In the figure, a∥e, m∥n, and m∠2 = 112°.


What is m∠6?


Enter your answer in the box

The total weight of the wall is 49,500 lb, and the average dead load per foot of wall length is 1237.5 lb/ft.

To find the total weight of the wall and the average dead load per foot of wall length, we need to calculate the total area of the wall and the area of the windows, then use that information to determine the weight of the remaining brick veneer.

First, we calculate the total area of the wall by multiplying the length and height:

40 ft * 11 ft = 440 ft²

Next, we calculate the area of the windows by multiplying the total area of the wall by 25% (the percentage of the wall that is windows):

440 ft² * 0.25 = 110 ft²

Now we can find the area of the brick veneer by subtracting the area of the windows from the total area of the wall:

440 ft² - 110 ft² = 330 ft²

To find the weight of the brick veneer, we can assume a weight of 150 lb/ft². We can calculate this by multiplying the area of the brick veneer by the weight per square foot:

330 ft² * 150 lb/ft² = 49,500 lb

Now to find the average dead load in lb/ft of the length of the wall, we divide the total weight of the wall by the total length of the wall:

49500 lb / 40 ft = 1237.5 lb/ft

So the total weight of the wall is 49,500 lb, and the average dead load per foot of wall length is 1237.5 lb/ft.

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On solving the provided question, we got to know that -  to plot the graph, required equation is 3x +y -8 = 0

a collection of numbers, symbols, and operators (like + and ) that represent a value. Examples -  2 + 3 is a formula and there is also the statement 3 x/2. The equals symbol does not appear in expressions. Actually, none of these = ≠ < > ≤ ≥

We frequently have to understand a written phrase in order to write an expression. For instance, the notation x + 6 can be used to represent the phrase "6 added to some number," where x stands for the unknown value. To plot the graph,we need to find the equation first.

and to find the equation -

(y - y1) = m( x - x1)

y1 = -4

x1 = -2

y = 3

x = -5)

equation  -

(-3)(x-1) = y-5

-3x + 3 = y-5

3x - 3 = 5-y

3x +y -8 = 0

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Answer: Maisie walked 6.4 miles.

Step-by-step explanation:

Since Maisie is walking at a constant pace of 1.6 miles per hour we can set up the following equation:

y = 1.6(x)

In this equation, Y is the number of miles Maisie walked in total and X is the number of hours she walked. All we have to do is plug in 4 hours as x and solve.

y = 1.6(4)

y = 6.4 miles.

No, 10, 12, and 15 are not the lengths of the sides of a right triangle.

A right triangle is a triangle with one 90 degree angle. The other two angles must be acute angles (less than 90 degrees).

The Pythagorean Theorem is a formula used to determine if three given side lengths can form a right triangle. The Pythagorean Theorem states that the sum of the squares of the two shorter sides of a right triangle is equal to the square of the longest side, also known as the hypotenuse.

In this case, the side lengths of the triangle are 10, 12, and 15. Therefore, the Pythagorean Theorem can be written as:

10^2 + 12^2 = 15^2

100 + 144 = 225

244 ≠ 225

Therefore, 10, 12, and 15 are not the side lengths of a right triangle.

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The Pythagorean theorem can be solved using a C programme, therefore yes. The Pythagorean theorem states that the hypotenuse's square length of a right triangle equals the sum of the squares of its other two sides. The slope is the side that faces the right angle.

Therefore, given the lengths of the two shorter sides (a and b), the length of the hypotenuse can be calculated using the formula: c = sqrt(a^2 + b^2).

Here is an example C program that calculates the length of the hypotenuse of a right triangle given the lengths of the other two sides:

#include <stdio.h>

#include <math.h>

Above command is for library

int main() {

 double a, b, c;

Above command to initiate the variable.

  printf("enter the first side's length.: ");

 scanf("%lf", &a);

To enter the value in program

 printf("enter the second side's length.: ");

 scanf("%lf", &b);

Enter the value and print the value

  c = sqrt(a*a + b*b);

Arithmetic command

   print("The hypotenuse's length is: %lf\n", c); return 0;}

Print the value and return the program value to zero.

This program prompts the user to enter the lengths of the two shorter sides of the triangle, calculates the hypotenuse length using the Pythagorean theorem, and then prints the result.

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Answer: The probability of a random student to have either ginger or blonde hair is 19/28.

Step-by-step explanation: Before anything is done, let's look and see what information the problem gives us and what we need to find out. We know that there's a 5/14 chance for a student to be ginger, and a 9/28 chance for them to be blonde. We need to find out the combined chance, as we want to know what the chances are for a student to have either hair color.

In order to do this, all we need to find is the sum of both fractions. Because the fractions have different denominators, we need to change one of them to match the other. 14 multiplied by 2 is equal to 28.

