is retractable measuring tape a simple machine?

Answers

Answer 1

Answer:

A simple machine is a device that multiply an applied force by the use of the mechanical advantage built into the machine. Therefore, a simple machine changes the direction in which the applied force acts or the magnitude of the applied force, or both in order to do work

A retractable measuring tape is a device used for length measurement such that the direction of the applied force is reversed during retraction, while the magnitude of the output force is constant and dependent on the coil in the measuring

Therefore, the measuring tape does not have a constant mechanical advantage or act as a force multiplier, and therefore;

It is not a simple machine

Explanation:


Related Questions

HELP ME ILL MARK U THE BRAINLIEST
the crane takes 2.5s to raise the box 3.0 m. Calculate the power output of the crane

Answers

Answer:

Power = 1800 W

Explanation:

Power = work / time

Power = 4500 / 2.5

Power = 1800 W

You can do only number 1 only

Answers

For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C

After rearranging the formula Q = It, to find for time, the new formula would be:
t = Q / I
From question:
Q = 100C
I = 0.1A

Therefore, time, t = 100 / 0.1 = 1000 s

Do only number 3 and thank

Answers

Charge = 0.2 Ah is the correct answer...

A cheerleader jumps off from the shoulders of two of her teammates. They all fell at the same rate, as a result. This type of collision is...?

Answers

Answer:

elastic collision

Explanation:

Derive the relation between wavelength, frequency and speed of sound.​

Answers

Explanation:

sorry I need some points foe this


The absorption of a photon causes a hydrogen atom
to change from the n = 2 to the n = 3 energy state.
What is the energy of the absorbed photon?
A) 4.9 eV
C) 1.9 eV
B) 3.4 eV
D) 10.2 eV

Answers

4.9 eV is the correct answer

Hope it helps you ^ _ ^

How are galaxies named?

Answers

Answer:

Some galaxies are given descriptive names (e.g. "Andromeda", "Whirlpool") if they are particularly distinctive in location or appearance. But most galaxies are known from their designation in a catalogue. One of the earliest catalogues of objects in the sky was made by Charles Messier.

Which one of the patterns is the quietest?​

Answers

I think it’s [ C ] because it not to high and it doesn’t have a lot of waves like the rest.

I hope this help sorry it it wrong but that’s what I think c:

Answer:

A

Explanation:

What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4

Answers

Answer:

[tex]x = 2\sqrt 2[/tex]

Explanation:

Given

[tex]Hypotenuse = 4[/tex]

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

[tex]x^2 + x^2 = 4^2[/tex] --- i.e. the other legs are equal

So, we have:

[tex]2x^2 = 16[/tex]

Divide both sides by 2

[tex]x^2=8[/tex]

Take square roots of both sides

[tex]x = \sqrt 8[/tex]

Simplify

[tex]x = 2\sqrt 2[/tex]

Answer:

7√2

Explanation:

Explique cómo es que las estrellas emiten una radiación, específicamente qué es lo que sucede a nivel atómico

Answers

Answer:

Las estrellas se forman debido a la unión de pequeños elementos y partículas como el hidrógeno y el helio que experimentan una fusión nuclear en el núcleo debido a la intensa presión para formar un nuevo átomo (como dos hidrógeno que se combinan para formar un átomo de helio) que es un proceso. que requiere una gran cantidad de energía para comenzar, por lo que cada reacción de fusión produce una gran cantidad de energía que puede mantener la reacción y equilibra la fuerza gravitacional que atrae las masas de las partículas hacia el centro de la estrella

A medida que la energía de la estrella se irradia, la superficie de la estrella cede la energía en forma de calor y luz de manera que debido a la alta temperatura de las partículas de los átomos de los elementos se mueven muy rápida y energéticamente para emitir fotones rápidamente. (alta frecuencia) que se ve como el alto brillo de la estrella

Explanation:

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

Answers

Answer:

The horizontal component of the vector is approximately -16.07

The vertical component of the vector is approximately 19.15

Explanation:

A vector quantity is a quantity that posses both magnitude and direction specifications

