Is HNO3 is a soluble or insoluble
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The atomic mass of an atom tell us How much the atom weighs

The atomic mass represents the total mass of an atom, including its protons, neutrons, and electrons. It is measured in atomic mass units (amu) and gives us an indication of the mass of the atom.

Moreover, the atomic mass helps in calculating other properties of atoms, such as the number of neutrons. By subtracting the number of protons (which corresponds to the atomic number) from the atomic mass, we can determine the approximate number of neutrons in an atom. Neutrons play a vital role in stabilizing the nucleus and influencing the atom's overall behavior.

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To determine the amount of sugar in a two-liter bottle of orange juice, we can use the information provided about the sugar content in a 250 mL glass.

The 250 mL glass contains 22 grams of sugar. To find the sugar content in a 2,000 mL bottle, we can set up a proportion:250 mL / 22 grams = 2,000 mL / x grams

Cross-multiplying and solving for x, we get:

x = (2,000 mL * 22 grams) / 250 mL

Simplifying the equation gives us: x = 176 grams

Therefore, a two-liter bottle of orange juice contains approximately 176 grams of sugar. It's important to note that this calculation assumes the sugar content remains constant throughout the bottle and that the measurement given for the 250 mL glass is accurate.

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Answer:

100 rbed  KJ |0| +2k

Explanation:

Answer:

a scientist forms hypothesis after carefully analyzing

Explanation:

if you look at the steps of scientific methods from biology, you'll see that after analyzing hypothesis is formed.

Approximately 7.26 grams of sodium propanoate must be dissolved in 0.25 dm^3 of 1 mol dm^-3 propanoic acid to create a buffer of pH 4.87.

To calculate the mass of sodium propanoate (C2H5COONa) that must be dissolved in 0.25 dm^3 of 1 mol dm^-3 propanoic acid (C2H5COOH) to create a buffer at pH 4.87, we can use the Henderson-Hasselbalch equation:

pH = pKa + log ([A-] / [HA])

where:

pH is the desired pH of the buffer (4.87 in this case)

pKa is the dissociation constant of the weak acid (4.87 in this case)

[A-] is the concentration of the conjugate base (sodium propanoate)

[HA] is the concentration of the weak acid (propanoic acid)

In a buffer solution, the ratio of the concentrations of the conjugate base and the weak acid is important. Let's assume that x moles of sodium propanoate are dissolved in 0.25 dm^3 of 1 mol dm^-3 propanoic acid. This means the concentration of propanoic acid will be (1 - x) mol dm^-3, and the concentration of sodium propanoate will be x mol dm^-3.

According to the equation, we have:

4.87 = 4.87 + log (x / (1 - x))

Simplifying the equation, we get:

0 = log (x / (1 - x))

Now, let's solve for x:

x / (1 - x) = 1

x = 1 - x

2x = 1

x = 1/2

So, the concentration of sodium propanoate (C2H5COONa) in the buffer solution should be 0.5 mol dm^-3.

To calculate the mass of sodium propanoate needed, we need to convert the volume of the solution to moles. Since the concentration is 0.5 mol dm^-3 and the volume is 0.25 dm^3, the number of moles of sodium propanoate required is:

moles = concentration × volume = 0.5 mol dm^-3 × 0.25 dm^3 = 0.125 moles

The molar mass of sodium propanoate is:

(2 × atomic mass of carbon) + (5 × atomic mass of hydrogen) + atomic mass of oxygen + atomic mass of sodium

= (2 × 12.01 g/mol) + (5 × 1.008 g/mol) + 16.00 g/mol + 22.99 g/mol

= 58.08 g/mol

Finally, we can calculate the mass of sodium propanoate using the number of moles:

mass = moles × molar mass = 0.125 moles × 58.08 g/mol = 7.26 grams

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Answer:

The total number of carbon atoms on the left-hand side of the equation is 6 x 2 = 12.

1.35 g of H₂SO₄ would require approximately 46 mL of 0.30 M H₂SO₄.

To determine the volume of 0.30 M H₂SO₄ that would contain 1.35 g of H₂SO₄, we need to use the molar mass of H₂SO₄ and perform a conversion.

