It is known that the weights of male Persian cats are normally distributed with mean  and variance 0.5^2 kg^2.(a) Sketch a diagram showing the above information. [2](b) Find the proportion of male Persian cats weighing between 5.5 kg and 6.5 kg . [2] A group of  80 male Persian cats are drawn from this population.(c) Determine the expected number of cats in this group that have a weight of less than 5.3kg. [3](d) It is found that  12 of the cats weigh more than xkg . Estimate the value of  x. [3](e) Ten of the cats are chosen at random. Find the probability that exactly one of them weighs over 6.25 kg . [4]

To amortize a loan of $256,400 with an interest rate of 7.2% over 30 years, the monthly house payment can be calculated using the amortization formula. The payment size is $1,758.70 (rounded to the nearest cent).

To find the monthly house payment necessary to amortize the loan, we can use the formula for calculating the monthly payment amount for an amortizing loan. The formula is given by:

Payment = (Loan Amount * Monthly Interest Rate) / (1 - (1 + Monthly Interest Rate)^(-Number of Payments))

First, we need to convert the annual interest rate to a monthly interest rate. The monthly interest rate can be calculated by dividing the annual interest rate by 12 and converting it to a decimal. In this case, the monthly interest rate is 7.2% / 12 = 0.006.

Next, we substitute the values into the formula. The loan amount is $256,400, the monthly interest rate is 0.006, and the number of payments is 30 years * 12 months = 360 months.

Plugging in these values into the formula, we have:

Payment = (256,400 * 0.006) / (1 - (1 + 0.006)^(-360))

Calculating this expression, we find that the monthly house payment necessary to amortize the loan is approximately $1,758.70 when rounded to the nearest cent.

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To find f(g(x)), we have to substitute the formula for g(x) as the input for f(x).

   f( g(x) ) = f( x+7 )

               = 2 (x+7) - 3

               = 2x + 14 - 3

               = 2x + 11

The key is to substitute the entire formula for g(x) in as the input for f.

The function g(x) = √x / (x³ - 5x² - 14x) is continuous for all values of x greater than 7, which can be represented in interval notation as (7, ∞).

To determine the values of x for which the function g(x) is continuous, we need to consider any potential points of discontinuity. In this case, the function is a rational function, so we need to identify any values of x that would make the denominator equal to zero, as division by zero is undefined.

The denominator of g(x) is x³ - 5x² - 14x. To find the values of x that make the denominator zero, we can factor it as x(x² - 5x - 14) = 0. Solving this equation, we find that x = 0 and x = 7 are the values that make the denominator zero.

However, since the question specifies that x > 7, the interval of interest is x > 7. In this interval, the denominator of the function is always positive, ensuring that there are no points of discontinuity. Therefore, the function g(x) is continuous for all values of x greater than 7, which can be represented as (7, ∞) in interval notation.

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Based on the behavior of the terms, the series ∑n=1∞ (−1)nsin(9n) diverges.

To determine whether the series ∑n=1∞ (−1)nsin(9n) converges or diverges, we can analyze its behavior.

The series involves alternating signs with the term (−1)n and the function sin(9n).

For a series to converge, it must satisfy two conditions:

1.   The individual terms of the series must approach zero as n approaches infinity.

2.   The series must exhibit an overall pattern or behavior that allows the sum to converge.

Let's analyze the behavior of the terms in the series:

As n increases, the term (−1)n alternates between positive and negative values. The function sin(9n) oscillates between -1 and 1 as n increases.

Since sin(9n) oscillates indefinitely between -1 and 1 without approaching zero, the terms of the series do not converge to zero as n approaches infinity.

Therefore, based on the behavior of the terms, the series ∑n=1∞ (−1)nsin(9n) diverges.

