5√3 is of the diagonal of rhombus .
What is a rhombus, exactly?
A parallelogram has a unique variation known as a rhombus. A rhombus has opposing sides that are parallel and opposing angles that are equal.
A rhombus's diagonals are right angles to one another, and all of its sides are equal in length. The term "rhombus" can also refer to a diamond or rhombus.
Since all the sides are equal, the altitude is
10 sin60° = 5√3
To see this, draw the rhombus ABCD and drop an altitude from D to AB.
Now you have a right triangle with hypotenuse=10 and base angle=60°
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Find the sum of all three - digit numbers which give a remainder of 5 when they are divided by 7 immediately
Answer: As Devansh Sehta has calculated, there are 82 terms and 82=7×11+5. When each term of S is divided by 7, the remainders, in order are 6, 3, 0, 4, 1, 5, 2, and these repeat.
Step-by-step explanation:
For any arithmetic sequence, record the remainders when successive terms are divided by n. Then the sum of every set of n consecutive remainders is divisible by 7. In this case, the first 77 terms add to a multiple of 7 as do the 5 remaining terms.
DJ was going to meet his family at the beach in NC. He looked on a map and saw that the beach he was going to was 800 km from his house and he knew he would average 110 km/hr on the highway. How long is it going to take him to get to the beach?
On average, it is going to take DJ 7.27 hours to get to the beach.
What is the average?Average refers to the quotient when a numerator is divided by a denominator.
In this situation, the average refers to the time, which is the quotient of the distance and speed.
The total distance going to the beach from his family = 800 km
The average speed = 110 km/hr
The time to cover the distance of 800 km at 110 km/hr = 7.27 hours (800/110).
Thus, DJ will take 7.27 hours to cover 800 km at 110 km/hr.
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The charge in dollars for cab rides in one city is modeled by f(c) = 4 + 2.5m, when m is the number of miles traveled. What is the charge for a 4-mile ride?
How do you solve this
Answer:
(f+g), (f-g), (f·g), domain is [-3, 3]f/g, domain is [-3, 3)Step-by-step explanation:
Given f(x) = √(3+x) and g(x) = √(3-x), you want the domains of various combinations of f and g.
DomainsThe domain of each of these functions is the interval on which it is defined. The domain of the square root function is all argument values greater than or equal to zero.
Domain of fThe argument of the square root will be non-negative when ...
3 +x ≥ 0
x ≥ -3 . . . . . . subtract 3
-3 ≤ x . . . . . . written using left-pointing arrow
Domain of gThe argument of the square root will be non-negative when ...
3 -x ≥ 0
3 ≥ x . . . . . add x
x ≤ 3 . . . . . written using left-pointing arrow
Intersection of domainsAny combination of functions f and g will only be defined on the domain where both f and g are defined. That is, the domain will be the intersection of the domains of f and g:
(-3 ≤ x) ∩ (x ≤ 3) = -3 ≤ x ≤ 3
Domain of f+gThe domain of f+g is the intersection of the domains of f and g.
[-3, 3]
Domain of f-gThe domain of f-g is the intersection of the domains of f and g.
[-3, 3]
Domain of f·gThe domain of f ·g is the intersection of the domains of f and g.
[-3, 3]
Domain of f/gThe domain of f/g is the intersection of the domains of f and g, excluding the value of x that makes g(x) = 0. That value is x=3.
[-3, 3)
__
Additional comment
The graphs of the combinations of functions are attached. You notice the graph of f/g tends to infinity as x → 3. It is undefined at x=3.
A class measure the radius and circumference of various
It can be seen that the radius and circumferance are not proportional.
What is a expression? What is a mathematical equation? What is constant of proportionality?A mathematical expression is made up of terms (constants and variables) separated by mathematical operators.A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.For any function y = f(x), Domain is the set of all possible values of [y] that exists for different values of [x]. Range is the set of all values of [x] for which [y] exists.The general equation of a straight line is y = mx + c. The equation can also be used to represent direct proportionality as -
y = mx
m = y/x
[m] is called constant of proportionality.
