In the following acid-base reaction,H₂PO₄⁻ is theH₂PO₄⁻ (aq) + NH₃ (aq) ---> HPO₄²⁻ (aq) + NH₄⁺ (aq)a) conjugate acidb) acidc) base

H3PO3 - is the formula for phosphorous acid

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Answer: the answer is D

Explanation: hope this helps just did it

Answer:

Explanation:

i dont kow

The complete ionic equation and the net ionic equation for the reaction of aqueous ammonia and aluminum nitrate is written as follows:

[tex]Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)[/tex]

[tex]Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)[/tex]

In an ionic equation all the ions are charges are balanced to the proper stoichiometric ratio. The states of each species have to be written in the brackets.

The reaction of aluminum nitrate and aqueous ammonia is written as follows:

[tex]Al(NO_{3})_{3}(aq) + 3NH_{4}OH(aq)\rightarrow Al(OH)_{3}(s) +3NH_{4}NO_{3}(aq)[/tex]

The complete ionic equation is written below:

[tex]Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)[/tex]

From this complete ionic equation the net ionic equation can be written by cancelling same species from both side as below:

[tex]Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)[/tex]

Therefore, the net product aluminum hydroxide is precipitated and the net ionic equation is written as above.

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We can use the law of ideal gases to solve this question.

The law of ideal gases is represented by the following formula:

Where P is the pressure, v is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature.

The first step is to convert kPa to atm, °C to K and mL to L.

Now, we can use these values to find n, which is the amount of moles of the gas:

The answer is 0.00264 moles of chlorine are released.

Answer:

6.15 moles

Explanation:

1 mole of C has 6.02 x 10^23 atoms

the number of mole in 3.7 x 10^24 is

(1 mole)(3.7 x 10^24)/(6.02 x 10^23)

= 6.15 moles

CO 2

H ₂0

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The term mole concept is used here to determine the molar mass of an element. The molar mass of the element is 80.62 g/ mol.

One mole of a substance is that quantity of it which contains as many particles or entities as there are atoms in exactly 12 g of carbon -12. The equation which is used to calculate the number of moles is:

The mass of one mole of molecules of a substance is defined as the molar mass. It is generally expressed in g mol⁻¹

Number of moles = Given mass / Molar mass

Here the given mass of the element is 10.4 g. The number of moles of the element is 0.129 mole. Then the molar mass is:

Molar mass = Given mass / Number of moles

= 10.4 g / 0.129 mol

= 80.62 g/ mol

Thus the molar mass of element is 80.62 g/ mol.

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The engineer determining the effectiveness of a new machine that produces ammonia from hydrogen and nitrogen is an example of a) Manufacturing and testing a prototype.

Ammonia can be obtained using the process called Haber's process. In designing a machine for manufacturing ammonia, a series of steps are to be taken. The first step is to identify the problem and the second is to find solutions to the problem.

To make the solutions obtained to be in practice, the third step includes drafting a strategic plan and design. After obtaining the design the last step is to test the design for its efficiency.

In the case of the machine designed for manufacturing Ammonia, determining the effectiveness of the machine could be tested by manufacturing and testing a sample.

Hence, the correct option is a).

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Answer:

Guys’ search it up on math thank me later

Explanation:

dhsjdjsusysgtjghtd fjfhfhcchdh

From the calculation, we now obtain the molarity of the sulfuric acid to be 5.8 Mol/L

The term concentration is defined as the ratio of the number of moles to the volume of the solution. We know that unit of the molarity of the solution is the moles per liters.

We know the following;

Mass of the acid =  571.6 g

Volume of the acid = 1.000 x 10^3 ml or 1 L

Molar mass of the acid = 98.08 g/mol

Hence;

Number of moles of the acid = 571.6 g/98.08 g/mol = 5.8 moles

Molar concentration of acid = 5.8 moles/ 1 L

= 5.8 Mol/L

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The moles of SO₂ formed if you have 467.2 g of ZnS and excess O₂ is 4.79 moles.

The balanced chemical reaction of the give equation is-

2 ZnS(s) + 3 O₂(g) → 2 ZnO(s) + 2 SO₂(g)

What is mole?

Mole is defined as fundamental measurement unit which is used to measure the amount of substance.

Number of moles of ZnS = Given mass

                                             Molar mass

Moles of ZnS = 467.2 g

                          97.47 g/mol

Moles of ZnS = 4.79 moles

From the reaction, we know that

2 moles of ZnS forms 2 moles of SO₂

4.79 moles of ZnS forms 2 x 4.7 moles of SO₂

                                         2

Moles of SO₂ = 4.79 mol

Hence, the moles of SO₂ can be formed is 4.79 moles.

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Answer:

Cats are eazy to take care for and relatively affordable

Answer:

cats r better cuz there cats ovi

Explanation:

there small, easy to take care of, and the are good with kids depending on the breed.

According to the given statement 4.64 grams of O₂(g) are needed to completely burn 27.6 g C₃H₂(g).