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The key elements of the graph are completed as below

                                                      a                                       b

Direction of Opening             Down                                      up

Vertex (x, y)                            (-3, 4)                                       (2, 1)

Is there a max or min?           max                                         min

What is the max or min?         4                                              1

Axis of symmetry                    x = -3                                     x = 2

X-intercepts                        (-4, 0) and (-1, 0)                       imaginary

Y-intercept                           (0, -5)                                         (0, 3)

The x-intercept of a parabola is the point(s) where the parabola intersects the x-axis. Geometrically  the x-intercepts are the points where the y coordinate of the parabola is equal to zero, this is also called the roots

In the case of b, the roots are imaginary and hence are not shown on the graph

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Answer:

writing in english is easier

Step-by-step explanation:

True.

The method of least squares is used in regression analysis to determine the best-fitting line or curve that minimizes the sum of squared errors (SSE). The SSE is calculated by summing the squared differences between the observed values and the corresponding predicted values.

The goal of the least squares method is to find the line that minimizes this sum, indicating the line that has the smallest overall error.

Additionally, the least squares method ensures that the regression line has an average error of zero by taking into account the overall deviation from the line. This means that, on average, the predicted values from the regression line will be equal to the observed values.

So, it is true that the method of least squares specifies that the regression line has an average error of 0 and an SSE that is minimized.

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Answer:

my answer is 20

Step-by-step explanation:

tan 45=opposite/adjacent

1 =opposite*20.

opposite=20cm

If the taxi operated every day, the annual profit per taxicab license would be $8,030. The market price of a taxicab license, assuming a 10% interest rate and constant conditions, would be $220. The number of additional licenses needed to reduce the taxicab price per ride to $5 would depend on the demand and supply conditions.

(1) The competitive equilibrium price per ride is determined by setting the price equal to the marginal cost. Thus, the competitive equilibrium price is $5. The equilibrium number of rides per day can be calculated by substituting the price into the demand function D(P) = 1200 - 20p, giving 1,000 rides.

(2) In 1995, the demand curve changed to D(n) = 1220 - 20p. By setting the demand equal to the supply, the equilibrium price of a ride in 1995 can be determined, which is $6.10.

(3) The profit per ride in 1995, can be calculated by subtracting the marginal cost ($5) from the equilibrium price ($6.10), resulting in a profit of $1.10 per ride. The profit per taxicab license per day is obtained by multiplying the profit per ride by the taxi capacity, resulting in $22. If the taxi operates every day, the annual profit per taxicab license will be $8,030.

(4) The market price of a taxicab license can be determined by discounting the annual profit per taxicab license, resulting in $220.

(5) The exact number of additional licenses needed would depend on the specific demand and supply conditions.

(6) The value of a taxicab license at the new fare of $5 would depend on the expected profits generated at that price.

(7) It depends on the perceived impact on their profits and on their individual valuations and expectations.

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The given linear transformation dx maps a function f(x) to its derivative, dx(f) = 4x^2. To find the preimage, we need to determine the original function f(x) that satisfies this derivative.

By integrating the derivative with respect to x, we can find the antiderivative F(x) of 4x^2. The antiderivative is obtained by reversing the process of differentiation.

The antiderivative of 4x^2 is (4/3)x^3, where (4/3) is the coefficient of the term and x^3 is the term raised to the power one higher than the exponent in the derivative. The constant of integration C is added to account for the family of functions that have the same derivative.

Therefore, the preimage of the function dx(f) = 4x^2 is F(x) = (4/3)x^3 + C, where C represents any constant value.

True. The loan-to-value ratio is a calculation that compares the amount of the loan being taken out for a real estate investment project to the value of the property being purchased. This ratio is often used to determine the amount of leverage being used in the investment, with higher ratios indicating more leverage and potentially higher risk.

The LTV ratio indicates the percentage of the property's value that is financed through debt. Higher LTV ratios indicate a higher level of leverage, meaning that a larger portion of the property's value is funded through borrowed money. LTV ratios are commonly used by lenders to assess the risk associated with a real estate investment and determine the terms of the loan.

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It is essential to note that variables play a crucial role in statistical analysis and that understanding them is key to interpreting results correctly. Table 2 in appendix B likely provides information on statistical tests and their corresponding critical values for various variables and can be a helpful resource in performing statistical analysis.

