just give me the right answer!
If the distance between two objects decreased, what would happen to the force of gravity between them?

It would increase.
It would stay the same.
It would depend on the speed.
It would decrease.

The mass of the girl is 30 kg  in order for the seesaw to be in equilibrium.

A particular kind of lever is a seesaw, which has a long beam coupled to a pivot known as the fulcrum.

As soon as you sit on one side of the beam and apply weight on one end, the beam falls to the ground. This is because the weight of your body is being pulled down by the force of gravity, along with the beam.

Let the  mass of the girl = m kg

In equilibrium;

40 kg × 300 cm = m × 400 cm

⇒ m = 30 kg.

Hence,  the mass of the girl is 30 kg.

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Answer:

Object 1

Explanation:

Newton's 2nd Law:  F = ma, therefore m = F/a

This shows that mass is inversely proportional to acceleration.  Because the resultant force (F) is held constant in this problem, the lower the acceleration, the greater the mass.  Therefore, the object that accelerates at 2 m/s² has the greater mass.  In other words, if the net force on both objects is the same, the object with the slower acceleration has the greater mass.  

Answer:

speed

Explanation:

you need to move fast so the tornado can't reach you

The relation between a frog's maximum height and maximum range is that when the frog jumps at an angle of 45°, its maximum height is half of the horizontal range.

The maximum height refers to the maximum vertical distance that an object can travel.

The maximum range is the maximum horizontal distance that an object can travel.

The maximum height, H that the projectile reaches when the range, R, is at its greatest is H = Rmax /4.

R = 4Hcot is the relationship between the horizontal range and maximum height.

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Answer:

it keeps moving until a force disturbs it

Explanation:

There is strong evidence to support the idea that the universe is expanding. One of the main pieces of evidence for this is the observation of the cosmic microwave background radiation, which is a faint glow of microwave radiation that permeates the entire universe. This radiation is thought to be a residual heat left over from the Big Bang, the event that is believed to have marked the beginning of the universe.

The cosmic microwave background radiation has a very even temperature throughout the universe, but if the universe were not expanding, we would expect to see some regions that are slightly hotter or cooler than others due to differences in density. However, measurements of the cosmic microwave background radiation show that it has a very uniform temperature, which suggests that the universe must be expanding in order to even out any temperature differences that may have existed in the past.

Other evidence for the expansion of the universe includes the observation of supernovae in distant galaxies, which are explosions of massive stars that can be used to measure the distances to those galaxies. These measurements have shown that the most distant galaxies are moving away from us at a speed that is proportional to their distance, which is consistent with the expansion of the universe.

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Resistors limits the current/amps but keep the voltage the same.

You don't want to attach them together with a wire since there would be too much current loose through, such that the battery heats up till it blows or something.

Current is directly corresponding to voltage; a doubling of the voltage will double the current. But the current is also inversely comparable to the resistance; a doubling of the resistance will halve the current.

So we can conclude that Resistance residue is the same, but power becomes four times i.e. multiplication. If the current is I and the voltage is V,

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Based on the image shown, the numbers that correspond to the term or phrase assuming that the electrons flow counterclockwise from 3 to 2 to 1, from 5 to 4 to 5, and to 3 are:

Electrochemical cells are cells that convert chemical energy to electrical energy.

The components of an electrochemical cell are:

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Answer:

a unit of length effectively equal to the average, or mean, distance between Earth and the Sun

Explanation:

If force is doubled, acceleration will also be doubled.

In this given question, force is doubled. We know that force is directly proportional to acceleration. As we increase the force on an object the acceleration increases proportionally. Therefore, if you double the force you double the acceleration.

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The distance travel while accelerating is 90m

The initial velocity of the particle is 15m/s and the final velocity is 45m/s, so the change in velocity is 45m/s - 15m/s = 30m/s. The particle accelerates uniformly for 3.0s, so the acceleration is 30m/s / 3.0s >>30/3=10 that is 10m/s^2.

The distance traveled during the acceleration is equal to the average velocity times the time elapsed, so the distance traveled is (15m/s + 45m/s)/2 * 3.0s = (15+45)/2*3= 90m .

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Answer:

To solve this problem, you can use the formula for work, which is work = force x distance. In this case, the distance the crate is moved is the height of the loading dock, or 4 meters. The amount of work performed is given as 600 joules. So, you can set up the equation like this:

600 joules = force x 4 meters

To solve for the force, you can divide both sides of the equation by 4 meters:

600 joules / 4 meters = force x 4 meters / 4 meters

This simplifies to:

150 newtons = force

So, the force necessary to raise the 150-newton crate up the ramp to the 4-meter loading dock is 150 newtons.

Lenses, which are pieces of curved, clear glass, were employed in early telescopes to focus light.

Curved mirrors are used by the majority of telescopes nowadays to collect light from the night sky. Light is focused by a telescope's mirror or lens' shape.

Astronomers use a telescope to observe distant things. Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from the night sky.

The original telescopes employed lenses, which are simply curved pieces of clear glass, to focus light. The "optics" of a telescope are the mirrors or lenses. Strong telescopes may view objects that are extremely faint and incredibly far away.

Therefore, Lenses, which are pieces of curved, clear glass, were employed in early telescopes to focus light.

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The speed at which a clock would have to be moving in order to run at half the rate of a clock at rest depends on the theory of relativity that you are using.

In special relativity, time dilation is the phenomenon where time appears to pass differently for objects in motion relative to an observer at rest.

According to the theory, time appears to slow down for an object as it approaches the speed of light. The rate at which time appears to pass for an object is given by the equation:

T' = T / [tex]\sqrt{(1 - (v^2 / c^2))}[/tex]

Where T is the time as measured by an observer at rest, T' is the time as measured by an observer moving relative to the object, v is the velocity of the object, and c is the speed of light.

In addition, this is a theoretical scenario, practically in order to measure time dilation in a laboratory, it is required a very high precision of measurements, that are currently not possible.

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Based on the data provided about the collision;

The magnitude of the impulse due to the collision of the vehicle with the wall is calculated using the formula of the impulse on an object given below as follows:

Impulse = change in momentum

Change in momentum = m(v - u)

where;

m is mass

v is the final velocity

u is the initial velocity

Impulse = 1759 (12 - 22)

Impulse = 21105.8 kg.m/s

The average force on the automobile will be:

Force = impulse/time

Force = 21105.8 / 0.11

Force = 191870.91 N

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The parallel component of the force of gravity is the net force. The perpendicular component of the force of gravity is directed opposite the normal force and as such balances the normal force.

In order to balance the normal force, the perpendicular component of gravity is pointed in the opposite direction. No other force can counteract the parallel component of the gravitational force.

The presence of an imbalanced force will then cause the object to accelerate downward along the inclined plane. This acceleration is brought on by the parallel part of the gravitational force. The net force is a parallel part of the gravitational force.

FGravity=m×g

where m is the object's mass and g is gravity's acceleration, which is 9.8 m/s2. In this case, the negative indicates that the force is downward-directed.

FParallel=FGravity×Cos(Θ)

FParallel=FGravity×Sin(Θ)

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The interaction between the Corn plants and milkweed plants demonstrates as competition.

Competition is typically considered to refer to the detrimental consequences that neighbors' presence has on a plant's fitness or growth, typically through lowering the resources available.

In addition to resources, disturbance, herbivory, and mutualisms, competition can be a significant factor in controlling plant populations. The resource involved is depending on the species and the region, as all plants require a few fundamental ingredients.

As corn plants and milkweed plants grow in the same area, the interaction between the Corn plants and  milkweed plants demonstrates competition.

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The ranking of the voltages, V₁, V₂, V₃, and V₄ in the order of decreasing voltage value is; V₂ > V₃ > V₁ > V₄

A voltage is the difference in potential or pressure that pushes or causes the flow of electric current in a circuit or conducting loop.

