In the diagram, R1 = 40.0 ohm, R2 = 25.4 ohm, and R3 = 70.8 ohm. What is the equivalent resistance of the group?​

In The Diagram, R1 = 40.0 Ohm, R2 = 25.4 Ohm, And R3 = 70.8 Ohm. What Is The Equivalent Resistance Of

Answers

Answer 1
Given :

[tex]R_1 = 40 ohms[/tex]

[tex]R_2 = 25.4 ohms[/tex]

[tex]R_3 = 70.8 ohms[/tex]

Solution :

The resistors [tex]R_1 and R_2 [/tex]are in series connection, so the equivalent resistance of [tex]R_1 and R_2[/tex] will be their sum.

[tex] \boxed{ \mathrm{R_t = R_1 + R_2}}[/tex]

[tex]R_t= 40 + 25.4[/tex]

[tex]R_t= 65.4 \: \: ohms[/tex]

Now, the equivalent resistance of [tex](R_1 and R_2)[/tex] and [tex]R_3 [/tex] is the total resistance of the circuit, and since they are in parallel connection, Total resistance :

[tex] \mathrm{ \dfrac{1}{ R_{eq}}} = \dfrac{1}{65.4} + \dfrac{1}{70.8} [/tex]

[tex] \dfrac{1}{R_{eq}} = \dfrac{65.4 + 70.8}{4630.32} [/tex]

[tex] \frac{1}{R_{eq}} = \dfrac{136.2}{4630.32} [/tex]

[tex]R_{eq} = \dfrac{4630.32}{136.2} [/tex]

[tex]R_{eq} = 33.996 \: \: ohms[/tex]

[tex] \boxed{ \mathrm{R_{eq} = 34 \: ohms}} \: (approx)[/tex]

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Answers

Complete question is;

Kamal said the distance from the top of the balloon to the ground in the Example image attached is √353 ft. What mistake might Kamal have made?

Answer:

the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse

Explanation:

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How does the circuit structure affect the brightness of a bulb? How does the circuit structure affect the energy required to keep bulbs lit? Summarize some of the tradeoffs (pros and cons) of wiring bulbs in series vs. Parallel.

Answers

Answer:

Part A

The relationship between the circuit structure and the brightness of the bulb are;

The brightness of the bulb depends on the voltage to which the bulb is connected to

Bulbs connected in parallel, are connected directly to the voltage of the power source and are therefore brighter than bulbs arranged in series due to the reduced potential difference between bulbs in series and the voltage source

Part B

Given that bulbs are brighter when arranged in parallel, they require more energy to keep the bulbs lit than when they are arranged in series

Part C

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Series Circuits Disadvantage

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Answer:

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Answer:

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Explanation:

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What is the potential difference across a circuit that delivers 4.2A to a 500W motor?

Answers

Answer:

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Explanation:

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The SI unit of power is Watt.

The  commercial unit of power is horse power.

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Answers

Answer:

the maximum speed of the ball is 12.65 m/s

Explanation:

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Answers

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Answers

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A train going at a speed of 18m / s brakes and stops in 15s calculates its acceleration and the distance traveled when braking

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A parallel plate capacitor of capacitance Co has plates of area A with separation d between them. When it is connected to a battery of voltage Vo, it has charge of magnitude Qo on its plates. It is then disconnected from the battery and the plates are pulled apart to a separation 2d without discharging them. After the plates are 2d apart, the new capacitance and the potential difference between the plates are: (Show all steps) [2 marks] a. ½ Co, ½ Vo b. ½ Co, 2Vo c. Co, Vo d. Co, 2Vo e. 2Co, 2Vo

Answers

Answer:

b. 1/2·C₀, 2·V₀

Explanation:

The capacitance on the parallel plate capacitor = C₀

The area of the plates  = A

The voltage on the battery = V₀

The magnitude of the charge on the plate = Q₀

The new distance between the plates = 2·d

From an online physics source, we have;

[tex]C_0 = \epsilon_0 \times \dfrac{A}{d}[/tex]

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ε₀ = Constant

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With the new distance, 2·d, we get;

[tex]C_{new} = \epsilon_0 \times \dfrac{A}{2\cdot d} = \dfrac{1}{2} \times \epsilon_0 \times \dfrac{A}{d} = \dfrac{1}{2} \times C_0[/tex]

Therefore;

[tex]The \ new \ capacitance \ C_{new} = \dfrac{1}{2} \times C_0[/tex]

The potential difference, 'V', is given as follows;

[tex]C = \dfrac{Q}{V}[/tex]

Therefore;

[tex]V = \dfrac{Q}{C}[/tex]

Given that Q = Q₀, we get;

[tex]V = \dfrac{Q_0}{\dfrac{1}{2} \times C_0} = 2 \times \dfrac{Q_0}{C_0} = 2 \times V_0[/tex]

∴ V = 2 × V₀

The new potential difference, V = 2·V₀

Therefore, after the plates are 2·d apart, the new capacitance and potential difference between the plates are;

1/2·C₀, 2·V₀.

