In mouse, genes X, Y and Z are on chromosome 2. The map of genes X, Y and Z is:

X--------20mu--------Y---------------30mu---------Z.

You cross an individual with genotype XXYYZZ to an individual with genotype xxyyzz, and F1 progeny are collected. Assume interference between regions (X-Y and Y-Z) is 40%. You then perform a cross between an F1 individual and an individual with genotype xYz/xyz. Among 1000 progeny, how many of them will be of the genotype xxyyzz?

Answers

Answer 1

Answer:

36 individuals xxyyzz

Explanation:

Available data:

X-Y = 20MUY-Z = 30MUCross: XXYYZZ   x    xyyzzF1= XxYyZzI = 40%2nd Cross: XxYyZz  x  xxYyzzF2 = 1000 individuals

We need to know how many individuals from the F2 are going to be xxyyzz

xxyyzz genotype is the result of a double recombinant event.

First, we need to analyze the given information:

→ Distances between genes

The genetic distance result from multiplying the recombination frequency of each region by 100 and expressing it in map units (MU). So, if we have the genetic distance we can divide it by 100 and get the recombination frequency:

Let us say that region I is the distance between X and Y. And region II is the distance between Y and Z.

GD = genetic distance

RF = Recombination frequency

GD (X-Y) = RF x 100

20MU = RF x 100

20MU/100 = RF

0.2 = RF (Region I)

GD (Y-Z) = RF x 100

30MU = RF x 100

30MU/100 = RF

0.3 = RF (Region II)      

Now we have the recombination frequency of Region I and Region II.

→ Interference    

Knowing the interference value will let us know the value of the coefficient of coincidence, which will also lead us to the number of individuals xxyyzz.

I = 40%

I = 1 - CC   ⇒ CC = coefficient of coincidence

Clearing this equation gives us the value of CC

CC = 1 - I

CC = 1 - 40% = 1 - 0.4

CC = 0.6

To calculate the coefficient of coincidence, CC, we can also use the next formula:

CC = observed double recombinant frequency/expected double recombinant frequency

Now, we are interested in knowing the value of the observed double recombinant frequency.

Note:  

observed double recombinant frequency = total number of observed double recombinant individuals/total number of individuals expected double recombinant frequency = recombination frequency in region I x recombination frequency in region II.

So, to get the value of the observed double recombinant frequency, first, we need to get the value of the expected double recombinant frequency. And we can do it because we already have the recombination frequencies in both regions.

expected double recombinant frequency = recombination frequency in region I x recombination frequency in region II

- Recombination Frequency - RI = 0.2

- Recombination Frequency  - RII = 0.3

expected double recombinant frequency = 0.2 x 0.3

expected double recombinant frequency = 0.06 = EDRF

Now that we know the value of the CC and the expected DRF, we can get the observed double recombinant frequency.

CC = observed double recombinant frequency/expected double recombinant frequency

- CC = 0.6

- EDRF = 0.06

CC x expected double recombinant frequency = observed double recombinant frequency

0.6 x 0.06 = observed double recombinant frequency

0.036 = observed double recombinant frequency = ODRF

Finally, as this is a frequency, we need to multiply it by the total number of individuals in the F2 to get the number of observed double recombinant individuals.

- ODRF = 0.036

- N = 1000

Double recombinant individuals = 0.036 x 1000 = 36 individuals xxyyzz.


Related Questions

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Nitrogenous base
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Answers

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Answers

Answer:

it was one of either it depends so Both

Explanation:

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A). Add less force
B). Add more force
C). increase the speed
D). add wheels

Answers

Answer:A.) add less force

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II. The energy from the caterpillar is transferred to the plant.
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Answers

Answer:

C) I, III, and IV only

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Answers

Answer:

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Answer:

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(c) Type AB mother, Type AB father

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Answers

Answer:

a) A and O

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c) A, B and AB

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Explanation:

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Genetic drift is the selection of random traits in a population; natural selection is the
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Genetic drift is the frequency of genes in a population; natural selectic is the frequency
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Genetic drift is the change in a population's genes over time; natural selection is the
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Answers

A) Genetic drift is the random increase or decrease of genes in a population. Natural selection is not random.

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Imagine what happens in an empty lot that has been cleared of all living things. As in a garden that is no longer planted, only soil remains. Weeds begin to grow in the soil. At first, only plants that need full sun to sprout grow there. But over time, these plants grow taller and shade the ground. Then, a different kind of plant begins to grow there, one that grows only in shady areas. Eventually, the lot is covered in mostly plants that sprout in shade.
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Answers

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Lab: Interdependence of Organisms

Interdependence Of Organisms

Question Being Answered:

How can the presence of one species benefit another in the same ecosystem?

Hypothesis:

If plants grow in soil that contains worms the plants growth will be greater because worms are able to help decompose organic matter and help distribute it through the soil in a form plants are able to use.

Process Of Lab:

In this lab you will grow two different groups of plants. Group A is considered the experimental group which will grow in soil with worms, Group B is considered the control group which will grow in soil without worms. After the plants grow you have to measure the plant growth for both groups and compare them.

Independent & Dependent

Independent Variable: Presence Of Worms

Dependent Variable: Plant Growth

Safety Procedure

Be sure to follow the safety procedure which means to

Wear safety goggles and lab gown while doing the experiment

Keep lab behavior purposeful

Look over the soil contents and make sure to follow warnings provided on any equipment

Wash hands and lab equipment once done with experiment

Treat living organisms with respect and provide proper care

Report any accidents that happen in the lab to your teacher

Lab Procedure

Step 1: Gather Materials

Two trays that are 10 cm 4’ deep

Potting soil

Lima bean seeds which need to be soaked overnight

Location with sunlight or growth lights

Worms

Graduated cylinder

Water

Black marker

Ruler with metric markings

Step 2: Prepare Two Trays Of Lima Bean Plants

Label the trays Control Group and Experimental Group

Add approximately 6-7 cm of soil to each tray

Plant 6 lima bean seeds in each tray being 2 cm deep and label the plants 1-6

Step 3: Give The Plants Water And Light During Sprouting Time

Keep the environments for both groups identical

Water all the plants following the watering schedule that was recommended on the seed packaging

Use the graduated cylinder to ensure the same amount of water is being given to both groups

Make sure all plants get the same amount of light

Step 4: Measure The Heights Of The Plants At The End Of Week 1

Measure the height of all twelve plants to the nearest cm. If a plant dies mark an x on the data table for that plant and write it in your notes

Use a calculator to find the average heights of the living plants in each groups

Calculate the difference in those average heights by subtracting the average height of the plants in the control group. Use this difference as a basis for comparison

Record measurement observations in your notes and the health of the plants such as leaf colors and size, wilting, unusual growth, brown spots, and any other marks you see

Step 5: Add Six Worms To The Soil Of The Experimental Group Of Plants

Write descriptive notes about the condition of the worms in your notes

Step 6: Measure The Heights Of The Plants At The End Of The Week 3

Repeat step 4

Step 7: Measure The Heights Of The Plants At The End Of Week 5

Repeat step 4

Step 8: Check The Health Of The Worms At The End Of The Study

Are the worms still alive?

Do they all seem healthy?

Have they changed in any way? If so list the ways changed

Are there any new worms

Be sure to write descriptive notes about their conditions in your notes

Step 9: Dispose Of All Material According To The Directions From Your Teacher




Week 1 (Before Adding Worms)

Week 3

Week 5

Plant 1

10cm

22cm

49cm

Plant 2

9cm

23cm

47cm

Plant 3

8cm

20cm

49cm

Plant 4

9cm

22cm

50cm

Plant 5

10cm

22cm

47cm

Plant 6

8cm

23cm

52cm

Control Group Average

9cm

22cm

49cm

Plant 1

8cm

24cm

50cm

Plant 2

9cm

28cm

60cm

Plant 3

8cm

26cm

49cm

Plant 4

8cm

25cm

53cm

Plant 5

8cm

27cm

58cm

Plant 6

7cm

26cm

60cm

Experimental Group Average

8cm

26cm

55cm

Difference In Average Heights

-1cm

4cm

6cm

Table answers go from left to right in the order I put

Answers

yeah no one is gonna read all if this lol

Answer:

Control GroupHeight (cm)Week 1 (beforeadding worms)Week 3Week 5Plant 110cm22cm49cmPlant 29cm23cm47cmPlant 38cm20cm49Plant 49cm22cm50cmPlant 510cm22cm47cmPlant 68cm23cm52cmControl Group Average9cm22cm49cmExperimental GroupHeight (cm)Week 1 (beforeadding worms)Week 3Week 5Plant 18cm24cm50cmPlant 29cm28cm60cmPlant 38cm26cm49cmPlant 48cm25cm53cmPlant 58cm27cm58cmPlant 67cm26cm60cmExperimental Group Average8cm26cm55cmDifference in Averages:(Experimental - Control)-1cm4cm6cm

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Answers

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: D

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Answers

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Explanation:

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Answers

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Have a good day
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Answers

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Answers

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Answers

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Answers

Answer:

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Answers

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Answers

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Answers

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Answers

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