Item 2
Which equation represents this sentence?

Twice the difference of 0.75 and a number is−3.


2(n−0.75)=−3

2(0.75−n)=−3

2n−0.75=−3

0.75−2n=−3

Answer:

Step-by-step explanation:

Add all together:

15.73miles + 3.6miles + 8.01miles = ...

= 19.33miles + 8.01miles

= 27.34miles

false for 4.

ture for the 1st one

brianliest me

Answer:

1 True. 2. True

[tex]\huge\green{\tt MathSolution:}[/tex]

C. y < × y < 4

Answer:

The Awnser is 27 for both I did that I-ready before

Step-by-step explanation:

Answer:

27 for both blanks

Step-by-step explanation:

I just did it on iready and I got it correct

I assume the integral is supposed to be

[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz[/tex]

Parameterize C by

[tex](x(t),y(t),z(t)) = (1-t)(1,0,0) + t(5,1,2) = (1+4t, t, 2t)[/tex]

with 0 ≤ t ≤ 1, and dx = 4 dt, dy = dt, and dz = 2 dt. Then the line integral is

[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = \int_0^1 (2t)^2(4\,dt) + (1+4t)^2\,dt + t^2(2\,dt)[/tex]

[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = \int_0^1(1+8t+34t^2)\,dt[/tex]

[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = 1+4+\frac{34}3 = \boxed{\frac{49}3}[/tex]

Answer:

I = $372.40

Step-by-step explanation:

Given the principal amount of $2,940, which is invested for 4 months at 3.8% interest rate:

Use the following simple interest formula to solve for the interest earned:

I = P × r × t

where:

I = interest earned

P = principal amount invested = $2,940

r = interest rate = 3.8% or 0.380

t = time = 4/12 months = ⅓ or 0.3333

Substitute to given values into the simple interest formula:

I = P × r × t

I = $2,940 × 0.380 × 0.3333

I = $372.40

Therefore, the simple interest earned in 4 months is $372.40.

Answer:

900 Miles

Step-by-step explanation:

Since 1 inch = 200 miles, then ....

    4.5 inches * (200 miles / 1 inch) = (4.5 inches * 200 miles) / (1 inch) = 900 miles

OR

    1 / 200 : 4.5 / m     ==>     1 * 4.5 / 200 * 4.5 = 4.5 / 900    ==>    m = 900

Thus, the actual distance between the two cities is 900 miles.

Answer:

wth that's hard I can't answer that

Answer:

(5π/8, 0)

Step-by-step explanation:

x intercept occurs when y = 0

0 = tan(x - 5π/8)

as tan0 = 0

x - 5π/8 = 0

x = 5π/8

Answer:

x-20

Step-by-step explanation:

check a math app if u want to see

Answer:

false i think

Step-by-step explanation:

16+1=17-1=16-2=14

Answer:

B.   21.  A    22.  c

Step-by-step explanation:

8.75 ÷1000   move decimal point three places to the left.

21.  A    a whole number  0.80

22.   C   nonterminating decimal.   0.6666...

Answer:

  20.1°

Step-by-step explanation:

Put the given numbers into the given formula and do the arithmetic.

  ∆L = 1050/(60·cos(29.5°)) ≈ 20.1°

The change in longitude is about 20.1 degrees.

__

Additional comments

A degree is 60 minutes: 1° = 60', so 30' = 0.5°.

This formula is accurate when the distance units are nautical miles.

Answer:

I am pretty sure the answer is 27.02.

Step-by-step explanation:

Hope this helps!

Answer:

78 buttons left

Step-by-step explanation:

I multiplied 24 children by 3 buttons because each child took 3 buttons and I got 72 buttons taken.

Then I subtracted 150 buttons which is the starting number by 72 buttons (the amount taken by the child's) to get 78 buttons left in the box. ( I just separated negative 72 buttons into -50 and -22 to make it easier)

Applying the steps, the result of the line integral is 99.

The curve is:

[tex]f(x,y,z) = xy i + 9y^2 j[/tex]

The vector field is:

[tex]r(t) = (x(t), y(t)) = (16t^6, t^4)[/tex]

Applying the vector field at the curve, we have that:

[tex]f(t) = (16t^{10}, 9t^8)[/tex]

The derivative of the vector field is:

[tex]r^{\prime}(t) = (96t^5, 4t^3)[/tex]

The dot product of the vector field along the curve with the derivative is:

[tex]f(t)r^{\prime}(t) = (16t^{10}, 9t^8)(96t^5, 4t^3) = 1536t^{15} + 36t^{11}[/tex]

Hence, the line integral is:

[tex]I = \int_{0}^{1} (1536t^{15} + 36t^{11}) dt[/tex]

[tex]I = 96t^{16} + 3t^{12}|_{t = 0}^{t = 1}[/tex]

[tex]I = 96 + 3[/tex]

[tex]I = 99[/tex]

A similar problem is given at https://brainly.com/question/12666512

Answer:

B. The x-coordinate is positive, and the y-coordinate is negative

Step-by-step explanation:

Counting for the quadrants starts and the positive x-axis and then moves counterclockwise. This means that the IV quadrant will be the bottom right quadrant. The right axis is the positive x-axis and the bottom axis is the negative y-axis. This means that the coordinate for the IV quadrant must look like (x,-y).

