Let A and B be two matrices of size 4 x 4 such that det(A)= 1. If B is a singular matrix then det(3A-2B7) +1 = Oo 1 None of the mentioned O -1 O 2

Answer

6 and 2/3 percent of an hour OR 6.666.... hour

I don’t know if you have to round or not but if it does just round

Step-by-step explanation:

Well 4 minutes of an hour is basically 4/60

4/60=1/15

1/15=x/100

solve the proportion by cross multiplying

100=15x

x=6.66666666

That is yoru percent

Answer:

48 is the answer

Step-by-step explanation:

9*4 +. 6*2

36 + 12

48

Answer:

a = 15

t = 5

Step-by-step explanation:

[tex] \frac{12}{a} = \frac{16}{20} \\ \\ 16a = 12 \times 20 \\ \\16 a = 240 \\ \\ a = \frac{240}{16} \\ \\ a = 15 \\ \\ \\ \frac{2}{8} = \frac{t}{20} \\ \\ 8t = 40 \\ \\ t = \frac{40}{8} \\ \\ t = 5[/tex]

Answer:

Step-by-step explanation:

1. Write the equation.

y = -2x

y = 5x - 21

2. Substitute the values.

(-2x) = 5x - 21

3. Solve the equation.

-2x = 5x - 21

-5x    - 5x

-7x = -21

4. Both negatives cancel

7x = 21

5. Divide both sides by 7

7x = 21

/7      /7

6. x = 3

7. Check the answer.

-2(3) = 5(3) - 21

-6 = 15 - 21

-6 = -6

Hope this helped,

Kavitha

P.S Sorry for taking so long.

Answer:

Step-by-step explanation:

By triangle sum theorem,

Sum of all angles of a triangle is 180°.

m∠1 + m∠2 + m∠3 = 180°

(m∠1 + m∠3) + m∠2 = 180°

2(m∠1) + 70° = 180° {Given → m∠1 = m∠3]

2(m∠1) = 110°

m∠1 = 55°

Therefore, m∠1 = m∠3 = 55°

Answer:

1) 1.2 minutes

2) 8.3 laps

3) 25.2 minutes

Answer:

[tex]1\frac{1}{3}[/tex]

Step-by-step explanation:

Answer:

____________________________________________________________

   Why?

Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. A trapezoid can never be a parallelogram. The correct answer is that all trapezoids are quadrilaterals.

____________________________________________________________    

   What's a  parallelogram?                                                                                      

 Its a four-sided plane rectilinear figure with opposite sides parallel.

____________________________________________________________

Please don't be afraid to point out errors :)  

____________________________________________________________

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The correct shape which is not a parallelogram is shown in Option D.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

There are four shapes are shown.

Now, We know that;

In a parallelogram, there are two pair of parallel lines.

But In option D;

There are only one pair of parallel lines.

Hence, The correct shape which is not a parallelogram is shown in Option D.

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According to the information, we can infer that no, they cannot raise their cumulative average to 2.3 after completing 15 fall semester credits. On the other hand, they would need an average GPA of 3.25 for their two junior year semesters combined (30 credits) to achieve their goal of a 2.3 cumulative GPA and 90 credits.

In order to calculate the new cumulative GPA, we need to consider both the current cumulative GPA and the GPA earned in the fall semester. Since the student's current cumulative GPA is 2.0 and they have already accumulated 60 credits, their total grade points earned so far would be 2.0 multiplied by 60, which equals 120 grade points.

To raise the cumulative GPA to 2.3, the student would need a total of 2.3 multiplied by (60 + 15) = 2.3 multiplied by 75 = 172.5 grade points by the end of the fall semester.

Since the student has already accumulated 120 grade points, they would need to earn an additional 52.5 grade points in the fall semester. To calculate the required semester GPA, we divide 52.5 by 15 credits, which gives us a required semester GPA of 3.5.

So, the student would need a semester GPA of 3.5 in order to raise their cumulative average to 2.3 after completing 15 fall semester credits.

They would need an average GPA of 3.25 for their two junior year semesters combined (30 credits) to achieve their goal of a 2.3 cumulative GPA and 90 credits.