The current flowing through the circuit can be found using the following formula;

[tex]I=\dfrac{V}{R}[/tex]

The formula for conductivity is presented as follows;

[tex]\sigma =\dfrac{l}{R\times A}[/tex]

Where;

σ = The conductivity of the material

l = The length

R = The resistance to electricity

A = The cross-sectional area of the conductor

Therefore;

[tex]R=\dfrac{V}{I}[/tex]

[tex]R=\dfrac{l}{A\times \sigma}[/tex]

[tex]\dfrac{V}{I} =\dfrac{l}{A\times \sigma}[/tex]

[tex]V=\dfrac{l \times I}{A\times \sigma}[/tex]

Based on the dimensions of the cylinders, obtained from a similar question, we get;

[tex]V_1=\dfrac{3\cdot L \times I}{\pi \cdot D^2\times \sigma} = 3\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]

[tex]V_2= \dfrac{2\cdot L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} = \dfrac{8\cdot L \times I}{\pi \cdot D^2\times \sigma} = 8\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]

[tex]V_3=\dfrac{L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} =\dfrac{4\cdot L \times I}{\pi \cdot D^2\times \sigma}= 4\times \dfrac{L \times I}{\pi \cdot D^2\times \sigma}[/tex]

[tex]V_4=\dfrac{L \times I}{\pi \cdot D^2\times \sigma} = 1\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]

Therefore;

V₁ = 3·V₄

V₂ = 8·V₄

V₃ = 4·V₄

The rank of the voltages in the order of decreasing value is therefore;

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The addition of two sound waves produces a new wave of higher amplitude if their compressions and refractions line up. It is also known as constructive interference.

Interference can be described as a phenomenon in which two waves combine by adding at every single point in space and time, to form a resultant wave of greater or lower amplitude.

Constructive and destructive interference occurs in the interaction of waves that are correlated with each other because they come from the same source.

When two sound waves propagate in the same direction in phase with each other, their amplitude gets added, and the resultant wave is produced from constructive interference.

When two waves interfere with each other and have a displacement in the opposite direction.  When a crest of a wave meets the trough of another wave, the waves undergo destructive interference.

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The number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.

Electrons are particles of matter that carry a negative electrical charge. Electrons are the smallest particles in the atom and are responsible for most of the atom's mass. Electrons orbit around the nucleus of the atom and are held together by the electromagnetic force. Electrons have a property called spin, which can have a value of either +1/2 or -1/2. Electrons are found in all elements and are important in chemical reactions as they are able to move around and form bonds with other atoms. Electrons are also important in electricity and magnetism.

The number of excess electrons on the balloon is equal to the charge of the balloon divided by the charge of an electron. Since the charge of an electron is 1.60 x 10-19 Coulombs, the number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.

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Yes, the skater is accelerating.

Acceleration is a change in speed OR direction OR both.  Since she's skating in a circle, her direction is constantly changing, so she is accelerating.

At A, her velocity points down.

At B, her velocity points right.

At C, her velocity points up.

At D, her velocity points left.

Since the efficiency of the pulley is 75% and the single movable pulley is used to lift 4000N load to the height of 50 cm, the effort distance, effort applied, output work and mechanical advantage are as follows:

Effort Distance = 50 cm

Effort Applied = 5333.33 N

Output work = 2000 J

Mechanical Advantage = 0.75.

When a single movable pulley is used to lift a load, the effort applied is equal to the weight of the load being lifted, and the effort distance is the distance the effort is applied.

Load (output force) = 4000 N

Height lifted = 50 cm = 0.5 m

Efficiency of the pulley = 75%

Given the above information, we can calculate the effort applied, output work, and mechanical advantage as follows:

Effort applied (input force) = Load ÷ Efficiency

= 4000 N ÷ 0.75

= 5333.33 N

Output work = Load x Height lifted

= 4000 N x 0.5 m

= 2000 J

Effort distance = Height lifted

= 50 cm

Mechanical advantage = Load ÷ Effort applied

= 4000 N ÷ 5333.33 N

= 0.75

It is worth noting that pulley efficiency is the ratio of output work to the input work. And since the efficiency of the pulley is 75% so the input work is greater than the output work, which means some of the energy is wasted in overcoming friction and other losses.

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Due to the possibility of misinterpretation, the poem "Wild Duck" can be read as either the speaker leaving her lover or the lover leaving her.

Lola Ridge's poem "Wild Duck" allows for more than one interpretation of the speaker's meaning. As a result, it is ambiguous. The ambiguity of the poem can be examined, and the following response to the prompt:

You could say that according to your interpretation of the poem, the speaker is telling us about a night when she bid her lover farewell.