If we multiply both the numerator and denominator of 5/14 by 2, we get 10/28. Now, all we have to do is add that to 9/28. When we do that, we get 19/28.

19/28 cannot be simplified, so it is our final answer. Hope this helps!

The solution for each system of equations is given as follows:

1) x = -4, y = -8.

2) x = 5, y = -1.

3) x = -7, y = 2.

4) No solution.

5) x = 2, y = -6.

6) x = -3, y = 4.

The system of equations are solved using the elimination method, writing  one variable as a function of another, replacing in the other equation, and then obtaining each variable.

For item 1, we eliminate x, as follows:

x = 12 + 2y.

Hence the solution for y is obtained as follows:

5(12 + 2y) + 3y = -44

60 + 10y + 3y = -44

13y = -104

y = -104/13

y = -8.

Then the solution for x is given as follows:

x = 12 + 2y = 12 + 2(-8) = -4.

For item 2, we have that:

y = 19 - 4x.

Hence:

7x - 2(19 - 4x) = 37

7x - 38 + 8x = 37

15x = 75

x = 5.

Hence the solution for y is of:

y = 19 - 4(5) = -1.

For item 3, we can simplify the second equation by two, hence:

-x + y = 9.

y = 9 + x.

Hence:

3x + 8(9 + x) = -5

3x + 72 + 8x = -5

11x = -77

x = -7.

Hence the solution for y is of:

y = 9 - 7 = 2.

For item 4, we have that:

x = 7 + 3y.

Hence:

2(7 + 3y) - 6y = 12

14 + 6y - 6y = 12

0y = -2. (no solution, division by zero).

For item 5, we have that:

y = -2 - 2x.

Hence:

5x + 3(-2 - 2x) = -8

5x - 6 - 6x = -8

-x = -2

x = 2.

Hence the solution for y is of:

y = -2 - 2(2)

y = -6.

For item 6, we simplify the second equation by two, hence:

2x + y = -2

y = -2 - 2x.

Replacing on the first equation, we have that:

2x + 5(-2 - 2x) = 14.

2x - 10 - 10x = 14

-8x = 24

8x = -24

x = -3.

Hence the solution for y is obtained as follows:

y = -2 - 2(-3)

y = -2 + 6

y = 4.

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The domain of a logarithm function is (0, ∞). The range of the logarithm function is all real numbers.

What is a function?

A function in mathematics from a set X to a set Y allocates exactly one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.

The given function is f(x) = log x.

When the value of x is less than or equal to 0, then the value of log x is undefined.

The possible value of x where f(x) exists is the domain of a function.

In the given function the value of x must be greater than zero.

The domain of the function is (0,∞).

log (0.1) = -1

log (0.023) = -1.638

The value of log x can be any real number.

The possible value of the logarithm function is any real number. Thus the range of the function is (-∞, ∞).

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Rate of speed of each cyclist is:

Alisha 10mi/hr

Jose 15mi/hr

Raul 10mi/hr

Ruthie 16mi/hr

Data given of each cyclist;

Formula used: [tex]r=\frac{d}{t}[/tex]

here,

r=rate of speed

d=distance

t=time

Alisha: Distance=40mi; Time=4hr

applying the formula

[tex]r=\frac{d}{t} \\r=\frac{40}{4} =10mi/hr[/tex]

Jose: Distance=30mi; Time=2hr

applying the formula

[tex]r=\frac{d}{t}\\ r=\frac{30}{2} =15mi/hr[/tex]

Raul: Distance=40mi; Time=4hr

applying the formula

[tex]r=\frac{d}{t} \\r=\frac{40}{4}=10mi/hr[/tex]

Ruthie: Distance=80mi; Time=5hr

applying the formula

[tex]r=\frac{d}{t} \\r=\frac{80}{5} =16mi/hr[/tex]

Alisha= 10mi/hr

Jose= 15mi/hr

Raul= 10mi/hr

Ruthie= 16mi/hr

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Total interest charged by bank in 2 months is 6793.83.

Compound interest is the interest paid on both principal and interest, compounded at regular intervals. At regular intervals, the interest so far accumulated is clubbed with the existing principal amount and then the interest is calculated for the new principal. The new principal is equal to the sum of the Initial principal, and the interest accumulated so far.

The interest that is obtained through the reinvestment of money is known as compound interest. The original principal investment grows substantially more quickly (sometimes referred to as exponentially) when interest is reinvested and allowed to compound over time.

