In each table, y and x are in a proportional relationship.
Select the table with a constant of proportionality of –3.
A. 'x' is 1 2 3. 'y' is -3,-6,-9
B. 'x' is 1, 2, 3. 'y' is -1, -2, 0
C. 'x' is 1, 2, 3. 'y' is -3, -3, -3
D. 'x' is 1, 2, 3. 'y' is -3, -3/2, -1
Answers
The table with a constant of proportionality of –3 are
A. 'x' is 1 2 3. 'y' is -3,-6,-9
A. 'x' is 1 2 3. 'y' is -3,-6,-9 C. 'x' is 1, 2, 3. 'y' is -3, -3, -3
A. 'x' is 1 2 3. 'y' is -3,-6,-9 C. 'x' is 1, 2, 3. 'y' is -3, -3, -3D. 'x' is 1, 2, 3. 'y' is -3, -3/2, -1
y = k × x
where,
k = constant of proportionality
A. 'x' is 1 2 3. 'y' is -3,-6,-9
y = k × x
-3 = k × 1
- 3 = k
k = -3
B. 'x' is 1, 2, 3. 'y' is -1, -2, 0
y = k × x
-1 = k × 1
-1 = k
k = -1
C. 'x' is 1, 2, 3. 'y' is -3, -3, -3
y = k × x
-3 = k × 1
-3 = k
k = -3
D. 'x' is 1, 2, 3. 'y' is -3, -3/2, -1
y = k × x
-3 = k × 1
-3 = k
k = -3
or
y = k × x
-3/2 = k × 2
-3/ 2 = 2k
k = -3/2 ÷ 2
k = -3/2 × 1/2
k = -3
Therefore, the table with a constant of proportionality of –3 are
A. 'x' is 1 2 3. 'y' is -3,-6,-9
A. 'x' is 1 2 3. 'y' is -3,-6,-9 C. 'x' is 1, 2, 3. 'y' is -3, -3, -3
A. 'x' is 1 2 3. 'y' is -3,-6,-9 C. 'x' is 1, 2, 3. 'y' is -3, -3, -3D. 'x' is 1, 2, 3. 'y' is -3, -3/2, -1
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