Answer:

(6, 10)

Step-by-step explanation:

You found (6, 4)

The second would be

(6, 10) making BD || to CA

Answer:

Add 6 to both sides

Step-by-step explanation:

The (usual) first thing to do when solving any equation is to simplify both sides of the equation. However, since we have nothing to simplify, we move onto the next step that'll be the first step: isolating the variable, x. To do so, we must do the inverse of subtracting 6 (which is adding 6).

Answer:

point B (8, 6)

Step-by-step explanation:

Given the linear graph of a vertical line, x = 8:

The solution to the given linear equation is any ordered pair that is found along the line of the graph.

Out of the given options, point B, (8, 6) is located on the line. Therefore, it is one of the solutions to the linear equation, x = 8.

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

49. [tex]x = \dfrac{1}{a}[/tex] and [tex]y = 3[/tex]

50. [tex]x = \dfrac{1}{2a}[/tex] and [tex]y = \dfrac{1}{b}[/tex]

Step-by-step explanation:

We are going to solve these systems of equations using the elimination method.

49. Given:

[tex]5ax + 4y = 17[/tex] (1)

[tex]\:\:ax + 7y = 22[/tex] (2)

Multiply Eqn(1) by 7 and multiply Eqn(2) by -4 to get

[tex]\:\:35ax + 28y = 119[/tex]

[tex]-4ax - 28y = -88[/tex]

Adding the two equations above, we get

[tex]31ax = 31 \Rightarrow x = \dfrac{1}{a}[/tex]

Substituting this value for a into Eqn(2), we get

[tex]y = 3[/tex]

50. Given:

[tex]4ax + \:\:by = 3[/tex] (3)

[tex]6ax + 5by = 8[/tex] (4)

Multiplying Eqn(3) by -5, we get

[tex]-20ax - 5by = -15[/tex]

[tex]\:\:\:\:\:\:6ax + 5by = \:\:8[/tex]

Adding the two equations above, we get

[tex]-14ax = -7 \Rightarrow x = \dfrac{1}{2a}[/tex]

Plugging in the value of x into Eqn(3), we get the value for y as

[tex]4a(\frac{1}{2a}) + by = 3[/tex]

or

[tex]2 + by = 3 \Rightarrow y = \dfrac{1}{b}[/tex]

Using the t-distribution, it is found that since the p-value of the test is 0.72 > 0.05, there is not significant difference between the values of each group.

At the null hypothesis, we test if the groups have the same values, that is, the subtraction of their means is 0:

[tex]H_0: \mu_2 - \mu_1 = 0[/tex]

At the alternative hypothesis, we test if the groups have different values, that is, the subtraction of their means is different of 0:

[tex]H_1: \mu_2 - \mu_1 \neq 0[/tex]

First, we have to find the mean and the standard deviation for both samples, hence, using a calculator:

[tex]\mu_1 = 18.75, \sigma_1 = 6.2507, \mu_2 = 19.75, \sigma_2 = 4.2678[/tex]

The standard errors are:

[tex]s_1 = \frac{\sigma_1}{\sqrt{n_1}} = \frac{6.2507}{\sqrt{8}} = 2.21[/tex]

[tex]s_2 = \frac{\sigma_2}{\sqrt{n_2}} = \frac{4.2678}{\sqrt{8}} = 1.5089[/tex]

For the distribution of differences, we have that:

[tex]\overline{x} = \mu_2 - \mu_1 = 19.75 - 18.75 = 1[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{2.21^2 + 1.5089^2} = 2.676[/tex]

We have the standard deviation for the samples, hence, the t-distribution is used. The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu[/tex] is the value tested at the null hypothesis, which is 0 for this problem. Hence, the value of the test statistic is:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

[tex]t = \frac{1 - 0}{2.676}[/tex]

[tex]t = 0.37[/tex]

To find the p-value, we have a two-tailed test, as we test if the means are different from a value, with t = 0.37 and 8 + 8 - 2 = 14 df.

Using a t-distribution calculator, this p-value is of 0.72.

Since the p-value of the test is 0.72 > 0.05, there is not significant difference between the values of each group.

A similar problem is given at https://brainly.com/question/15682365