In a certain clothing store, 3 shirts and 5 ties cost $60, and 2 shirts and 3 ties cost $39. What is the cost of each shirt? If s = the cost of a shirt and t = the cost of a tie, which system of equations represents the problem? 3s 5t = 60 and 2s 3t = 39 s t = 60 and 5s 8t = 99 3t 5s = 60 and 2t 3s = 39.

Answer:

25%

Step-by-step explanation:

4/16 days were under 78 degress

Step-by-step explanation:

Use the Distributive Property:

[tex]-2(5x-1)+7(5x-1)-3(5x+1)[/tex]

[tex]-10x+2+35x-7+15x-3[/tex]

P is correct.

Simplify:

[tex]40x-8[/tex]

T is correct using FOIL or distribution.

Use the FOIL method to simplify:

Use 5x-1 then multiply with -2, 7, and -3.

Note: With -3, -5x + 1 is in the parenthesis, we need to change -3 to 3.

Changing -3 to 3 will equal the distribution of -3(-5x+1).

Our expression: [tex](5x-1)(-2+7+3)[/tex]

S is correct.

Answer:

90 boxes.

Step-by-step explanation:

Simplify the equation. You get 1 box per 6 minutes.

Answer:

adjacent. x=55

Step-by-step explanation:

Answer:

Adjacent

x=55

Step-by-step explanation:

Vertical angles are made by the same lines but are opposite of each other. These angles are not opposite, and thus they are not vertical. Adjacent angles, on the other hand, share a common side and vertex. In other words, they touch. So, since these share both a common side and vertex, they are adjacent.

Additionally, the large-angle (that contains the smaller, adjacent angles) is a right angle, meaning that it has a measure of 90 degrees. So, if we know that part of the angle is 35 degrees, then the missing angle must be equal to 90-35. 90-35=55 degrees.

Answer:

Calculate one-time simple interest, and simple interest over time

Determine APY given an interest scenario

Calculate compound interest

Answer:

Compound interest

$5557.88

Step-by-step explanation:

Everything starts at 100% and since it depreciates you subtract 13.5 from 100 =86.5% now we want percentage as a decimal so we divide by 100=0.865 our multiplier

Now you have the original amount that you purchased for times by the multiplier to the power of number of years=10

23700 times 0.865 power of 10

=5557.88

Law of cosine is applicable to all the triangles. The value of the angle by which the boat turns is 39.195°.

Law of cosine helps us to find the third side of the triangle when 2 sides and an angle are known. It is formulated as,

[tex]c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}[/tex]

a, b, c is the sides of the triangle and,

[tex]\gamma[/tex] = angle opposite c

A.)

Given to us

A boat traveled north for 28 miles, then turned x° southwest and traveled for 25 miles before stopping.

When it stopped, the boat was 18 miles from its starting point.

According to the given statements, sides and angles can be written,

a = 25 miles

b = 28 miles

c = 18 miles

[tex]\theta = x^o[/tex]

Substitute the values,

[tex]c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}[/tex]

[tex]18=\sqrt{25^{2}+28^{2}-2(25)(28) \cdot \cos \theta}\\\\\theta = 39.195^o[/tex]

Hence, the value of the angle by which the boat turns is 39.195°.

B.)

Given to us

Starting at the dock, it travels 18 miles to the left, then 25 miles up and to the right, and then 28 miles down and back to the dock.

The angle between 25 miles and 28 miles is x degrees.

According to the given statements, sides and angles can be written,

a = 25 miles

b = 28 miles

c = 18 miles

[tex]\theta = x^o[/tex]

Substitute the values,

[tex]c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}[/tex]

[tex]18=\sqrt{25^{2}+28^{2}-2(25)(28) \cdot \cos \theta}\\\\\theta = 39.195^o[/tex]

Hence, the value of the angle by which the boat turns is 39.195°.

Learn more about the Law of cosine:

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Answer:

Its 39 degrees on Edge

Step-by-step explanation:

Your welcome

Answer:

Is there a picture that goes with this because we can't solve with the information given

Step-by-step explanation:

Please upload a picture or comment more details and I will edit my answer to solve Thanks :)

The length of the line segment AB is √3 inches.

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Given, length of the diagonal of rectangle ABCD = 2 inches.

We have to find the length of the line segment AB.

We know, opposite sides of a rectangle are equal.

Thus, AB = CD

Now consider triangle DCB, which is a right angled triangle

In triangle DCB, angle C is 90°

Angle D is 30°

Angle B is 60°

By Pythagoras theorem,

sin θ = opposite/hypotenuse

sin 60° = CD/BD

√3/2 = CD/2

CD = 2(√3/2)

CD = √3

Thus, AB = CD = √3

Therefore, the length of the line segment is √3 inches.