The molar mass of H₂SO₄ can be calculated by summing the atomic masses of its constituent elements:

2(1.01 g/mol of H) + 1(32.07 g/mol of S) + 4(16.00 g/mol of O) = 98.09 g/mol

Now, we can use the formula:

moles = mass / molar mass

moles of H₂SO₄ = 1.35 g / 98.09 g/mol = 0.0138 mol

The molarity (M) of a solution is defined as the number of moles of solute divided by the volume of the solution in liters. Rearranging this equation, we have:

volume = moles / Molarity

volume = 0.0138 mol / 0.30 mol/L = 0.046 L

Finally, we can convert the volume from liters to milliliters by multiplying by 1000:

volume = 0.046 L × 1000 mL/L = 46 mL

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The equations that show ionization are:

NaCl(s) → Na+(aq) + Cl-(aq)

H3O+(aq) + Cl-(aq)

CaCl2(s) → Ca2+(aq) + 2Cl-(aq)

The equations that show ionization are:

NaCl(s) → Na+(aq) + Cl-(aq)

This equation represents the dissociation of solid sodium chloride (NaCl) into sodium ions (Na+) and chloride ions (Cl-) in aqueous solution.

H3O+(aq) + Cl-(aq)

This equation represents the ionization of hydronium ion (H3O+) and chloride ion (Cl-) in an aqueous solution.

CaCl2(s) → Ca2+(aq) + 2Cl-(aq)

This equation represents the dissociation of solid calcium chloride (CaCl2) into calcium ions (Ca2+) and chloride ions (Cl-) in aqueous solution.

The other equations listed do not specifically show ionization. The equation O2(g) → O2(aq) represents a change of state from a gas (g) to an aqueous solution (aq), but it does not involve the formation of ions. The equation CO2(g) + 2H2O(l) → HCO3-(aq) + H3O+(aq) represents a chemical reaction involving the formation of ions (bicarbonate ion and hydronium ion), but it does not show ionization from a solid or gas. The equation HCI(g) + H2O(l) does not show ionization.

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Isolating and modifying cellulose from a melon seed coat involves several steps. Here's a general outline of the process:

Seed Coat Removal ; Cleaning ; Drying ; Grinding ; Cellulose Extraction ; Cellulose Modification.

Seed Coat Removal: Start by separating the melon seed coat from the seeds. This can be done by manually peeling or cutting away the outer coat.

Cleaning: Wash the seed coat thoroughly to remove any dirt, debris, or other impurities.

Drying: After cleaning, allow the seed coat to dry completely. This can be done by spreading it out on a clean surface and leaving it to air dry or using a low-temperature oven.

Grinding: Once the seed coat is dry, grind it into a fine powder. This can be achieved using a blender, food processor, or mortar and pestle.

Cellulose Extraction: Extract cellulose from the powdered seed coat using a chemical or enzymatic method. One common approach is the acid hydrolysis method:

a. Prepare a solution of dilute acid (such as hydrochloric acid) and add the powdered seed coat to it.

b. Heat the mixture under controlled conditions, typically around 60-80°C, for a specific duration.

c. Filter the mixture to separate the cellulose residue from the liquid acid solution.

d. Wash the cellulose residue with water multiple times to remove any remaining acid or impurities.

e. Dry the cellulose thoroughly, either through air drying or using a low-temperature oven.

Cellulose Modification: The isolated cellulose can be modified to enhance its properties or functionality. This step can include processes such as chemical derivatization or physical treatments. For example, cellulose can be chemically modified by esterification or etherification to introduce new functional groups.

It's important to note that the specific conditions and methods for isolation and modification may vary depending on the desired characteristics of the cellulose and the intended applications.

Additionally, proper safety precautions and adherence to applicable regulations should be followed when working with chemicals and equipment during the process.

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In the given chemical reaction, H2SO4 reacts with water to form HSO4- (hydrogen sulfate) and H3O+ (hydronium) ions. Since H2SO4 is a strong acid, it dissociates completely in water, meaning that all the H2SO4 molecules will ionize.

