Answer:
hgt tdyrghgcderhgfe
Explanation:
rghttyhhhggggftttgf d's weyhvfswertfcdsettyhgftgdfvhgg fee e4y
A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars combine.
Answer:
ok what is the question
Answer:
If the question is what is the magnitude of the final velocity of the combined cars ? Answer: 1.5 m/s
Explanation:
If the refractive index of water is 1.33, then its critical angle is...
Frank has a liquid. It has a mass of 6 g and a volume of 9 ml. What is its density?
Solve these two please its urgent, If i like your answer ill give brainly....
Answer: green car and red car
Explanation:
Answer:
it is white car for the first question and for the second it goes green slowest and white fastest red is in the middle
A pitcher throws a 145 g baseball at a velocity of 30.00 m/s. How much kinetic energy does the ball have?
Final Answer:
65.25 J is the kinetic energy that the ball has.
Explanation:
M = 145g
(Reminder: kg must be used in this formula, thus we need to convert 145g to kg)
M = 145g x 1kg/1000g
(cross out g, then multiply 145 to 1kg)
M = 145kg/1000 = 0.145kg
M = 0.145 kg
V = 30.00 m/s
Solution:
KE = 1/2mv^2
KE = 1/2(0.145kg)(30.00m/s)^2
(Square first the velocity)
KE = 1/2(0.145kg)(900.00m^2/s^2)
KE = 1/2(130.5 kg*m^2/s^2)
KE = 65.25 kg*m^2/s^2
(Reminder: 1 kg*m^2/s^2 = 1 J)
KE = 65.25 J
Final Answer:
65.25 J is the kinetic energy that the ball has.
What is the net force on the book in the Figure below? If the book moves, in
which direction will it move (Left or Right)? PLEASE ANSWER BOTH PARTS
OF THIS QUESTION.
Explanation:
One force acting on you—and all the other objects on ... Look at the physics book in the Figure below. ... case, the object will move in the same direction as the net force .
Answer:
2N to the left
Explanation:
If you wake up in the morning, go to school, go to the grocery store, and then return to the same place where you woke up, what is your displacement for the day
Answer:
0 I think
Explanation:
c) Find the kinetic of a ball of mass 200
grams moving at a speed of 20 m/s. [Ans; 20 )]
Solution,
Mass (m): 200 g
velocity (v) = 20 m/s
kinetic Energy (k. E)= ?
We know,
According to the formula,
Answer:
the answer is k.E =0.5
Explanation:
i only think about it and i answer it
What is its speed if it takes 0.5 seconds to cover the distance?
Answer:How far is the distance?
Explanation:
Brady has extreme persistent worry and fear that impacts his daily life. How would this disorder be classified in the DSM-5? (2 points) Group of answer choices Anxiety Disorder Substance Use and Addictive Disorder Obsessive-Compulsive and Related Disorder Feeding and Eating Disorder
Answer:
Anxiety
Explanation:
Answer:
anxiety disorder
Explanation:
just took the quiz
A man has been guarding a house for one hour . Why is it not considered work in science
Answer: because there is no displacement or movement in the watchman's work. According to science when displacement or movement take place it is said to be work. Jul 9, 2020
Hope it helps!
Another name for semi-arid climate is
Answer: an steppe climate
Explanation:
A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42°. What is the force of
static friction acting on the box if box has a gravitational force of 112.1 N ?
0 70 N
O 80 N
O 75 N
O 85 N
Mark this and return
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Submit
Answer:
The correct option is;
75 N
Explanation:
The given parameters are;
The angle of inclination of the ramp, θ = 42°
The gravitational force of the box = m × g = 112.1 N
Let [tex]F_f[/tex] represent the force of static friction acting on the box
Given that the box is at rest, we have
The component of the gravitational force acting along the inclined plane = The force of static friction acting on the box, [tex]F_f[/tex]
We have that the component of the gravitational force acting along the inclined plane = m × g × sin (θ) = [tex]F_f[/tex]
[tex]F_f[/tex] = m × g × sin (θ)
Substituting the values, gives;
[tex]F_f[/tex] = 112.1 × sin (42°) ≈ 75.0095409728
∴ The force of static friction acting on the box = [tex]F_f[/tex] ≈ 75 N
Answer:
C: 75N
Explanation:
She wants to travel back to Madison by train. The distance from Chicago to Madison is 147 miles and takes 2.47 hours. If she makes no stops, what is her average speed?