To learn more on trigonometry click:

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Answer:

The numerator of the first fraction 8 is greater than the numerator of the second fraction 3 , which means that the first fraction 812 is greater than the second fraction 312 and that 23 is greater than 14 .

Step-by-step explanation:

Answer:

-3/2

Step-by-step explanation:

[tex]2 \frac{3}{4} - 4 \frac{1}{4} \\ = > \frac{11}{4} - \frac{17}{4} \\ = > \frac{ - 6}{4} \\ = > \frac{ - 3}{2} [/tex]

Answer:

3.25

Step-by-step explanation:

Answer:

3.25

Step-by-step explanation:

through ling division, the answer is 3.25.

Answer:

2 with a remainder of 10

Step-by-step explanation:

11 goes into 32  2 times which is 22. Then there is 10 leftover as a remainder.

Hi there!

The answer is →[tex]15 \sqrt{3}[/tex]←

(Check the attached image for the explanation)

Answer:

34

Step-by-step explanation:

We know the area is 52 cm and that one length is 13cm. This means that in order to find the missing length, we need to divide 52 by 13. this gives us 4, meaning that the missing side is 4 cm.

Now we add 26 (Double of 13 because it is both sides) to 8 (Double of 4 because they are same lengthening sides)

We then get 34.

Hope this helps :)

Area of a polygon can be derived from sum of area of its sub-parts. The area of the considered polygon is given by: Option C: 316 cm²

Some polygon are of standard shapes like rectangle, triangle, parallelogram etc, but some are not standard and can be of any shape. For finding their area, we divide that non-standard polygon in parts such that it gets divided in standard polygons.

Then, we get:

Area of non-standard polygon = sum of all standard polygons forming that initial polygon.

For the given case, dividing the polygon in the shapes whose area we know(which is called here as standard polygons), as shown in the figure attached below, we get:

Area of polygon = Sum of area of those composing parts.

Area of polygon =  Area of upper triangle ABC + Area of bottom rectangle BDEF

Height of ABC triangle = height of polygon - height of rectangle

Height of ABC = 18 - 14 = 4 cm

Base of ABC = length of BC = length of BD - length of CD = 21-10 = 11 cm

Thus, area of ABC = [tex]\dfrac{1}{2} \times base \times height = \dfrac{1}{2} \times 4 \times 11 = 22 \: \rm cm^2[/tex]

Area of rectangle BDEF = length times width = [tex]14 \times 21 = 294\: \rm cm^2[/tex]

Thus, area of polygon = Area of ABC + Area of BDEF = 22 + 294  cm²

Area of polygon = 316 cm² (option C)

Learn more about total area here:

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Answer: 338 cm^2

Hope this helps! :)

Please mark me brainliest.

Given Function is

[tex] \: [/tex]

[tex] \: \: [/tex]

Now , Put The Value Of x = - 2

[tex] \: \: [/tex]

[tex] \frak{f(x) = {x}^{2} - 3x }[/tex]

[tex] \: \: [/tex]

[tex] \frak{f( \red{ - 2}) = { (\red{ - 2})^{2}} - 3 ( \red{- 2})}[/tex]

[tex] \: \: [/tex]

[tex] \frak{f{ (\red{ - 2})} = \red{ - 4} + 6}[/tex]

[tex] \: \: [/tex]

[tex] \boxed{\frak { \large \: f( \red{ - 2}) = \red 2}}[/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

[tex] \: \: [/tex]

Hope Helps! :)

Given the data from the question, the value of the function f(–2) is obtained as 10

Substituting the the value of x into the expression, we have

f(x) = x² – 3x

f(–2) = (–2)² – 3(–2)

f(–2) = 4 + 6

f(–2) = 10

From the calculation made above, we can conclude that the value of f(–2) is 10

Learn more about function:

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Answer:

2=(2,4,6,8,10,12,14,16,18)

4=(4,8,12,16)

Answer:

2.1use bodmas

32/32=1

-25*25=-625

96+-96==0

ans=1-625

=-624

Answer:

- 624

Step-by-step explanation:

96+(-96)+32/32 - 25*25

-> 0+32/32-(25)(25)

-> 32/32 - (25)(25)

-> 1-(25)(25)

-> 1- 625

-> -624

Answer:

a= $60

b= $660

Step-by-step explanation:

0.05 x 600 = 30

30x2 =60

Answer: For stamped, the answer is $25.96. For One Crazy Summer, the answer is $20.49. For A Girl Named Summer, the answer is $26.49.

Step-by-step explanation:

The equation is simple. Add the $3.99 to the original price, then add 13%.