Given that 0.0005 moles of H2SO4 have reacted and the solution volume is 500 L, we can calculate the concentration of H3O+ ions in the solution. Since 1 mole of H2SO4 produces 1 mole of H3O+ ions, the concentration of H3O+ ions is:Concentration of H3O+ = (0.0005 moles) / (500 L) = 1.0 x 10^-6 M

The pH of a solution is defined as the negative logarithm (base 10) of the H3O+ concentration. Therefore:pH = -log10(1.0 x 10^-6)

Using logarithmic properties, the pH can be calculated:

pH ≈ -(-6) = 6

Therefore, the pH of the solution is approximately 6, indicating that it is slightly acidic.

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Answer:

K= ( [h2]² [O2] )/[H2O]²

Explanation:

characters arent in my keyboard

Answer:

the answer is a

Explanation:

First, we shall determine mole of each gas present. This is shown below:

For argon, Ar

Mole = mass / molar mass

Mole of argon, Ar = 3.03 / 40

Mole of argon, Ar = 0.076 mole

For krypton, Kr

Mole = mass / molar mass

Mole of krypton, Kr = 1.16 / 83.8

Mole of krypton, Kr = 0.014 mole

Finally, we shall determine the total pressure of the mixture. Details below:

PV = nRT

P × 2.5 = 0.09 × 0.0821 × 298

Divide both sides by 2.5

P = (0.09 × 0.0821 × 298) / 2.5

Total pressure = 0.88 atm

The partial pressure for each gas can be obtain as follow:

For argon, Ar

Partial pressure = (Mole / total mole) × total pressure

Partial pressure Ar = (0.076 / 0.09) × 0.88

Partial pressure Ar = 0.74 atm

For krypton, Kr

Partial pressure of Kr = Total pressure - Partial pressure of Ar

Partial pressure of Kr = 0.88 - 0.74

Partial pressure of Kr = 0.14 atm

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Answer:

The volume of Component 1 is 36 cubic inches.

Explanation:

To calculate the volume of a composite solid, we need to determine the individual volumes of the different components and then add them together.

In this case, the composite solid consists of multiple components with the following dimensions:

Component 1:

Length: 4 inches

Width: 3 inches

Height: 3 inches

To find the volume of Component 1, we multiply the length, width, and height together:

Volume of Component 1 = Length x Width x Height = 4 in x 3 in x 3 in = 36 cubic inches

Therefore, the volume of Component 1 is 36 cubic inches.

Please provide the dimensions of the remaining components of the composite solid, and I will calculate the total volume by summing up the individual volumes.

Answer:

Explanation:

a

Answer:

The answer is D - Keq = [H2]^2 × [O2]

[2]^2

Explanation:

The equilibrium constant (Keq), is a quantitative measure of the position of equilibrium in a chemical reaction. It is defined by the ratio of the concentrations (or partial pressures) of the products to the concentrations (or partial pressures) of the reactants.

For a general chemical reaction:

aA+bB + CC+dD

Explanation: The equilibrium constant expression is given by:

Keq = [C]^c x [D]^d

[A]^a x [B]^b

Where [A], [B], [C], and [D] represent the molar concentrations of the species A, B, C, and D, respectively. The coefficients a, b, c, and d represent the stoichiometric coefficients of the balanced equation.

The given reaction is 2H2O(g) ↔ 2H2(g) + O2(g)

The equilibrium constant expression for the given system can be expressed as follows:

Keq = [H2]^2 × [O2]

[2]^2

Where:

[H2] represents the molar concentration of hydrogen gas (H2).

[O2] represents the molar concentration of oxygen gas (O2).

[H2O] represents the molar concentration of water vapor (H2O).

The equilibrium constant expression for the given system can be expressed as follows: Keq = [H2]^2 × [O2]

[2]^2

Answer:

A. 63

B. 34.6

Explanation:

The mass of sulfur dioxide required is approximately 6.36 grams.

To determine the number of grams of sulfur dioxide (SO2) required to exert a pressure of 0.705 atm in a 2.50L tank at 0 °C, we can use the ideal gas law equation: PV = nRT.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15, so the temperature becomes 273.15 K. The ideal gas constant (R) is 0.0821 L·atm/(mol·K).Rearranging the ideal gas law equation to solve for the number of moles (n), we get n = PV / RT.

Plugging in the given values, n = (0.705 atm) * (2.50 L) / [(0.0821 L·atm/(mol·K)) * (273.15 K)]. Calculating this expression, we find that n is approximately 0.0993 moles.The molar mass of sulfur dioxide is 64.06 g/mol (32.06 g/mol for sulfur + 2 * 16.00 g/mol for oxygen).

