In the figure above, AB = AD, BC = CD, BE = 2, BC = 4, and AC = 10. What is the area of triangle ABD?
Answers
The properties of items in a question can be used to simplify the solution to the questions
The area of triangle ΔABD is 20 - 4·√3
The reason the above value for the area of ΔABD is correct is as follows:
The given parameters are;
AB = AD, BC = CD, BE = 2, BC = 4, AC = 10
Given that AB = AD, and BC = CD, we have that the figure ABCD is a kite
∴ AC is perpendicular to BD by properties of the diagonals of a kite
ΔBCE is a right triangle
By Pythagoras' theorem, [tex]\overline{CE}[/tex]² = [tex]\overline{BC}[/tex]² - [tex]\overline{BE}[/tex]²
Which gives;
[tex]\overline{CE}[/tex]² = 4² - 2² = 12
[tex]\overline{CE}[/tex] = 2·√3
Given that AC is the perpendicular bisector of BD, by the properties of a kite, we have;
BD = BE + DE, where BE = DE definition of bisected line
∴ BD = BE + BE = 2·BE
Area of a triangle = (1/2) × Base length × Height
AE = The altitude (height) of the ΔABD = AC - CE
∴ AE = 10 - 2·√3
BD = The base length of ΔABD = 2·BE (Length of BE = 2)
∴ BD = 2 × 2 = 4
The area of triangle ΔABD = (1/2) × BD × AE
∴ The area of triangle ΔABD = (1/2) × 4 × (10 - 2·√3) = 20 - 4·√3
The area of triangle ΔABD = 20 - 4·√3
Learn more about the properties of a kite here:
https://brainly.com/question/24110637
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