It took 14.50 mL of 0.455M NaOH to fully neutralize 12.0mL of HCl. What is the concentration of the HCl?
HCl + NaOH \rightarrow→ NaCl + H2O

Answers

Answer 1

Answer:

0.550 M HCl

Explanation:

M1V1 = M2V2

M1 = 0.455 M NaOH

V1 = 14.50 mL NaOH

M2 = ?

V2 = 12.0 mL HCl

Solve for M2 --> M2 = M1V1/V2

M2 = (0.455 M)(14.50 mL) / (12.0 mL) = 0.550 M HCl

Answer 2

Answer:

The appropriate answer is "0.549 M".

Explanation:

The given values are:

N₁ = 14.50 mL

V₁ = 0.455 M

N₂ = 12 mL

Let

V₂ = C = ?

As we know,

⇒  [tex]N_1\times V_1=N_2\times V_2[/tex]

On substituting the values, we get

⇒  [tex]14.50\times 0.455 = 12\times C[/tex]

⇒            [tex]6.5975=12\times C[/tex]

⇒                   [tex]C=\frac{6.5975}{12}[/tex]

⇒                       [tex]=0.549 \ M[/tex]


Related Questions

calorimetry and specific heat lab report can someone please write this for me ​

Answers

If anyone still needed help on this, someone wrote out the student table on brainly.com, look up Lab: Calorimetry and Specific Heat.

The page should say something along the lines of please Please i need it Lab: Calorimetry and Specific Heat

This one should help you a lot more. Good luck.

Answer:

If anyone still needed help on this, someone wrote out the student table on brainly.com, look up Lab: Calorimetry and Specific Heat.

The page should say something along the lines of please Please i need it Lab: Calorimetry and Specific Heat

This one should help you a lot more. Good luck.

Explanation:

Explain what you think controls a material’s porosity

Answers

The primary porosity of a sediment or rock consists of the spaces between the grains that make up that material. The more tightly packed the grains are, the lower the porosity.

4.00 g of O2 gas are in a sealed, 2.00 L gas canister at 22.0 °C what is the pressure inside this container (in atm)?

Answers

Answer:

1.51448 atms

Explanation:

A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrate the excess complexing reagent after the addition of 70.00 mL of 0.009005 M EDTA to a 20.00 mL aliquot of the Co2 solution.

Answers

Answer:

85.952 ml [tex]Zn^2^+[/tex]  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of [tex]CoSO_4[/tex] =[tex]\frac{Given mass }{molar mass}[/tex]

                                                       =[tex]\frac{1.817}{155}[/tex]

                                                          =0.01172

Molarity = [tex]\frac{no. of moles}{volume of solution}[/tex]

           =[tex]\frac{0.01172}{20}[/tex]

        =0.000586 moles

Excess of EDTA = concentration of EDTA - concentration of CoSO4

                            = 0.009005 - 0.000586

                           = 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 [tex](Zn^2^+)[/tex]

           [tex]0.008419\times100ml=0.009795\times V2[/tex]

           [tex]V2=\frac{0.008419\times100}{0.009795}[/tex]

             V2 =85.952 ml

Therefore , 85.952 ml [tex]Zn^2^+[/tex] needed to titrate the excess complexing reagent .

A strong acid, such as hydrochloric acid cannot be poured down a sink because it will react and dissolve the metal in the pipes. Yet a strong base, commonly found in drain cleaner, can be poured down a sink. A strong acid can be neutralized with a strong base, creating a salty water solution. What will happen when 10.0 g of hydrochloric acid were mixed with 10.5 grams of calcium hydroxide?

Answers

Answer:

15.2 grams of calcium chloride are produced and HCl is the limiting reactant.

Explanation:

Hello there!

In this case, according to the described scenario, it is possible to realize that the reaction between hydrochloric acid and calcium hydroxide is:

[tex]2HCl+Ca(OH)_2\rightarrow CaCl_2+2H_2O[/tex]

Whereas there is a 2:1 mole ratio of the acid to the base. In such a way, with the given masses, we can compute how much calcium chloride product is produced due to the chemical reaction via stoichiometry:

[tex]m_{CaCl_2}^{by HCl}=10.0gHCl*\frac{1molHCl}{36.46gHCl}*\frac{1molCaCl_2}{2molHCl} *\frac{110.98gCaCl_2}{1molCaCl_2} =15.2gCaCl_2\\\\m_{CaCl_2}^{by Ca(OH)_2}=10.5gHCl*\frac{1molCa(OH)_2}{74.09gCa(OH)_2}*\frac{1molCaCl_2}{1molCa(OH)_2} *\frac{110.98gCaCl_2}{1molCaCl_2} =15.7gCaCl_2[/tex]

Whereas we infer that the correct amount is 15.2 g since HCl is the limiting reactant as it produces the fewest grams of the desired product. Consequently, the calcium hydroxide is the excess reactant here.