Finally, we can calculate the mass of sulfur dioxide using the formula: mass = n * molar mass = 0.0993 moles * 64.06 g/mol. Thus, the mass of sulfur dioxide required is approximately 6.36 grams.

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Answer:

The correct empirical formula, if the ratio is 1:1:3, is: FeS3

Explanation:

In this case, the empirical formula indicates the simplest whole-number ratio of atoms present in a compound. The ratio 1:1:3 means that for every 1 atom of the first element, there is 1 atom of the second element and 3 atoms of the third element. Among the options provided, FeS3 is the only one that fits this ratio.

Answer:

A Brønsted-Lowry acid is a substance which donates protons to other substances. (option c.)

Explanation:

For Brønsted-Lowry acids, are the ones that donates protons and bases, the ones that accepts H⁺ from others compounds.

In this reaction:

NH₃  +  HCl → NH₄Cl

The hydrocloridic acid donates the proton to ammonia to make ammonium chloride. So the HCl, is a Brønsted-Lowry acid while the ammonia is a base.

There are cases, like water that behaves as acid and base.

These compounds are called amphoteric because it can donate H⁺ or OH⁻ at the same time.

H₂O ⇄  H⁺  +  OH⁻

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An approximation for the density of water at 22.4 Celcius degrees is:

D = 0.9975 g/ml

To find this, we can use tables of density (sadly, we don't have a function that we can just evaluate to get this).

These are tables that give the density of water as for different temperatures.

Using a table, we know that:

for 21°C the density is 0.9982067 g/ml

for 25°C  the density is 0.9970470 g/ml

So ten density will be a value between these two, a good estimation for the density will be:

D = 0.9975 g/ml

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a Approximately 895 kg/h of pure sunflower oil was obtained from the first stage of the process.

b.  503 kg/h is needed for the process

c.  43.5 kg/h is unextracted oil is left in the seeds

a. Given a feed of 10,000 kg/h of sunflower seeds containing 13.5 wt % oil, the total weight of oil in the feed can be calculated as follows:

(10,000 kg/h) * (13.5/100) = 1,350 kg/h

Let X be the weight of the pressed sunflower seeds obtained from the first stage of the process.

Since the oil content of the pressed seeds is 5 wt %, the total weight of oil in the pressed seeds is:

(5/100) * X = 0.05X

Considering the mass balance of the whole process, we know that the total mass of the feed equals the total mass of the products:

10,000 kg/h = X + pure oil stream

And in terms of oil:

1,350 kg/h = 0.05X + pure oil stream

We have two equations with two unknowns (X and pure oil stream). The equations can be solved by substitution:

From the first equation, we can express X as:

X = 10,000 kg/h - pure oil stream

Substituting X in the second equation:

1,350 kg/h = 0.05 * (10,000 kg/h - pure oil stream) + pure oil stream

Simplifying the equation:

1,350 kg/h = 500 kg/h - 0.05 * pure oil stream + pure oil stream

Combining like terms:

1,350 kg/h = 500 kg/h + (1 - 0.05) * pure oil stream

Further simplifying:

850 kg/h = 0.95 * pure oil stream

Solving for the pure oil stream:

pure oil stream = 850 kg/h / 0.95 ≈ 894.74 kg/h

So, approximately 895 kg/h of pure sunflower oil was obtained from the first stage of the process.

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Answer:

The TRUE statement about strong acids is that they are 100% ionized in water.

Explanation:

The TRUE statement about strong acids is that they are 100% ionized in water. This means that all the acid molecules dissociate in water to produce a high concentration of hydronium ions (H3O+) and the corresponding anions. Examples of strong acids include hydrochloric acid (HCl), sulfuric acid (H2SO4), and nitric acid (HNO3).

30.53 grams of O₂ are required for the complete combustion of 8.60 grams of pentane C₅H₁₂.

To determine the mass of O₂ required for the complete combustion of pentane to CO₂ and H₂O  we need to balance the combustion equation first.

