What is acceleration?Acceleration of an object is rate of change of velocity with respect to time. Due to having both direction and magnitude, it is a vector quantity of SI unit meter/second².
Given parameters:
Initial velocity; V₀ = 13.2 m/s
Final velocity; V = 15.1 m/s
time; t = 8.00 s
acceleration of the object; a = ?
We know, for accelerated object;
acceleration; a = (V - V₀) / t
⇒a = (15.1 - 13.2) / 8.00 ≈ 0.238 m/s²
Hence, acceleration of the object is 0.238 m/s².
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A rock climber stands on top of a 53 m -high cliff overhanging a pool of water. He throws two stones vertically downward 1.0 s apart and observes that they cause a single splash. The initial speed of the first stone was 1.5 m/s. How long after the release of the first stone does the second stone hit the water?
Express your answer to two significant figures and include the appropriate units.
A rock climber stands on the top of a 53 m high cliff overhanging a pool of water, so for 3.1 seconds, after which the second stone hit the water.
What is the average speed?The overall distance the object covers in a given amount of time is its average speed. The scalar quantity represents the average speed. It does not have direction; it is represented by magnitude.
Average Speed= [tex]Total\ Distance/ Total\ time[/tex]
According to the question, the given values are :
v₁ = 1.5 m/s
y₂ = 52 m
y₁ = 0 m
Acceleration, a = 9.8 m/s²
Use Formula :
y₂ = y₁ + v₁t + 0.5 at²
52 = 0 + 1.5t + 0.5 (9.8)t²
4.9 t² + 1.5 t - 52 = 0
[tex]t=-b\frac{+}\ \sqrt{b^2-4ac}/2a[/tex]
t = -1.5 + [tex]\sqrt{2.25+1019.2}[/tex]/9.8
t = (-1.5 + 31.9)/9.8
t = 3.10 seconds.
Hence, the time period will be 3.10 seconds.
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Which one of the following vector pairs is equal in magnitude and opposite in direction?Vectors
explained image
a)one short and one long arrow going towards each other
b)one short and one long arrow going right in the same direction
c)two of the same size arrows going right in the same direction
d)two of the same size arrows going in towards eachother
Select one:
a. A
b. B
c. C
d. D
Answer
(D) the vectors must be the same size and pointing opposite to each other
An elephant ran 300 meters in 20 seconds, what was his speed?
Answer: 40 km/hr ( c )
Explanation:
Distance =20 km
Time =30 min=
60
30
hr=
2
1
hr
∴ Speed =
time
Distance
=
(
2
1
hr)
20 km
⇒ Speed =40 km/hr
Option (C) is correct.
derive triangular law or parallelogram law of vectors to find the magnitude of the resultant and direction of two vectors