in a sale normal prices are reduced by 10% Nathaniel bought a pair of shoes in the sale for £54

what was the original price of the shoes?
​

The solution of given inequality 3-|4-n| >1 is 2<n<6.So option D is correct.

An inequality is a relation that compares two numbers or other mathematical expressions in an unequal way. The majority of the time, size comparisons between two numbers on the number line are made.

The given inequality is 3 - |4-n| > 1

Since |4-n| is the absolute value

Absolute value describes the distance from zero that a number is on the number line, without considering direction. The absolute value of a number is never negative.

So ( 4-n ) may be negative or positive.

For positive value of ( 4-n )

3-( 4-n ) > 1

3-4+n>1

n>2

For negative value of (4-x)

3+( 4-n )>1

3 + 4-n >1

7 - n > 1

-n> 1 -7

-n > -6

n < 6

Hence, 2 < n < 6 i.e. option D is the solution to the inequality 3-|4-n| >1.

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Answer: d

Step-by-step explanation:

Step-by-step explanation:

substitute with 10 in the equation

Answer:

I don't understand what you mean

Answer: -23/6

Step-by-step explanation:

Answer: y=(x-3)^2 -14

Step-by-step explanation:

use the formula (b/2)^2 to create a new term to complete the square

Answer:

Nothing ( 0 )

Step-by-step explanation:

5(x - 1) = 5x - 1

5x - 1 = 5x - 1

5x - 5x = 1 - 1

0 = 0

A function is said to be an odd function if its graph is symmetric with respect to the origin.

Examples of odd functions are;

The odd functions are; C, D E, H, J, K, N

 y = - 4x + - 8 is equation of slope-intercept form.

What is in slope-intercept form?

the equation of slope - intercept form

                               y = mx + c

( -1 , -4 ) is point shown in graph

            slope = -y/x

                     = - ( -4)/-1  = 4/-1 = -4

             - 4 = -4 * - 1 + c

            - 4 = 4 + c

            c = - 4 - 4 = - 8

put value of c in the equation of slope - intercept form

             y = - 4x + - 8

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The number of mail were handled by the United States Postal Service in 1995 than in 1965 is 0.4.

Given that, United States Postal Service handled [tex]7.2 \times 10^{10}[/tex] mails in the year 1965. They handled [tex]1.8 \times 10^{11}[/tex] mails in the year 1995.

Scientific notation is a method for expressing a given quantity as a number having significant digits necessary for a specified degree of accuracy, multiplied by 10 to the appropriate power such as [tex]1.56\times10^7[/tex].

Number of mail were handled by the United States Postal Service in

1995 than in 1965 = Number of Postal Service handled mails in the year 1965 ÷ Number of Postal Service handled mails in the year 1995

= [tex]\frac{7.2 \times 10^{10}}{1.8 \times 10^{11}}[/tex]

= 4 × [tex]10^{-1}[/tex]

= 0.4

Therefore, the number of mail were handled by the United States Postal Service in 1995 than in 1965 is 0.4.

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Answer:

Step-by-step explanation:

AC= E

AC= CD

BC= EE

Please write the problems I cant see them well

The value of x is given by 6 units and the value of TV is given by 7 units.

A circle may be defined as a closed loop which has a fixed point around which the loop is made called the center and the fixed distance from the center of the circle to its periphery is known as the radius of the circle. We are given a circle with center at Z. In the circle QR and ST are the chords such that QR = ST = 14 that is both are of equal length, and we know that equal chords are at equal distance from the center. Therefore,

VZ = UZ

23 = 3x + 5

18 = 3x

=> x = 18/3

=> x = 6 units.

Now, we also know that perpendicular drawn from center of the circle to the chord bisects the chord. Thus,

TV = (1/2)×ST

TV = (1/2)×14

TV = 7 units.

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Answer:

X/2 = 12

7X = 168

Step-by-step explanation:

180 = X/2 + 7X

180 = 7.5 X

X = 24

Given:

Required:

We need to find the set that has the subset E.

Explanation:

Recall that a set A is a subset of another set B if all elements of set A are elements of set B.Consider the set A = {1, 2, 4, 7, 10, 11, 9, 6}.