C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

From the balanced equation  we can see that

1 mole of C₅H₁₂ reacts with 8 moles of O₂  to produce 5 moles of CO₂ and 6 moles of H₂O.

molar mass of C₅H₁₂

(5 × 12.011) + (12 × 1.008) = 72.151 g/mol

convert to moles

8.60 g  / 72.151 g/mol = 0.1193 mol

the mole ratio between C₅H₁₂ and O₂ is 1:8.

0.1193 mol × 8 mol  / 1 mol  = 0.9544 mol

hence solving for the mass of O₂ using its molar mass

0.9544 mol  × (32.00 g / 1 mol ) = 30.53 g O2

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The pH of the aqueous solution with a hydronium ion concentration of 3.0 ×[tex]10^-^6[/tex] M is approximately 5.52, and to calculate the pH of an aqueous solution, one need to determine the concentration of hydronium ions ([H3O+]).

The pH is defined as the negative logarithm (base 10) of the hydronium ion concentration. pH is a measure of the acidity or alkalinity of a solution. It is a logarithmic scale that indicates the concentration of hydronium ions (H3O+) in a solution. The pH scale ranges from 0 to 14, with 7 being considered neutral.

In this case, the concentration of hydronium ions [H3O+] is given as 3.0 × [tex]10^-^6[/tex] M.

Using the formula for pH:

pH = -log[H3O+]

Let's calculate the pH:

pH = -log(3.0 ×[tex]10^-^6[/tex])

pH ≈ -(-5.52)

pH ≈ 5.52

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Answer: The chemicals that cannot be distilled are called non-volatile solutes. These are substances that do not evaporate at the boiling point of the solvent, which is typically water. Therefore, when a solution containing a non-volatile solute is heated to boil, the solvent evaporates leaving behind the solute. Distillation is not effective at removing non-volatile solutes because the solute remains in the boiling flask and does not evaporate with the solvent and can be condensed back into liquid form.

Explanation:

Answer:1950s-1960s

Explanation:

Cobalt-60 is a radioactive isotope of cobalt that has a half-life of 5.27 years and decays by beta decay to nickel-60. It is commonly used in radiation therapy for cancer treatment and is also used as a source of gamma rays for industrial applications such as sterilization of medical equipment and food preservation. Cobalt-60 was first discovered in 1939 by Glenn T. Seaborg and John Livingood, and its potential for medical and industrial applications was quickly recognized. However, its widespread use did not occur until the 1950s and 1960s, when the technology for producing and handling radioactive sources became more advanced and the benefits of using cobalt-60 were more widely understood. Today, cobalt-60 remains an important tool in medical and industrial settings for its ability to deliver precise doses of radiation and its efficiency in sterilization processes.

The name of the compound from the structure that we can see in the question is;

4,4-dibromohex-2one

The International Union of Pure and Applied Chemistry (IUPAC) established a systematic set of guidelines for naming organic compounds.

Find the compound's longest continuous chain of carbon atoms. The compound's name is derived from this chain, which also acts as the compound's parent chain.

Assign a number to each carbon atom in the parent chain to give each carbon atom in the compound a special identification. The end that is closest to the functional group or substitutes is where the numbering begins.

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The equation of the circle in standard form is (x - h)² + (y - k)² = (r)².

To derive the equation of a circle in standard form based on the given figure, we can use the distance formula. Let's complete the table step by step:

The distance from the center of the circle C(h, k) to the point D(x, y) on the circumference is the radius r. Using the distance formula, we have:

Distance formula: √((x₂ - x₁)² + (y₂ - y₁)²)

Plugging in the values for C(h, k) and D(x, y):

r = √((x - h)² + (y - k)²)

The circumference of the circle intersects the x-axis at two points. In these points, the y-coordinate is 0. Therefore, we substitute y = 0 into the equation derived in step 1:

r = √((x - h)² + (0 - k)²)

r = √((x - h)² + k²)

Similarly, the circumference intersects the y-axis at two points, where the x-coordinate is 0. We substitute x = 0 into the equation derived in step 1:

r = √((0 - h)² + (y - k)²)

r = √(h² + (y - k)²)

Now, let's square both sides of the equations derived in steps 2 and 3 to eliminate the square root:

(r)² = (x - h)² + k²

(r)² = h² + (y - k)²

Rearranging the equations from steps 4, we obtain the standard form of the equation of a circle:

(x - h)² + (y - k)² = (r)²

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COMPLETE QUESTION IS IN IMAGE