Answer:
59.51 mph.
Explanation:
The following data were obtained from the question:
Distance (d) = 147 miles
Time (t) = 2.47 hours.
Speed (S) =?
Speed is defined as the distance travelled per unit time. Mathematically, it is expressed as:
Speed (S) = Distance (d) / time (t)
S = d/t
With the above formula, we can obtain the speed of the girl as illustrated below:
Distance (d) = 147 miles
Time (t) = 2.47 hours.
Speed (S) =?
S = d/t
S = 147 miles / 2.47 hours.
S = 59.51 miles per hour (mph)
Thus, the speed of the girl is 59.51 mph.
Un bloque de 20kg de masa se desplaza horizontalmente en la dirección de eje X por acción de una fuerza horizontal variable F = 6x, donde F se mide en Newton y "x" en metros. Si se desprecia el rozamiento determine: a) El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x=+10m hasta la posición x=+20m b) La rapidez del bloque en la posición x=+20m, si su rapidez en la posición x=+10m fue √10 m/s.
Answer:
a) El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.
b) La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.
Explanation:
a) El trabajo expermentado por el bloque ([tex]W[/tex]), medido en joules, es definida por la siguiente ecuación integral:
[tex]W = \int\limits^{x_{max}}_ {x_{min}} F(x) \, dx[/tex] (1)
Donde:
[tex]x_{min}[/tex], [tex]x_{max}[/tex] - Posiciones mínima y máxima del bloque, medidos en metros.
[tex]F(x)[/tex] - Fuerza horizontal aplicada al bloque, medida en newtons.
Si conocemos que [tex]F(x) = 6\cdot x[/tex], [tex]x_{min} = 10\,m[/tex] y [tex]x_{max} = 20\,m[/tex], entonces el trabajo realizado por esta fuerza es:
[tex]W = \int\limits^{20\,m}_{10\,m} {6\cdot x} \, dx[/tex] (2)
[tex]W = 6\int\limits^{20\,m}_{10\,m} x\, dx[/tex]
[tex]W = 3\cdot x^{2}\left|\limits_{10\,m}^{20\,m}[/tex]
[tex]W = 3\cdot [(20\,m)^{2}-(10\,m)^{2}][/tex]
[tex]W = 900\,J[/tex]
El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.
b) La rapidez final del bloque se determina mediante de Teorema del Trabajo y la Energía, es decir:
[tex]W = K_{f}-K_{o}[/tex] (3)
Donde son [tex]K_{o}[/tex], [tex]K_{f}[/tex] las energías cinéticas traslacionales inicial y final, medidos en joules.
Al aplicar la definición de energía cinética traslacional, expandimos y simplificamos la ecuación como sigue:
[tex]W = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})[/tex] (4)
Donde:
[tex]m[/tex] - Masa del bloque, medido en kilogramos.
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Rapideces inicial y final del bloque, medidos en metros por segundo.
[tex]\frac{2\cdot W}{m} = v_{f}^{2}-v_{o}^{2}[/tex]
[tex]v_{f} = \sqrt{\frac{2\cdot W}{m}+v_{o}^{2}}[/tex]
Si conocemos que [tex]W = 900\,J[/tex], [tex]m = 20\,kg[/tex] y [tex]v_{o} = \sqrt{10}\,\frac{m}{s}[/tex], entonces la rapidez final del bloque es:
[tex]v_{f} = \sqrt{\frac{900\,J}{2\cdot (20\,kg)}+10\,\frac{m^{2}}{s^{2}} }[/tex]
[tex]v_{f} \approx 5.701\,\frac{m}{s}[/tex]
La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.
Which of the following represent an atom from period 3?WILL MARK BRAINLIEST
Answer:
First one
It has 3 orbital
The diagram first represents an atom from period three of the modern periodic table.
How many periods are there in the periodic table?There are seven periods and 18 groups in the periodic table where each element is arranged on the basis of its increasing atomic number.