Element 6 from E is not an element of A.

Set E is not a subset of set A.

B = {2, 4, 6}.

7B

Set E is not a subset of set B

D = {4, 6, 8, 10, 12, ...}

2D

D.

C = {1, 2, 3, 4, 5, 7, 8, 9, 10}

Set C has all the elements of E.

C

Final answer:

The computation of the expression using the fewest possible terms is D. 21 over 40 times t plus positive 22

It should be noted that on Mathematics, an expression is used to show the relationship between the variables that are given or illustrated.

In this case, the expression given is illustrated as three fourths times t minus 5 plus two fifths times t end quantity minus quantity five eighths times t plus 17 end quantity.

This will be:

= (3/4t - 5 + 2/5t) - (5/8t + 17)

= (15/20t + 8/20t - 5) - (5/8t + 17)

= 23/20t - 5 - 5/8t + 17

= 46/40t - 5 - 25/70t + 17

= 21/40t + 12

Therefore, the correct option is D.

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Let the expression we will add be "A", thus we can write:

We can use the distributive property on the right hand side and then use a bit algebra to solve for "A". The distributive property is shown below:

Let's do the algebra. The steps are shown below:

Thus, we need to add 4x + 2 to "5x + 7" to make it equal to "9(x+1)".

The correct answer is:

Using proportional relationships, it is discovered that they will cover 32 miles overall by walking 12 laps and running 20 laps.

For the second issue, the appropriate response is:

Brown 12 10 14 30

Green 20 25 35 75

Total 32 35 49 105

What is a direct proportional relationship?

In a direct proportional connection, the output variable is determined by multiplying the input variable by the proportionality constant, k, as in the example below:

y = kx.

For the first question, we have that out of a total distance of 8 miles, they:

Walk 3/8 of the distance.

Run 5/8 of the distance.

Hence the proportional relationships for the distances are given as follows:

Walked = 3/8 x Total Distance.

Ran = 5/8 x Total Distance.

For a total distance of 32 miles, the distances walked and ran are given as follows:

Walked: 3/8 x 32 = 3 x 4 = 12 miles = 12 laps.

Ran: 5/8 x 32 = 5 x 4 = 20 miles = 20 laps.

For the second question, we have that the table has to following the given ratios of the first row to the second row, with the third row being the sum of the first two rows, hence the third table is correct.

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ANSWER

EXPLANATION

First, we have to draw horizontal lines at the minimum and maximum heights. These are 10 feet and 210 feet, respectively.

Then, we calculate the midline,

And we have to draw this line too.

As mentioned, the period is the time it takes to do one revolution, which this wheel makes in 90 seconds. Thus, the period is 90 seconds and the first cycle starts at t = 0 and ends at t = 90 s,

Then, we know that the graph is sinusoidal, so we have to draw the first cycle - note that if the period is 90 s, the graph must intersect the midline at 45 seconds,

And finally, draw another cycle just like the first one.

We have the temperature points measured on the Fahrenheit scale.

The highest point is 110°f

The lowest point is -28°f

The difference between the two points would be as follows

In conclusion, the difference is 138°f

we know that

cost between $25 us and $40 us

Convert 21,130 RP to US

we have

1 RP=0.0147 US

so

Applying proportion

0.0147/1=x/21,130

solve for x

x=21,130*0.0147

x=310.61 US

so

310.61 US is not in the interval [25 US, 40 US]

that means

For the given  polynomial function f(x) =(x+9)(x-5)(x+7) the real number solutions are x = -9, -7,5.

As given in the question,

Given polynomial function :

f(x) =(x+9)(x-5)(x+7)

Real number solutions for the given polynomial function

f(x) =(x+9)(x-5)(x+7)

Values for which f(x) =0

0= (x+9)(x-5)(x+7)

Equate all the value to zero we get,

⇒ (x+9) =0 , (x-5) =0 , (x+7) =0

⇒ x = -9 , 5, -7

For x= -9 , 5, -7  polynomial function f(x) =(x+9)(x-5)(x+7) value is equal to zero.

Therefore, for the given polynomial function f(x) =(x+9)(x-5)(x+7) the real number solutions are x = -9, -7,5.

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The sets of P is a subsets of the universal sets.

Sets are defined as the collection of objects whose elements are fixed and can not be changed.

In other words, a set is a collection of elements or numbers or objects, represented within the curly brackets { }. For example a collections of alphabets {a, b, c, d, e, f, g, h}

Therefore, universal set (usually denoted by U) is a set which has elements of all the related sets, without any repetition of elements.

Hence,

universal set = ∪ = {1,2,3,4,5,6,7,8,9,10}

Therefore,

P = {1,3,5,7,9}.

P is a subsets of the universal sets.

The subsets is a part of the universal set.

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By using trigonometric relations for right triangles, we will see that the height of the tower is 81.92 meters.

First, we know that a pole with a height of 3.3m casts a shadow of 1.48m. We can see the height of the pole and the length of the shadow as the legs of a right triangle, with that, we can get the angle at which the sun hits the pole (this angle is such that the height will be the adjacent cathetus).

Using the trigonometric relation:

tan(a) = (opposite cathetus)/(adjacent cathetus)

We can get:

a = Atan( (opposite cathetus)/(adjacent cathetus))

With taht we can find the angle, where:

opposite cathetus = 1.48m

adjacent cathetus) = 3.3m

Then:

a = Atan(1.48/3.3) = 24.16°

For the tower that angle will be the same one, and again, the height is the adjacent cathetus and the shadow the opposite cathetus, so we can write the same equation than before:

tan(24.16°) = shadow/height.

Solving that for the height we get:

height = shadow/tan(24.16°) = 36.75m/tan(24.16°)  = 81.92m

The height of the tower is 81.92 meters.

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In the picture, There is graph with a triangle SNZ. The reflected triangle of y=3 as (1,2),(5,3) and (5,5).

Given that,

In the picture, There is graph with a triangle.

The triangle is SNZ.

We have to find the reflection across y=3.

We have to draw a line on y=3.

On the line y=3,

Z point is there so it will be same that is (5,3).

Now, the point S is on (5,1)

Here, y is 1 that is 3+2=5

So, we take the reflected S point as (5,5)

Now, the point N is on (1,4)

Here, y is 4 that is 3-1=2

So, we take the reflected N point as (1,2).

Therefore, we get the reflected triangle of y=3 as (1,2),(5,3) and (5,5).

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The reflected triangle of y=3 as (1,2),(5,3) and (5,5)

In the picture, there is graph with a triangle SNZ

We have to find the reflection across y=3

A reflection is a mirror image of the shape. An image will reflect through a line, known as the line of reflection. A figure is said to reflect the other figure, and then every point in a figure is equidistant from each corresponding point in another figure

We have to draw a line on y=3

On the line y=3

Z point is there so it will be same that is (5,3).

The point S is on (5,1)

Here, y is 1 that is 3+2=5

Take the reflected S point as (5,5)

The point N is on (1,4)

Here, y is 4 that is 3-1=2

Take the reflected N point as (1,2)

Therefore, the reflected triangle of y=3 as (1,2),(5,3) and (5,5)

The reflected triangle of y=3 as (1,2),(5,3) and (5,5)

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The statement which is not true for the given number line is |c| < d.

The visual representation of numbers on a straight line, either horizontally or vertically, is known as a number line. When numbers are written down on a number line, it is straightforward for humans to compare them and perform basic arithmetic operations on them. One might assume that a number line starts at zero (0). There are only negative numbers to the left of zero and only positive numbers to the right of zero. In other words, as we move to the right on a number line, the value of the numbers increases. This shows that the numbers on the right are more numerous than those on the left.

When any value is written within the mod, it is always considered a positive value.

So, accordingly option (B) |c| < d is the correct answer.

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Answer:

21 + t > 33

t > 12

Hope this helps!

Step-by-step explanation:

Given:

To find:

We need to find the same transformation of the given function.

Explanation:

The function g(x) is translated 6 units right and 4 units down to get f(x).

Consdier the function :

:

Final answer:

The following functions have the same transformation as give f(x0.