Total loan amount = 875000

total time = 2 months

Rate = 4.75%

Total interest = 875000(1 + [tex]\frac{4.75}{100}[/tex])[tex]\)^{\frac{1}{6} }[/tex] - 875000 =  6793.83

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The three equations for this problem are:

Let's call the number of chocolate cakes x, the number of fruit cakes y, and the number of sponge cakes z

so the

let's use the third equation to get the value of x,y and z:

If you get the values and substitute, then the answer would be:

4 chocolate cakes, 5 fruit cakes, 2 sponge cakes

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In each of the cases, the series ∑an is convergent. This means that the limit of the sequence of partial sums of the series is finite.

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The solution of the pair of equations y = 0 and y = -3 is y = -3/2.

The given pair of equations is:

y = 0

y = -3

We can solve this pair of equations using elimination. To do this, we first add the two equations together, which gives us:

y + y = 0 + (-3)

2y = -3

We then divide both sides by 2 to get the solution for y:

2y/2 = -3/2

y = -3/2

Therefore, the solution of the pair of equations y = 0 and y = -3 is y = -3/2.

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Answer:

3(x+1)(x-3)

Step-by-step explanation:

Well, this isn't an equation, but we can factor it like this:

[tex]3x^2-6x-9=3(x^2-2x-3)=3(x+1)(x-3)[/tex]

Answer:

the answer is 1

Step-by-step explanation:

4(2x-3)=6x+2

8x-12=6x+2

+6x   +6x

14x-12 =2

    +12 +12

14x=14

x=1 and don't worry we all make mistakes

Answer:

you can eliminate the x terms in this system by multiplying each side by 3.

Step-by-step explanation:

in order to eliminate a variable from a system of equations, you must multiply whatever variable you want to eliminate (in this case, x) by a number that will make the variable you want to eliminate in the first (4y+3x=-6) and second (which is y-x= -5) equations cancel out when adding them together

a written example for further clarification:

step 1:

4y + 3x = -6

3*(y - x = -5)

up here, you can see i'm multiplying the bottom equation by 3 in order to change the value of x from x to -3x, so that when you add the top and the bottom equations together, x is nowhere to be found in the resulting equation (this is what you want)

step 2:

distribute the 3 to all terms in the second equation. this gives you:

(3y-3x = -15).

step 3:

now add this new equation to the first equation (4y+3x=-6).

This gives you:

4y+3x=-6

+

3y-3x=-15

then just add the like terms (4y and 3y, 3x and -3x, -6 and -15).

which gives you (7y=-21)

see how x is not in the resulting equation? you have now successfully eliminated it :] hope this helped!

Answer:

2n^2-8n-24

Step-by-step explanation:

Uhm i just did this one with one of my classmates like 2-3 months ago so it just came to mind.

Hope this helped tho! :)

Using multiplication we know that the product of 3 * - 4 is -12.

One of the four fundamental arithmetic operations, along with addition, subtraction, and division, is multiplication.

A product is the output of a multiplication operation.

The addition method, lengthy multiplication, grid method, and drawing lines are four different ways to multiply.

So, we have:

3 * -4

Here, we know that 3 is a positive number and -4 is a negative number.

And so the product will be a negative number.

Now, calculate the product as follows:

3 * -4

-12

Therefore, using multiplication we know that the product of 3 * - 4 is -12.

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Answer:

Approx 3.92

Step-by-step explanation:

Using the normal distribution and the central limit theorem, it is found that there is a 0.0901 = 9.01% probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50.

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Using the concept of fraction, the percentage edited on the video is 62.5 percent.

What is Percentage

Percentage is a standard mathematical concept used to express a portion of a whole number in terms of a hundred. It is denoted by the symbol “%” and is often expressed as a fraction or a decimal. For example, 25% can be expressed as 0.25 or 1/4.

In this problem, Thorton has done a 2.5 hours work. The percentage he has edited can be calculated using fraction or ratio as;

percentage edited = (2.5 / 4) × 100

Percentage = 0.625 × 100

Percentage = 62.5 %

From the above, Thorton has edited 62,5 percent of the video for his school project.

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Answer: first u have to find the perimiter for each side

Step-by-step explanation:

the answer is 100 d z

Answer:

i am not to sure but if i am corroct it IS polynomial

Step-by-step explanation:

hope this helps

[tex]sin(C)=\cfrac{\stackrel{opposite}{4}}{\underset{hypotenuse}{9}}\qquad \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2 - b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \sqrt{9^2 - 4^2}=a\implies \sqrt{65}=a \\\\[-0.35em] ~\dotfill[/tex]

[tex]tan(C)=\cfrac{\stackrel{opposite}{4}}{\underset{adjacent}{\sqrt{65}}}\implies tan(C)=\cfrac{4}{\sqrt{65}}\cdot \cfrac{\sqrt{65}}{\sqrt{65}}\implies tan(C)=\cfrac{4\sqrt{65}}{65}[/tex]

Answer: 12.96

Step-by-step explanation: you should multiply 12 * 0.08 = 0.96

then just add 0.96 + 12 = 12.96

The average rate of change is equivalent to 2.

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Given is the table as shown below -

[x] :  0  1  2  3  4

[y] :  -2 -3 1  3  6

The rate of change in the interval 0 < x < 4 is -

AROC = (6 + 2)/(4 - 0)

AROC = 8/4

AROC = 2

Therefore, the average rate of change is equivalent to 2.

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Three examples of perfect squares is 1) 9, as it is equal to 3 x 3.2) 16, as it is equal to 4 x 4.3) 25, as it is equal to 5 x 5.

Perfect squares are numbers that can be expressed as the product of two equal integers, such as 4, 9, and 16. These numbers can be written as the square of a single number, such as 2² = 4, 3² = 9, and 4² = 16. Perfect squares are also known as whole squares, and they provide an easy way to find the square root of a number.

Perfect squares are numbers that are the result of multiplying a number by itself. For instance, 4 is a perfect square because it is equal to 2 x 2.

Similarly, 9 is a perfect square because it is equal to 3 x 3. Perfect squares can be easily identified by their square root, which is the number that can be multiplied by itself to produce the perfect square.

For example, the square root of 16 is 4, since 4 x 4 = 16.

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The third term of the arithmetic sequence will be negative 14.

A series of integers called an arithmetic succession or arithmetic chain of events has a fixed difference between the terms.

Let a₁ be the first term and d be a common difference.

Then the nth term of the arithmetic sequence is given as,

aₙ = a₁ + (n - 1)d

The first term is 20 and the common difference is calculated as,

aₙ = aₙ₋₁ - 17

aₙ - aₙ₋₁ = - 17

d = - 17

Then the third term is calculated as,

a₃ = 20 + (3 - 1) (-17)

a₃ = 20 + 2 (-17)

a₃ = 20 - 34

a₃ = - 14

The third term of the arithmetic sequence will be negative 14.

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For acceptable x values of √12(x-1)+√√2(x-1)², the option is equivalent to the quotient given here (x-1) ² is [tex]$2 \sqrt{3} \sqrt{x-1}-\sqrt{2}(x-1)$\\[/tex] .

The equivalent of the quotient displayed above for allowable x values is

[tex]$\sqrt{1} \cdot 2(x-1)+\sqrt{\sqrt{2}}(x-1)^2$[/tex]

[tex]$2(x-1)+\sqrt[2 \cdot 2]{2}(x-1)^2$\\[/tex]

[tex]\$2(x-1)+\sqrt[4]{2}(x-1)^2$\\$(2 x-2)+\sqrt[4]{2}\left(x^2+2 x(-1)+(-1)^2\right)$\\$(2 x-2)+\sqrt[4]{2}\left(x^2-2 x+1\right)$\\$2 x-2+\sqrt[4]{2}\left(x^2-2 x+1\right)$\\$2 x+\sqrt[4]{2}\left(x^2-2 x+1\right)-2$\\$2 x+\left(\sqrt[4]{2} \cdot x^2-\sqrt[4]{2} \cdot 2 x+\sqrt[4]{2}\right)-2$\\$2 x+\left(\sqrt[4]{2} \cdot x^2-2 \cdot \sqrt[4]{2} \cdot x+\sqrt[4]{2}\right)-2$\\$2 x+\sqrt[4]{2} \cdot x^2-2 \cdot \sqrt[4]{2} \cdot x+\sqrt[4]{2}-2$[/tex]

[tex]$f(x)=\sqrt{12(x-1)}-\sqrt{2(x-1)^2}$[/tex]

[tex]$\frac{d}{d x}\left(\sqrt{12(x-1)}-\sqrt{2(x-1)^2}\right)$[/tex]

[tex]$\sqrt{12(x-1)}-\sqrt{2(x-1)^2}=2 \sqrt{3} \sqrt{x-1}-\sqrt{2}(x-1)$[/tex]

[tex]$\sqrt{12(x-1)}-\sqrt{2(x-1)^2}$[/tex]

[tex]$\sqrt{12(x-1)}=2 \sqrt{3} \sqrt{x-1}$[/tex]

[tex]$\sqrt{2(x-1)^2}=\sqrt{2}(x-1)$\\$=2 \sqrt{3} \sqrt{x-1}-\sqrt{2}(x-1)$\\[/tex]

Values that might result in a fraction's denominator being equal to zero are excluded. Finding these omitted values is crucial for resolving a rational statement because you cannot divide by 0.

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The probabilities for the game of roulette that involves spinning a wheel with 38 slots, for a and b, are 0.4737, or 18/38, or 47.37%.

The following are the rationales:

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