Given is a graph as shown in the figure.
For the proportional relationship -
(25 - 18)/(4 - 3) should be equal to (38 - 25)/(6 - 4)
7/1 = 13/2
7/1 = 6.5
7 ≠ 6.5
Therefore, it can be seen that the radius and circumferance are not proportional.
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2/3x- 12 for x=18
show work
Why do you need to state restrictions on the variable when dividing rational expressions?.
It is important to state the restrictions before simplifying rational expressions because the simplified expression may be defined for restrictions of the original.
What is rational expressions?
The ratio of two polynomials is a rational expression. F can be expressed in the form p/q, where p and q are polynomials, if f is a rational expression.
Fractional terms are seen in rational expressions. We include constraints because with some x values, the equation may become undefined. Undefined inquiries are hypothetical or ideal. The seven expressions for undefined words are (∞-∞),∞^∞, N/0, 0⁰, 1^∞, ∞/∞ and 0×∞ respectively. N/0 is the most typical constraint on rational expressions. Any number divided by 0 is therefore undefined. For instance, if you substitute 0 for x in the case of the function f(x) = 6/x2, the outcome is 6/0, which is undefined. If you graphed this function, you would see a break at x=0.
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if the equation x^2 + 16x + c = 0 has only one real solution, the value of c must equal
If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
Discriminant:The quadratic formula includes the discriminant, which comes after the square root. The discriminant of a quadratic equation is important because it indicates the quantity and kind of solutions.
The formula for the Discriminant of a Quadratic Equation ax²+bx +c = 0 is given by
Discriminant Δ = b² - 4acHere we have
x² + 16x + c = 0 equation has only one real solution
Compare given equation with ax²+ bx + c = 0
=> a = 1, and b = 16
As we know when an equation has only one real solution
then its Discriminant will be equal to zero
=> b² - 4ac = 0
By the above values,
=> 16² - 4(1)c = 0
=> 256 - 4c = 0
=> 4c = 256
=> c = 256/4
=> c = 64
Therefore,
If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
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In a race, Jason's position was −11 1/5 feet relative to the leader after 1 3/4 minutes. On average, how much did Jason's position relative to the leader change per minute? Enter your answer as a mixed number, in simplified form, in the box.
The way Jason's position relative to the leader changed per minute is; 6²/₅ ft/minute
How to solve fractions?We are told that Jason's position was 11 ¹/₅ feet relative to the leader after 1 ³/₄minutes.
Now, the fractions are in mixed fraction form and so let us convert them to improper fractions to get;
⁵⁶/₅ and ⁷/₄
Thus, the way Jason's position relative to the leader changed per minute is; ⁵⁶/₅ ÷ ⁷/₄
= ⁵⁶/₅ * ⁴/₇
= 32/5
= 6²/₅ ft/minute
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I need help on these questions.
A boat travel 42 mile uptream in 3 hour looking for a lot diver. It then travel downtream 70 mile in 2 hour. Write a ytem to repreent the ituation. Then find the peed of the boat and the peed of the current. Ue b for boat and c for current
The speed of boat is 14 miles per hour and the speed of current 35 mile per hour
Speed:
The general formula to calculate the speed is written as
Speed = Distance/Time
Given,
A boat travel 42 mile uptream in 3 hour looking for a lot diver. It then travel downstream 70 mile in 2 hour.
Here we need to find the speed of boat and the speed of current.
While we looking into the given question, we have identified the following values,
Distance = 42 mile
time = 3 hour
Then the speed is calculated as,
=> speed = 42/3
=> speed = 14 miles per hour
Similarly, for the current is
distance = 70 miles
time = 2 hour
Then the speed is calculated as,
=> speed = 70/2 = 35 miles per hour.
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What is the equation in STANDARD FORM of the line that passes through the points (-4, 47) and (2, -16)?
A) y = -10.5x + 5
B) 2x + 21y = 105
C) 2x -21y = 979
D) 21x + 2y = 10
:)
The equation of the straight line is 2y + 21x = 10. The correct option is (D).
