Jeff can weed the garden twice as fast as his sister Julia. Together they can weed the garden in 3 hours. How long would it take each of them working alone? Which of the following equations could be used to solve this problem?

See below for the proof of the equation 4h² - 4dh + x² = 0 using the Pythagoras theorem

The Pythagoras theorem states that:

Hypotenuse² = Opposite² + Adjacent²

The question is incomplete, as the figure is not given.

So, I will complete the proof using the following parameters:

Substitute the above values in the following equation

Hypotenuse² = Opposite² + Adjacent²

So, we have:

(2√dh)² = x² + (2h)²

Evaluate the exponents

4dh = x² + 4h²

Subtract 4dh from both sides

0 = x² + 4h² - 4dh

Rewrite as:

4h² - 4dh + x² = 0

Hence, the equation has been proved

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Answer:

if this is 4.88/16 then the answer is 0.305.

Answer:

13r+10

Step-by-step explanation:

1. Combine Like Terms

(2r+11r)+(7+3)

13r+10

Answer:

13r+10

Step-by-step explanation:

2r+7+11r+3

collect like terms

2r+11r+7+3

13r+10

The sides

12-3a

12-3a

4(2a-5)=8a-40

so for perimeter we + them

(12-3a)+(12-3a)+(8a-40)

=

2a-16

You should plot the total distance traveled from the base camp on the x-coordinate while the elevation should be plotted on the y-coordinate.

A graph simply refers to a type of chart which is commonly used to graphically represent data on both the vertical and horizontal lines of a cartesian coordinate (x-coordinate and y-coordinate).

In this scenario, you would plot the total distance traveled from the base camp on the x-coordinate while the elevation of the camps would be plotted on the y-coordinate as shown in the image attached below.

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Answer:Angle BCE

Step-by-step explanation:

look across from point C

Answer:

9 / 2 = 4.5

4.5 - 4 = 0.5

Answer:

[tex]2[/tex]

Step-by-step explanation:

[tex] {16}^{ \frac{1}{4} } \: is \: the \: same \: as \\ \\ \sqrt[4]{16} = \sqrt[4]{ {4}^{2} } [/tex]

Note we broke down the 16 into 4 squared*. This is because 4 squared is the same as 16. The four and the two would cancel each other leaving:

[tex] \sqrt[2]{4} \;\\ or \\ \: \sqrt [2]{{2}^{2}} [/tex]

Like before the two and the two would cancel each other out leaving:

[tex]2[/tex]

Answer:

C. 2

Step-by-step explanation:

edge

Answer:

4/19

Step-by-step explanation:

Jar a: 3/8

Jar b: 1/11

8+11 = 19

3+1= 4

4/19

Answer:

10

Step-by-step explanation:

32 - 12 (because C is 12 years younger) = 20

20 / 2 (because twice Anna's age, so we do the inverse) = 10

Anna is 10 years old.

Hope this helps!

Answer:44

Step-by-step explanation:

Step-by-step explanation

Here ...I'm not too sure about the question as you have written

P = 2 ( 1 + 6 ) and ask to solve for L ...

.So I guess the question you have written is wrong .. ...and I guess there should be L in the place of 1.

...So let me correct the question....

P = 2 ( l + 6 )

P = 2l + 12

P - 2l = 12

- 2l = 12 - P

- 2l = - P + 12

Change the sign of both side of the equation...

2l = P + 12

divide both side by the same number...

L = ( P + 12 ) ÷ 2

[tex]l = \frac{1}{2} p - 12 \times \frac{1}{2} \\ [/tex]

Calculate the product of rational numbers...

[tex]l = \frac{1}{2} p - 6 \\ [/tex]

Answers:

===========================================================

Explanation:

Think of a hexagonal room with n = 6 walls, i.e. the floor is a hexagon with n = 6 sides. The floor and ceiling are parallel to each other, and congruent hexagons. That's 2 faces so far. Then we have another 6 faces to account for the walls. This gives 2+6 = 8 faces of a hexagonal prism.

In more general terms, a prism with a base of n sides will have 2 parallel and congruent base faces, and n walls or lateral faces. This gives n+2 total faces.

------------------------

Let's go back to the hexagonal prism. The floor has 6 sides to it, and so does the ceiling. We have 6+6 = 12 edges so far. Then we have another 6 edges where each of the rectangular walls meet up. That gives 12+6 = 18 edges total of this hexagonal prism room.

For any more general case, each base has n sides. That gives 2n sides so far for just the bases. Then add on another n for the lateral edges and we get 3n total edges.

--------------------------

Once again lets revisit the room with the hexagonal floor and ceiling. The floor has 6 vertices and the ceiling has the same vertex count. Therefore, this prism has 6+6 = 12 vertices.

For the general case, each base has n vertices. There are 2 such identical bases giving 2n vertices total.

---------------------------

One way to check the answer:

We could use Euler's Polyhedron Formula which is

F+V-E = 2

where,

For the hexagonal prism we found

Then notice how

F+V-E = 2

8+12-18 = 2

20-18 = 2

2 = 2

This confirms the formula works for a hexagonal prism.

Now let's check it for the more general case

We found earlier that,

So,

F+V-E = 2

n+2+2n-3n = 2

3n-3n+2 = 2

0n+2 = 2

0+2 = 2

2 = 2

This helps confirm the answer for any prism with the base of n sides.

#34.

If one's price be d

#35

So old area=150(100)=15000

New area increase

New area

Option C

#36

Prime numbers inbetween

#37

#38

1hr additional=1.5(2)=3$

Equation is

So

Option A

Answer:

here i have tried 2 question hope it help u

Answer:

Hope the picture will help you.....................

Answer:

[tex]0 < x < 6[/tex]

Step-by-step explanation:

This question asks to solve an inequality which can be written as:

[tex]\sqrt{x^2-6x+9} < 3[/tex]

Solve for x:

[tex]\sqrt{x^2-6x+9} < 3\\x^2-6x+9 < 9\\x^2-6x < 0\\x(x-6) < 0[/tex]

From here we can deduce that the inequality is [tex]0[/tex] when:

[tex]x = 0[/tex] or [tex]x = 6[/tex]

We can write the solution as:

[tex]0 < x < 6[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 3x - 3x+ 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{}(x - 3) - 3(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3)(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: { (x - 3) {}^{} } [/tex]

Now, we have been given that value of x :

[tex]\qquad \sf  \dashrightarrow \:x < 3[/tex]

So, let's plug the value of x as 3 in the given expression ~

[tex]\qquad \sf  \dashrightarrow \:3 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

Therefore, we can conclude that :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } < 0[/tex]

Value of the expression should be less than 0

There are 258 ways to color the octagon such that no two adjacent vertices are the same color

The given parameters are:

Since no two adjacent vertices are the same color, we use the following  chromatic polynomial of an octagon equation

Ways = (r - 1)⁸ + (r -1)

Substitute 3 for r

Ways = (3 - 1)⁸ + (3 -1)

Evaluate

Ways = 258

Hence, there are 258 ways to color the octagon

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[tex]v = \frac{4}{3} \pi {r}^{3} [/tex]

[tex]v = \frac{4}{3} \times \pi \times {2}^{3} [/tex]

[tex]v = 33.51 \: {m}^{3} [/tex]

[tex]v = \pi {r}^{2} h[/tex]

[tex]v = \pi \times {2}^{2} \times 6[/tex]

[tex]v = 75.40 \: {m}^{3} [/tex]

[tex]v = 75.40 + 33.51[/tex]

[tex]v = 108.91 \: {m}^{3} [/tex]

Hence, the volume of the given compound shape is 108.91 cubic meters.

sphere:

= 33.51 m^3

cylinder:

= 75.40 m^3

all together:

= 108.91 m^3

Answer:

180-108=72   72/2=36 degrees

Step-by-step explanation:

Please ad brainliest

Answer:

[tex]2x - 2y = 24 \\ 2(x - y) = 24 \\ x = 12 + y......eq(1) \\ 4x + 7y = - 40......eq(2) \\ substituting \: the \: value \: of \: x \: in \: eq(2) \\ 4(12 + y) + 7y = - 40 \\ 48 + 4y + 7y = - 40 \\ 11y = - 40 - 48 \\ y = \frac{ - 88}{11} \\ y = - 8 \\ putting \: the \: value \: of \: y \: im \: eq(1) \\ x = 12 - 8 \\ = 4[/tex]

Step-by-step explanation:

3x-2y=24......eqi

x+2y=48........eqii

now solving eq i&ii

4x=72

x=72/4

x=18

now putting the value of x in eqii

18+2y=48

2y=48-18

y=30/2

y=15

Check the picture below.

Yes

Step-by-step explanation:

[tex] \cos( \alpha ) = \frac{base}{hypoteneuse} [/tex]

Its just correct..

Answer:

[tex]f(x)=-2\cos(2x)+1[/tex]

Step-by-step explanation:

Recall the general cosine equation

Identify amplitude

[tex]\text{Amplitude}=\frac{\text{Max-Min}}{2}=\frac{3-(-1)}{2}=\frac{4}{2}=2[/tex]

Identify period and solve for b

[tex]\frac{3\pi}{2}-\frac{\pi}{2}=\pi\\ \\\frac{2\pi}{|b|}=\pi\\ \\2\pi=b\pi\\\\2=b[/tex]

Identify midline

[tex]y=d=1[/tex]

Final Equation

[tex]f(x)=-2\cos(2x)+1[/tex]

Also, the reason why [tex]a=-2[/tex] is because a cosine function starts at its maximum, but since it starts at its minimum, the value of [tex]a[/tex] must be negative and causes the wave to flip about the midline.

Answer:

x/3+3=x/8+1/11

x+9/3=11x+8/88

88(x+9)=3(11x+8)

88x+729=33x+24

88x-33x=729-24

55x=705

x=705/55

x=12.80

Answer:

135 cubes

Step-by-step explanation:

Volume of cuboid :

Volume of a small cube :

Number of cubes :

Step-by-step explanation:

Q1. volume of a cylinder

Ans. The way you find a volume of a regular object is multiplying the base area by height Here the base area is a circle so formula would be pi times r square (πr^2). To get the volume multiply it by 4. Final answer would be π(3)^2*4

✒️ Equation

••••••••••••••••••••••••••••••••••••••

A. To find the x - intercept, let y = 0.

[tex]\tt \: \: \large \tt \: \begin{array}{|c|} \hline \tt \: 4x \: - \: 3y \: = \: \tt\underline{\green{ 12 }} \\ \tt 4x \: - \: 3(0) \: = \: \tt\underline{\blue{ 12 }} \\ \tt4x \: - \: 0 \: = \: \tt\underline{\pink{ 12 }} \\ \tt \tt\underline{\red{ \: x \: = \: 3 }} \\ \\ \tt \: x ↬\: the \: intercept\\ \tt\\ \hline\end{array} \: \\ [/tex]

[tex] \\ [/tex]

To find the y - intercept, let x = 0

[tex]\large \tt \: \begin{array}{|c|} \hline \tt 4x \: - \: 3y \: = \: \tt\underline{\green{ 12 }} \\ \tt 4(0) \: - \: 3y \: = \: \tt\underline{\blue{ 12 }} \\ \tt \: 0 \: - \: 3y \: = \: \tt\underline{\pink{ 12 }} \\ \tt \tt\underline{\red{ y \: = \: - 4 }} \\ \\ \tt \: x ↬\: the \: intercept \\ \ \\ \hline\end{array} \: [/tex]

[tex] \\ [/tex]

B. Replace x with 0 and solve for y. Then replace y with 0 and solve for x.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt y \: - \: intercept: \: y \: = \: \frac{1}{3}(0) \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \tt = \tt\underline{\red{ 0 }} \\ \\ \tt \: x \: and \: y ↬ intercepts: (0,0)\\ \\ \tt \: x \: ↬ \: intercepts: \: 0 = \: \frac{1}{3} x \\ \quad\quad \quad \quad\quad\quad\quad\quad\quad \: \tt \tt\underline{\red{ \: 0 \: = \: x }} \ \\ \\ \hline\end{array} \\ [/tex]

[tex] \\ [/tex]

The equation in b is a linear equation in the form y = mx, where m is any real number. the graph of any equation in the form y = mx is always a line that passes through the origin, which means that both the x - and - y - intercepts are (0,0).

[tex]\large \tt \: \begin{array}{|c|} \hline \tt intercept \: for \: m \: of \: y \: = \: \tt\underline{\red{ mx }} \\ \hline\end{array}[/tex]

[tex] \\ [/tex]

C. Replace y with 0, then solve for the x.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt x ↬ \: intercept : \: 0 \: = \: 2x \: \ + 5 \\ \\ \tt - 5 \: = \: 2x\\ \\ \tt \: \frac{ - 5}{2} \: = \: x\\ \\ \tt \: x \: ↬ \: intercept \ \\ \hline\end{array}[/tex]

Now, replace x with 0, and then solve for y.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt y ↬ \: intercept: \: y \: = \: 2(0) \: + \: 5 \\ \\ \tt \: y \: = \: 0 \: + \: 5 \\ \\ \tt \: y \: = \: 5 \\ \\ \tt y ↬ \: intercept \ \\ \\ \hline\end{array}[/tex]

The equation in 11c is written in the form y = mx + b. note than in the form, when x is replaced by 0 to find the y↬intercept. you are left with the constant b.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt \: the \: y ↬ intercept \: of \: y \: = \: mx \: + \: b \\ \hline\end{array}[/tex]

If the equation is in the form y = mx + b, where m and b are real numbers, then the y ↬intercept is b.

[tex] \\ [/tex]

D. Remember that the graph of y = 6 is horizontally line parallel to the x axis that passes through the y axis at (0,6). since the line is parallel to x axis, it will not incest tha x-axis. Hence, there is no x ↬ intercept.

[tex] \\ \\ \\ [/tex]

[tex]\pmb{(ノ‥)ノ}\qquad\qquad\qquad\qquad\boxed{\tt{[05-12-2022]}} \\ \qquad\qquad\qquad\qquad\qquad\qquad\boxed{\tt{[03:11 \: am]}}[/tex]

Answer:

................

Step-by-step explanation:

Answer:

32π cm^3.

Step-by-step explanation:

The volume of a cone is 1/3 of the volume of a cylinder with the same base area and height.

So the empty space = 2/3 * 48π

= 32π cm^3.