In an oscillating LC circuit, when 81.0% of the total energy is stored in the inductor's magnetic field, (a) what multiple of the maximum charge is on the capacitor and (b) what multiple of the maximum current is in the inductor

Este problema describe el funcionamiento de una tobera adiabática (sin flujo de calor), la cual tiene una corriente de entrada que difiere de la de salida espacial y energéticamente, pero que conservan el mismo flujo másico de 250 kg/h. De este modo, usamos un balance de energía con el fin the determinar la velocidad a la que sale el fluido, según es requerido en el problema:

[tex]mu_1+mP_1v_1+mgh_1+\frac{1}{2} mv_1^2=mu_2+mP_2v_2+mgh_2+\frac{1}{2} mv_2^2[/tex]

En la que se tiene que la incógnita es la velocidad de salida, [tex]v_2[/tex], y es posible simplificar el flujo másico, [tex]m[/tex], al estar como factor común en ambos lados y despreciar la energía potencial (mgh), ya que no hay diferencia de altura significativa entre la entrada y salida de la tobera.

De este modo, es posible reemplazar los valores dados para obtener la siguiente expresión:

[tex]2510\frac{kJ}{kg} +1378kPa*0.147\frac{m^3}{kg} +\frac{1}{2} (5\frac{m}{s} )^2=2263\frac{kJ}{kg}+138.7kPa*1.099\frac{m^3}{kg} +\frac{1}{2} v_2^2[/tex]

Y así, hallar la velocidad de salida como sigue:

[tex]2725.066\frac{kJ}{kg}=2415.431\frac{kJ}{kg} +\frac{1}{2} v_2^2\\\\v_2=\sqrt{2(2725.066\frac{kJ}{kg}-2415.431\frac{kJ}{kg} )} \\\\v_2=24.9\frac{m}{s}[/tex]

Para revisar:

Answer:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

Explanation:

X and Y components:

Y = 6.36 m/s

X = 10.18 m/s

Position after 0.5 seconds:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

The x and y positions of the ball 0.50s after it is kicked are 5.09 meter and  1.95 meter respectively.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Initial speed of the soccer ball at an angle 32° above the horizontal is: u = 12m/s.

Time interval: t = 0.50 second.

Now, x component of initial velocity = u cosθ = 12 × cos 32° m/s = 10.17 m/s.

y component of initial velocity = u sinθ = 12 × sin32° =6.36 m/s.

Hence,

after 0.50 s, x-position of the ball =  u cosθ t

= 10.17 × 0.50 meter

= 5.09 meter.

after 0.50 s, y-position of the ball =  u sinθ t -gt²/2

= 6.36 × 0.50 - (9.8×0.50²/2) meter

= 1.95 meter.

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Answer:

15-45/2 = -7.5 downwards

Explanation:

cos(60) x 45 = z

z = 45/2

sin (30) x 70 = y

y = 15

15-45/ 2 = -7.5 downwards

100000 Pascal

Explanation:

pressure= force/area

Max pressure= force/min area

so f=5

min area= 5×10^-5

5÷5*10^-5 = 100000pascal

The distance that the canoe moves in this process is 1.29 meters.

We first have to find the center of mass

[tex]X = \frac{MsXs+McXc}{Mw+Mc} \\\\[/tex]

Where

Ms = Woman's mass = 45

Mc = Canoe's mass = 60kg

Xs = position from left= 1 cm

Xc = position from left end of canoe's mass = 2.5cm

When we put these values into the equation we have:

[tex]X=\frac{45*1+60*2.5}{45+60} \\\\= 1.857\\[/tex]

The center of gravity lies at the center of this boat. Therefore,

[tex]Xc = \frac{L}{2} \\\\L = 5 m long\\\\\frac{5}{2} =2.5[/tex]

5.00 - 1. 00 = 4 meters

[tex]\frac{45*4+60*2.5}{45+60} = 3.14meters\\\\[/tex]

To get the distance that is moved by this canoe

distance = 3.143-1.857

= 1.286

≈ 1.29 meters

The distance that the canoe moves in this process is 1.29 meters.

