The magnitude of the frictional force of the box is 65 N
From the question given above, the following data were obtained:
Mass (m) = 25 KgForce applied (Fₐ) = 135 NNet force (Fₙ) = 70 NFrictional force (Fբ) =?The frictional force acting on the box can be obtained as follow:
Fₙ = Fₐ – Fբ
70 = 135 – Fբ
Collect like terms
70 – 135 = – Fբ
–65 = –Fբ
Multiply through by –1
Fբ = 65 NThus, the frictional force of the box is 65 N
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A new moon is discovered orbiting Neptune with an orbital speed of 9.3 x103 m/s. Neptune's mass is 1.0 x1026 kg. A) What is the radius of the new moon's orbit? B) What is the orbital period? Assume that the orbit is circular. (G = 6.673 x10-11 N-m²/kg?
A type of matter in which two or more elements are combined
chemically is called a _______
Answer:
COMPOUND
Explanation:
Why are movie scenes in outer space often unrealistic?
Answer:
see explanation
Explanation:
by my calculations, i believe it may be because they have to pretend to be in space.
one of them is Space & Interstellar Travel
An 50 kg student runs and jumps onto a 25 kg tire swing, which is initially at rest, and rides the swing up into the air. The swing (and the student) then rises a vertical distance of 1.5 m. What was the initial speed, in m/s of the swing? Remember the acceleration due to gravity near Earth's surface, g = 9.81 m/s^2
A. 29 m/s
B. 5.4 m/s
C. 1.7 m/s
D. 15. m/s
E. 3.8 m/s
Will mark brainliest
Answer:
Option B, 5.4m/s
Explanation:
Using the formula v² = u ² - 2gh
v = 0(final velocity is zero at maximum height), u = ?, g = 9.81m/s², h = 1.5m
0² = u² - 2×9.81×1.5
0 = u² - 29.43
29.43 = u²
u = √29.43
= 5.42m/s
what class of motion did aristotle attribute to the moon?
12/3/21 A wave in the ocean has a wavelength of 24 m and a frequency of 8 Hz,What is the wave's speed?
Answer:
192 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 8 × 24 = 192
We have the final answer as
192 m/sHope this helps you
will mark brainliest if answer
I won't touch the object because there is a warning sign and that means you stay out if it because it is a danger sign that High Resistance Material that means it is dangerous.
The density of air is 1.3 kg/m'. Calculate the mass of air in the room.
Answer:
The density of air is 1.3 kg/m'. Calculate the mass of air in the room.
On average, how many stars would we have to search before we would expect to hear a signal? assume there are 500 billion stars in the galaxy.
We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.
To find out the number of stars that we will need to search to find a signal, we need to use the following formula:
total of stars/civilizations500,000,000,000 (500 billion) stars / 100 civilization = 5,000,000,000 (5 billion)
This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.
Note: This question is incomplete; here is the complete question.
On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.
Assuming 100 civilizations existed.
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Express the sum of 2.52 kg + 131 g in kilograms with the correct number of significant
figures.
Convert second term into kg
131 = 0.131
Term has become:
2.52 + 0.131
The total is:
2.651 kg
If the half-life of iodine-131 is 8 days, how much of a 5.00 sample is left after 32 days?
A) 0.31
B) 2.5
C) 1.25
D) 0.62
Answer:
Option A, 0.31
Explanation:
n = Time taken / half life
n = 32/ 8
= 4
Remaining fraction = 1/2^n
= 1/2⁴
= 1/16
Amount of iodine-131 left = 1/16 × 5
= 0.3125
A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?
Answer:
109.52 HzExplanation:
The frequency of the wave when given it's velocity and wavelength only can be found by using the formula
[tex]f = \frac{c}{ \lambda} \\ [/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in meters
From the question we have
c = 230 m/s
[tex] \lambda[/tex] = 2.1 m
[tex]f = \frac{230}{2.1} = 109.523809... \\ [/tex]
We have the final answer as
109.52 HzHope this helps you
A car travels 120 miles in 12 hours. What is
the car's speed?
Select one:
O a. 10 m/s
b. 10 mph
c. 1200 mph
O d. 0.1 m/s
Answer:
I hope it will help you...
#CARRYONLERANING
Draw a diagram that represents how a mechanical wave interacts with a particular material.
Create a diagram and include reflection, absorption, and transmission.
Write a brief description (3+ sentences) of the interaction of the mechanical waves and the material. Include an explanation of how the amplitude and frequency of the wave are affected.
85 POINTS!!
When mechanical waves interact with material, it transfer its energy to the material.
What are mechanical waves?Mechanical waves are the type of waves that require a medium for transporting their energy from one region to another. Mechanical waves depend on particle interaction in order to transport their energy.
The amplitude and frequency of the wave are negatively affected due to the striking of mechanical waves with the material.
Learn more about waves here: https://brainly.com/question/75996
Answer:
i have a screenshot just use mine https:/ss27
Explanation:
A kilowatt-hour is a unit of
1. force
2. power
3. work
4. voltage
5. current
6. None of these
7. torque
(I tried 2 and 6, but they were both wrong :( )
Answer:
option 4 is the correct answer
If the 0.10 kg baseball on the right has a
kinetic energy of 5 J, what is its velocity?
Answer:
10 m/sExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
Since we're finding the velocity we make v the subject
That's
[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]
From the question
k = 5 J
m = 0.1 kg
We have
[tex]v = \sqrt{ \frac{2 \times 5}{0.1} } = \sqrt{ \frac{10}{0.1} } = \sqrt{100} \\ = 10[/tex]
We have the final answer as
10 m/sHope this helps you
1 kg ball has eight joules of kinetic energy. what is its speed?
[tex]\\ \sf\Rrightarrow KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow 8=\dfrac{1}{2}v^2[/tex]
[tex]\\ \sf\Rrightarrow v^2=16[/tex]
[tex]\\ \sf\Rrightarrow v=√16[/tex]
[tex]\\ \sf\Rrightarrow v=4m/s[/tex]
Answer:
the answer is 4m/s
3. Suppose Earth orbited a star whose mass was double the mass of the sun. If the radius of Earth's orbit remained
the same as it is now, then compared with gravitational force between Earth and the sun, the gravitational force
between Earth and the star would be -
A. half as much
B. the same
C. two times as much
D. four times as much
Answer:
F1 = G M m / R^2 current force on earth
F2 = G M * 2 m / R^2 force if mass were doubled
F2 / F1 = 2 the force would be twice as large
The gravitational force between two objects not only depends on the mass but also the distance between them. If the distance to the star is same as to sun, then by doubling mass force also doubles. Thus option C is correct.
What is universal law of gravitation?Gravitational force is the attractive force by which an object attracts other objects into its centre of mass. We are all standing in the ground because of the gravitational pull by earth.
The gravitational force between two objects of mass M1 and M2 at a distance r is written as follows:
g = G M1 M2/ r ² . where, G is gravitational constant.
As per this relation, gravitational force is directly proportional to the mass and inversely proportional to the square of the distance.
If the star has a distance from earth equal to the distance between sun and earth, but its mass is double the mass of sun, then the gravitational force will be two times compared with the sun.
To find more on gravitational force, refer here:
https://brainly.com/question/12528243
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A 50 kg swimmer goes off end of water slide at 10 m/s- what is swimmers momentum ?
Answer:
The swimmer's momentum is 500 Kg m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Where in an equation for photosynthesis does glucose belong? on the left, because it is a product on the left, because it is a reactant on the right, because it is a product on the right, because it is a reactant
Answer: The answer is on the right, because it is a product.
Explanation: During photosynthesis, light energy converts carbon dioxide and water (the reactants) into glucose and oxygen (the products).
Glucose belongs to the right side in photosynthesis equation because it is a product on the right.
What is Photosynthesis?Photosynthesis is the conversion of light energy into chemical energy by green plants and other organisms. Light energy is collected and utilized by green plants during photosynthesis to transform water, carbon dioxide, and minerals into oxygen and energy-rich organic molecules Glucose.photosynthesis equation can be written as6CO2 + 6H2O → C6H12O6 + 6O2.
Carbon dioxide + Water → Glucose + oxygen
Hence, the correct option is C.
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If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, what must be true of the magnitude of the reaction force?
According to Newton third law of motion, what must be true of the magnitude of the reaction force is that the reaction force will be equal and opposite to the action force of 110 newtons
From Newton third law of motion which state that in every action of force, there will be equal and opposite reaction.
If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, the mass 35 kg will produce a reaction force which is equal and opposite to the action force 110 newton received from mass 75 kg.
Therefore, what must be true of the magnitude of the reaction force from mass 35 kg is that the mass will produce an equal and opposite force equal to 110 Newtons.
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where in space did the expansion of the universe begin?
Answer:
The big bang
Explanation:
It is theorized the expansion of the universe began with the big bang, the universes expansion therefore did not begin in a spot of the universe rather the universe expanded from the big bang.
What is the equivalent resistance of a 12-ohm resistor wired in parallel with a 4-ohm resistor?
А
0.06 ohms
B
0.33 ohms
С
3.0 ohms
D
16.0 ohms
[tex]R=\frac{R1.R2}{R1+R2} = \frac{12.4}{12+4}=\frac{48}{16}=3<ohms>[/tex]
The answer is : C. 3.0 ohms
Ok done. Thank to me :>
If you were to mix 10 grams of salt into 100 grams of water, how much will the total mass of the solution be?
Group of answer choices
90 grams
100 grams
110 grams
10 grams
110 grams
mass of salt + mass of water
10 + 100
110g
Answer:
110 grams
Explanation:
If you were to mix 7 grams of sugar into 100 grams of water, how much will the total mass of the solution be?
No mass was gained or lost, so the mass would be 107 grams.
100 grams
107 grams
93 grams
95 grams
No mass was gained or lost, so the mass would be 107 grams.
(For your problem it would be 10+ 100= 110g)
You slide towards the window when a car makes a sudden turn
Answer:
thats ummm
Explanation:
law of inertia
Newton’s 1 law
(50 POINTS) please answer each question:
what is the Distance from Earth (light years)
what is the Visual Luminosity in comparison to Sun
what is the Surface Temperature (Kelvin)
stars:
Sun
Alpha Centauri A
Sirius B
Barnard’s Star
Vega
Proxima Centauri
Answer:
i know the first one.
Explanation:
the distance from earth in light years is 6 trillion miles.
free tingsssssssssss
Explanation:
yayyy thx u soo muchihuhuhu
Answer:
thx
Explanation:
This is not meant to be a long, mathematically-intensive problem. If you find yourself going down that road, you might want to rethink your approach.
Answer:
rethink your approach to what?
Explanation:
A furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
Answer:
furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
Explanation:
furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
[tex] \huge \boxed{ \sf lol}[/tex]