Chemical equations are symbolic depictions of chemical reactions where the reactants and products are stated in terms of their respective chemical formulae.

Mass of C₃H₂ = 27.6 g

Molar mass of C₃H₂  = 38.05 g/mol

Molar mass of O₂= 32 g/mol

We have to calculate the moles of C₃H₂

moles of C₃H₂ = given mass C₃H₂/molar mass C₃H₂

moles of C₃H₂ = 27.6/38.05 = 0.725 mol

We have to calculate the moles of C₃H₂

The balanced chemical equation is:

C₂Hg (g) + 5O₂(g) → 3 CO₂(g) + 4H₂O(g)

From the reaction, we conclude that

As, 1 mole of C₂Hg react with 5 mole of O₂

So, 0.725 mole C₃H₂ of  react with 0.725/5 = 0.145 mole of O₂

We have to calculate the mass of O₂

Mass of O₂ = Moles of O₂ * Molar mass of O₂

Mass of O₂ = (0.145moles) * (32g/mol) = 4.64g

The mass of O₂ needed is, 4.64 grams.

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The compound with the highest boiling point is hexanone. Hexanone has the highest boiling point among the following substances at degree Celsius, and its structure is much more compact than that of the other substances.

The temperature at which a liquid's vapor pressure matches that of the surrounding environment's liquid is known as the boiling point. As gas forms below the surface and escapes upwards at this temperature, the liquid starts to bubble.

Important information about an organic compound's structural make-up and physical characteristics can be learned from its boiling point. The boiling point of a chemical can be used to identify and describe the substance. At higher atmospheric pressures, water boils more quickly than it does at lower atmospheric pressures.

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The question requires us to balance a given reaction and then determine the excess reagent for this same reaction, given that 3.4 moles of Ca(NO3)2 and 2.4 moles of LiPO4 are used.

First, let's balance the equation so we can make the required calculations from it. A simple way to balance this reaction is to start with metals (Li and Ca) and consider the anions NO3 and PO4 instead of the isolated N, O and P atoms:

1) We write the given equation:

___Ca(NO3)2 + ____Li3PO4 --> ___LiNO3 + ____Ca3(PO4)2

2) We check the amount of Ca and Li on both sides of the reaction:

On the left side -> 1 Ca and 3 Li

On the right side -> 3 Ca and 1 Li

3) Then, we change the coefficients in order to have the same amount of Ca and Li on both sides:

3

4) Next, we check the amount of NO3 and PO4 anions:

Left side -> 3*2 NO3 = 6 NO3 and 1 PO4

Right side -> 3*1 NO3 = 3 and 2 PO4

4) We need to adjust some numbers in order to have the same amount of all considered species:

5) At last, we check again:

Left side -> 3 Ca, 6 NO3, 6 Li, 2 PO4

Right side -> 3 Ca, 6 NO3, 6 Li and 2 PO4

a) Then, the balanced reaction is:

1

b) Now that we know the stoichiometric coefficients, we can determine the excess reagent.

From the balanced reaction, we know that we need 3 moles of Ca(NO3)2 to react with 2 moles of Li3PO4. Then, we can write:

3 mol Ca(NO3)2 --------------- 2 mol Li3PO4

3.4 mol Ca(NO3)2 ------------ x

exexcesslimiting (more than 2.27 moles)

We can also determine the excess reactant from the following relation:

y ------------- 2.4 mol Li3PO4

In this case, solving for y, we have that we would need 3.6 moles of Ca(NO3)2 to react with 2.4 moles of Li3PO4, meaning that there is less than required of Ca(NO3)2, thus this is the limiting reactant while Li3PO4 is the excess reactant.

The formula for the base dissociation constant (Kb) is Kb = [NH4+][OH-]/[NH3].

Kb is a temperature-dependent constant that is typically calculated at 25 degrees Celsius. Ammonia has a Kb value of 1.8E-5 (the notation "E-5" stands for "ten in power -5").

A basic solution is created when ammonia and water are combined. Ammonium hydroxide is created when a little amount of dissolved ammonia combines with water. This compound then breaks down into ammonium and hydroxide ions.

A material that absorbs hydrogen ions or protons in solution is referred to as a base. The base dissociation constant is the equilibrium constant for the equilibrium created when a weak base interacts with water.

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Answer:

that is some above

Explanation:

because of the chemical reaction

I fell confident that I can identify the different rates of chemicals.

This is known to be be a powerful diagnostic tool and it is called a reaction's rate. It is one that is seen when we can create methods to increase production by understanding how quickly items are made and what slows down reactions.

Therefore, reaction rate, in regards to chemistry, is seen as the speed with which a said or given chemical reaction moves or functions.