How to represent a straight line on a graph?To represent a straight line on a graph consider two points namely x and y intercepts of the line. To find x-intercept put y = 0 and for y-intercept put x = 0. Then draw a line passing through these two points.
The given points are (-4, 47) and (2, -16) respectively.
The equation of the straight line passing through them can be written as,
(y - 47)/(x - (-4)) = (-16 - 47)/(2 - (-4))
=> (y - 47)/(x + 4) = -63/6
=> (y - 47)/(x + 4) = -21/2
=> 2(y - 47) = -21(x + 4)
=> 2y - 94 = -21x - 84
=> 2y + 21x = -84 + 94
=> 2y + 21x = 10
Hence, the standard form of the straight line passing through given points is 2y + 21x = 10.
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what is the rate of change of the surface area of the prism at that instant (in square kilometers per minute)?
The surface area, A, is changing at a rate of 288 km/min decreasing.
Given,
Base length, l = 6 km
Height, h = 10 km
dl/dt = -9 km/min
dh/dt = 12 km/min
Surface area of a prism, A = 2 × (lw + lh + wh)
For a square prism,
Length, l = width, w = 6km
A = 2 × (l² + lh + lh)
= 2(l²) + 4lh
A = 2(l²) + 4 lh
= 2 × (l² + 2lh)
dA/dt = 2 × (2I × dI/dt + 0 × dh/dt + 2 × 2h × dl/dt + 2l × dh/dt)
dA/dt = 2 × (2l × dl/dt + 0 + 2 × 2h × dl/dt + 2l × dh/dt)
= 2 × (2(6) × (-9) + 2(10) × (-9) + 2(6) × (12))
= 2 × (- 108 + -180 + 144)
= 2 × -144
= -288 km/min
The rate of change of the surface area, A is decreasing by 288 km/min.
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Question is incomplete. Completed question is given below;
The length s(t)s(t)s, (, t, )of the side of the base of a square prism is decreasing at a rate of 9 kilometers per minute and the height h(t)h(t)h, (, t, )of the prism is increasing at a rate of 12 kilometers per minute. At a certain instant t_0t 0 t, start subscript, 0, end subscript, the base's side is 6 kilometers and the height is 10 kilometers. What is the rate of change of the surface area A(t)A(t)A, (, t, )of the prism at that instant?
Adelyn is planning to sell popcorn to raise money for a fundraiser.
She will need to rent a popcorn popper and will also need to purchase popcorn kernels, oil, salt, and bags.
She has at most $90 to spend on the fundraiser.
The rental of the popcorn popper costs $50.
The cost of popcorn kernels, oil, salt, and bags is $0.25 per serving.
Which inequality could be used to find out how many servings of popcorn that Adelyn will be able to make?
Answer: 50 + 0.25 is less than 90
Step-by-step explanation:
can someone help with this thank you so much .
Answer:
NO=6
Step-by-step explanation:
If MP=16 and NP=13 that means MN=3 and MO=9 so that makes NO=6
Pls help fast i need help right neow.
[tex]\angle R \cong \angle STV[/tex]: Alternate interior angles theorem
[tex]\angle TSV \cong \angle U[/tex]: Alternate interior angles theorem
[tex]\angle R \cong \angle TSV[/tex]: Transitive property of congruence
[tex]\angle R \cong \angle U[/tex]: Transitive property of congruence
Write the equation of the line passing through the points (10,3) and (-2,-3).
The equation of the line is
Answer:
[tex]y=\frac{1}{2} x-2[/tex]
Verizon charges $0.50 per minute plus a monthly base fee. In October, Noah used 200 minutes and his bill was $100
The monthly base fee of the situation is $0
How to determine the monthly base fee of the situationFrom the question, we have the following parameters that can be used in our computation:
Charges per minute = $0.50 per minute
Number of minutes = 200 minutes
Total charges = $100
The above parameters mean that
Total charges = Monthly Base fee + Charges per minute x Number of minute
Substitute the known values in the above equation, so, we have the following representation
Monthly base fee + 0.50 * 200 = 100
This gives
Monthly base fee + 100 = 100
Subtract 100 from both sides
Monthly base fee = 0
Hence, the monthly base fee is $0
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Determine if the two triangles are necessarily congruent. If so, fill in a flowchart proof to prove that they are.
