In the figure, KP = 50, KQ = 45, PQ = 38. What is RQ?​

Answer:

L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

Step-by-step explanation:

f ( t ) = 10 cos ( 12t + 60°) u(t)

attached below is a detailed solution of the given problem

L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

Answer:  roughly 151.81788 square meters of metal

=====================================================

Explanation:

The base is a square with side lengths x, so its area is x*x = x^2

Let h be the height of the tank. We have four identical wall panels that have area of xh square meters. The four walls lead to a lateral surface area of 4xh. Overall, the entire tank requires x^2+4xh square meters of metal. We're ignoring the top since the tank is open.

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Let's set up a volume equation and then isolate h.

volume = length*width*height

108 = x*x*h

108 = x^2*h

x^2*h = 108

h = 108/(x^2)

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Plug that into the expression we found at the end of the first section.

x^2+4xh

x^2+4x(180/(x^2))

x^2+(720/x)

------------

Depending on what class you're in, the next step here will vary. If you are in calculus, then use the derivative to determine that the local min happens at approximately (7.11379, 151.81788)

If you're not in calculus, then use your graphing calculator's "min" feature to locate the lowest point on the f(x) = x^2+(720/x) curve.

This lowest point tells us what x must be to make x^2+(720/x) to be as small as possible, where x > 0.

In this context, it means that if the square base has sides approximately 7.11379 meters, then you'll need roughly 151.81788 square meters of metal to form the open tank. This is the least amount of metal required to build such a tank, and that will have a volume of 108 cubic meters.

Answer:

[tex]\text{B) }56\:\mathrm{cm^2}[/tex]

Step-by-step explanation:

The area of a triangle with height [tex]h[/tex] and base [tex]b[/tex] is given by [tex]A=\frac{1}{2}bh[/tex]. By definition, the base and the height must intersect at a 90 degree angle. Therefore, the diagram gives a base of 14 cm and a height of 8 cm. Substituting these values, we get:

[tex]A=\frac{1}{2}\cdot 8\cdot 14=\boxed{\text{B) }56\:\mathrm{cm^2}}[/tex]

Answer:

29

Step-by-step explanation:

tan c = opposite / adjacent

c = tan -1 (25/45) = 29

Answer:

Step-by-step explanation:

tan C = opp/adj

sin C = 25/45

sin C = 0.5556

C = sin^-1 0.5556

= 33.75

9514 1404 393

Answer:

  x ≈ 2.87

Step-by-step explanation:

We  can subtract 6 to put the equation into a form easily solved.

  x^2 +2x +1 = 15

  (x +1)^2 = 15

  x +1 = √15 . . . . . for the greatest solution, we only need the positive root

  x = √15 -1 ≈ 2.87

Answer:

D. No; the graph fails the vertical line test.

Step-by-step explanation:

If any vertical line intersects a graph more than once it is NOT a function

Answer:

20%

Step-by-step explanation:

Decrease in amount = original - new amount

Decrease in amount = 110 - 88 = $22

Decrease % = decrease/original x 100%

= 22/110 x 100%

= 20%

9514 1404 393

Answer:

  Part A: 2 ft²

  Part B: draw a diagonal (AC, for example); 1 ft²

Step-by-step explanation:

Part A:

The area of a parallelogram is given by the formula ...

  A = bh

where 'b' is the length of the base, and 'h' is the perpendicular distance between the bases.

Using the numbers shown on the diagram, the area is ...

  A = (3 ft)(2/3 ft) = 3·2/3 ft²

  A = 2 ft² . . . . . area of the parallelogram

__

Part B:

Typically, a polygon is partitioned into triangles by drawing diagonals from one of the vertices. It does not matter which one. (In a quadrilateral, only one diagonal can be drawn from any given vertex.) Here, the "base" of each triangle is the same as the base of the parallelogram: 3 feet. The "height" of each triangle is the same as the height of the parallelogram: 2/3 ft.

The area of a triangle is given by the formula ...