Regards!

Atoms in the same PERIOD have the same...

A. Number of energy levels
B. Size
C. Temperature
D. Reactivity

Answers

Answer:

A. Number of energy levels

Mixtures that would be considered buffers include which of the following? I. 0.10 M HCl + 0.10 M NaCl II. 0.10 M HF + 0.10 M NaF III. 0.10 M HBr + 0.10 M NaBr

Answers

Answer:

II. 0.10 M HF + 0.10 M NaF.

Explanation:

A buffer system may be formed in one of two ways:

A weak acid and its conjugate base.A weak base and its conjugate acid.

Which of the following mixtures could be considered a buffer?

I. 0.10 M HCl + 0.10 M NaCl. No, because HCl is a strong acid.

II. 0.10 M HF + 0.10 M NaF. Yes, since HF is a weak acid and F⁻ (coming from NaF)  is its conjugate base.

III. 0.10 M HBr + 0.10 M NaBr. No, because HBr is a strong acid.

For any molecule at the surface the resulting surrounding forces equal zero
True
False
????????????????????????????????????????????????????,,

Answers

False is the correct answer
I think it’s true
Hope it is!

Which of the following combinations of quantum numbers is permissible?Question 23 options: n = 1, l = 2, ml = 0, ms = n = 4, l = 3, ml = 1, ms = n = 3, l = 3, ml = 1, ms = n = 2, l = 1, ml = –1, ms = 0 n = 4, l = 3, ml = 4, ms =

Answers

Answer: n= 4, , l= 3, [tex]m_l[/tex] = 1,  permissible

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1).For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as [tex]m_l[/tex]. The value of this quantum number ranges from [tex](-l\text{ to }+l).[/tex]

Spin Quantum number : It describes the direction of electron spin. This is represented as [tex]m_s[/tex]. The value of this is [tex]+\frac{1}{2}[/tex] for upward spin and [tex]-\frac{1}{2}[/tex] for downward spin.

a) n=1 , l= 2, [tex]m_l[/tex] = 0,  not permissible as l can not greater than n.

b) n= 4, , l= 3, [tex]m_l[/tex] = 1,  permissible

c) n= 3, l= 3, [tex]m_l[/tex] = 1, not permissible as l can not equal than n.

d) n= 4 , l= 3, [tex]m_l[/tex] = 4,  not permissible as [tex]m_l[/tex] can not greater than l.

125.0 mL of 2.00 M NaCl solution is diluted to a concentration of 1.50 M. How many mL of water was added to the original volume? (Hint: must find V2 first) 1

166.7 ml
30.9 mL
41.7 ml
292 mL
(no links and please show work)​

Answers

Answer:

Option A

Explanation:

As we know

C1V1 = C2V2

C1 = concentration of solution before dilution

V1 = Volume of solution before dilution

C2 = concentration of solution after dilution

V2 = Volume of solution after dilution

Substituting the given values in above equation, we get -

125 mL * 2.00 M  = X mL * 1.50 M

X mL = 125 mL * 2.00 M  / 1.50 M

X = 167 mL

Hence, option A is correct

Question 10 of 23
Which characteristic makes a digital signal more useful than an analog signal
for storing information?
A. A digital signal includes a spectrum of colors.
B. A digital signal is more difficult to copy.
C. A digital signal cannot be heard by humans.
O D. A digital signal moves between a discrete number of values.

Answers

Answer: O D. A digital signal moves between a discrete number of values.

Explanation:

The digital signals are considered more reliable over the analog signals as they encode the information in a coded form. The bits or samples of the data are transmitted and converted into digital and numerical value. The stream of encoded data is in the form of continuous data at regular time intervals. It provides information in waveform and the data is in compact form. The data is in the form of binary bits 0 and 1 so greater the number of bits greater will be the greater will be the resolution of the information.

Element A has two isotopes. The first isotope is present 18.18% of the time and has a mass of
147.99. The second isotope has a mass of 127.76. Calculate the atomic mass of element A. (To two
decimals places)

Answers

The atomic mass of element A, given that the first isotope has abundance of 18.18% and a mass of 147.99, is 131.43 amu

How do i determine the atomic mass of element A?

From the question given above, the following data were obtained:

Abundance of 1st isotope (1st%) = 18.18%Mass of 1st isotope = 147.99Mass of 2nd isotope = 127.76 Abundance of 2nd isotope (2nd%) = 100 - 18.18 = 81.82%Atomic mass of element A=?

The atomic mass of the element A can be obtain as illustrated below:

Atomic mass = [(Mass of 1st × 1st%) / 100] + [(Mass of 2nd × 2nd%) / 100]

Inputting the given parameters, we have:

Atomic mass = [(147.99 × 18.18) / 100] + [(127.76 × 81.82) / 100]

Atomic mass = 26.90 + 104.53

Atomic mass = 131.43 amu

Thus, the atomic mass of element A obtained from the above calaculation is 131.43 amu

Learn more about average atomic mass:

https://brainly.com/question/24185848

#SPJ1

How many moles of hydrogen

are in 3.06 x 10^-3 g of glycine C2H5NO2

Answers

Answer:

2.04x10⁻⁴ mol

Explanation:

First we convert 3.06x10⁻³ grams of glycine into moles of glycine, using its molar mass:

3.06x10⁻³ g ÷ 75 g/mol = 4.08x10⁻⁵ mol C₂H₅NO₂

In order to calculate the number of hydrogen moles, we multiply the number of glycine moles by 5, as there are 5 hydrogen moles per glycine mol:

4.08x10⁻⁵ mol C₂H₅NO₂ * 5 = 2.04x10⁻⁴ mol H

7. A 795.0 mL volume of hydrogen gas is collected at 23 oC and 1055 torr. What volume will it occupy at STP?

Answers

The volume of hydrogen gas at STP is 670.7 mL.

The given information is,Volume of hydrogen gas = 795.0 mLTemperature (T) = 23 oCPressure (P) = 1055 torrWe are required to find the volume of hydrogen gas at STP.STP stands for Standard Temperature and Pressure. It is used as a standard for measurement of gas volume and pressure. The standard temperature is 0 oC or 273.15 K and the standard pressure is 1 atm or 760 mmHg or 101.325 kPa.1 atm = 760 mmHg = 101.325 kPaSTP Conditions:T = 273.15 KP = 1 atmFrom the ideal gas law, we havePV = nRTWhere, P is pressureV is volumeT is temperature n is the number of moles of gasR is the gas constantFor the comparison of volumes, we must have the same value of n and R on both sides of the equation.So, we can write the above equation asP₁V₁/T₁ = nR/P₂V₂/T₂Where,P₁, V₁ and T₁ are the initial valuesP₂, V₂ and T₂ are the final valuesFor the given data, we can write1055 torr x 795.0 mL / (273.15+23) K = nR/1 atm x V₂/273.15 KThe initial pressure and volume do not match the standard conditions. We have to convert the given pressure and volume to the standard conditions.Using the ideal gas law, we can writePV = nRTWe can rewrite this equation asP₁V₁/T₁ = P₂V₂/T₂Where,P₁, V₁ and T₁ are the initial valuesP₂, V₂ and T₂ are the final valuesFor the given data, we can write1055 torr x 795.0 mL / (273.15+23) K = P₂ x V₂ / (273.15 K)Rearranging this equation, we getP₂V₂ = 1 atm x 795.0 mL / (273.15 K) x 1055 torrP₂V₂ = 768.47 mLWe can now use the final pressure and volume to calculate the volume at STP.P₁V₁/T₁ = P₂V₂/T₂V₂ = P₁V₁T₂ / T₁P₁ = 1 atmV₁ = 768.47 mLT₁ = 23 oC + 273.15 = 296.15 KV₂ = 1 atm x 768.47 mL / 1055 torr x 296.15 K / 273.15 KV₂ = 670.7 mL

For more questions on volume

https://brainly.com/question/27100414

#SPJ8

A sample of chlorine gas has a volume of 0.30 L at 273 K and 1 atm pressure. What temperature (in ∘C) would be required to increase the volume to 1.0 L ?

Answers

Answer:

[tex]T_2=637\°C[/tex]

Explanation:

Hello there!

In this case, considering this problem as pressure constant, since the change is exhibited in temperature and volume only, it is possible for us to use the Charles' law as shown below:

[tex]\frac{V_2}{T_2}=\frac{V_1}{T_1}[/tex]

Thus, by solving for the final temperature, we obtain:

[tex]T_2=\frac{T_1V_2}{V_1}\\\\T_2=\frac{273K*1L}{0.30L}\\\\T_2=910K-273\\\\T_2=637\°C[/tex]

Best regards!

A change in velocity can occur without a change in speed *
A: True

B: False?

Answers

Answer: True

Explanation: For example, changing direction can change velocity

List four reasons why the temperature of a flame is lower than the adiabatic flame temperature."