You could argue that the metaphor comparing the speaker to wild ducks and the speaker's statement that her heart "races along the train rails" are examples from the poem that support your claim.

You could argue that a different reading would imply that the speaker is the one being dumped by her lover.

You could cite the second stanza, which is not included here, where the speaker claims that the "known you" have emptied her soul, as proof for your claim.

But it's crucial to remember that the first interpretation appears to be the most plausible one. The metaphor involving the wild duck and the personification of the heart that runs on rails are quite clear, even though the poem does leave some room for ambiguity. The person who wants to leave someone behind is the speaker.

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The velocity of the experimental vehicle after 2 seconds is 14 m/s.

The displacement of the experimental vehicle after 2 seconds is 14 m.

The velocity of the experimental vehicle is the speed of the in a given direction starting from rest.

The velocity, v, of the experimental vehicle after 2 seconds is calculated using the formula below:

v = u + at

where;

u is the initial velocity = 0 m/s

a is the acceleration = 7 m/s²

t is time = 2 seconds

v = 0 + 7 * 2

v = 14 m/s

The displacement, s, of the vehicle is calculated below as follows:

v² = u² + 2as

14² = 0² + 2 * 7 * s

s = 196 / 14

s = 14 m

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The evaluation of the capacitor (in series) network is as follows;

Part A

Q = 3.2 μC

Part B

Q₁ = 3.2 μC

Part C

Q₂ = 3.2 μC

Part D

U = 76.8 μJ

Part E

U₁ = 34 2/15 μJ

Part F

U₂ = 53 1/3 μJ

Part G

V₁ = 21 1/3 V

Part H

V₂ = 26 2/3 V

A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.

The specified parameters are;

The voltage across ab = 48 V

The capacitance of the first capacitor, C₁ = 150 nF

Capacitance of the second capacitor, C₂ = 120 nF

Part A

The total charge in a capacitor network can be found as follows;

[tex]C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF[/tex]

[tex]C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF[/tex]

[tex]Q_{eq} = C_{eq}\times V_{ab}[/tex]

Therefore;

[tex]Q_{eq}[/tex] = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC

Part B

The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;

Q = C₁V₁ = C₂V₂

The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC

The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC

Part C

The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.

Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC

Q₂ = 3.2 μF

Part D

The total energy stored in the network can be obtained using the formula;

U = (1/2)·C·V²

Where;

U = The energy in the capacitor

C = The equivalent capacitance of the network = 66 2/3 nF

V = The voltage

Therefore;

[tex]U = \dfrac{1}{2} \times C_{eq}\times V^2[/tex]

[tex]U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8[/tex]

Part E

The energy stored in the 150 nF capacitor is found as follows;

[tex]Q_{eq}[/tex] = Q₁ = C₁ × V₁

V₁ = [tex]Q_{eq}[/tex] ÷ C₁

Therefore;

V₁ = 3.2 μC ÷ 150 nF = [tex]21\frac{1}{3}[/tex] V

U₁ = 0.5×C₁×V₁²

Part F

The energy stored in the 120 nF capacitor, U₂, can be found as follows;

V₂ = 3.2 μC ÷ 120 nF = [tex]26\frac{2}{3}[/tex] V

U₂ = 0.5 × 150 nF × [tex]\left(26\frac{2}{3} \, V\right)^2[/tex] = [tex]53\frac{1}{3}\, \mathrm{ \mu J}[/tex]

Part G;

The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V

Part H

The potential difference across the 120 nF, obtained in part F, is 26 2/3 V

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a) The average velocity at 4s is 12 m/s

b) The instantaneous velocity at t= 6s is 12 m/s

c) The average acceleration is; 12  - 0/ 4 - 0 n= 3 m/s^2

d) The time for the race is 10 s

We know that the velocity time graph is the kind of set up that has two axis and we can be able to use it to be read off the velocity of the acceleration  of the object. I would want us to recall  that the acceleration is the rate of change of the velocity of the object with time.

Now we have that;

The graph for the velocity of the object can be obtained by looking at the image that has been shown and then we read off the points that are on the graph. The  vertical axis shows the velocity of the graph while the horizontal axis shows the time that is covered in the graph.

The acceleration would be the ratio of the change in the velocity to the change in the time of the object.

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Answer:ssssw

Explanation: