Physics College

In a physics lab, Ray Zuvlite arranges two mirrors with a right angle orientation as shown. Ray then directs a laser line at one of the mirrors. The light reflects off both mirrors as shown. If angle A is 38°, determine the what is the angle measure of angles B, C, and D?

Answers

Answer 1

The angle measure of angle B = 25° and angle C = 65° and angle D = 25°.

What is meant by measure?Through the use of a protractor, angles are measured in degrees (°). In order to calculate or draw angles in terms of degrees, a protractor is a measuring tool that is utilized. Using a protractor, for instance, we can observe that the black arrow in the image below crosses the 90° line at 100°. Thus, the angle has a 100° measurement. A degree is a unit of measurement for a plane angle in which one complete rotation equals 360 degrees, generally indicated by the symbol °. It is included in the SI brochure as an acceptable unit even though it is not a SI unit—the radian is the SI unit of angular measure.

The given parameters are;

The orientation of the two mirrors = At right angle to each other

The laser light is directed at one of the mirror

The measure of angle, A = 25°

The measures of angle B, C, and D are found as follows;

We have;

∠A = ∠B = 25°, by angle of incidence equals angle of reflection

∠B = 25°

∠B + ∠C = 90° by sum of the acute angles of a right triangle

25° + ∠C = 90°

∴ ∠C = 90° - 25° = 65°

∠C = 65°

∠E = ∠C = 65° by angle of incidence equals angle of reflection

∴ ∠E = 65°

Line 'L' is perpendicular to the second mirror, therefore, the angle between line 'L' and the second mirror = 90° = ∠E + ∠D

∠E + ∠D = 90°,  by angle sum property

Therefore;

65° + ∠D = 90°

∴ ∠D = 90° - 65° = 25°

∠D = 25°

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Related Questions

establish the relation among energy, density, strain and stress

Answers

Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation.

Two physical science classes are playing tug of war. Mrs. Hankinson’s class pulls left with a force of 100 N, while Mrs. Wade’s class pulls with a force of 105 N in the opposite direction.


What is the net force, and which class won?


A. 205 N, Mrs. Wade's class

B. 5 N, Mrs. Wade's class

C. 205 N, it was a tie

D. 5 N, Mrs. Hankinson's class

Answers

The net force is 5 N and the class that won is Mrs. Wade's class (Option B)

How do I determine the net force?

We can obtain the net force by using the following formula:

Net force = Opposite force - force of pull

Now, we shall determine the net force as illustrated below:

Force by Mrs. Hankinson’s class = 100 NForce by Mrs. Wade’s class = 105 NNet force =?

Net force = Opposite force - force of pull

Net force = Mrs. Wade’s class - Mrs. Hankinson’s class

Net force = 105 - 100

Net force = 5 N

From the above calculation, we can say that the net force is 5 N and the class that won given the above data is Mrs. Wade’s class

Therefore, the correct answer to the question is:

5 N, Mrs. Wade's class (Option B)

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