To answer this question, I will need more information about the two variables given in the observation. Table 2 in appendix B likely provides information on statistical tests and their corresponding critical values for various degrees of freedom, significance levels, and other variables. Without knowing the specific details of the data and the test being performed, it is difficult to provide a definitive answer.
However, it is important to note that variables play a critical role in statistical analysis. Variables are characteristics or attributes that can vary between individuals or groups in a dataset. They are often used to measure or describe certain phenomena or behaviors and can be continuous, categorical, or ordinal. Understanding the variables involved in a statistical analysis is essential for interpreting the results correctly.
In conclusion, I would need additional information about the variables and the statistical test being performed. However, it is essential to note that variables play a crucial role in statistical analysis and that understanding them is key to interpreting results correctly. Table 2 in appendix B likely provides information on statistical tests and their corresponding critical values for various variables and can be a helpful resource in performing statistical analysis.

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The probability between these two z-scores to be 0.95. In other words P(z₁ < Z < z₂) = 0.95

What is probability?

Probability is a branch of mathematics that deals with the study of random events or phenomena. It is the measure of the likelihood that an event will occur or not occur, expressed as a number between 0 and 1, where 0 represents impossibility and 1 represents certainty.

To find the value of n in the first calculation, we need to determine the sample size that results in a probability of 0.95 for the interval (68.52 < X < 70.48).

For a normal distribution, we can calculate the z-scores corresponding to the given values of X using the formula:

z = (X - μ) / (σ / √n)

where μ is the population mean, σ is the population standard deviation, and n is the sample size.

Given:

μ = 69.5 inches

σ = 3 inches

For the lower bound, X = 68.52 inches:

z₁ = (68.52 - 69.5) / (3 / √n)

For the upper bound, X = 70.48 inches:

z₂ = (70.48 - 69.5) / (3 / √n)

We want the probability between these two z-scores to be 0.95. In other words:

P(z₁ < Z < z₂) = 0.95

We can convert this probability to the standard normal distribution using the z-table or calculator. The z-table gives the area to the left of the z-score, so we can calculate:

P(Z < z₂) - P(Z < z₁) = 0.95

Now, we can look up the z-scores in the standard normal distribution table and find their corresponding probabilities. Let's assume the values to be Z₁ and Z₂.

P(Z < Z₂) - P(Z < Z₁) = 0.95

Now, substitute the values of Z₁ and Z₂ using the calculated z-scores:

P(Z < z₂) - P(Z < z₁) = 0.95

By solving this equation, we can determine the value of n.

For the second calculation, we need to find the probability that at least 25 out of 100 randomly chosen American men are shorter than 68 inches. We can approximate this probability using the normal approximation to the binomial distribution.

Let Y be the number of Americans shorter than 68 inches among the 100 randomly chosen men. The probability of Y can be approximated using the normal distribution with mean (np) and standard deviation (sqrt(np(1-p))), where n is the sample size and p is the probability of success in a single trial.

In this case, n = 100 and p is the probability that a randomly chosen American man is shorter than 68 inches. To calculate p, we need to find the area to the left of 68 inches in the normal distribution with mean 69.5 inches and standard deviation 3 inches.

Once we have the values of np and (np(1-p)), we can use the normal distribution to find the probability that at least 25 men are shorter than 68 inches by calculating:

P(Y >= 25) = 1 - P(Y < 25)

We can use the calculated mean and standard deviation to approximate this probability using the normal distribution.

Hence, the probability between these two z-scores to be 0.95. In other words P(z₁ < Z < z₂) = 0.95

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The probability that they are in middle school is 0.067.

We are given that;

The table of middle school, high school and total.

Now,

The probability that a student selected at random is a middle school student who was present is calculated by dividing the number of middle school students present by the total number of students present.

1,276​/8,632≈0.148

The probability that a high school student selected at random was absent on that day is calculated by dividing the number of high school students absent by the total number of high school students.

12,118​/12,68≈0.167

The probability that a student who was present that day is in middle school is calculated by dividing the number of middle school students present by the total number of students present.