X+3.99+13%, and X equals the original price.

Hope this helps!

I believe these are the answers:

1. True.

2. False.

3. False.

4. True.

Let me know if those are right. :)

Answer:

1005

Step-by-step explanation:

If you just kept subtracting from 2580 then the next and then the next number you would get 1005

Answer:

A or the total number of spikes Bella has

Answer: The number of Beetiebots to decorate

Step-by-step explanation:

Answer:

x = 4

Step-by-step explanation:

Let's look at the ratio of the hypotenuse of both triangles:

25 : 5 = 25/5 = 5

we can see that the measures of the sides of the larger triangle are 5 times those of the smaller triangle.

Therefore, 3x + 8 = 4 x 5

⇒ 3x + 8 = 20

⇒ 3x = 20 - 8 = 12

⇒ x = 12 ÷ 3 = 4

⇒ x = 4

Answer:

x=4

Step-by-step explanation:

As you can see, these triangles are demonstrating a scale factor. It is upscaling by 5. To find out what x is equal to, we need to upscale the smaller side. In this scenario, we have to multiply 4 by 5. This will get you 20. Now we can make an equation.

20=3x+8

We can subtract 8 from both sides.

Now we have:

12=3x

now dividing 12 by 3, we get

x=4

Answer:

9

Step-by-step explanation:

Answer: he has 30 sweets

Step-by-step explanation:

3:2 - five parts all together

50 divide 5 = 10

10 x 3 because the 3 in 3:2

=30

Answer:

hii I am new can be friends

Answer:

1&0

Step-by-step explanation:

Enter a value for side 1 in metres with optional centimetres.

Enter a value for side 2 in metres with optional centimetres.

Click associated Get Results button.

Square metres (m2) and centimetres (cm2) remainder is shown.

Multiple calculations can be placed in the textbox below by pressing Move Results.

Multiple calculations total area is shown in the Grand Total Square Metres text box.

Step-by-step explanation:

Given that:

∛(2) * 2^(-1/13) * ¹²√(32)

= ∛(2) * 2^(-1/13) * ¹²√(2⁵)

[since, ⁿ√(a) = a^(1/n)]

= 2^(1/3) * 2^(-1/13) * 2^{5 * (1/12)}

= 2^(1/3) * 2^(-1/13) * 2^{(5*1)/12}

= 2^(1/3) * 2^(-1/13) * 2^(5/12)

[since, a^m * a^n = a^(m+n)]

= 2^{(1/3) - (1/13) + (5/12)}

Take the LCM of 3, 13 and 12 is 156.

= 2^[{(1*52) - (1*12) + (5*13)}/156]

= 2^{(52 - 12 + 65)/156}

= 2^{(117 - 12)/156}

= 2^(105/156)

Now reduce the power fraction in simplest form by cancelling method.

= {2^(35)}^(1/52) (or)

= ⁵²√{2^(35)}

Answer: Hence, the simplified form of ∛(2) * 2^(-1/13) * ¹²√(32) = ⁵²√{2^(³⁵)}.

Please let me know if you have any other questions.

Applying the law of indices to the roots, we have that

[tex]\sqrt[n]{x} = x^{\frac{1}{n} }[/tex]

So,

[tex]\sqrt[3]{2}[/tex] × [tex]2^{-\frac{1}{13} }[/tex] × [tex]\sqrt[12]{32}[/tex] = [tex]2^{\frac{1}{3} }[/tex] × [tex]2^{-\frac{1}{13} }[/tex] × [tex]32^{\frac{1}{12} }[/tex]

=  [tex]2^{\frac{1}{3} }[/tex] × [tex]2^{-\frac{1}{13} }[/tex] × [tex](2^{5} )^{\frac{1}{12} }[/tex]

= [tex]2^{\frac{1}{3} }[/tex] × [tex]2^{-\frac{1}{13} }[/tex] × [tex]2^{\frac{5}{12} }[/tex]

Since we have the same base in all three numbers, we have that from the law of indices, [tex]a^{x}[/tex] × [tex]a^{y}[/tex] = [tex]a^{x + y}[/tex]

= [tex]2^{\frac{1}{3} }[/tex] × [tex]2^{-\frac{1}{13} }[/tex] × [tex]2^{\frac{5}{12} }[/tex]

[tex]= 2^{\frac{1}{3} + (-\frac{1}{13}) + \frac{5}{12} } \\= 2^{\frac{1}{3} - \frac{1}{13} + \frac{5}{12} }[/tex]

Taking L..C.M of the denominators of the exponents, the L.C.M is 156.