  A = 1/2bh

  A = 1/2(3 ft)(2/3 ft) = (1/2)(3)(2/3) ft²

  A = 1 ft² . . . . . . . . area of each triangle

_____

Additional comment

It should be no surprise that the area of each of the two congruent triangles is 1/2 the area of the parallelogram.

9514 1404 393

Answer:

  B, D, E, A, C

Step-by-step explanation:

The main idea here is to use your English comprehension skill to determine the meaning of the phrase, then use your math understanding to write it in symbols. Turning off your brain at the sight of a "word problem" will not be productive.

The wording "some number" or "a variable" or "unknown value" all refer to a variable, typically represented by a single letter. Letters commonly use are {a, b, c, x, y, z}, but variables are not restricted to that set (nor to single letters, nor lower case letters).

In most cases, the math expression is a direct translation of the English expression using the usual math symbols. Values are generally increased by addition, decreased by subtraction, squared using an exponent of 2. A product is the result of multiplication, and a quotient is the result of division.

Top-to-bottom, the boxes on the left will be filled with B, D, E, A, C.

Answer:

I think its 0.

Step-by-step explanation:

Double negatives make a positive, add the like terms. Hope this helps

Answer:

The answer is "nominal, qualitative".

Step-by-step explanation:

The information available is not numerically structured in a form name.

The measuring level is therefore nominal. Qualitative information is also called, which can be seen but not measured. Thus data given is qualitative. 

Answer:

y=2x-1

Step-by-step explanation:

Answer:

A = 30 inches^2

Step-by-step explanation:

The area of a trapezoid is given by

A = 1/2 (b1+b2)h  where b1 and b2 are the lengths of the bases

A = 1/2 ( 10+5) * 4

A = 1/2 (15)*4

A = 30 inches^2

Answer:

Area of trapezoid is 30 inches ².

Step-by-step explanation:

A trapezoid having length of Base ¹ and Base ² are 10 in. and 5 in. and it's height is 4 in. Find the area of trapezoid.

Area of trapezoid is given by

= 1/2 × ( B¹ + B² ) × h

Where, B¹ = 10 in.

B ² = 5 in.

h = 4 in.

substitute the values

Area = 1 / 2 × ( 10 in × 5 in ) × 4 in

multiplying the values

Area = 1 / 2 × 15 in. × 4 in

Area = 1 / 2 × 60 in ².

Area = 30 in².

Hence, Area of trapezoid is 30 inches ².

Answer:

[tex]b = 74^o[/tex] --- acute base

Step-by-step explanation:

Given

See attachment for the figure

Required

The acute base angle of the trapezoid

From the question, the isosceles triangle and the trapezoid share the same base.

Represent the base angle with b.

So:

[tex]b + b + 32^o = 180^o[/tex] --- angles in a triangle

[tex]2b = 180^o-32^o[/tex]

[tex]2b = 148^o[/tex]

Divide by 2

[tex]b = 74^o[/tex]

Answer:

x ≥ −3

Step-by-step explanation:

Step One : Add 9 to both sides.

x − 9 + 9 ≥ −12 + 9

x ≥ −3

There is no more to be done, that is our answer. x ≥ −3.

Hope this helps, please mark brainliest! :)

Answer:

13,956,779.6764

Answer:

13956 779.7 (•‿•) this is my ans.

[tex] \frac{35e {}^{9} }{5 {e}^{8} } \ \\ \\ \frac{7e {}^{9} }{e {}^{8} } \\ \\ \\ = 7e[/tex]

Step By Step Explanation:

Alternate Forms:

Answer:

Scale of the drawing would be 20/12 inch and 0.6 (6/12) inch

Step-by-step explanation:

For most of the residential buildings an scale of 1 inch = 12 feet can be used to draw the residential units.

In that case the scale of the drawing would be 20/12 inch and 0.6 (6/12) inch

Dave should label the dimensions in inches

Answer:

the last one

Step-by-step explanation:

12+(16/4+2)2

12+(4+2)2

12+6*2

12+12

24

Answer:

D

Step-by-step explanation:

A. 17.33

B. 11

C. 14

D. 24

Answer:

The length of the hypotenuse is 8 units

Step-by-step explanation:

Recall the notation SOH CAH TOA. This means that in  aright angled triangle,

Sin A = a/c where a is the length of the opposite side and c is the length of the hypotenuse.