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The concept of conservation of energy and harmonic motion allows to find the result for the power where the kinetic and potential energy are equal is:

        x = 0.135 cm

Given parameters

To find

A simple harmonic movement is a movement where the restoring force is proportional to the displacement, the result of this movement is described by the expression.

          x = A cos wt + fi

          w² = [tex]\frac{k}{m}[/tex]

Where x is the displacement from the equilibrium position, A the initial amplitude of the system, w the angular velocity t the time, fi a phase constant determined by the initial conditions, k the spring constant and m the mass.

The speed is defined by the variation of the position with respect to time.

       v = [tex]\frac{dx}{dt}[/tex]

let's evaluate

       v = - A w sin (wt + Ф)

Since the body releases for a time t = 0 the velocity is zero, therefore the expression remains.

       0 = - A w sin Ф

For the equality to be correct, the sine function must be zero, this implies that the phase constant is zero

        x = A cos wt

Let's find the point where the kinetic and potential energy are equal.

        K = U

        ½ m v² = m g x

we substitute

        ½ A² w² sin² wt = g A cos wt

        sin² wt = [tex]\frac{2g}{A}[/tex]  cos wt

let's calculate

      w = [tex]\sqrt{\frac{7}{0.220} }[/tex]  

      w = 5.64 rad / s

      sin² 5.64t = 2 9.8 / 0.052 cos 5.64t

      sin² 5.64t = 376.92 cos 5.64 t

      1 - cos² 5.64t = 376.92 cos 5.64t

      cos² 5.64t -376.92 cos564t -1 = 0

we make the change of variable

       x = cos 5.64t

      x²- 376.92 x - 1 = 0

      x = 0.026

      cos 5.64t = 0.026

Let's find the displacement for this time

       x = 5.2 10-2 0.026

       x = 1.35 10-3 m

In conclusion Using the concepts of conservation of energy and harmonic motion we can find the result for the could where the kientic and potential enegies are equal is:

        x = 0.135 cm

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Answer:

333.5 MJ

Explanation:

ΔV = m·g·Δh

     = 8500 · 9.81 · (15000-11000)

     = 8500 · 9.81 · 4000

     = 333 540 000

     ≈ 333.5 ·10⁶J = 333.5 MJ

The change in potential energy is 333.5 MJ

Potential energy is defined as the energy possessed by an object because of its position relative to other objects, tension within itself, its electric charge, or other factors. Any object that is raised above its rest position has energy stored in it, so it is called potential energy because it has the potential to do work when released.

It can be expressed as:

P.E.= mgh

where, m is the mass of an object measured in grams 'g'

g is the acceleration due to gravity which is [tex]9.8 m/s^2[/tex]

h is the height measured in meter 'm'

Here,

the given information is

m= 8500kg

Δh= [tex]h_2 - h_1[/tex] = 15000-11000 = 4,000m

So, P.E. = 850 x 9.8 x 4000 = 333 540 000=  333.5 ·10⁶J = 333.5 MJ

Thus, the change in potential energy is 333.5 MJ

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Answer:

Main Difference Between Mechanical and Electromagnetic waves

A wave is composed of some kind of disturbance that propagates. We can classify waves into many different types based on their properties. One of the properties of the waves depends on whether they need a medium to propagate or not. The primary difference between electromagnetic and mechanical waves is also based on this property. Mechanical waves need a medium, while electromagnetic waves do not need a medium to propagate. Electromagnetic waves can travel through a vacuum. The other differences between mechanical and electromagnetic waves are given below:

Electromagnetic waves can travel through a vacuum, that is an empty space, whereas mechanical waves cannot. They need a medium to travel such as water or air. Ripples in a pond are an example of mechanical waves whereas electromagnetic waves include light and radio signals, which can travel through the vacuum of space.

Mechanical waves can be classed as elastic waves because their transmission depends on the medium's (water, air etc.) elastic properties.

Electromagnetic waves are caused because of the varying magnetic and electric fields. They are produced by the vibration of the charged particles.

Because of these differences, the speed of each type of wave varies significantly. Electromagnetic waves travel at the speed of light but mechanical waves are far slower.

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Answer:

low

Explanation:

the higher the kinetic energy, the More the vibration of molecules, thus heat is more on the side with highly vibrating molecules

Answer:

friction force

Explanation:

force of friction is opposite to the force applied it resist the motion

Answer:

104f

Explanation:

(40°C × 9/5) + 32 = 104°F

Answer:

We are given the length, the mass and the density of the cylinder. First let us calculate for the volume by dividing the mass by the density.

volume = mass /density

where mass = 2.17 kg = 2170 g, therefore:

volume = 2170 g / (2.33 g/cm^3)

volume = 931.33 cm^3

We know that the volume of a cylinder has the formula:

volume = π r^2 h

since h = 16.8 cm, therefore calculating for radius:

931.33 cm^3 = π r^2 (16.8 cm)

r^2 = 17.646 cm^2

r = 4.2 cm

Hence the diameter (d) is:

d = 2 r

d = 8.4 cm

Explanation:

The diameter of the cylindrical rod is approximately 0.382 cm.

To find the diameter of the cylindrical rod, we can use the formula for the volume of a cylinder and then solve for the diameter.

The formula for the volume of a cylinder is:

V = π[tex]r^{2}[/tex]h,

where V is the volume, r is the radius, and h is the height (or length) of the cylinder.

In this case, we know the length of the cylinder (h) is 16.8 cm. We need to find the radius (r) in order to calculate the diameter.

The mass of the cylinder can be related to its volume and density using the formula:

m = ρV,

where m is the mass, ρ is the density, and V is the volume.

Rearranging this formula, we can solve for V:

V = m / ρ.

Now we have two equations:

V = π[tex]r^{2}[/tex]h,

V = m / ρ.

Setting these two equations equal to each other, we can solve for r:

π[tex]r^{2}[/tex]h = m / ρ.

Substituting the given values:

π[tex]r^{2}[/tex] * 16.8 cm = 2.17 kg / (2.33 g/[tex]cm^3[/tex]).

Let's solve this equation for r:

[tex]r^{2}[/tex] = (2.17 kg / (2.33 g/[tex]cm^3[/tex])) / (π * 16.8 cm).

[tex]r^{2}[/tex]  ≈ 0.036775 [tex]cm^2[/tex].

Taking the square root of both sides:

r ≈ 0.191 cm.

Finally, we can find the diameter (d) by multiplying the radius by 2:

d ≈ 2 * 0.191 cm.

d ≈ 0.382 cm.

Therefore, the diameter of the cylindrical rod is approximately 0.382 cm.

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Answer:

Vertical acceleration 9.8 m/s² downward

Horizontal acceleration 0.0 m/s²

assuming no air resistance.

Answer:

yes

Explanation:

because gravity moves things

Answer:

Explanation:

v² = u² + 2as

v² = 33² + 2(3.0)(500)

v² = 4089

v = 63.9452...

v = 64 m/s

Answer:

Fnet = 5 Newton

Explanation:

Fnet = 10 N - 5 N

Fnet = 5 N

Answer:

The two main factors that affect kinetic energy are mass and speed.

Explanation:

Kinetic energy is the energy that is caused by the motion. The kinetic energy of an object is the energy or force that the object has due to its motion. Your moving vehicle has kinetic energy; as you increase your vehicle's speed, your vehicle's kinetic energy increases.

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Based on Newton's third law, the pressure is the same on points that are at the same level but on opposite sides.

When an object is immersed in a fluid at rest,

Therefore, the net force along horizontal firection is equal to zero.

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Answer:

Explanation:

The change in force = 9.81(1.95 - 0.300) = 16.2 N

The change in length is 0.750 - 0.200 = 0.550 m

K = ΔF/Δx = 16.2/0.550 = 29.4 N/m

Answer:

1.96 N

Explanation:

⇒This is your full answer

Answer:

Decline in soil health is a serious worldwide problem that decreases complexity and stability of agricultural ecosystems, commonly making them more prone to outbreaks of herbivorous insect pests. Potato (Solanum tuberosum L., Solanaceae) and onion (Allium cepa L., Amaryllidaceae) production is currently characterized by high soil disturbance and heavy reliance on synthetic inputs, including insecticides. Evidence suggests that adopting soil conservation techniques often (but not always) increases mortality and decreases reproductive output for the major insect pests of these important vegetable crops. Known mechanisms responsible for such an effect include increases in density and activity of natural enemy populations, enhanced plant defenses, and modified physical characteristics of respective agricultural habitats. However, most research efforts focused on mulches and organic soil amendments, with additional research needed on elucidating effects and their mechanisms for conservation tillage, cover crops, and arbuscular mycorrhizae.

Introduction

Soil erosion is a serious problem worldwide (Amundson et al., 2015). Although it is often overshadowed in public discourse by other concerns, such as climate change and invasive species, soil deterioration receives considerable attention from the scientific community (Montgomery, 2007; Borrelli et al., 2017; Berhe et al., 2018). In addition to the loss of agricultural productivity, soil erosion has been linked to increased emissions of greenhouse gases and reduced water quality (Amundson et al., 2015; Berhe et al., 2018). Global soil erosion is forecasted to increase in the near future because of cropland expansion, especially in the least economically developed areas (Borrelli et al., 2017).

Answer:

I think that the answer is 4.318 as a=f/p

Answer:

we deal our body movement during sleeping

Answer:

I don't see anything so you should repost

Answer:

Gravitational potential energy

kinetic energy

Answer:

Explanation:

Assuming x direction is horizontal any y direction is vertical

As the moment of inertia of the pulley is I = (½)mR²

The pulley mass will appear as ½ its actual mass in the system.

F = ma

5.00(9.81) = (5.00 + 2.60/2 + 12.0)a

a =  49.05 / 18.3

a = 2.6803278...

a = 2.68 m/s²

A) T = 12.0(2.68) = 32.16... = 32.2 N

B) T = 5.00(9.81 - 2.68) = 35.65 = 35.7 N

C) aₓ = 2.68 m/s²

D) Fx = 32.2 N

   Fy = 35.7 + 2.60(9.81) = 61.2 N

A)The tension in the horizontal segment of the wire will be  32.2 N

B)The tension in the vertical segment of the wire will be 35.7 N

Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².It is a vector quantity. It requires both magnitudes as well as direction to define.

The given data in the problem is;

m is the mass box resting on a horizontal  =12.0 kg

the uniform solid disk of mass of 2.60 kg

d is the diameter = 0.500 m.

A)The tension in the horizontal segment of the wire will be  32.2 N

The acceleration is found as;

[tex]\rm F = ma \\\\ a= \frac{49.05}{18.3} \\\\ \rm a= 2.68 \ m/sec^2[/tex]

The tension in the horizontal segment of the wire is found as;

T=ma

T= 12.0 ×2.68

T=32.2 N

Hence the tension in the horizontal segment of the wire will be  32.2 N

B)The tension in the vertical segment of the wire will be 35.7 N

T=m(g-a )

T= 5.00 × (9.8-2.68)

T=35.7 N

Hence the tension in the vertical segment of the wire will be 35.7 N

C)  the x-component of the acceleration of the box. will be 2.68 m/s².

aₓ = 2.68 m/s²

D)The x- and y-components of the force that the axle exerts on the pulley will be 32.2 and 61.2 N respectively.

Fx = 32.2 N

Fy = 35.7 + 2.60(9.81) = 61.2 N

Hence the x- and y-components of the force that the axle exerts on the pulley will be 32.2 and 61.2 N respectively.

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Rest in physics generally refers to the state in which an object is stationary.

Hence, in Physics, an object is in a state of rest when it does not move from one point to another.

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