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Answer

Moles = 1.22 moles

Explanation

Given

Mass of water = 22 g

We know the molar mass of water = 18,01528 g/mol

Required: Moles of H2O

Solution

To calculate the number of moles, use

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 22g/18,01528 g/mol

n = 1.22 mol

Answer:mole =22gm/ 18gm = 1.22moles

Explanation:A mole is calculated by dividing the given weight from molecular weight of the compound. In this case Molecular weight of H2O = 18 grams. So answer is 22/18= 1.22

Since Tricia is investigating a crime, the best form of remedy that Tricia can use to solve this  issue is option A. She should talk to witnesses who observed the crime.

A witness is said to be a term that is defined as a person who has observed an occurrence or who testifies to what they have observed.

Note that a person who witnesses a robbery as well as testifies in court about what they observed is an example of a witness and they are the best people to get accurate information regarding the crime from.

Hence, option A is correct.

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Answer:  A

Explanation:

Answer:

In liquids, particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

The density of a solution with a mass of 5,780.1 ng and a volume of 995 gallons is calculated as 5.736. Grams per cubic centimeter can be stated as SI unit of measurement for density.

Either you have to measure the solid's dimensions or measure the liquid's volume using a measuring jug. To get a number in meters cubed, convert any necessary units.

Further in order to determine the mass of the object or material, place it on a scale.

Density is the mass of a material or substance that is calculated per unit volume. d = M/V, where d can be stated as density, M as mass, and V as volume, that is the formula for density.

The amount of "stuff" is contained in a specific quantity of space is determined by its density. For instance, a block of the harder, lighter element gold (Au) will be denser than a block of the heavier element lead (Pb) (Au).

Styrofoam blocks are less dense than bricks. Mass per unit volume is how it is defined.

Typically, there are two forms of density: absolute density and relative density. Relative

Density = m/v

= 5780.1/995

= 5.736

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Answer: 74.54kg

Explanation:

Gasoline is 0.79 g/mL

1Kg/1000g x 0.79g/mL x 1000mL/1L x 1L/1.06 quarts x 4 quarts/1gallon x 25 gallons

1 x 0.79 x 1000 x 1 x 4 x 25  divided by 1000 x 1 x 1 x1.06 x 1 =74.54Kg

The molarity of a CaCl₂ solution that is prepared by dissolving 27.1 g of CaCl₂ in sufficient water to give 779 mL of solution is 0.31M.

Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.

The molarity of a substance can be calculated by dividing the number of moles of the substance by the volume.

According to this question, 27.1 g of CaCl₂ is dissolved in sufficient water. The number of moles can be calculated as follows:

moles = 27.1g ÷ 110.98 g/mol

moles = 0.24mol

Molarity of CaCl₂ = 0.24mol ÷ 0.779L

Molarity of CaCl₂ = 0.31M

Therefore, 0.31M is the concentration required to prepare by dissolving 27.1 g of CaCl₂ in sufficient water.

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In an aqueous solution of ethanol, C₂H₅OH, the molecules that would be present in the solution are ethanol molecules and water molecules.

Aqueous solutions are solutions containing water as the solvent of the solution.

An aqueous solution simply means dissolved in water.

When dissolved in water, ionic compounds dissociate to form ions in aqueous solutions.

Other polar solutes which are non-ionic will simply dissolve in water as a result of the interaction of the polar ends of the molecules. However, no ions will be formed by these polar non-ionic solutes.

For example, a solution of ethanol in water is a non-ionic aqueous solution.

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Taking into account the reaction stoichiometry, if 42.9 g of iron is reacted with 27.5 g of oxygen, 61.335 grams of iron(III) oxide are produced.

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 96 grams of O₂ reacts with 223.4 grams of Fe, 27.5 grams of O₂ reacts with how much mass of Fe?

mass of Fe= (27.5 grams of O₂× 223.4 grams of Fe)÷ 96 grams of O₂

mass of Fe= 63.995 grams

But 63.995 grams of Fe are not available, 42.9 grams are available. Since you have less mass than you need to react with 27.5 grams of O₂, Fe will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 223.4 grams of Fe form 319.4 grams of Fe₂O₃, 42.9 grams of Fe form how much mass of Fe₂O₃?

mass of Fe₂O₃= (42.9 grams of Fe×319.4 grams of Fe₂O₃)÷ 223.4 grams of Fe

mass of Fe₂O₃= 61.335 grams

Then, 61.335 grams of Fe₂O₃ are produced.

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Answer:

What does chemistry mean in science?

Chemistry is a branch of natural science that deals principally with the properties of substances, the changes they undergo, and the natural laws that describe these changes.

Explanation:

The following graph shows water solubility of some salts versus temperature curves on the chart shows the melt that has the largest solution temperature is the curve b

Water solubility is the because of its polarity and ability to form hydrogen bonds and also water makes an excellent solvent means it can dissolve so many kind of molecules

Here given graph shows water solubility of some salts versus temperature and in that curve a, c and d  show the low temperature but b curve show almost high temperature and that's why the melt that has the largest solution temperature and also has a positive sign and curve c and d are show constant water solubility and curve b shoe first high then low and then more high that's why the curve b has the largest temperature

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