Explanation: To calculate the average GPA for the two junior year semesters, we need to consider the total grade points earned and the total number of credits taken.

Currently, the student has accumulated 60 credits and 120 grade points. In order to achieve a cumulative GPA of 2.3 after completing 90 credits, they would need a total of 2.3 multiplied by 90 = 207 grade points.

To calculate the required grade points for the two junior year semesters, we subtract the current grade points (120) from the desired total grade points (207), which gives us 207 - 120 = 87 grade points needed for the junior year.

Since the student plans to take 30 credits during their junior year, they would need to earn 87 grade points in those 30 credits. Dividing 87 by 30 gives us an average GPA of approximately 2.9 for the two junior year semesters.

According to the above, the student would need an average GPA of 3.25 (rounded up) for their two junior year semesters combined to achieve their goal of a 2.3 cumulative GPA and 90 credits.

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Answer:

3:1 (Girls:Boys)

6 divided by 2

The velocity of the Pacific plate, expressed in centimeters per year (cm/yr), can be determined from the slope of the best-fit line in a geologic study.

In a geologic study, if data points representing the position of the Pacific plate are collected over a period of time, a best-fit line can be calculated to represent the trend of plate movement.

- The slope of this line represents the rate of change of position over time, which corresponds to the velocity of the plate. By examining the slope of the best-fit line and converting it to centimeters per year, we can determine the velocity at which the Pacific plate is moving.

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Answer:

3:2

Step-by-step explanation:

a square has the same side lengths so just √36 = 6 to find the sides of the squares then compare the two sides in ratio form 6:4 then reduce

Answer:

52

Step-by-step explanation:

Using the Pythagorean theorem

a^2+b^2 = c^2

20^2 + 48^2 = c^2

400 +2304=c^2

2704=c^2

Taking the square root of each side

sqrt(2704) = sqrt(c^2)

52 = c

Answer:

[tex]hypotenuse^{2}[/tex] = [tex]altitude^{2}[/tex] + [tex]base^{2}[/tex]

[tex]hyp^{2}[/tex] = [tex]48^{2}[/tex] + [tex]20^{2}[/tex]

       = 2304 + 400

       = 2704

∴[tex]hyp[/tex] = [tex]\sqrt{2704}[/tex]

       = 52

hope this answer helps you....

Answer:

If you just solve normally, you will get x=2 and x=-3. But if you plug these in to check your work, you will find that they are wrong. Your answer is no solution

Step-by-step explanation:

ln(2x+3)+ln(x-2)=ln(x^2-2x)

Rule: log(a) + log(b) = log(a*b)

ln( (2x+3)(x-2) ) = ln(x^2-2x)

Rule: If log(a) = log(b) then a = b

(2x+3)(x-2) = x^2 - 2x

2x^2-x-6=x^2-2x

x^2+x-6=0

Using Quadratic Formula:

x = 2 and x = -3

But, plugging these numbers back into the original equation is false!

The 98% confidence interval for the distribution of differences is given as follows:

(-2.58%, 5.78%).

The difference of the sample means is given as follows:

6.6 - 5 = 1.6%.

The standard error for each sample is given as follows:

The standard error for the distribution of differences is then given as follows:

[tex]s = \sqrt{0.53^2 + 1.64^2}[/tex]

s = 1.72.

The critical value, using a t-distribution calculator, for a two-tailed 98% confidence interval, with 19 + 22 - 2 = 39 df, is t = 2.4286.

The lower bound of the interval is given as follows:

1.6 - 2.4286 x 1.72 = -2.58%.

The upper bound of the interval is given as follows:

1.6 + 2.4286 x 1.72 = 5.78%.

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Answer:

80 tsp.

Step-by-step explanation:

400 divided by 5 is 80, so 80 tsp's.

Answer:

80 tsp.

Step-by-step explanation:

400 mL = 80 tsp

A lamina occupies the region of a disk in the first quadrant where 2 ≤ r ≤ 16, and the density at each point is given by the function ρ(r, θ) = 3[tex](r^2).[/tex] Further analysis is required to determine the mass and other properties of the lamina.