At a distance of 2d, the potential difference will be twice the potential difference before while the capacitance will be half the value before.

Given to us

The capacitance on the parallel plate capacitor = C₀The area of the plate = AThe voltage on the battery = V₀The magnitude of the charge in the plate = Q₀The new distance between the plates = 2d

What is Capacitance?

We know capacitance can be written as,

[tex]C= \dfrac{\epsilon_0 A}{d}[/tex]

where C is the capacitance,

A is the area,

d is the distance and

ε₀ is the electrostatic constant,

Capacitance before,

[tex]C= \dfrac{\epsilon_0 A}{d}[/tex]

Capacitance Afterwards,

[tex]C= \dfrac{\epsilon_0 A}{2d}[/tex]

[tex]C=\dfrac{1}{2} \times \dfrac{\epsilon_0 A}{d}[/tex]

[tex]C=\dfrac{1}{2} \times C_0[/tex]

What is Voltage(Potential difference)?

We know that  for the voltage we can write,

[tex]\rm Voltage = \dfrac{Charge}{Capacitance}[/tex]

Voltage before

[tex]V=\dfrac{Q_0}{C_0}[/tex]

Voltage Afterwards

[tex]V_{new} = \dfrac{Q_0}{C_{new}}[/tex]

[tex]V_{new} = \dfrac{Q_0}{\dfrac{1}{2} \times C_0}[/tex]

[tex]V_{new} = 2 \times\dfrac{Q_0}{C_0}[/tex]

[tex]V_{new} = 2 \times V_0[/tex]

Hence, At a distance of 2d, the potential difference will be twice the potential difference before while the capacitance will be half the value before.

Learn more about Capacitance:

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Please dont delete this question......

Answers

Answer:

c

Explanation:

Answer:

C.

Explanation:

What is quantum, in your own words but be more detailed.

Answers

Answer: Quantum is really just an amount of any physical entity involved in an interaction.

Explanation:

state one part of the body where you have a fixed joint​

Answers

Examples of fixed joints include the joints between the bones in the skull and the joint where the radius and ulna bones meet in the lower arm

Answer:

Your skull

Explanation:

your skull has fixed joints

A jet plane travels at 40.8 km at an average speed of 340 m/s calculate how long this journey took- giveyour answer to the nearest minute

Answers

Answer:

[tex]2\ \text{minutes}[/tex]

Explanation:

d = Distance traveled = 40.8 km

s = Speed of jet = 340 m/s

Time is given by

[tex]t=\dfrac{d}{s}[/tex]

[tex]\Rightarrow t=\dfrac{40.8\times 10^3}{340}[/tex]

[tex]\Rightarrow t=120\ \text{s}[/tex]

[tex]\Rightarrow t=\dfrac{120}{60}=2\ \text{minutes}[/tex]

The time taken to complete the journey is [tex]2\ \text{minutes}[/tex].

Please select the word from the list that best fits the definition

Device that measures electric current

Answers

Answer:

ammeter

Explanation:

An ammeter is a measuring device used to measure the electric current in a circuit.

A classroom has a volume of 165 m^3. How many moles of gas are in the room if the temperature is 20.0°C and the pressure is 1.00 atm? (Make sure to put P, V, and T in the right units.) (Unit = mol)​

Answers

The number of mole of the gas present in the room given the data is 0.069 mole

Data obtained from the question Volume (V) = 165 m³Temperature (T) = 20 °C = 20 + 273 = 293 KPressure (P) = 1 atm Gas constant (R) = 8.21 m³.L/Kmol Number of mole (n) =?

How to determine the number of mole

The number of mole of the gas present in the room can be obtained by using the ideal gas equation as illustrated below

PV = nRT

n = PV / RT

n = (1 × 165) / ( 8.21 × 293)

n = 0.069 mole

Learn more about ideal gas equation:

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Answer:

6859 moles

Explanation:

n=(PV)/RT=(100000*165)/(8.21*293 Kelvin)=6859 moles

20 deg Celsius is 293 Kelvin

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