The atom represents in the diagram first is known as the sodium element. The atomic number of sodium is 11. Its electronic configuration is 2, 8, and 1. It requires three shells for the distribution of electrons. Apart from sodium, other members of period three include magnesium, aluminum, Silicon, Phosphorus, Sulfur, chlorine, and argon.
The diagram two represents an element of helium, while the diagram three represents an element of oxygen.
Therefore, the diagram first represents an atom from period three of the modern periodic table.
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Please help me out! This is a big question!
True or false?
Because of the Doppler effect, as an observer and source move closer the pitch of the sound from the source gets higher; if the observer and source are moving farther apart the pitch will sound lower to the observer.
Answer:
true
Explanation:
I just had a test on this
Answer:
true
Explanation:
cause it is
Se lanza verticalmente hacia arriba un proyectil y alcanza una altura máxima de 100 metros de altura. ¿Cuál fue la velocidad hacia arriba con la que fue lanzada?
Answer:
v = 44,3 m/s
Explanation:
La velocidad la podemos hallar usando la siguiente expresión:
[tex] v_{f}^{2} = v_{0}^{2} - 2gh [/tex]
En donde:
h: es la máxima altura = 100 m
[tex]v_{f}[/tex]: es la velocidad final = 0 (en la altura máxima)
[tex]v_{0}[/tex]: es la velocidad inicial =?
g: es la gravedad = 9,81 m/s²
Resolviendo la ecuación anterior para v₀, tenemos:
[tex] v_{0} = \sqrt{2gh} = \sqrt{2*9,81 m/s^{2}*100 m} = 44,3 m/s [/tex]
Entonces, el proyectil fue lanzado hacia arriba con una velocidad de 44,3 m/s.
Espero que te sea de utilidad!
A bullet is shot from a rifle with a speed of 3,015 feet per second. Assuming the billet moves at a constant velocity what is the time rescuers die the biller to strike a target 4,146 meters away
Answer:
Explanation:
Given
final speed v = 3015ft/s
initial speed = 0m/s
Distance S = 4146m/s
Required
Time
Using the equation of motion to get the time;
S = (v+u)/2 * t
since 1m = 3.28084ft'
4146m = 3.28084 * 4146 = 13,602.36264feet
13,602.36264 = 3015+0/2 * t
13,602.36264 = 1,507.5t
t = 13,602.36264/ 1,507.5
t = 9.023 secs
Hence it will take 9.023 seconds the rescuer die the biller to strike a target
When forces are balanced, what happens to the motion of the object?
Group of answer choices
Objects never have balanced forces.
Objects with balanced forces change motion.
Objects with balanced forces are able to change at will.
Objects with balanced forces remain unchanged.
Answer:
C-objects with balanced forces remain un changed
Explanation:
because the forces that act on the body cancel each other and the net force=0
Irene drops a clay ball at time t=0. The ball stops when it hits the ground. Which of the following graphs best shows the velocity v of the clay ball from when it is dropped until it hits the ground?
Answer:
Graph-
Explanation:
The graph best shows the velocity v of the clay ball from when it is dropped until it hits the ground is attached below.
What is velocity?Velocity is the time rate of change of displacement. The displacement and velocity both are vector quantities. They represent magnitude and direction as well.
Irene drops a clay ball at time t=0. The ball stops when it hits the ground.
When the clay ball drops, only force acting is due to acceleration due to gravity.
The velocity of the clay ball decreases with the time.
Thus, the graph best shows the velocity v of the clay ball from when it is dropped until it hits the ground is attached.
Learn more about velocity.
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HURRY I NEED IT NOW What is the density at 20oC of 12.0 milliliters of a liquid that has a mass of 4.05 grams?
0.338 g/mL
2.96 g/mL
16.1 g/mL
48.6 g/mL
Density is the mass per unit volume of any object. It is calculated by dividing the mass of an object by its volume. This is:
ρ = m/V
ρ = 4.05 g / 12 mL
ρ = 0.3375 g/mL
ρ ≅ 0.338 g/mLOPTION A
A penny is dropped from the 82nd Floor Observatory of the Empire State Building. The penny will fall for 8.1s before hitting the ground. 1. How far does the penny fall? 2. How fast is the penny going when it hits the ground?
Answer:
vf=79.38 m/s
y= 321.5 m
Explanation:
Free Fall Motion
A free-falling object falls under the exclusive influence of gravity. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
1.