The given information describes a lamina occupying a region in the first quadrant of a disk. The radial distance from the origin is limited to the range 2 ≤ r ≤ 16. The density of the lamina at any point within this region is determined by the function ρ(r, θ) = 3[tex](r^2)[/tex], where r represents the radial distance and θ represents the angle in the polar coordinate system.

To fully analyze the lamina, additional calculations are necessary. One important calculation is determining the mass of the lamina, which involves integrating the density function over the given region. By integrating the function ρ(r, θ) = 3[tex](r^2)[/tex] over the appropriate range of r and θ, we can find the total mass of the lamina. Additionally, other properties such as the center of mass or moment of inertia of the lamina could be determined by using appropriate formulas and integration techniques.

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Answer:

c is the only one that would result in an integer

Step-by-step explanation:

i hope this helps :)

Option c ∛ 27 would result in an integer.

An integer is the number zero, a positive natural number or a negative integer with a minus sign. The negative numbers are the additive inverses of the corresponding positive numbers.

Given here, ∛27= 3 while the other options ∛60 is not an integer because 60 is not  cubic number similarly for 9 , 18 are not cubic numbers and thus their subsequent cubic roots will not yield an integer.

Hence, Option c ∛ 27 would result in an integer.

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Answer:

5x+4y-40=0

Step-by-step explanation:

A = $4,312.00

I = A - P = $2,112.00

hey!

Equation:

A = P(1 + rt)

Calculation:

First, converting R percent to r a decimal

r = R/100 = 8%/100 = 0.08 per year.

Solving our equation:

A = 2200(1 + (0.08 × 12)) = 4312

A = $4,312.00

The total amount accrued, principal plus interest, from simple interest on a principal of $2,200.00 at a rate of 8% per year for 12 years is $4,312.00.

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have a good day! hope i helped in some way

Answer:

x=6 and x=-2

Step-by-step explanation:

so

x(x-4)=12

first distribute

then move the terms

and the u get

x=6 and x=-2

hope this helped

Answer:

x=6, x=-2

Step-by-step explanation:

x(x-4)=12

distributive property, x^2-4x=12

x^2-4x-12=0

(x-6)(x+2)

therefore, x=6, x=-2

Answer:

Each cereal bar weighs 16.8 oz

Step-by-step explanation:

Multiply 12 times 1.4 to get 16.8

Add 16.8 and 1.75 to get 18.55

Hope this helps! Pls mark brainliest

The solution to the system of differential equations is x₁(t) = e⁻⁵ˣ + 3e³ˣ and x₂(t) = 2e⁻⁵ˣ + 5e³ˣ

Let's solve the given system of differential equations: x₁' = -5x₁ + 0x₂ ...(1) x₂' = -16x₁ + 3x₂ ...(2)

To solve this system, we can rewrite it in matrix form. Let's define the vector X = [x₁, x₂] and the matrix A as:

A = [[-5, 0], [-16, 3]]

The system can then be written as X' = AX, where X' is the derivative of X with respect to time.

Now, let's find the eigenvalues and eigenvectors of matrix A. The eigenvalues are obtained by solving the characteristic equation det(A - λI) = 0, where I is the identity matrix.

A - λI = [[-5 - λ, 0], [-16, 3 - λ]]

det(A - λI) = (-5 - λ)(3 - λ) - 0(-16) = λ² + 2λ - 15 = (λ + 5)(λ - 3)

Setting the characteristic equation equal to zero, we find the eigenvalues: λ₁ = -5 λ₂ = 3

To find the corresponding eigenvectors, we substitute each eigenvalue back into the matrix A - λI and solve the system of equations (A - λI)v = 0, where v is the eigenvector.

For λ₁ = -5: A - (-5)I = [[0, 0], [-16, 8]]

Using Gaussian elimination, we can solve the system of equations to find the eigenvector corresponding to λ₁: -16v₁ + 8v₂ = 0 => -2v₁ + v₂ = 0 => v₁ = (1/2)v₂

Let v₂ = 2, then v₁ = 1. Therefore, the eigenvector corresponding to λ₁ is v₁ = [1, 2].

For λ₂ = 3: A - 3I = [[-8, 0], [-16, 0]]

Solving the system of equations, we find: -8v₁ = 0 => v₁ = 0

Thus, the eigenvector corresponding to λ₂ is v₂ = [0, 1].

Now, let's express the solution of the system in terms of the eigenvalues and eigenvectors.

X(t) = c₁e(λ₁t)v₁ + c₂e(λ₂t)v₂

Substituting the eigenvalues and eigenvectors we found earlier, we have: X(t) = c₁e⁻⁵ˣ[1, 2] + c₂e³ˣ[0, 1]

Using the initial conditions, x₁(0) = 1 and x₂(0) = 5, we can find the values of c₁ and c₂.

At t = 0: [1, 5] = c₁[1, 2] + c₂[0, 1] 1 = c₁ 5 = 2c₁ + c₂

Solving these equations, we find: c₁ = 1 c₂ = 3

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Complete Question:

Solve the system of differential equations

x₁' = – 5x₁ + 0x₂

x₂' = – 16x₁ + 3x₂

x₁(0) = 1, x₂(0) = 5

Let λ be an eigen value of an invertible matrix. Then, [tex]\lambda^{-1}[/tex] is surely an eigenvalue of [tex]A^{-1}[/tex].

What is an invertible matrix?

For a matrix to be invertible, it must have a unique matrix that, when multiplied with the original matrix, gives the identity matrix.

[tex]A * B = B * A = I[/tex]

Suppose A is an invertible matrix and λ is an eigenvalue of A with a corresponding nonzero eigenvector x, i.e., Ax = λx.

To show that [tex]\lambda^{-1}[/tex] is an eigenvalue of [tex]A^{-1}[/tex], we need to find a nonzero vector y such that [tex]A^{-1}y[/tex] = [tex]\lambda^{-1}y[/tex].

Let's start by multiplying both sides of the equation Ax = λx by [tex]A^{-1}[/tex]:

[tex]A^{-1}(Ax) = A^{-1}(\lambda x)[/tex]

(x is nonzero, so we can divide by x)

[tex]A^{-1}(Ax/x) = A^{-1}(\lambda x/x)\\A^{-1}(A(x/x)) = A^{-1}(\lambda)[/tex]    

Since [tex]A^{(-1)}A = I[/tex] (identity matrix), and x/x = 1, we have:

[tex]A^{(-1}(I) = A^{(-1)}[/tex] λ

[tex]A^{(-1)}[/tex] = λ[tex]A^{(-1)}[/tex]

Now, let y = A^(-1)x. We can rewrite the equation above as:

[tex]A^{(-1)}x[/tex] = λ[tex]A^{(-1)}y[/tex]

([tex]A^{(-1)}x[/tex]/λ) = [tex]A^{(-1)}y[/tex]/λ

(x is nonzero, so we can divide by x)

([tex]A^{(-1)}x/x[/tex])/λ = [tex](A^{(-1)}y/y[/tex])/λ

([tex]A^{(-1)}(x/x)[/tex])/λ = ([tex]A^{(-1)}y/y[/tex])/λ

([tex]A^{(-1)}(1)[/tex])/λ = ([tex]A^{(-1)}y/y[/tex])/λ

([tex]A^{(-1)}[/tex])/λ = ([tex]A^{(-1)}y[/tex])/λ

Since [tex]A^{(-1)}[/tex] is a matrix and λ is a scalar, we can rearrange the equation as follows:

([tex]A^{(-1)}[/tex])/λ = [tex]A^{(-1)}[/tex]y/λ

(1/λ)[tex]A^{(-1)}[/tex] =[tex]A^{(-1)}[/tex]y/λ

This shows that 1/λ is an eigenvalue of [tex]A^{(-1)}[/tex] with the corresponding eigenvector y. Therefore, we have shown that if λ is an eigenvalue of A, then [tex]\lambda^{(-1)}[/tex] is an eigenvalue of [tex]A^{(-1)}[/tex]

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Answer:

3

Step-by-step explanation:

dude kinda obv that its 3

Answer:

answer would be 3

Step-by-step explanation:

Answer:

47

Step-by-step explanation:

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