Assuming both forces act horizontally, the net force is in Kathryn's direction with a magnitude of 5 N.
If "towards Kathryn" is taken the be the positive direction, then the net force is
∑ F = 20 N - 15 N = 5 N
Consider a polymer formed by a chain process. By how much does the kinetic chain length change if the concentration of initiator decreases by a factor of 10.0 and the concentration of monomer increases by a factor of 5.0?
What is the definition of kepal law
Cars have safety features to protect people during a crash. A bumper is one type of safety feature. Which bumper design do
you think is safer?
a bumper that crumples
a bumper that's rigid
Answer:
Explanation:
second one ??? pls i hope im right
Answer:
A bumper that crumbles (plato)
Explanation:
Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja. If Derek pulls horizontally on the dog with a force of 10.0 N and Anudja pulls with a horizontal force of 11.0 N, what is the horizontal acceleration of the dog?
Answer:
a = 3.33 m/s²
Explanation:
The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:
F = ma
where,
F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N
m = mass of the dog = 0.3 kg
a = horizontal acceleration of dog = ?
Therefore,
1 N = 0.3 kg(a)
a = 1 N/0.3 kg
a = 3.33 m/s²
Which of the following is most likely to occur at a convergent boundary?
A: Mountain formation
B: Seafloor spreading
C: Faults
D: Mid-Atlantic rift
Answer:A: mountain formation
Explanation:
Humpback whales sometimes catch fish by swimming rapidly in a circle, blowing a curtain of bubbles that confuses a school of fish and traps it in a small area, where the whales can easily catch and eat them. Suppose a 25,000-kg humpback whale swims at 2.0 m/s in a circle of radius 8.2 m. What centripetal force must the whale generate?
Answer:
1.2 x [tex]10^4[/tex] N
Explanation:
The centripetal force of a body moving in a circle is given by:
Centripetal force = [tex]\frac{Mv^2}{r}[/tex]
where M = mass of the object, v = velocity with which the object is moving, and r = radius of the circle.
In this case, M = 25,000 kg, v = 2.0 m/s, and r = 8.2 m. Hence;
Centripetal force generated by the whale = 25,000 x 2^2/8.2
= 12,195.12 N = 1.2 x [tex]10^4[/tex] N to two significant digits.
Find the Acceleration of a car with the mass of 1200kg and a force of 11x10^3 N
Answer:
9.17 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{11 \times {10}^{3} }{1200} \\ = 9.16666...[/tex]
We have the final answer as
9.17 m/s²Hope this helps you
what is the correct term for the people who came before us?
Answer:
Ancestors!
Explanation:
I know a thing or two~
Answer:
It depends on what the context is, if you mean people that came long before us you might be refering to ancestors, but if you mean people that came before us at any time then you would be refering to a predecessor.
Explanation:
What is a physical combination of two or more substances that are blended together without forming a new substance?
Answer:
It is called a mixture.
Explanation:
A mixture is a physical combination of 2 or more substances that are blended together without forming a new substance.
What is inertia?
An object's tendency to move quicker
An object's tendency to change direction
An object's tendency to resist changes in motion
An unbalanced force on an object
Answer:
I think the answer should be an object's tendency to resist changes in motion.
Explanation:
Inertia is resistance of any physical object to any changes in its velocity.
Answer:
an object's tendency to resist changes in motion.
Explanation:
23)
What statement BEST describes a gas?
A)
Gases have definite shape and variable volume.
B)
Gases have variable shape and variable volume.
0
Gases have a definite shape and definite volume.
D)
Gases have a variable shape and definite volume.
Answer:
b
Explanation:
A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.380 m/s^2. Suppose it moves with constant acceleration for 3.80 s.
Required:
a. Find the position of the particle after this time.
b. Find its velocity at the end of this time interval.