The penny will fall for t=8.1 s before hitting the ground, thus the height from which it was dropped is:
[tex]\displaystyle y=\frac{9.8\cdot 8.1^2}{2}[/tex]
y= 321.5 m
2.
The final velocity is:
[tex]vf=9.8\cdot 8.1[/tex]
vf=79.38 m/s
As shown in the figure, a 2.00-kg block is held in place against the spring by a 50-N horizontal external force. The external force is removed, and the block is projected with a velocity v1 = 1.2 m/s at as it separates from the spring. The block descends a ramp and has a velocity v2 = 2.0 m/s at the bottom. The track is frictionless between points A and B. The block enters a rough section at B, extending to E. The coefficient of kinetic friction between the block and the rough surface is 0.30. The velocity of the block is v3 = 1.4 m/s at C. The block moves on to D, where it stops.
A) What is the total energy of the spring block system before the block descends down the ramp.
B) How high is the ramp?
C) How far did the block move from B to C?
D) How far did the block move from C to D?
E) What is the work done by friction on the block from B to D?
F) What is the Mechanical energy of the spring-block system at E?
G) How much was the spring compressed by the external force
H) What is the spring constant?
Answer:
Explanation:
A ) Total energy of spring block system at height = kinetic energy at the bottom
= 1/2 m V²
= .5 x 2 x 2²
= 4 J
B )
height of ramp be h
mgh = 1/2 m ( v₂² - v₁² )
2 x 9.8 x h = 2² - 1.2²
19.6 h = 4 - 1.44
h = .1306 m
13.06 cm
C ) If distance between B and C be x₁
work done by friction = reduction in kinetic energy
= μ mg x₁ = 1/2 m ( 2² - 1.4² )
.3 x 9.8 x₁ = 1.02
x₁ = 34.7 cm
D )
If distance between C and D be x₂
work done by friction = reduction in kinetic energy
= μ mg x₂ = 1/2 m ( 1.4² - 0 )
.3 x 9.8 x₂ = .98
x₂ = 33.33 cm
E )
Total work done by friction
= 1/2 m v² - 0 , v = 2 m /s
= .5 x 2 x 2²
= 4 J .
F )
Mechanical energy of the system at E = 0
G ) 1/2 k x² = 1/2 m v²
kx = 50 N , where x is compression and k is spring constant
k²x² / 2k = 1/2 m v²
50² / k = 2 x 1.2²
k = 868.05 N / m
H ) kx = 50
x = 50 / k
= 50 / 868.05
= 5.76 cm .
the energy transferred by
waves moving through the ground is called
i hope it helped thanks
The diagram below shows a wave with its wavelength indicated in red.
wavelength
What will happen to the wave's frequency if its wavelength is made twice as long?
A. It will stay the same.
B. It will go to zero
C. It will double.
D. It will decrease
Answer:
answer is D.it will decrease
Answer:
D. It will decrease
Explanation: Study island ;)
PLEASE HELP ME ANSWER DUE SOON BRAINLIEST FOR WHOEVER
Answer:
1) mechanical
2) transverse
3) medium
4) longitudinal
Explanation:
A 120-kg roller coaster cart is being tested on a new track, and a crash-test dummy
is loaded into it. The roller coaster starts from rest at point A which is 25 m above
point B. If the track near to point B is in the shape of a circle with a radius of 15 m,
and the cart is moving at 22 m/s at point B, what centripetal acceleration does the
cart experience at that point?
Answer:
32 m/s².
Explanation:
From the question given above, the following data were obtained:
Mass (m) of cart = 120 Kg
Radius (r) = 15 m
Velocity (v) = 22 m/s
Centripetal acceleration (a) =?
The centripetal acceleration experienced by the cart can be obtained as illustrated below:
a = v²/r
a = 22² / 15
a = 484 / 15
a = 32.27 ≈ 32 m/s²
Thus, the centripetal acceleration experienced by the cart is approximately 32 m/s².
The ball is pulled by a force called gravity. In what direction does gravity always pull the ball?
Answer:
Gravity always pulls the ball toward the center of earth (the ground).
Explanation:
A foam square has a mass of 62 g and a volume of 72 cm3. What is the density?
Answer:
36cm
Explanation: