Jason stands in the corner of a very large field. He walks, on a bearing of 030°,
a distance of d metres. Jason then changes direction and walks twice as far on a new
bearing of 120°. At the end of the walk Jason calculates both the distance he must
walk and the bearing required to return to his original position. Given that the total
distance walked is 120 metres, what answers will Jason get if he is correct?

Answers

Answer 1

Answer:

Step-by-step explanation:

d + 2d = 120

3d = 120

d = 40 m

east distance was 40cos30 + 80cos120 = -5.35898 m

north distance was 40sin30 + 80sin120 = 89.282032

as 30° and 120° bearings are 90° apart, Jason needs to walk

D = √(d² + (2d)²) = d√5 or 40√5 meters or about 89.44 m to return to his original position.

we could also use √(-5.35898² + 89.282032²) = 89.44 m

direction will be

θ = arctan -89.28/5.359 = -86.565° or a bearing of 273.4°


Related Questions

Jaime is three years younger than his brother Keegan. In five years, the sum of their ages will be thirty-nine.
How old are they now?

Answers

Answer:

Keegan is 16 and Jamie is 13.

Step by Step Explanation:

So if we were to take the number 39 and divide it by 2, we would get 19.5. Since Jaime is 3 years younger, we would subtract 3 from one of the 19's. Then we would add 1.5 to both of the numbers since that 3 we subtracted has to go somewhere in that 39, and we come up with the numbers 21 and 18. Since it is asking how old they are NOW and not in the future, we subtract 5 from both numbers to account for the 5 years, and we end up with the years 16 and 13.

Math:

39÷2 = 19.5

19.5 19.5

-3

___________

16.5 19.5

+1.5 +1.5

___________

18 21

-5 -5

13 16

(8,4) and has a slope of 5/2

Answers

I’m guessing you want the equation? Rise is 5, run is 2 (slope=rise/run). To find the equation, we need a y intercept. the graph must move 8 units left to reach the y axis. To move 8 units left in the negative direction, we must also move 20 units down (because the shift required is 4 times greater than the slope, we must multiply the other coordinate by 4 to find how far to move the coordinate). When x=0, y=(4-20). This can be written as y=-16. The equation would be y=(5/2)x-16

can't believe that you got me in a suit and tie I had to take a pull so I wouldn't cry
You got a line out the church door sayin' goodbye
Yeah, I believe 'em when they say you're in a better place
NAME THE SONG AND THE SINGER 50 POINTS!!!!!

Answers

Answer:

give heaven some hell by Hardy

Step-by-step explanation:

three hundred two times one hundred fifty three
302×153​

Answers

Answer:

46,206

Step-by-step explanation:

simple math

Answer:

the answer is 46,206

Step-by-step explanation:

Good luck!!!!

help me please guys im being times and trying to get this done fast!

Answers

Answer:

C.

Step-by-step explanation:

You're trying to figure out how many more hours he needs to work in order to have worked for 240 hours.

Find an equation for the line below

Answers

Answer:

  y = 1/2x +7/2

Step-by-step explanation:

The two marked points are 2 units apart vertically, and 4 units apart horizontally. The slope of it is ...

  m = rise/run = 2/4 = 1/2

The value of the y-intercept can be found from

  b = y -mx . . . . . . where (x, y) is a point on the line

Using the point (-1, 3), we find the y-intercept to be ...

  b = 3 -(1/2)(-1) = 3 1/2 = 7/2

Then the slope-intercept equation is ...

  y = mx +b

  y = 1/2x +7/2

I WILL GIVE BRAINLEST HURRY PLEASE ITS DUE RIGHT NOW HURRY PLEASE plssss help me if your good at finding area in shapes plsss​

Answers

45x10x15=6,750 is the answer

1. According to the fundamental theorem of algebra, how many zeros does the function [tex]f(x) = 3x^6 - 7x^5 - 53x^3 - 43x - 34[/tex] have?

2. What are the zeros of [tex]f(x) = 6x^3 + 25x^2 - 24x + 5[/tex]

Answers

Answer:

See below for answers

Step-by-step explanation:

1) The Fundamental Theorem of Algebra states that in an nth-degree polynomial, there are n zeroes at most, including those that are complex. Therefore, there are 6 zeroes in the function since it's a 6th-degree polynomial.

2) Reduce the polynomial and use the Zero Product Property:

[tex]0=6x^3+25x^2-24x+5[/tex]

[tex]0=(6x^2-5x+1)(x+5)[/tex]

[tex]0=(3x-1)(2x-1)(x+5)[/tex]

[tex]x_1=\frac{1}{3},x_2=\frac{1}{2},x_3=-5[/tex]

Please Help I am giving many points!

Answers

Answer:

D

Step-by-step explanation:

n = 5

an = 176

an = a1*x^(n -1)

a5 = a1 * x^4 = 176

a7 = a1 * x^6 = 704

a7/a6 = a1 * x^6 / a1*x^4 = 704 / 176

Cancel out a1

x^6/x^4 = 704/176      Divide numerator and denominator by 176

x^2 = 4                        Take the square root of both sides

x = 2 or - 2

176 = a1 * x^4

176 = a1 * 16

a1 = 11

a1 is going to be 11 whether x is 2 or minus 2.

hi mallllll. hehehe

once again its [tex]a_{1} = -11[/tex]

Create your own example for each cases of multiplying
polynomials

Case 1: Distributive Property
Case 2: FOIL Method
Case 3: Binomial to Polynomial

Pls needed badly
If you have nothing to answer dont answer

Answers

Step-by-step explanation:

CASE 1:2x(3x+7) = 6x^2+14x.CASE 2:(2x + 3)(3x – 1)CASE 3:x2 + 4x

-12/5+3/10/11/14-(-9/14)

Answers

Answer:

-6/5

Step-by-step explanation:

I hope it helps, bye

3 divided by 4 1/2 write in simplest form

Answers

[tex]3 \div 4 \frac{1}{2} \\ = 3 \div \frac{9}{2} \\ = 3 \times \frac{2}{9} \\ = \frac{2}{3} [/tex]

Answer:

[tex] \frac{2}{3} [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

A test has twenty questions worth 100 points. The test consists True/False questions worth 3 points each and multiple choice questions worth 11 points each. Howmany multiple choice questions are on the test?

Answers

Multiple choice questions = 5

True questions = 15

Given that:

Total number of questions = 20

Total worth of point = 100

Multiple choice questions (M) = 11 points each

True false questions (T) = 3 points each

Hence,

M + T= 20 ____(1)

11M + 3T = 100 ____(2)

M = 20 – T

Using the relation in (2)

11(20 – T) + 3T= 100

220 – 11T + 3T= 100

220 – 8T = 100

-8Tf = 100 – 220

-8T = – 120

T = 120/8

T = 15

Mc = 20 – 15

Mc = 5

Multiple choice questions = 5

True false questions = 15


[tex]6 \times 2[/tex]
please I need ur help​

Answers

Answer:

12

Step-by-step explanation:

You do 6+6, or 2+2+2+2+2+2=12

Answer: 12

Just add 6, 2 times so 6, 12
Or add 2, 6 times so 2,4,6,8,10,12

Does 28/4 have a remainder

Answers

No but it equals to 7 :)

Remainder=0

Quotient=7

Thanks!!

For each equation find a value for x that makes the equation true 10=3x-6

Answers

Answer:

5.3333

or 5 and 1/3

Step-by-step explanation:

10 = 3x - 6

add six

16 = 3x

divide by 3

5.3333 = x

I hope this helps!!

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 18 feet and a height of 15 feet. Container B has a diameter of 16 feet and a height of 18 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full.

To the nearest tenth, what is the percent of Container A that is full after the pumping is complete?

Answers

Answer:

5.2%

Step-by-step explanation:

Volume of cylinder= πr²h

In Container A,

D= 18ft, r=18/2=9ft, h=15ft

volume= 22/7 × 9² × 15

= 26730/7 cubic ft.

In Container B,

D=16ft, r= 16/2=8ft, h=18ft

volume= 22/7 × 8² × 18

= 25344/7 cubic ft.

percent of amount of water left in Container A= percent of container A that is full after pumping

Amount of water left in Container A,

26730/7 - 25344/7 = 1386/7

Therefore, % of container A that is full= 1386/7 ÷ 26730/7 × 100

(1386×7×100)/(7×26730)= 5.185

To the nearest tenth= 5.2%

13. Jay has 12 classic cars in his garage. He paid
$3,500 for each car 5 years ago. The cars are
currently worth $4,200 each. How much more
must the average value of the cars rise for the
combined value of these 12 cars to be exactly
$10,800 more than Jay paid for them?
A. $200.00
B. $700.00
C. $800.50
D. $ 841.67
E. $958.33
(May need worked out, please!?)

Answers

Answer:

I believe the answer would be A. $200.00

Step-by-step explanation:

This is because if jay has 12 cars that he paid 3,500$ each for, the total cost would have been $42,000.

And the current price is 4,200$ for each car.

If you add 200$ to each 4,200$ car, you get 4,400$

After, you take the amount for each car (4,400) and multiply it by 12 (the amount of cars purchased) and you get 52,800.

You then need to subtract the recent cost of 12 cars (52,800) by 42,000$ (the original cost for 12 cars) and you will get $10,800.

52,800-42,000=10,800

therefore, A.$200.00 would be the correct answer

I'm not sure if all calculations are correct, but I hope this helps! :)

The average value of the cars must rise by $200 for the combined value of the 12 cars to be exactly $10,800 more than what Jay paid for them. Therefore, the correct answer is A. $200.00.

To find out how much more the average value of the cars must rise for the combined value to be $10,800 more than what Jay paid for them, we need to calculate the difference between the current combined value and the total price Jay paid, and then divide it by the number of cars.

Given:

Number of cars (n) = 12

Price Jay paid for each car (P) = $3,500

Current worth of each car (W) = $4,200

Total price Jay paid (T) = n * P = 12 * $3,500 = $42,000

Current combined value of the cars (C) = n * W = 12 * $4,200 = $50,400

Difference in value = C - T = $50,400 - $42,000 = $8,400

Additional increase needed = $10,800 - $8,400 = $2,400

To find the average increase needed per car, we divide the additional increase by the number of cars:

Average increase per car = Additional increase / Number of cars = $2,400 / 12 = $200

Therefore, the average value of the cars must rise by $200 for the combined value of the 12 cars to be exactly $10,800 more than what Jay paid for them.

The correct answer is A. $200.00.

To know more about average value, refer here:

https://brainly.com/question/32515383

#SPJ2

Translate the phrase into an algebraic expression: 12acorns per qsquirrels?

Answers

Answer:

12/q  acorns/squirrel


Set A = 3, 4, 7
Set B = 4, 8, 9
What is the union of sets A and B?

Answers

Answer:

Step-by-step explanation:

A∩B = 4

4 is in both set so it unites them therefore it’s the union

which expression represents 100 less than 3 times the sum of 18 and 2

Answers

Answer: 3 times (18+ 2) - 100

3 (18+2) - 100 = -40

Step-by-step explanation:

Mrs. Goldstein pours 3 juice boxes into a bowl to make punch each juice box hold 236 ml how much juice it does Mrs.Goldstein pour into the bowl

Answers

708 ml

When each box contains 236 ml of juice and she pours three boxes into the bowl, you need to multiply 236 by 3. After completing the calculation, you would get 708.

Which expression is equivalent to 142 +35 - 2142
7z(2-5-39)
7zy(2-5-3)
21-5-39
7(2z-5-39)
HELP FAST

Answers

The last one on the bottom
7 (2x +5 -3y)

a box 4cm by 6cm by 8cm is painted on all six faces and then cut into cubes with the 2 cm sides. how many oof these cubes have only one side painted?

Answers

Answer:

hola saludos desde kansas city

What is 5/8 divided by 1/4

Answers

Answer:

the answer should be 2.5

Step-by-step explanation:

when divided 5/8 u get 0.625 and when u divided 1/4 u get 0.25 and u divided both answer u get 2.5

15 1/2 as an integer

Answers

2 good luck on ur work :)

a plane flies 5.0km due north from a point O and then 6.0km on a bearing of 060° the pilot then changes course on a bearing of 120° for 4.0km. find how far and in what direction the plane is from the starting point?​

Answers

The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

A plane that travels a distance [tex]r[/tex], in kilometers, with a bearing of [tex]\theta[/tex] sexagesimal degrees can be represented in standard position by means of the following expression:

[tex]\vec r = r\cdot (\sin\theta, \cos \theta)[/tex] (1)

We can obtain the resulting vector ([tex]\vec R[/tex]) by the principle of superposition:

[tex]\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})][/tex] (2)

If we know that [tex]r_{1} = 5\,km[/tex], [tex]\theta_{1} = 0^{\circ}[/tex], [tex]r_{2} = 6\,km[/tex], [tex]\theta_{2} = 60^{\circ}[/tex], [tex]r_{3} = 4\,km[/tex] and [tex]\theta_{3} = 120^{\circ}[/tex], then the resulting vector is:

[tex]\vec R = 5\cdot (\sin 0^{\circ}, \cos 0^{\circ}) + 6\cdot (\sin 60^{\circ}, \cos 60^{\circ}) + 4\cdot (\sin 120^{\circ}, \cos 120^{\circ})[/tex]

[tex]\vec R = (5\sqrt{3}, 6) \,[km][/tex]

The magnitude of the resultant is found by Pythagorean theorem:

[tex]\|\vec R\| = \sqrt{R_{x}^{2}+R_{y}^{2}}[/tex]

And the bearing is determined by the following inverse trigonometric relationship:

[tex]\theta_{R} = \tan^{-1} \left(\frac{R_{y}}{R_{x}}\right)[/tex] (3)

If we know that [tex]R_{x} = 5\sqrt{3}\,km[/tex] and [tex]R_{y} = 6\,km[/tex], then the magnitude and the bearing of the resultant is:

[tex]\|\vec R\| = \sqrt{(5\sqrt{3})^{2}+6^{2}}[/tex]

[tex]\|\vec R\| \approx 10.536\,km[/tex]

[tex]\theta_{R} = \tan^{-1} \left(\frac{6}{5\sqrt{3}} \right)[/tex]

[tex]\theta_{R} \approx 34.715^{\circ}[/tex]

The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

To learn more on vectors, we kindly invite to check this verified question: https://brainly.com/question/21925479

-7(-2 ( 3x+1)+ 4) +9​

Answers

Answer:

correct answer is explained in the picture attached

Launch Problem

Melanie was training for a race. The line plot below shows the number of miles Melanie ran last week.


5. How many miles did Melanie run altogether last week?

Answers

Answer:

5 miles

Step-by-step explanation:

add the points together.

it seems like each point is how many miles they ran each day.

1/4 + 2(1/2) + 3/4 + 3(1) = 5

pls help... I need to write some words to post this​

Answers

Answer:

k=100, n=3, 1.5625, 10

Step-by-step explanation:

To find n and k, we can plug x and z in.

First we can try this for (1,100). We will get:

[tex]100=\frac{k}{1^{n} }[/tex]

Since 1 to any power is 1, we can assume that the denominator is 1 and therefore k=100.

Armed with k=100, we can plug numbers into the second equation.

[tex]12.5=\frac{100}{2^{n} }[/tex]

Moving [tex]{2^{n} }[/tex] to the left side, we get:

[tex]2^n=\frac{100}{12.5} }=8[/tex]

therefore we can solve and we see that n=3.

We can do the same for x=4, but since we have n, k, and x, we can plug these in to get z

[tex]z=\frac{100}{4^{3}} =1.5625[/tex]

We will do the same as previous but instead plug in x

[tex]\frac{1}{10}=\frac{100}{x^{3} }[/tex]

We isolate [tex]x^{3}[/tex] and get

[tex]x^{3} =1000[/tex]

Therefore x=10

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