The magnitude of the given vector, R = 25 units

The direction of the vector, θ = 130°

Therefore the location of the vector, starting from the origin of the Cartesian plane, is in the second quadrant having an angle of 180° - 130° = 50° to the horizontal

Given that the x-coordinate  is negative in the second quadrant, we have;

The horizontal component of the vector, Rₓ = The x-coordinate of the vector = R×cos(θ)

∴ The horizontal component of the vector, Rₓ = 25 × cos(130°) = -25 × cos(50°) ≈ -16.07

The horizontal component of the vector, Rₓ ≈ -16.07

The vertical component of the vector, [tex]R_y[/tex] = The y-coordinate of the vector = R×sin(θ)

∴ The vertical component of the vector, [tex]R_y[/tex] = 25 × sin(130°) ≈ 19.15

The vertical component of the vector, [tex]R_y[/tex] ≈ 19.15

The vector can be resolved as R = -16.07·i + 19.15·j

A 350 kilogram car is traveling at a constant velocity of 15 m/s. What is the net force acting on the car?

Answers

Answer:

The net force acting on the car is zero.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 350 Kg

Velocity (v) = constant = 15 m/s

Net Force (F) =?

An object moving with a constant velocity is not accelerating. The acceleration of such object is zero. Thus, the net force acting on the object is also zero. This can further be explained as shown below:

Mass (m) = 350 Kg

Acceleration = 0 (since the velocity is constant)

Net Force (F) =?

Force (F) = mass (m) × Acceleration (a)

F = m × a

F = 350 × 0

F = 0

Thus, the net force acting on the car is zero.

A man who weighs 75kg on the surface of the earth whose mass is 6*10^24kg. If the radius of earth is 6480km ,calculate the force of attraction between them.

Answers

Answer:

718.02N is the answer to the question

31) A box is pushed, up a ramp, at constant velocity with a force of 14 N.
What is the magnitude of the friction force working on the box? *

Answers

There could be multiple answered to that n=4{e)

The magnitude of the frictional force working on the box is 14 N.

According to Newtons's first law, an object will continue in its state of rest or state of uniform motion unless it is acted upon by an unbalanced force. This means that motion or acceleration is caused by an unbalanced force.

Since the box is moving at constant velocity, the frictional force on the box and the force that moves the box forward are exactly equal in magnitude but opposite in direction.

Learn more: https://brainly.com/question/9352088?

Craig is modeling the discovery of electromagnetism. Which procedure should he use?

A. moving a magnet into a coil of wire in a closed circuit
B. moving a magnet into a coil of wire in an open circuit
C. bringing a compass near a wire that has no electric current
D. bringing a compass near a wire that has an electric current

Answers

Answer:

A

Explanation:

moving a magnet into a coil of wire in a closed circuit

Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism. Option A is correct.

What is electromagnetism ?

The physical interplay of electric charges, magnetic moments, and the electromagnetic field is known as electromagnetism.

The electromagnetic field can be static, moving slowly, or forming waves.

Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism.

Hence, option A is correct.

To learn more about the electromagnetism, refer to the link;

https://brainly.com/question/3427992

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Do solar panels create enough energy to power the car throughout the day?

Answers

Answer:

Yes, but only if it's sunny.

Explanation:

As you know, solar panels generate energy through the sun's rays of light (better known as sunlight). Therefore, as long as the sun is shining high in the sky, the car will generate electricity and be able to function. If this vehicle was only powered by solar panels, it would not function during the night, in cloudy areas, and/or in dark places (such as parking garages or home garages).

Hope this helps!

A cubic box has a 0.8 meter side. Find the volume of air in the box in cubic meter?

Answers

Answer:

[tex]V=0.512\ m^3[/tex]

Explanation:

Given that,

The side of a cubic box, s = 0.8 m

We need to find the volume of air in the box.

We know that,

The volume of a cube is given by :

[tex]V=s^3[/tex]

So,

[tex]V=0.8^3\\\\V=0.8\times 0.8\times 0.8\\\\=0.512\ m^3[/tex]

So, the volume of air in the box is [tex]0.512\ m^3[/tex].

what is the momentum of an object weighing 7.5 kg moving at 1.6 m/s?

Answers

Answer:

[tex]momentum = mass \times velocity \\ = 7.5 \times 1.6 \\ = 12 \: kg {ms}^{ - 1} [/tex]

Mass is 7.5 kg

Velocity is 1.6 m/s

we know that,

momentum = mass × velocity

or; momentum =7. 5 kg × 1. 6 m/s

or; momentum = 12 kgms^1

A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains in static equilibrium. What is the mass of the meterstick

Answers

Hey i dont have an answer but i need the points for finals today. Thank you
I don’t know the answer sorry I need points

please helpppp... thank u ❤️​

Answers

Answer:

For Ryan:

[tex]at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^{ - 1} [/tex]

For the football kicked:

[tex]s = ut - \frac{1}{2} g {t}^{2} \\ for \: range : s = 0 \\ u \sin( \theta) = \frac{gt}{2} \\ t = \frac{2u \sin(\theta) }{g} \\ range(x) = ut \\ x = \frac{ {2u {}^{2} \sin(\theta) }^{} }{g} \\ \frac{50 \times 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 \times 9.8 \times 50 \\ u = 2318.9 \: {ms}^{ - 1} \\ \theta = 12.2 \degree[/tex]

Answer:

the highest point for the first question is 0 meters per second

the answer for question 2 is 45 degrees

An ohmic dipole of resistance 100 ohm is crossed by a current of intensity 120 ma. Calculates the voltage across this chemical dipole

Answers

Answer:

12.0 Volt

Explanation:

Step 1: Given data

Resistance of the ohmic dipole (R): 100 Ohm

Intensity of current (I): 120 mA (0.120 A)

Step 2: Calculate the voltage (V) across this chemical dipole

To calculate the voltage across the ohmic dipole, we will use Ohm's law.

I = V/R

V = I × R

V = 0.120 A × 100 Ohm = 12.0 V

how do icebergs form

Answers

Answer:

They break off large ice sheets found at the North and South poles.

Answer:

The answer is D

Explanation:

They break off large ice sheets found at the poles.

How much power is required to do 180 J of work in 2.4s?​

Answers

75
p = w / t
p = 180 / 2.4
p = 75

The power required to do 180 J of work in 2.4 s is 75 W.

What is power?

Power can be defined as the rate at which work is done.

To calculate the power, we use the formula below

Formula:

P = E/t............. Equation 1

Where:

P = PowerE = Energy or workt = Time.

From the question,

Given:

E = 180 Jt = 2.4 s

Substitute these values into equation 1

P = 180/2.4P = 75 W.

Hence, the power required to do 180 J of work in 2.4 s is 75 W.

Learn more about power here: https://brainly.com/question/24858512

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Can anybody answer ??

Answers

Answer:

C. Electromagnetic wave

Explanation:

Please give me brainliest

Answer:

C. electromagnetic

Explanation:

because 5g uses higher frequency radio waves a type of electromagnetic radiation which are within the spectrum considered safe.

3kg ball traveling at 10 m/s east collides with 5 kg ball traveling at 2m/s east after the collision the balls stick together what is the final velocity of the 3kg ball ?

Answers

Answer:

Explanation:

The formula for this is designed around the fact that momentum must be conserved:

[tex][(m_{ball1}*v_{ball1})+(m_{ball2}*v_{ball2})]_b=[(m_{ball1}+m_{ball2})v_{both}]_a[/tex]

This is because they sitck together after they collide. Filling in:

[(3*10)+(5*2)] = [3 + 5]v and

30 + 10 = 8v so

40 = 8v and

v = 5

They are both moving east at a velocity of 5 m/s since they stuck together.

To clean the floor, David exerts a 40 N force on a broom handle to push it 2 m. If the broom handle makes a 40° angle with the floor, what is the work done by David on the broom? If the broom handle were angled at 65° would David do more or less work? Explain your answer. Use the Guess method.

Answers

Answer:

Explanation:

Work done = Force * Displacement

There is no displacement vertical so only the horizontal part of force did work.