Answers

Answer:

substances is never entirely a one way

Explanation:

no possibility of obtaining complete combustion at hig

temperature.

always loss of heat from the temperature

its temperature is lower than the constant volume process because some of the energy is utilized to change the volume of the system

Four reasons why the temperature of flame is lower than adiabatic flame temperature is that there is  no possibility of obtaining complete combustion at high temperature due to high thermal energy.There is always loss of heat from temperature,its temperature is lower than constant volume process because some of  energy is utilized to change the volume of the system.

What is thermal energy?

Thermal energy is defined as a type of energy which is contained within a system which is responsible for temperature rise.Heat is a type of thermal energy.It is concerned with the first law of thermodynamics.

Thermal energy arises from friction and drag.It includes the internal energy or enthalpy of a body of matter and radiation.It is related to internal energy and heat .It arises when a substance whose molecules or atoms are vibrating faster.

These vibrating molecules and atoms collide and as a result of which heat is generated in a substance , more the collision of particles , higher is the thermal energy.

Learn more about thermal energy,here:

https://brainly.com/question/18989562

#SPJ2

A mole equals 6.02 x 10^23 . Answer these questions below.

1. How many ants are in 1.25 moles of ants?

2. How many moles of pencils are in 4.92 * 10^26 pencils?

3. How many molecules are in 0.26 moles of molecules?

4. How many moles of molecules are in 3.46 * 10^19 molecules?

5. 5.3 * 10^20 atoms are equal to how many moles of atoms?

6. 0.11 moles of atoms are equal to how many atoms?


Answers

Answer:

1. 1.25 mol ants x 6.02*10^23 ants/1 mol ants = 7.53*10^23 ants

2. 4.92*10^26 pencils x 1 mol pencils/6.02*10^23 pencils = 817 mol pencils

3. 0.26 mol molecules x 6.02*10^23 molecules/1 mol molecules = 1.6*10^23 molecules

4. 3.46*10^19 molecules x 1 mol molecules/6.02*10^23 molecules = 5.75*10^-5 mol molecules

5. 5.3*10^20 atoms x 1 mol atoms/6.02*10^23 atoms = 8.8 mol atoms

6. 0.11 mol atoms x 6.02*10^23 atoms/1 mol atoms = 6.6*10^22 atoms

I would suggest looking into "dimensional analysis" for help with this type of material. Dimensional analysis will stick with you all throughout chemistry, so picking it up will be extremely beneficial.

By examining data from distant stars, astronomers can determine
if a star is moving away from or toward Earth. Which of the
following pieces of data would be most helpful in determining
the motion of a star?
A The star gives off blue-white light.
B
The star gives off mainly radio waves and X-rays.
C
The light spectrum given off by the star is shifted toward the
red end.
.
D
The surface temperature of the star is approximately 10,000°
Celsius.

Answers

Answer:

The answer is A ahahahha

Explanation:

Because it just is

Assertion: The conversion of a gas directly into solid is called condensation. Reason : Naphthalene leaves no residue when kept in open for some time. *

Answers

The reason is not an explanation of the assertion as we can see, the concepts are not related.

What is condensation?

The process by which a substance transforms from a gaseous state to a liquid state is known as condensation. When a gas's temperature is dropped, the gas molecules experience energy loss and coalesce to create a liquid.

The kinetic energy of gas molecules is transformed into potential energy during condensation when they slow down and move closer to one another. The molecules can then change from a gaseous state to a liquid state since they can no longer maintain their gaseous state

Hence, the reason is not an explanation of the assertion

Learn more about condensation:https://brainly.com/question/1287204

#SPJ1

The elemental composition of propane gas (C3H8) is 81.68% C and 18.32% H by mass. What is the maximum amount of C3H8 in grams that can be formed from 160.0 g C and 160.0 g H

Answers

Molar mass of C3H8 = C 3 (12.01 g/mol) = 36.03 (g/mol)

H 8 (1.008 g/mol) = 8.064 (g/mol)

44.09 (g/mol)

74.6 g propane x 1 mole propane x 6.022 x 10

23

molecules

44.09 g propane 1 mole propane

= 1.02 x 10

24 molecules propane

What is one way humans can preserve biodiversity

Answers

Answer:

Reducing the amount of water you use, by having a 5-minute shower or not running the water when washing up the dishes, can help protect vital wetlands. Plant scientists are also working to help conserve by developing crop varieties that use less water.

Explanation:

Answer:

1. Most of the endangered organisms may represent a source of income.

2. The conservation or preservation may conflict with morals.

3. The role of the species or organisms might not be understood.

Explanation:

Biodiversity simply means the amount or number of living organisms that exist in the world.

The practice of protecting these existing living organisms for specific known purposes is regarded as the preservation or conservation of biodiversity.

This process or practice of preserving biodiversity is important to meet most of the human needs, such as generating income, source of food and fuel among others.

Part A
A solution of cough syrup contains 5.00% active ingredient by volume. If the total volume of the bottle is 68.0 mL, how many milliliters of ac
ingredient are in the bottle?
Express your answer with the appropriate units.

Answers

There are 3.4 milliliters of the active ingredient in the cough syrup bottle.

To calculate the volume of the active ingredient in the cough syrup bottle, we need to multiply the total volume of the bottle by the percentage of the active ingredient.

Given:

Total volume of the bottle = 68.0 mL

Percentage of active ingredient = 5.00%

First, we convert the percentage to a decimal by dividing it by 100:

Percentage of active ingredient = 5.00% = 5.00/100 = 0.05

Next, we calculate the volume of the active ingredient:Volume of active ingredient = Total volume of the bottle × Percentage of active ingredient

Volume of active ingredient = 68.0 mL × 0.05

Volume of active ingredient = 3.4 mL

Therefore, there are 3.4 milliliters of the active ingredient in the cough syrup bottle.

It's important to note that the calculation assumes a homogeneous distribution of the active ingredient throughout the solution.

For more such questions on  cough syrup visit:

https://brainly.com/question/2970281

#SPJ8

Can I get some help for these chemistry questions .

Answers

1. C6H10O5 + 6O2 → 6CO2 + 5H2O

2. MgO + H2O → Mg(OH)2

3. 151.2444 grams of carbon dioxide are required to produce 3.44 moles of carbonic acid in the blood.

1. The complete, balanced chemical reaction for the burning of cellulose (C6H10O5), or wood, is:

C6H10O5 + 6O2 → 6CO2 + 5H2O

This reaction represents the combustion of cellulose in the presence of oxygen, resulting in the formation of carbon dioxide (CO2) and water (H2O).

2. The balanced equation for the reaction between magnesium oxide (MgO) and water (H2O) to produce magnesium hydroxide (Mg(OH)2) is:

MgO + H2O → Mg(OH)2

According to the equation, 1 mole of magnesium oxide reacts with 1 mole of water to produce 1 mole of magnesium hydroxide. Therefore, if 2.55 moles of magnesium oxide react, the same number of moles of magnesium hydroxide will be produced.

3. The balanced equation for the reaction between carbon dioxide (CO2) and water (H2O) to form carbonic acid (H2CO3) is:

CO2 + H2O → H2CO3

According to the equation, 1 mole of carbon dioxide reacts with 1 mole of water to produce 1 mole of carbonic acid. Therefore, if 3.44 moles of carbonic acid are produced, the same number of moles of carbon dioxide is required.

To calculate the mass of carbon dioxide, we need to know its molar mass, which is approximately 44.01 g/mol. Therefore, the mass of carbon dioxide required to produce 3.44 moles of carbonic acid is:

Mass = Moles × Molar mass

Mass = 3.44 moles × 44.01 g/mol

Mass = 151.2444 g

Therefore, 151.2444 grams of carbon dioxide are required to produce 3.44 moles of carbonic acid in the blood.

For more such qeustions on carbon dioxide visit:

https://brainly.com/question/21256960

#SPJ8

For each of these pairs of half-reactions, write the balanced equation for the overall cell reaction and calculate the standard cell potential. Express the reaction using cell notation. You may wish to refer to Chapter 20 to review writing and balancing redox equations.
1.
Pt2+(aq)+2e-Pt(s)
Sn2+(aq)+2e-Sn(s)
2.
Co2+(aq)+2e-Co(s)
Cr3+(aq)+3e-Cr (s)
3.
Hg2+(aq)+2e-Hg (I)
Cr2+(aq)+2e-Cr (s)

please help out

Answers

1. For the pair of half-reactions:

Pt2+(aq) + 2e- → Pt(s)    ... (1)

Sn2+(aq) + 2e- → Sn(s)    ... (2)

To obtain the balanced equation for the overall cell reaction, we need to multiply the half-reactions by appropriate coefficients to ensure that the number of electrons transferred is equal. In this case, we can multiply equation (1) by 2 and equation (2) by 1:

2(Pt2+(aq) + 2e-) → 2(Pt(s))

Sn2+(aq) + 2e- → Sn(s)

Combining the equations, we have:

2Pt2+(aq) + Sn2+(aq) → 2Pt(s) + Sn(s)

The cell notation for this reaction is:

Pt2+(aq) | Pt(s) || Sn2+(aq) | Sn(s)

To calculate the standard cell potential (E°), we need to know the standard reduction potentials for Pt2+/Pt(s) and Sn2+/Sn(s) half-reactions. Referring to standard reduction potential tables, we find:

E°(Pt2+/Pt(s)) = +1.20 V

E°(Sn2+/Sn(s)) = -0.14 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = 0.00 V - (-0.14 V) = +0.14 V

Therefore, the standard cell potential for this reaction is +0.14 V.

2. For the pair of half-reactions:

Co2+(aq) + 2e- → Co(s)    ... (3)

Cr3+(aq) + 3e- → Cr(s)    ... (4)

To balance the number of electrons transferred, equation (4) can be multiplied by 2:

2(Co2+(aq) + 2e-) → 2(Co(s))

Cr3+(aq) + 3e- → Cr(s)

Combining the equations, we have:

2Co2+(aq) + Cr3+(aq) → 2Co(s) + Cr(s)

The cell notation for this reaction is:

Co2+(aq) | Co(s) || Cr3+(aq) | Cr(s)

To calculate the standard cell potential (E°), we refer to the standard reduction potentials:

E°(Co2+/Co(s)) = -0.28 V

E°(Cr3+/Cr(s)) = -0.74 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = -0.74 V - (-0.28 V) = -0.46 V

Therefore, the standard cell potential for this reaction is -0.46 V.

3. For the pair of half-reactions:

Hg2+(aq) + 2e- → Hg (l)    ... (5)

Cr2+(aq) + 2e- → Cr(s)    ... (6)

The equation for the overall cell reaction can be obtained by multiplying equation (6) by 2:

2(Hg2+(aq) + 2e-) → 2(Hg (l))

Cr2+(aq) + 2e- → Cr(s)

Combining the equations, we have:

2Hg2+(aq) + Cr2+(aq) → 2Hg (l) + Cr(s)

For more such questions on balanced equation.

https://brainly.com/question/11904811

#SPJ8

how to calculate relative abundance of copper isotopes​

Answers

Answer: Atomic mass (Cu) = (x)(63.0 amu) + (1 – x)(65.0 amu) = 63.5 amu 63.0x + 65 – 65.0x = 63.5 –2x = –1.5 x = 0.75 The percent abundance of each isotope is 75.0 % (Cu-63) and 25.0 % (Cu-65).

Explanation: As you know, the average atomic mass of an element is determined by taking the weighted average of the atomic masses of its naturally occurring isotopes.

Simply put, an element's naturally occurring isotopes will contribute to the average atomic mass of the element proportionally to their abundance.

Make the arbitrary assignment of the reduction of Zn2+(aq) to Zn(s) as you 0 V for your brief list.

Zn^2+(aq) +2e- → Zn(s) E = 0 V

Answers

The arbitrary assignment of the reduction of Zn2+(aq) to Zn(s) as E = 0 V serves as a reference point for determining the relative reduction potentials of other redox reactions. This assignment is based on the convention that the standard reduction potential

In the case of the Zn2+(aq) to Zn(s) reduction, the reaction involves the gain of two electrons by Zn2+ ions, leading to the formation of solid zinc metal. The assigned reduction potential of 0 V indicates that, under standard conditions (1 M concentration, 25°C, and 1 atm pressure), the Zn2+ ions have a tendency to accept electrons and be reduced to Zn metal.

Any reduction potential above 0 V suggests a greater tendency for reduction, while a negative reduction potential indicates a lower tendency for reduction compared to the Zn2+(aq) to Zn(s) reaction.

This reference potential allows us to compare the reactivity of other redox systems and predict the feasibility of different reactions. The more positive the reduction potential, the greater the tendency for reduction to occur. Therefore, if we encounter a reduction potential of +0.34 V for another reaction, we can infer that it is more likely to occur spontaneously compared to the Zn2+(aq) to Zn(s) reduction. Conversely, if we encounter a reduction potential of -0.50 V, we can conclude that the reverse reaction (oxidation) is more favorable than the reduction of Zn2+(aq) to Zn(s).

Overall, the assignment of E = 0 V for the reduction of Zn2+(aq) to Zn(s) provides a benchmark for understanding the electrochemical behavior of other redox reactions and allows us to make predictions based on the relative reduction potentials.

For more such questions on reduction

https://brainly.com/question/21851295

#SPJ8

Element A has two isotopes. The first isotope is present 19.52% of the time and has a mass of 265.1.
The second isotope has a mass of 182.27. Calculate the atomic mass of element A. (To two decimals
places)

Answers

The atomic mass of element A is 198.39 (to two decimal places).

To calculate the atomic mass of element A, we need to consider the relative abundance of each isotope and its corresponding mass. The atomic mass is the weighted average of the masses of all the isotopes, taking into account their relative abundance.

Given:

Isotope 1: Relative abundance = 19.52%, Mass = 265.1

Isotope 2: Relative abundance = 100% - 19.52% = 80.48%, Mass = 182.27

To calculate the atomic mass, we multiply the relative abundance of each isotope by its mass and sum up the results.