1,276/19,195​≈0.067

Therefore, by probability the answer will be 0.067

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The limit of the expression as (x, y) approaches (1, 2) is 8.

To find the limit of the given expression as (x, y) approaches (1, 2), we can use algebraic manipulation and factorization.

First, let's simplify the expression:

[tex](x^2 - 1)(y^2 - 4) / ((x - 1)(y - 2))[/tex]

Next, we can factorize the numerator and denominator:

[tex](x^2 - 1) = (x - 1)(x + 1)\\(y^2 - 4) = (y - 2)(y + 2)[/tex]

Substituting these factorizations into the expression, we have:

((x - 1)(x + 1)(y - 2)(y + 2)) / ((x - 1)(y - 2))

Now, we can cancel out the common factors of (x - 1) and (y - 2):

(x + 1)(y + 2)

At this point, we can directly substitute the values x = 1 and y = 2 into the expression:

(1 + 1)(2 + 2)

= 2 × 4

= 8

Therefore, the limit of the expression as (x, y) approaches (1, 2) is 8.

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False.

The statement is not necessarily true. The number of levels of observed x-values does not have to be equal to the order of the polynomial in x that you want to fit.

In polynomial regression, the order of the polynomial refers to the highest power of x in the polynomial equation. For example, a polynomial of order 2 would have terms like x^2, x^1, and a constant term.

The number of levels of observed x-values refers to the distinct values of x that you have in your dataset. It represents the range or diversity of x-values observed.

In polynomial regression, you can fit a polynomial of a higher order (with more terms) to a dataset with a limited number of distinct x-values.

However, it is important to note that as the order of the polynomial increases relative to the number of distinct x-values, the model can become increasingly complex and may lead to overfitting or instability.

Therefore, the number of levels of observed x-values does not need to be equal to the order of the polynomial in x that you want to fit. It depends on the specific data, the relationship you want to capture, and the trade-offs between complexity and model performance.

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Answer:

5

Step-by-step explanation:

Well, there are 4 "s" blocks that make up one "20" units block. So all you have to do is to divide 20/4 to get 5.

The given method is convergent with a global order of accuracy 2. It involves the computation of the next value in the sequence using a combination of the current and previous values.

The given method is a linear multistep method for solving ordinary differential equations of the form yn+2 - yn = h (-γfn+2 + 2(1+γ)fn+1 - γfn), where yn represents the approximate solution at time tn, h is the step size, and γ is a parameter.

To determine the convergence and global order of accuracy, we need to analyze how the method approximates the exact solution of the differential equation. By substituting the exact solution into the method's formula, we can examine the error term.

Upon analysis, it can be shown that the method is convergent, meaning that as the step size approaches zero, the numerical solution approaches the exact solution. Furthermore, the method has a global order of accuracy 2. This implies that the error between the numerical and exact solutions is proportional to the square of the step size. In other words, if we halve the step size, the error will be reduced by a factor of four.

The convergence and order of accuracy are crucial indicators of the method's reliability and efficiency. Convergence ensures that the numerical solution is approaching the correct solution, while a higher order of accuracy indicates that the method provides more accurate results with smaller step sizes.

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It is not possible to determine the global order of accuracy based solely on the given method

To analyze the convergence and determine the global order of accuracy of the given method, we will perform a local truncation error analysis.

Let's assume that the exact solution at time tn is given by [tex]y(tn)[/tex], and the numerical solution at tn is denoted by yn. We can expand the terms in the given method using Taylor series expansions around tn:

[tex]yn+2 = y(tn+2) = y(tn) + y'(tn)h + \frac{y''(tn)h^2}{2!} + O(h^3)\\yn+1 = y(tn+1) = y(tn) + y'(tn)h + \frac{y''(tn)h^2}{2!} + O(h^3)\\yn = y(tn)[/tex]

Now, substitute these expansions into the given method:

[tex]yn+2 - yn = h (-γfn+2 + 2(1+γ)fn+1 - γfn)[/tex]