The horizontal force = Force * cos(angle with floor)

Work done = 40*cos(40°)*2

= 61.28 J

As cos(65°) is less than cos(40°), work done will be less at 65°.

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

Answers

Answer:

The horizontal component of the vector ≈ -16.06

The vertical component of the vector ≈ 19.15

Explanation:

The magnitude of the vector, [tex]\left | R \right |[/tex] = 25 units

The direction of the vector, θ = 130°

Therefore, we have;

The horizontal component of the vector, Rₓ = [tex]\left | R \right |[/tex] × cos(θ)

∴ Rₓ = 25 × cos(130°) ≈ -16.06

The horizontal component of the vector, Rₓ ≈ -16.06

The vertical component of the vector, R[tex]_y[/tex] = [tex]\left | R \right |[/tex] × sin(θ)

∴  R[tex]_y[/tex] = 25 × sin(130°) ≈ 19.15

The vertical component of the vector, R[tex]_y[/tex] ≈ 19.15

(The vector, R = Rₓ + R[tex]_y[/tex]

[tex]\underset{R}{\rightarrow}[/tex] = Rₓ·i + R[tex]_y[/tex]·j

∴ [tex]\underset{R}{\rightarrow}[/tex] ≈ -16.07·i + 19.15j)

Which situation results in the most attraction between two magnets?
A. The north pole of one magnet is near the south pole of the other
magnet
B. The north pole of one magnet is far away from the north pole of
the other magnet.
C. The north pole of one magnet is far away from the south pole of
the other magnet.
D. The south pole of one magnet is near the south pole of the other
magnet

Answers

A is the correct answer

Transforma las siguientes unidades utilizando factores de conversión (no vale poner el número solo) a. 85 atm a mmHg b. 60 Pa a atm c. 780 mmHg a Pa d. 740 mmHg a atm

Answers

Answer:

a. 6.5 × 10⁴ mmHg

b. 5.9 × 10⁻⁴ atm

c. 1.0 × 10⁵ Pa

d. 0.97 atm

Explanation:

Transformaremos las siguientes unidades utilizando factores de conversión.

a. 85 atm a mmHg

Usaremos el factor de conversion 1 atm = 760 mmHg.

85 atm × 760 mmHg/1 atm = 6.5 × 10⁴ mmHg

b. 60 Pa a atm

Usaremos el factor de conversion 1 atm = 101325 Pa.

60 Pa × 1 atm/101325 Pa = 5.9 × 10⁻⁴ atm

c. 780 mmHg a Pa

Usaremos el factor de conversion 760 mmHg = 101325 Pa.

780 mmHg × 101325 Pa/760 mmHg = 1.0 × 10⁵ Pa

d. 740 mmHg a atm

Usaremos el factor de conversion 1 atm = 760 mmHg.

740 mmHg × 1 atm/760 mmHg = 0.97 atm

Explain concept of donor levels and accepter levels in extrinsic semiconductors and How can Fermi level be defined for conductors , insulators and semiconductors when temperature increases above zero Kelvin.

Answers

Answer:

DONORS: If the material for which it substitutes has more electrons than the original

ACCEPTORS: If the replacement material has fewer electrons than the original material

Fermi level: the point where the probability of finding the last electron is ½

Explanation:

When in a semiconductor material a small fraction of an element is replaced by another with different valences, an excess charge is created.

If the material for which it substitutes has more electrons than the original, there is an excess of electrons, these excess electrons are weakly bound in the material and their orbits are large, in an energy versus moment diagram their energy places them a little more below the conduction band, these materials are called DONORS.

If the replacement material has fewer electrons than the original material, one electron is missing to complete the bonds, so there is a movement of the other electrons, an easier way to analyze this movement of the (n-1) electrons is to suppose that The missing charge has a positive charge and to study its movement, this positive charge is called a hole, its binding energy is small so the orbit of the hole is large, in an energy diagram it is located a little above the band of valence, these are called ACCEPTORS

The Fermi level is defined as the point where the probability of finding the last electron is ½, when the temperature is changed the density of states of the bands changes, therefore the location point moves, but its [probability remains ½

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