Answer:
a
[tex]x_2 = -2.3356[/tex]
b
[tex]v = -1.384 \ m/s[/tex]
Explanation:
From the question we are told that
The initial position of the particle is [tex]x_1 = 0.180 \ m[/tex]
The initial velocity of the particle is [tex]u = 0.060 \ m/s[/tex]
The acceleration is [tex]a = -0.380 \ m/s^2[/tex]
The time duration is [tex]t = 3.80 \ s[/tex]
Generally from kinematic equation
[tex]v = u + at[/tex]
=> [tex]v = 0.060 + (-0.380 * 3.80)[/tex]
=> [tex]v = -1.384 \ m/s[/tex]
Generally from kinematic equation
[tex]v^2 = u^2 + 2as[/tex]
Here s is the distance covered by the particle, so
[tex](-1.384)^2 = (0.060)^2 + 2(-0.380)* s[/tex]
=> [tex]s = -2.5156 \ m[/tex]
Generally the final position of the particle is
[tex]x_2 = x_1 + s[/tex]
=> [tex]x_2 = 0.180 + (-2.5156)[/tex]
=> [tex]x_2 = -2.3356[/tex]
You used measurements of distance and time to find velocity. When you calculate the uncertainty on your measurements of time, what units will that uncertainty have?a. counts/time b. time^2 c. time d. time/counts
Answer:
C
Explanation:
The uncertainty will carry the unit of time because it's the time in itself that has error, and not the distance, nor the velocity.
Had it been the uncertainty was to the velocity, then we would say both the unit of the distance and that of the time would have been affected. But as it stands, only that of time will be affected.
When a student shines a 540 nm laser through this grating, how many bright spots could be seen on a screen behind the grating?
Complete Question
A commercial diffraction grating has 600 lines per mm.
When a student shines a 540 nm laser through this grating, how many bright spots could be seen on a screen behind the grating?
Answer:
The number of bright spots is [tex]m = 7[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 540 nm = 540 *10^{-9} \ m[/tex]
The number of lines per length the commercial diffraction grating has is [tex]L = 600 \ lines / mm = 600 * 1000 \ lines / m = 600 *10^{3} \ lines / m[/tex]
Generally the condition for constructive interference is mathematically represented as
[tex]dsin(\theta) = n\lambda[/tex]
Here d is the separation between the gratings which is mathematically represented as
[tex]d=\frac{1}{L}[/tex]
=> [tex]d=\frac{1}{600 *10^{3}}[/tex]
=> [tex]d= 1.67 *10^{-6 } \ m[/tex]
and n is the order of bright fringe, the maximum number is seen when [tex]\theta = 90^o[/tex]
So
[tex]1.67 *10^{-6}sin(90) = n * 540 *10^{-9 }[/tex]
=> [tex]n = 3[/tex]
Generally the number of bright spot (considering central bright fringe and the same order of bright fringe on each side of the central bright fringe) is mathematically represented as
[tex]m = n * 2 + 1[/tex]
=> [tex]m = 3 * 2 + 1[/tex]
=> [tex]m = 7[/tex]
Which of the following is an example of Newton’s second law of motion?
A.....Catie’s skateboard hits a curb and she falls forward onto the grass.
B.....a tissue and a rock are dropped from a ladder. The rock exerts a greater force when it hits the ground.
C.....a person stands on a chair and pushes down, and the chair pushes upwards on
the person.
D......Tires from a bike push against the road, and the road pushes back.
Answer:
B
Explanation:
Newton’s Second Law of Motion
Newton’s Second Law of Motion states that ‘when an object is acted on by an outside force, the mass of the object equals the strength of the force times the resulting acceleration’.
This can be demonstrated dropping a rock or and tissue at the same time from a ladder. They fall at an equal rate—their acceleration is constant due to the force of gravity acting on them.
The rock's impact will be a much greater force when it hits the ground, because of its greater mass. If you drop the two objects into a dish of water, you can see how different the force of impact for each object was, based on the splash made in the water by each one.
Answer:
b
Explanation:
A 72.0-kg person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface of the door. The doorknob is located 0.800 m from axis of the frictionless hinges of the door. The door begins to rotate with an angular acceleration of 2.00 rad/s2, What is the moment of inertia of the door about the hinges? A) 2.74 kg m2 B) 1.88 kg m2 C) 0.684 kg m2 D) 4.28 kg m2 E) 7.52 kg m2
Answer:
[tex]I=2\ kgm^2[/tex]
Explanation:
Given that,
Mass of a person, m = 72 kg
Force acting on a doorknob, F = 5 N
The doorknob is located 0.800 m from axis of the frictionless hinges of the door.
The angular acceleration of the dor, a = 2 rad/s²
We need to find the moment of inertia of the door about the hinges.
The person applies a torque to the door and it is given by :
[tex]\tau=Fr[/tex] ...(1)
Also, the torque is equal to :
[tex]\tau=I\alpha[/tex] ...(2)
From equation (1) and (2) we get :
[tex]Fr=I\alpha[/tex]
I is the moment of inertia
[tex]I=\dfrac{Fr}{\alpha }\\\\I=\dfrac{5\times 0.8}{2}\\\\=2\ kgm^2[/tex]
So, the moment of inertia of the door about the hinges is [tex]2\ kgm^2[/tex].
A child swings a sling with a rock of mass 1.3 kg, in a radius of 0.6. From rest to an angular velocity of 6 rad/s. What is the rotational kinetic energy of the rock?
Answer:
8.42Joules
Explanation:
The rotational kinetic energy, denoted by E(rotational), can be calculated using the formula:
E(rotational) = 1/2 × I × ω²
Where;
I = moment of inertia (kgm²)
ω = angular velocity (rad/s)
However, we need to calculate the moment of inertia in this question by using the formula:
I = m × r²
Where;
m = mass (1.3kg)
r = radius (0.6m)
I = 1.3 × 0.6²
I = 1.3 × 0.36
I = 0.468 kgm²
Since I = 0.468 kgm², ω = 6 rad/s, we can calculate rational kinetic energy using:
K.E(rotational) = 1/2 × I × ω²
K.E(rotational) = 1/2 × 0.468 × 6²
K.E(rotational) =1/2 × 0.468 × 36
K.E(rotational) = 18 × 0.468
K.E(rotational) = 8.424
K.E(rotational) = 8.42Joules
The second floor of a house is 6 m above the street level. How much work is required to lift a 300-kg refrigerator to the second-story level?
Answer:
Work done, W = 18 kJ
Explanation:
Given that,
The mass of a refrigerator, m = 300 kg
The second floor of a house is 6 m above the street level.
We need to find the work required to lift the refrigerator to the second-story level.
Work done, W = F × d
Putting all the values,
W = 300 × 10 × 6
W = 18000 J
or
W = 18 kJ
So, 18 kJ of work is done in lifting the refrigerator to the second-story level.
How is energy that is stored in food released?
A- atoms increase in movement
B- atoms are split
C- heat is released
D-chemical bonds in fats are proteins are broken
Answer:
i think its A
Explanation:
Answer:
D
Explanation:
The chemical energy stored in food is released by cells through the process of respiration. (cellular respiration)
This stored energy is released whenever these chemical bonds are broken in metabolic processes such as cellular respiration. Cellular respiration is the process by which the chemical energy of “food” molecules is released and partially captured in the form of ATP.
Guys I really need help here
a) Find the energy needed
to to heat a tank holding water of 60 kg to rise the temperature from 10 degree Celsius to 60 degree Celsius (c=4200
J/K°C)
b)find the time for rising this much temperature if the power of heater is 3KW
Answer:
c
Explanation:
what tells you the strength of a wave?
how was the theory of plate tectonics developed?
Answer:
Plate tectonic theory began in 1915, when Alfred Wegener developed his "continental drift" idea. Wegener believed that continents plowed through ocean basin crust, explaining why many coasts (such as those in South America and Africa) appear to fit together like a puzzle.
A car traveling 13 m/s to the north collides with a car traveling 19 m/s to the
south. Each car has a mass of 1250 kg. If the system is defined as the two
cars, what is the change in momentum of the system due to the collision?
A. 0 kg*m/s
B. 40,000 kg*m/s
O c. 16,250 kg-m/s
D. 23,750 kg-m/s
Answer: 0kg(m/s)
Explanation:
A metallic laboratory spring is typically 5.50cm long and 0.140 cm in diameter and has 50.0 coils. If you connect such a spring in an electric circuit, how much self-inductance must you include for it if you model it as an ideal solenoid?
L = ________?
Answer:
um hm err
Explanation:
What is the final speed of a free electron accelerated from rest through a potential difference of -120 V? The mass of the electron is 9.11x10-31kg. You need to express the speed in km/s.
You should round your answer to an integer, indicate only the number, do not include the unit.
Answer:
The final speed of the electron is 6,497 km/s
Explanation:
Given;
mass of the electron, m = 9.11 x 10⁻³¹ kg
electron potential, V = -120 V
Apply work energy theorem;
¹/₂mv² = eV
Where;
v is the final speed of the electron
e is the charge of the electron, = 1.602 x 10⁻¹⁹ C
[tex]v = \sqrt{\frac{2eV}{m} }\\\\v = \sqrt{\frac{2(1.602*10^{-19})(120)}{9.11*10^{-31}} }\\\\v = 6496473.75 \ m/s\\\\v = 6,497 \ km/s[/tex]
Therefore, the final speed of the electron is 6,497 km/s
What total distance did this student travel?
Seems like some of your question is missin
Explanation:
On a smooth horizontal floor, an object slides into a spring which is attached to another mass that is initially stationary. When the spring is most compressed, both objects are moving at the same speed. Ignoring friction, and considering the two masses and spring as a system, what is conserved during this interaction?A) momentum and potential energyB) kinetic energy onlyC) momentum and kinetic energyD) momentum onlyE) momentum and mechanical energy
Answer:
E) momentum and mechanical energy
Explanation:
In the context, an object is attached to the another mass with a spring which is initially at a rest position. Now when the spring is compressed, the two masses moves with the same speed. Now since the both the masses combines with the spring to move together they are considered as one system and in this case the momentum and the kinetic energy will be conserved.
The kinetic energy and momentum of the system after collision and the kinetic energy and momentum of the two masses before collision will be constant.
At standard temperature and pressure, carbon dioxide has a density of 1.98 kg/m3. What volume does 1.70 kg of carbon dioxide occupy at standard temperature and pressure?
Answer:
volume= 0.85m^3Explanation:
The density of a substance is defined as the mass per unit volume of the substance, the unit is in kg/m^3 and it is represented by the greek letter rho
Step one:
given data
we are told that the density of Co2= 1.98 kg/m3
and the mass of Co2 is= 1.70 kg
we know the relation between mass, volume and density is
[tex]density=mass/volume[/tex]
make volume subject of formula we have
[tex]volume=mass/density[/tex]
substitute we have
[tex]volume=1.7/1.98\\\\volume= 0.85m^3[/tex]
a. An object weighs 7.84 N when it is in air and 6.86 N when it is immersed in water. What is the specific gravity of the object?
b. How much pressure does it take for a pump to supply a drinking fountainwith 300 kPa, if the fountain is 30.0 m above the pump?
Answer:
a
[tex]W_s = 8[/tex]
b
[tex]P = 594 000 \ Pa[/tex]
Explanation:
Considering question a
From the question we are told that
The weight of the object in air is [tex]W_1 = 7.84 \ N[/tex]
The weight of the object in water is [tex]W_2 = 6.86\ N[/tex]
Generally the specific gravity of the object is mathematically represented as
[tex]W_s = \frac{W_1 }{W_1 - W_2 }[/tex]
=> [tex]W_s = \frac{7.84}{7.84 -6.86 }[/tex]
=> [tex]W_s = 8[/tex]
Considering question b
From the question we are told that
The pressure required is [tex]P_r = 300 \ kPa = 300 *10^{3} \ Pa[/tex]
The height is [tex]h = 30.0 \ m[/tex]
Generally the pressure require to get the water to the given height is mathematically represented as
[tex]P_h = \rho * g * h[/tex]
Here [tex]\rho[/tex] is the density of water with value [tex]\rho = 1000 \ kg / m^3[/tex]
So
[tex]P_h = 1000 * 9.8 * 30[/tex]
=> [tex]P_h = 294000 \ Pa[/tex]
Generally the pressure require to pump the water to the given height at the require pressure is mathematically represented as
[tex]P = P_h + P_r[/tex]
=> [tex]P = 294000 + 300*10^{3}[/tex]
=> [tex]P = 594 000 \ Pa[/tex]
A vector B , with a magnitude of 8.0 m, is added to a vector A , which lies along an x axis. The sum of these two vectors is a third vector that lies along the y axis and has a magnitude that is twice the magnitude of A . What is the magnitude of A?
Answer:
the magnitude of A is 3.577
Explanation:
According to the question it is given that there is a magnitude of 8.0 m that added to the vector A that lies on x axis also the sum of two vectors would be third vector by considering the y axis and the magnitude is the twice of the magnitude B
The computation of the magnitude of A is shown below:
[tex]A \hat{i} + B = 2A \hat{j}\\\\A \hat{i} + 8 = 2A \hat{j}\\\\8 = 2A \hat{j} - A \hat{i}\\\\\mid8\mid = \sqrt{(2A \hat{j})^2 + (- A \hat{i})^2} \\\\8 = \sqrt{5A} \\\\A = \frac{8}{\sqrt{5} }[/tex]
A = 3.577
Hence, the magnitude of A is 3.577