Given that sinA=1/2 and a = 4, the hypotenuse c

sin A = 4/c

1/2 = 4/c

cross multiply

c * 1 = 4 * 2

c = 8 units

Answer:

The PERIMETER P is the distance around the rectangle.

Let's call the width of the rectangle W and the length of the rectangle L.

As you go around the edge there two equal lengths and two equal widths.

The formula for the perimeter of a rectangle is P=2*L+2*W.

P=2L%2B2W

Substitute 290 for P and 62 for the width.

290=2L%2B2%2862%29

Solve for L.

290=2L%2B2%2862%29

290=2L%2B124

290-124=2L

2L=166

L=83

The equation L=83 means that the length is 83 cm.

CHECK your work.

2(62)+2(83) = 124+166 = 290cm.

The length of the rectangle is 83cm.

Answer:

A.

Step-by-step explanation:

She would receive $11.67

A is the correct math

Answer:

correct answer is c

Step-by-step explanation:

2.44x10^-3

Answer:

12.7 cm

Step-by-step explanation:

We can obtain CB using Pythagoras :

CB = √12² - 6²

CB = √108

CB = 10.39

Using CB,

We can apply trigonometry on triangle BCD to obtain the length of CD

Sin θ = opposite / hypotenus

Sin 55 = CB / CD

Sin 55 = 10.39 / CD

CD = 10.39 / sin 55

CD = 12.68

CD = 12.7 cm

Answer:

[tex]\text{D. }1,920}\:\mathrm{in^3}[/tex]

Step-by-step explanation:

The volume of a rectangular prism is given by [tex]A=l\cdot w\cdot h[/tex], where [tex]l[/tex] is the length of the prism, [tex]w[/tex] is width, and [tex]h[/tex] is height.

Therefore, the area of the given prism is equal to [tex]8\cdot 12 \cdot 20=\boxed{\text{D. }1,920\:\mathrm{in^3}}[/tex].

Answer:

100

Step-by-step explanation:

482 ÷ 5 = 96.4

96.4 -> 100

Hope this helps! Brainliest?

Answer:

Quotient: 96

Step-by-step explanation:

482/5= 96R2

Quotient: 96

Remainder: 2

Step-by-step explanation:

Please see the photo for the method

We're given the one-sided limit,

[tex]\displaystyle\lim_{x\to1^+}\frac{\sin(1-x)-e^{x-1}+1}{\ln(x)}[/tex]

Evaluating the limand directly at x = 1 gives the indeterminate from

(sin(1 - 1) - exp(1 - 1) + 1) / ln(1) = 0/0

so we can potentially solve the limit by applying L'Hopital's rule. Doing so gives

[tex]\displaystyle\lim_{x\to1^+}\frac{\sin(1-x)-e^{x-1}+1}{\ln(x)}=\lim_{x\to1^+}\frac{-\cos(1-x)-e^{x-1}}{\frac1x}=\frac{-\cos(0)-e^0}{\frac11}=\boxed{-2}[/tex]

Answer:

5x + 2y = 12

3x + 4y = 13.50

One Hersey bar = 1.5

One pack of Starburst = 2.25

Step-by-step explanation:

Let :

Cost of one Hersey bar = x

Cost of one pack of Starburst = y

System of equation :

For Jack :

5x + 2y = 12 - - - (1)

For Joey :

3x + 4y = 13.50 - - - (2)

To determine the cost per Hersey bar and pack of Starburst

5x + 2y = 12 - - - (1)

3x + 4y = 13.50 - - (2)

Multiply (1) by 3 and (2) by 5

15x + 6y = 36 - - - (3)

15x + 20y = 67.50 - - - (4)

Subtract (4) from (3)

-14y = - 31.50

y = 31.50 / 14

y = 2.25

Using (1)

5x + 2y = 12

Put y = 2.25

5x + 2(2.25) = 12

5x + 4.50 = 12

5x = 12 - 4.50

5x = 7.50

x = 1.5