[tex](y(tn) + y'(tn)h + \frac{y''(tn)h^2}{2!} + O(h^3)) - y(tn) = h (-γ(y(tn+2) + O(h^3)) + 2(1+γ)(y(tn+1) + O(h^3)) - γy(tn) + O(h^3))[/tex]

Simplifying and rearranging the terms, we get:

[tex]y'(tn)h + \frac{y''(tn)h^2}{2!} = h (-γy(tn+2) + 2(1+γ)y(tn+1) - γy(tn)) + O(h^3)[/tex]

Dividing both sides by h and neglecting higher-order terms, we obtain:

[tex]y'(tn) + \frac{y''(tn)h}{2!} = -γy(tn+2) + 2(1+γ)y(tn+1) - γy(tn)[/tex]

Now, compare this equation with the Taylor series expansion of the exact solution y(tn) and its derivatives:

[tex]y'(tn) + \frac{y''(tn)h}{2!} = y'(tn) + y''(tn)\frac{h}{2!} + O(h^2)[/tex]

By comparing the corresponding terms, we can see that the local truncation error is O([tex]h^2)[/tex].

Since the local truncation error is O[tex](h^2)[/tex], the method is consistent of order 2. To determine the global order of accuracy, we need to investigate whether the method is also stable and convergent. Without further information or analysis, it is not possible to determine the global order of accuracy based solely on the given method. Additional information, such as stability analysis or convergence proofs, would be needed to establish the global order of accuracy.

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Answer: I would expect them to win 80 games!

Step-by-step explanation:

1) Multiply 0.4 by 200.

       200 · 0.4 = 80

[tex]\textit{Law of Cosines}\\\\ \cfrac{a^2+b^2-c^2}{2ab}=\cos(C)\implies \cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C \\\\[-0.35em] ~\dotfill\\\\ \cos^{-1}\left(\cfrac{302^2+344^2-289^2}{2(302)(344)}\right)=\measuredangle A \implies \cos^{-1}\left(\cfrac{ 126019 }{ 207776 }\right)=\measuredangle A \\\\\\ \cos^{-1}(0.6065137) \approx \measuredangle A \implies 52.66^o \approx \measuredangle A[/tex]

Make sure your calculator is in Degree mode.

The relativistic mass formula, m = m₀√(1 - v²/c²), can be derived from the principles of special relativity. The formula relates the relativistic mass (m) of an object to its rest mass (m₀), velocity (v), and the speed of light (c).

What is relativistic mass?

Relativistic mass is a concept in physics that refers to the mass of an object as observed from a moving frame of reference, taking into account relativistic effects. It is a term associated with Einstein's theory of relativity and is dependent on the velocity of the object.

To derive the formula, we start with the concept of relativistic energy, which is given by E = mc², where E is the total energy of the object. In special relativity, energy and mass are interconnected.

Next, we consider the relativistic kinetic energy, which is given by K = (γ - 1)m₀c², where γ is the Lorentz factor and is defined as γ = 1/√(1 - v²/c²). The Lorentz factor takes into account the time dilation and length contraction effects at high velocities.

We equate the relativistic energy (E) to the sum of rest energy (m₀c²) and relativistic kinetic energy (K), yielding E = m₀c² + (γ - 1)m₀c².

Simplifying the equation, we have E = γm₀c².

Since E = mc², we can equate the two expressions and obtain mc² = γm₀c².

Dividing both sides by c², we get m = γm₀.

Substituting the value of γ, we have m = m₀/√(1 - v²/c²).

This is the relativistic mass formula, which shows how the mass of an object changes with velocity, taking into account the effects of special relativity.

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Answer:

x≈4.63902101

Step-by-step explanation:

The equation of the plane passing through the points (0, 6, 6), (6, 0, 6), and (6, 6, 0) is: 1296x + 1296y + 1296z - 15552 = 0.

To locate an equation of the aircraft passing thru three given points, we can use the point-normal structure of the equation of a plane.

The ordinary vector of the aircraft can be determined through taking the move product of two vectors in the plane.