Help please
The given statements are:
angle A = angle O (note the single tickmarks)side AC = side OM (these sides share a similar tickmark)angle C = angle M (note the double tickmarks)We can then use the ASA congruence theorem to prove the triangles are congruent, aka they are mirror copies of one another.
Each "A" refers to facts (1) and (3) shown above. Fact (2) is the "S" of ASA.
ASA = angle side angle
amelia paid a weekly salary of $500 to sell jewelry at international Diamond Center in addition,she makes a total of 12% of commission off all of her sales. How much does Amelia make this week if she sells $22,540 worth of jewerly this week?
Answer:
Step-by-step explanation:
a sample of size 115 will be drawn from a population with mean 48 and standard deviation 12 . use the ti-83 plus/ti-84 plus calculator. (b) find the 25th percentile of x . round the answer to at least two decimal places. the 25th percentile is
Using the ti-83 plus/ti-84 plus calculator, the 25th percentile of x is equal to 47.25 with a mean of 48 and a standard deviation of 12, respectively.
what is mean ?A dataset's mean is calculated by dividing the sum of all values by the total number of values. The term "average" is frequently used to describe it because it is the most widely used central tendency metric.
calculation
a) µ = 48
σ = 12
n= 115
X = 45
Z =(X - µ )/(σ/√n) = (45-48)/(12/√115)= -2.68
P(X<45) = P(Z<-2.68) = 0.0037
b) µ = 48.00
σ = 12.00
n= 115.00
P(X ≤ x) = 0.2500
z value at 0.25= -0.674 (excel formula =NORMSINV(0.25))
z=(x-µ)/(σ/√n)
X=z * σ/√n +µ= -0.674*12/√115+48= 47.25
Using the ti-83 plus/ti-84 plus calculator, the 25th percentile of x is equal to 47.25 with a mean of 48 and a standard deviation of 12, respectively.
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Please help with ixl
Answer:
<AFC
Step-by-step explanation:
Vertical angles are pairs of opposite angles that are created by two intersecting lines. As an example, the other pair of vertical angles are <CFD and <AFE.
The Pythagorean Theorem, given by the formula a² + b² = c², relates the
three sides of a right triangle. Solve the formula for the positive value of b in
terms of a and c.
Answer:
Below
Step-by-step explanation:
a^2 + b^2 = c^2 subtract a^2 from both sides
b^2 = c^2 - a^2
take the positive sqrt of both sides ( since you can't have a negative length)
b = sqrt (c^2 - a^2)
help pls
Write the equation of the line in slope-intercept form that is perpendicular to
y = -x – 18 and passes through (-6, 11).
Hence, the slope which is perpendicular to the line to [tex]y = -x - 18[/tex] and passes through [tex](-6, 11)[/tex] is [tex]y=x+17[/tex].
What is the equation?
The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.
Here given that,
The line in slope-intercept form that is perpendicular to [tex]y = -x - 18[/tex] and passes through [tex](-6, 11)[/tex].
As we know the slope of line is
[tex]y=mx+c[/tex]
where [tex]m[/tex] is the slope and [tex]c[/tex] is the y intercept.
Given points are [tex](-6,11)[/tex].
If we want to describe the perpendicular line to the original line then the slope of line is
[tex]m_2=-\frac{1}{m_1}[/tex]
In our given slope of line
[tex]y = -x -18[/tex]
where [tex]m_1=-1[/tex]
So,
[tex]m_2=-\frac{1}{m_1}\\\\m_2=-\frac{1}{-1}\\\\m_2=1[/tex]
Now for the slope of second line we use the point slope from the construct equation then,
[tex]y-y_1=m_2(x-x_1)\\\\y-11=1(x-(-6))\\\\y-11=x+6\\\\y=x+6+11\\\\y=x+17[/tex]
Hence, the slope which is perpendicular to the line to [tex]y = -x - 18[/tex] and passes through [tex](-6, 11)[/tex] is [tex]y=x+17[/tex].
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Is 4,6,8 a right triangle
Answer: It is an obtuse triangle.
Answer: No
Step-by-step explanation:
To know if a triangle is a right triangle, we can use Pythagorean Theorem to test.
Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex]
[tex]4^2+6^2=8^2[/tex] [exponents]
[tex]16+36=64[/tex] [add]
[tex]52\neq 64[/tex]
Therefore, this is not a right triangle.
slope of a line that passes through the points (-4,-7) and (-2,-19) in simplest form
Answer:
m=-6
Step-by-step explanation:
use slope formula to solve
m= rise/run=y2-y1/x2-x1
Madison is reeling in her string at a steady rate the linear equation 3y - 9x = -81 can be used to find y the number of feet of kite string she still needs to reel in after x seconds after the points (0, -27). And (-9,0) on the line? Show your work
Point ( 0 , -27 ) on the line and ( -9 , 0 ) are not on the line
Given :
Madison is reeling in her string at a steady rate the linear equation 3y - 9x = -81 can be used to find y the number of feet of kite string she still needs to reel in after x seconds .
Points ( 0 , -27 )
when x = 0
3y - 9 * 0 = -81
3y - 0 = -81
3y = -81
y = -81 / 3
y = -27
so point ( 0 , -27 ) on the line .
when y = 0
3 * 0 - 9x = -81
0 - 9x = -81
-9x = -81
x = 81/9
x = 9
so ( -9 , 0 ) are not on the line
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for the trapezoid below,solve for x. X= blank
Answer:
180-125 = x
x= 55 ( allied angle)
For the function: y = startroot x minus 7 endroot minus 1 the domain is : x ≥ the range is: y ≥
The domain the function is In interval notation [7, ∞). The range of the function is in the interval (-1, ∞).
What is function?A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable). A "vertical line test" can be used when examining a graph to determine whether a relation is a function. The relation is not a function if any point on the graph can be used to draw a vertical line that crosses the relation twice.
Here,
y=√(x-7)-1
x-7≥0
x≥7
at x=7
y=√(7-7)-1
y=-1
The function's domain is represented by the interval notation [7, ∞). The function's range falls within the range [-1, ∞).
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At the beginning of an experiment, a scientist has 176 grams of radioactive goo. After 135 minutes, her sample has decayed to 11 grams. What is the half-life of the goo in minutes? Find a formula for G ( t ) , the amount of goo remaining at time t . G ( t ) = How many grams of goo will remain after 32 minutes?
Answer:
The amount of goo remaining after 32 minutes is approximately 54.7 grams.
Step-by-step explanation:
The half-life of a substance is the amount of time it takes for half of the substance to decay. To find the half-life of the goo in the experiment, we need to solve the equation G ( t ) = G ( 0 ) / 2 for t , where G ( 0 ) is the initial amount of goo and G ( t ) is the amount of goo remaining after time t .In this case, G ( 0 ) = 176 grams and G ( 135 minutes ) = 11 grams, so we can write the equation as follows:11 grams = 176 grams / 2Solving for t , we get:t = 135 minutes * ( 1 / 2 ) = 67.5 minutesThis is the half-life of the goo in the experiment.To find the amount of goo remaining after time t , we can use the equation G ( t ) = G ( 0 ) * ( 1 / 2 ) ^ ( t / t1/2 ) , where G ( 0 ) is the initial amount of goo, t is the time at which we want to find the amount of goo remaining, and t1/2 is the half-life of the goo.In this case, G ( 0 ) = 176 grams, t = 32 minutes, and t1/2 = 67.5 minutes, so we can plug these values into the equation to find the amount of goo remaining after 32 minutes:G ( 32 minutes ) = 176 grams * ( 1 / 2 ) ^ ( 32 minutes / 67.5 minutes )This equation tells us that the amount of goo remaining after 32 minutes is approximately 54.7 grams.