Atomic mass = (Relative abundance of Isotope 1 * Mass of Isotope 1) + (Relative abundance of Isotope 2 * Mass of Isotope 2)

Atomic mass = (19.52/100 * 265.1) + (80.48/100 * 182.27)

Calculating the values:

Atomic mass = (0.1952 * 265.1) + (0.8048 * 182.27)

Atomic mass = 51.72752 + 146.661296

Atomic mass = 198.388816

Rounding to two decimal places, the atomic mass of element A is 198.39.

For more such question on mass. visit :

https://brainly.com/question/24191825

#SPJ8

Which layer of the Earth includes the crust? a atmosphere b hydrosphere c asthenosphere d lithosphere

Answers

Answer:

D

Explanation:

Hope that helps :)

are two double bonds in
uble dash.
:0=C=O
NO2-

Answers

Answer:

Yes

Explanation:

There are in double dash :) ( = )

Answer:

yes

Explanation:

Because the double dash shows a double bond it simply means that two electrons from each atom are being shared

Other Questions
the complete array of formal political institutions of any society is known as Two firms produce close substitute products. They face interdependent demand curves, q =10-2p+p, for firm 1, and q2= 10-2p + P for firm 2 The firms have identical cost functions, c(q) = 4q1+ F and c(q) = 4q, -F. Derive equilibrium prices and quantities under Bertrand price competition. A work breakdown structure can BEST be thought of as an effective aid for __________ communication.A. Teaching the projectB. My instructorC. GoodsD. Stakeholder Exercise 7-15 Dishonoring a note LO P4 Following are transactions for Ridge Company. Mar. 21 Accepted a $12,400, 180-day, 7% note from Tamara Jackson in granting a time extension on her past-due account receivable. Sept. 17 Jackson dishonored her note. Dec. 31 After trying several times to collect, Ridge Company wrote off Jackson's account against the Allowance for Doubtful Accounts. Complete the table to calculate the interest amounts at September 17 and use the calculated value to prepare your journal entries. (Do not round intermediate calculations. Round your final answers to nearest whole dollar. Use 360 days a year.) Complete this question by entering your answers in the tabs below. Interest Amounts General Journal Complete the table to calculate the interest amounts at September 17. Total Through Maturity Principal Rate (%) Time Total interest Journal entry worksheet < 1 2 3 Accepted a $12,400, 180-day, 7% note from Tamara Jackson in granting a time extension on her past-due account receivable. Note: Enter debits before credits. Date Mar 21 General Journal Debit Credit > Journal entry worksheet < 1 2 3 Jackson dishonored her note. Date Sept 17 Note: Enter debits before credits. General Journal Debit Credit Journal entry worksheet < 1 2 3 After trying several times to collect, Ridge Company wrote off Jackson's account against the Allowance for Doubtful Accounts. Note: Enter debits before credits. Date Dec 31 General Journal Debit Credit An orifice with a 50 mm in diameter opening is used to measure the mass flow rate of water at 20C through a horizontal 100 mm diameter pipe. A mercury manometer is used to measure the pressure difference across the orifice. Take the density of water to be 1000 kg/m and viscosity of 1.003 x 10- kg/m-s. If the differential height of the manometer is read to be 150 mm, determine the following: a) Volume flow rate of water through the pipe b) Average velocity of the flow c) Head loss caused by the orifice meter d) What will be height of water column required if replaced with water manometer 100 mm 50 mm 150 mm 6. Given below are three lists of industries, costing methods, and cost unit. Mention the method of costing and cost units applicable against each of the industries :- Industry Method Cost unit (i) Ad Shannon Company segments its income statement into its North and South Divisions. The companys overall sales, contribution margin ratio, and net operating income are $760,000, 60%, and $45,600, respectively. The North Divisions contribution margin and contribution margin ratio are $240,000 and 75%, respectively. The South Divisions segment margin is $66,000. The company has $91,200 of common fixed expenses that cannot be traced to either division. Required: Prepare an income statement for Shannon Company that uses the contribution format and is segmented by divisions. (Do not round your intermediate percentage answers and round your final percentage answers to 1 decimal place (i.e. .1234 should be entered as 12.3).) Divisions Total Company North South Amount % Amount % Amount % Sales $ 760,000 $ 320,000 $ 440,000 Variable expenses 304,000 80,000 224,000 Contribution margin 456,000 0.0 240,000 0.0 216,000 0.0 Traceable fixed expenses 319,200 169,200 150,000 Territorial segment margin 136,800 0.0 $ 70,800 0.0 $ 66,000 0.0 Common fixed expenses 91,200 Net operating income $ 45,600 0.0 sheet is drawn here Let S represent the statement, 16 +16-2 +16.3+...+16n= 8n(n+1)(2n+1)/3(a) Verify S (b) Write Sk (c) Write S_k+1 modeling is particularly effective when paired with ___________ when training novice performers who have learning disabilities. The following are primary purchasers of preferred stock except:a. Corporate investors,b. Insurance companies,c. Pension funds,d. Individual investors. The number of elements of Z3[x] / is 6 9 8 O 3 Question * The number of reducible monic polynomials of degree 2 over Zz is: 2 6 O 4 8 Konkuk Foundation (KF) began operations on January 1st 2021, the first day of its fiscal year with the assets, liability and net asset balances shown in the following table. Record the eight transactions (1-8) below on the worksheet provided with the exam.Account Beginning BalanceCash $25,000Grants Receivable 2,000Inventory 2,000Unrestricted Net Assets 50,000Pledges Receivable 1,000Property, plant, and equipment 25,000Wages Payable $5,000Be sure to identify the accounts impacted by each transaction and show that the transactions are balanced. You must enter each transaction in the worksheet provided.1) Took out a $50,000 bank loan. SF also signed a contract with a local car dealer to buy a van for their summer program and gave the dealer a $1,000 deposit. 2) Received $50,000 in contribution pledges and cash contributions from members of the Konkuk community. $25,000 of the contributions were received in cash. KF expects that 20% of the remaining pledges will not be collected. 3) Received a check for $10,000 from the Korea Society. This amount includes the final payment of $2,000 from a grant made by the Korea Society in 2019 as well as new grant for the remainder. 4) Purchased a van for $50,000. The van is expected to have a useful life of 10 years and no residual value. KF uses straight-line depreciation. The van was purchased at the beginning of the year. 5) Purchased $5,000 worth in supplies for the Summer Camp. KF paid 80% of the cost of the supplies in cash. 6) KF paid its employees $30,000 in wages during the fiscal year. Wage expense for the year was $25,000. The payment included the wages payable balance outstanding from fiscal year 2020. 7) By the end of the year, LU used $4,000 worth of supplies to operate their summer camp. 8) Complied with terms of the bank loan, which require KF to pay the bank $1,400. That includes interest for the year at an annual rate of 2% plus a portion of the principal.40. Prepare a Balance Sheet for KF as of December 31, 2021, the last day of fiscal year, along with a comparative balance sheet for the prior fiscal year, 2020.41. Prepare an Activity Statement for KF for the fiscal year ending December 31, 2021.42. Prepare a Cash Flow Statement for KF for the fiscal year ending December 31, 2021. Express the confidence interval 77.1% 3.8 % in interval form. ______Express the answer in decimal format (do not enter as percents). In the past, patrons of a cinema complex have spent an average of $2.50 for popcorn and other snacks. The amounts of these expenditures have been normally distributed. Following an intensive publicity campaign by a local medical society, the mean expenditure for a sample of 18 patrons is found to be $2.10. The standard deviation is found to be $0.90. Which of the following represents an 80% confidence interval for the population average amount spent by patrons of a cinema complex on popcorn and other snacks following an intensive publicity campaign by a local medical society? ($1.65, $2.55) ($1.73, $2.47) ($1.49, $2.71) ($1.82, $2.38) ($1.56, $2.64) Which statement is true about the definition of done (DoD)? The DOD should evolve as system capabilities evolve The teams share one common DOD At the higher levels there is only one DOD for everything that passes through Agile Release Train to a Solution increment or a release DOD is not used by teams because it is used as a method to manage technical debt across the ART Prove that there is a way to arrange all the dominoes in a cycle respecting the usual rules of the game using graph theory. When calculating the probability P(z -1.65) under the StandardNormal Curve we obtain: P1321 AGENCY COSTS AND CAPITAL STRUCTURE Galaxy Enterprises has earnings before interest and taxes of $9 million and $90 million of debt outstanding with a required rate of return of 7.3%. The required rate of return on assets in the industry is 12%. The corporate tax rate is 21%, but there are no personal taxes. The present value of Galaxys bankruptcy costs is $18 million. Compute Galaxys firm value. The weights of four randomly and independently selected bags of potatoes labeled 20.0 pounds were found to be 20.9, 21.4, 20.7, and 21.2 pounds. Assume Normality. Answer parts (a) and (b) below. a. Find a 95% confidence interval for the mean weight of all bags of potatoes. (Type integers or decimals rounded to the nearest hundredth as needed. Use ascending order). A mining companys reclamation plan is not permitted because there is no evidence that funding has been secured to repurpose the land in the manner proposed. What issue related to land reclamation is this an example of?A. Cost issueB. Conflict of interest issue C. Standards an measurements issue D. Quality assurance issue