So,

[tex]2^{\frac{1}{3} - \frac{1}{13} + \frac{5}{12} }\\= 2^{\frac{52 - 12 + 5 X 13}{156} } \\= 2^{\frac{52 - 12 + 65}{156} }\\= 2^{\frac{40 + 65}{156} }\\= 2^{\frac{105}{156} }[/tex]

Simplifying the exponent, we have

[tex]2^{\frac{105}{156} } \\= 2^{\frac{35}{52} }[/tex]

So, [tex]\sqrt[3]{2}[/tex] × [tex]2^{-\frac{1}{13} }[/tex] × [tex]\sqrt[12]{32}[/tex] = [tex]2^{\frac{35}{52} }[/tex]

Learn more about indices here:

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Answer:  " [tex]3\sqrt{154}[/tex] " ;

           or, write as:  " 37.229 " .
__________

Step-by-step explanation:
The digits of "1386" ;

add up to:  " (1 + 3 + 8 + 6) " ;

                 = " (1 + 3) + 8 + 6 " ;

                 = " (4) + 8 + 6 ;

                 = " (4 + 8 + 6) " ;

                 = " (4 + 8) + 6) " ;

                 = " (12) + 6 "

                 =  "18 " ;  

"18" is divisible ("evenly") ; by both: "2" :  {" 18 ÷ 2 = 9 ".} ;
                                            and by:  "3" :  {" 18 ÷ 3 = 6 ".}

Note:  If a number is "evenly divisible by both: "2" and "3" ; then said number is divisible by "6" ;
_________

Other: If the sum of the digits of a number result in a number that is evenly divisible by "9" ; then said number is evenly divisible by "9" ;
_________
  The sum of the digits of "1386" is: "18" ;
and:  the sum of the digits of:  "18" ;  ⇒ " 1 + 8 = 9" .
  {and:  " 9 ÷ 9 = 1 ".}.
_________
Note: If  number that ends with the last 2 (two) digits; in consecutive order; in which, taken as a "separate number" , is evenly divisible by "4" ; then, the entire said number is evenly divisible by "4".
  Note:  The number given:  "1386 " ; ends with:  "86" ;
             and:  " 86 ÷ 4  = 21.5" ; so we know that:
     "1386" is not evenly divisible by "4".
_________
Note: If a number ends with the digit: "5" ; or "0" ; then the number is evenly divisible by: "5" .  The number:  "1386" ; does not meant either of these criteria.
_________

Note: If a number ends with the digit:  "0" ; then the number is evenly divisible by: "10" .  The number:  "1386" ; does not meant this criterion.

_________
Note:  If a number ends with the last 2 (two) digits; in consecutive order; in which, taken as a "separate number" , is evenly divisible by "7" ; then, the entire said number is evenly divisible by "7".
 Note: The number given:  "1386 " ; ends with:  "86" ;
             and:  " 86 ÷ 7  = 12[tex]\frac{2}{7}[/tex] " ; so we know that:
     "1386" is not evenly divisible by "7".
_________
Note: If a number ends with the last 2 (two) digits; in consecutive order; in which, taken as a "separate number" , is evenly divisible by "4" ; then, the entire said number is evenly divisible by "4".
  Note: The number given:  "1386 " ; ends with:  "86" ;
             and:  " 86 ÷ 4  = 21.5" ; so we know that:
     "1386" is not evenly divisible by "4".
_________

Note:  If a number ends with the last 3 (three) digits; in consecutive order; in which, taken as a "separate number" , is evenly divisible by "8" ; then, the entire said number is evenly divisible by "8".
  Note:  The number given: "1386" ; ends with: "386" ;
             and:  " 386 ÷ 8 = 28[tex]\frac{1}{4}[/tex] " ; so we know that:
      "1386" is not evenly divisible by "8" ;
_________
Since: we know that "1386"  is evenly divisible by "9" ;

and "9" is a perfect square;  

  {since: " 3² = 3 * 3 = 36 " ; and since:  " [tex]\sqrt[]{9} = 3[/tex] " }.

Let's see what the other factor of "1386" is when "9" is a factor:
  " 1386 ÷ 9 = 154 " ;  

_________
So:  √(154) ;

            =  √9  * √(154) ;

            =   3 *   √(154) ;

Let's look at the factors of 154:
_________
 ⇒   1 & 154;  2 and 77;

List this factors of "154" as:  1, 2, 77, 154;

    →  none of which are "perfect squares" ;

→  So, the answer is:  " [tex]3\sqrt{154}[/tex] " ;

     or: further calculate with a calculator:
         →   " [tex]3 * \sqrt{154} =[/tex][tex]37.2290209379725698[/tex] " ;

          →     round to:   " 37.229 ".

_________
Hope this is helpful.  Best wishes!
_________