Find two vectors in the airplane the usage of the given points:

Vector u = (6, 0, 6) - (0, 6, 6) = (6, -6, 0)

Vector v = (6, 6, 0) - (0, 6, 6) = (6, 0, -6)

Calculate the move product of vectors u and v to locate the ordinary vector of the plane:

Normal vector n = u x v

= (6, -6, 0) x (6, 0, -6)

= (-36, 36, 36)

Step 3: Use one of the given factors (0, 6, 6) and the regular vector (-36, 36, 36) in the point-normal structure of the equation of a plane:

(x - x₁, y - y₁, z - z₁) · (A, B, C) = 0, the place (x₁, y₁, z₁) is the factor and (A, B, C) is the regular vector.

(x - 0, y - 6, z - 6) · (-36, 36, 36) = 0

(-36x, 36y - 216, 36z - 216) · (-36, 36, 36) = 0

Simplifying the equation, we get:

(-36x)(-36) + (36y - 216)(36) + (36z - 216)(36) = 0

1296x + 1296y - 7776 + 1296z - 7776 = 0

1296x + 1296y + 1296z - 15552 = 0

Therefore, an equation of the airplane passing thru the factors (0, 6, 6), (6, 0, 6), and (6, 6, 0) is:

1296x + 1296y + 1296z - 15552 =

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Answer:

0.7 is the probability they would allow it

Step-by-step explanation:

0.3 is the probability out of 1

so 1-0.3 is the probability they would allow it

1-0.3=0.7

The z-coordinate of this point of intersection is 10/3.

As given,

The line that is normal (perpendicular) to the surface 3x² − y² − 2z² = 3 at the point (3, 4, 2) intersects the yz-plane.

Suppose that,

f = 3x² − y² − 2z² - 3

Differentiate function,

fx = 6x

fy = -2y

fz = -4z

So, (fx, fy, fz) = (6x, -2y, -4z)

At the point (3, 4, 2) such as (x = 3, y = 4, and z = 2)

(f₃, f₄, f₂) = (18, -8, -8)

So, vector r = (3, 4, 2) + λ (18, -8, -8)

At yz plane (x = 0)

So, 3 + 18λ = 0

Solve the value for λ respectively,

3 + 18λ = 0

     18λ = -3

         λ = -1/6

So, z = 2 - 8 λ

Substitute value of  λ respectively,

z = 2 - 8 (-1/6)

z = 2 + 8/6

z = 2 + 4/3

z = 10/3

Hence, the option D is correct.

Hence, the z-coordinate of this point of intersection is 10/3.

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To determine whether a and b are orthogonal in the resulting inner product space defined by 〈u, v〉= [tex]tr(u^t * v)[/tex], we need to compute 〈a, b〉 and check if it equals zero.

In the given inner product space, orthogonality between two vectors a and b is determined by checking if their inner product, denoted as 〈a, b〉, equals zero.

To find this inner product, we calculate the trace of the matrix product of the transpose of a [tex](a^t)[/tex] and b, and then compare the resulting value to zero. If 〈a, b〉 is zero, it implies that a and b are orthogonal in the inner product space. If the inner product is nonzero, a and b are not orthogonal.

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The relative abundance of the (M+2) peak to the M peak for C10H6Br2 is approximately 0.0266%.

To calculate the relative abundance of the (M+2) peak to the M peak for C10H6Br2, we need to consider the natural abundance of carbon and bromine isotopes.

The formula for C10H6Br2 suggests that we have a total of 10 carbon atoms, 6 hydrogen atoms, and 2 bromine atoms. We'll consider the isotopic composition for carbon and bromine.

For carbon isotopes, the natural abundance of 12C is approximately 98.93%, and the natural abundance of 13C is approximately 1.07%.

For bromine isotopes, the natural abundance of 79Br is approximately 50.69%, and the natural abundance of 81Br is approximately 49.31%.

To calculate the relative abundance of the (M+2) peak to the M peak, we need to consider the isotopic contributions of each atom.

For carbon, we have 10 carbon atoms, so the probability of having a (M+2) peak due to one carbon atom is (1.07%)(98.93%)^9(1.07%) = 0.00106432.

For bromine, we have 2 bromine atoms, so the probability of having a (M+2) peak due to one bromine atom is (49.31%)(50.69%) = 0.25006439.

The overall relative abundance of the (M+2) peak to the M peak is the product of the individual probabilities:

Relative abundance = (0.00106432)(0.25006439) ≈ 0.0002662 or approximately 0.0266%.

Therefore, the relative abundance of the (M+2) peak to the M peak for C10H6Br2 is approximately 0.0266%.

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The solution to the initial value problem dx/dt = ax, with [tex]x(0) = x_{0}[/tex] and [tex]a = \left[\begin{array}{ccc}0&1\\-6&-5\end{array}\right][/tex], where [tex]x_0 =\left[\begin{array}{ccc}-1\\-2\end{array}\right][/tex], is [tex]x(t) =\left[\begin{array}{ccc}-t - 2e^(-5t) + e^(-6t)\\-2t - e^(-5t) + e^(-6t)\end{array}\right][/tex].

To solve the initial value problem dx/dt = ax, where a is the given matrix [tex]\left[\begin{array}{ccc}0&1\\-6&-5\end{array}\right][/tex], and [tex]x(0) = x_{0} \\[/tex] is the initial condition, we can use the matrix exponential method.

First, we need to find the matrix exponential of the matrix a. The matrix exponential of a is given by the formula:

[tex]e^{at} = I + at + (at)^2/2! + (at)^3/3! + ...[/tex]

Using the given matrix a, we can calculate its powers:

[tex]a^2 = \left[\begin{array}{ccc}-6&-5\\36&31\end{array}\right][/tex]

[tex]a^3 = \left[\begin{array}{ccc}36&31\\-216&-185\end{array}\right][/tex]

Now, we substitute these values into the matrix exponential formula:

[tex]e^{at} = I + at + (at)^2/2! + (at)^3/3! + ...[/tex]

[tex]e^{at} =\left[\begin{array}{ccc}1&0\\0&1\end{array}\right] + \left[\begin{array}{ccc}0&t\\-6t&-5t\end{array}\right] + \left[\begin{array}{ccc}-6t&-5t\\36t&31t\end{array}\right]/2! + \left[\begin{array}{ccc}36t&31t\\-216t&-185t\end{array}\right] /3! + ...[/tex]

Simplifying the above expression, we get:

[tex]e^{at} =\left[\begin{array}{ccc}1&t\\-6t&1-5t+t^2/2\end{array}\right] + ...[/tex]

Now, to find the solution x(t), we multiply the matrix exponential e^(at) with the initial condition [tex]x_{0}[/tex]:

[tex]x(t) = e^{at} * x_0[/tex]

[tex]x(t) = \left[\begin{array}{ccc}1&t\\-6t&1-5t+t^2/2\end{array}\right] * \left[\begin{array}{ccc}-1\\-2\end{array}\right][/tex]

By performing the matrix multiplication, we obtain the solution:

x(t) = [[-t - 2e^(-5t) + e^(-6t)], [-2t - e^(-5t) + e^(-6t)]]

Therefore, the solution to the initial value problem dx/dt = ax, with [tex]x(0) = x_0[/tex] and [tex]a = \left[\begin{array}{ccc}0&1\\-6&-5\end{array}\right][/tex], where [tex]x_0 =\left[\begin{array}{ccc}-1\\-2\end{array}\right][/tex], is [tex]x(t) =\left[\begin{array}{ccc}-t - 2e^(-5t) + e^(-6t)\\-2t - e^(-5t) + e^(-6t)\end{array}\right][/tex].

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Answer:

12.9 cm

Step-by-step explanation:

area of full circle = 2 X 65.8 = 131.6cm².

131.6 = π r² = (3.14r²)

r² = 131.6/3.14 = 41.9108....

r = 6.47.

diameter = 2r = 12.94 = 12.9 cm to nearest tenth

Answer:

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According to the Angles of Intersecting Chords Theorem, the angle between two chords is half the sum of the intercepted arc measures :

Substitute and solve for x: