List the location in order from lear to greatest pressure

Answer:

61 degrees, I just did the test.

Explanation:

Answer: 61 degrees

Explanation:

I just did the question and got it right

Answer:

T' = o.707T

Explanation:

[tex]T = 1/2\pi \sqrt{k/m} \\\\m'=2m then\\T' = 1/2\pi \sqrt{k/m'}\\ = 1/2\pi \sqrt{k/2m}\\T' = \frac{(1/2\pi \sqrt{k/m}\\)}{1.4} T' = \frac{T}{1.4}\\T' = 0.707T[/tex]

Answer:

45.9m

Explanation:

Given parameters:

Final velocity  = 30m/s

Initial velocity  = 0m/s

Unknown:

Height of fall  = ?

Solution:

  The motion equation to solve this problem is given below;

            V² = U² + 2gH

            V²  = 0 + (2 x 9.8 x H)

           30²  = 19.6H

              H = [tex]\frac{900}{19.6}[/tex]   = 45.9m

Answer:

The distance traveled by the particle before it stops is 41.06 m.

Explanation:

We can find the distance traveled by the particle using the following equation:

[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]

Where:

[tex] v_{f}[/tex]: is the final velocity = 0 (when it stops)

[tex] v_{0}[/tex]: is the initial velocity = 30 m/s

a: is the acceleration = -4t m/s²

t: is the time

d: is the distance

First, we need to calculate the time:

[tex] v_{f} = v_{0} + at [/tex]

[tex] 0 = 30 m/s + (-4t m/s^{2})t [/tex]

[tex]0 = 30 m/s - 4t^{2} m/s^{3}[/tex]    

[tex]t = 2.74 s[/tex]

Now, the acceleration is:

[tex] a = -4t = -10.96 m/s^{2} [/tex]                    

Hence, the distance is:          

[tex] d = \frac{v_{f}^{2} - v_{0}^{2}}{2a} = \frac{-(30 m/s)^{2}}{2*(-10.96 m/s^{2})} = 41.06 m [/tex]      

Therefore, the distance traveled by the particle before it stops is 41.06 m.

I hope it helps you!                                                          

Answer:

(B)  1.23 x 10⁴ J

Explanation:

Given;

radius of the sphere, r = 7.0 m

diameter of the sphere, d = 2r = 14.0 m

mass of the person sitting on the sphere, m = 90.0 kg

The gravitational potential energy of the person is given by;

P.E = mgh

where;

g is acceleration due to gravity = 9.8 m/s²

h is the height above the ground level = d = 14.0 m

P.E = mgh

P.E = (90)(9.8)(14)

P.E = 12348 J

P.E = 1.2348 x 10⁴ J

Therefore, the gravitational potential energy of the person is 1.2348 x 10⁴ J

Answer:

what i and confused

Explanation:

Answer:

nerd

Explanation:

I H4+3 U

Answer:

Explanation:

a ) The angle required = angle of repose = θ

Tanθ = .81

θ = 39⁰

b ) when angle of incline θ = 44

Net force on the block = mg sinθ - μ mg cosθ where μ is coefficient of kinetic friction

acceleration = gsinθ - μ g cosθ

= 9.8 ( sin44 - μ cos44 )

= 9.8 ( .695 - .69 x .72 )

= 9.8 ( .695 - .497 )

= 1.94 m /s²

Answer:

i think its d

Explanation:

i took this quiz and got 100 percent

Answer:

This question appear incomplete

Explanation:

This question appear incomplete. However, when capacitors are connected in series, the total capacitance is usually less than the capacitance of individual capacitor. This is because the total capacitance can be calculated as 1 ÷ 1/C₁ + 1/C₂ +1/C₃...

The formula above does not refer to the charge; this is because capacitors connected in series have the same charge (regardless of the capacitance). Also, the largest potential difference occur in the capacitor with the smallest/lowest capacitance.

Answer:

2 m/s

Explanation:

The total time = 1 hour

The vertical displacement = 1 - 1

Vertical displacement = 0

Horizontal displacement = 4 - 2

Horizontal displacement = 2

Total displacement = sqrt (2^2 - 0^2)

Displacement - 2

Average velocity is displacement/time

= 2x1

=  2 m/s

The average velocity is 2 metres per second.

Answer:

a= v/t

a = 4/2

a = 2 m/s^2

And F = M a

F = 10 × 2

F = 20 N

Answer:

v = 2.45 m/s

Explanation:

first we find the time taken during this motion by considering the vertical motion only and applying second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height of cliff = 15 m

Vi = Initial Vertical Velocity = 0 m/s

t = time taken = ?

g = 9.8 m/s²

Therefore,

15 m = (0 m/s) t + (1/2)(9.8 m/s²)t²

t² = (15 m)/(4.9 m/s²)

t = √3.06 s²

t = 1.75 s

Now, we consider the horizontal motion. Since, we neglect air friction effects. Therefore, the horizontal motion has uniform velocity. Therefore,

s = vt

where,

s = horizontal distance covered = 4.3 m

v = original horizontal velocity = ?

Therefore,

4.3 m = v(1.75 s)

v = 4.3 m/1.75 s

v = 2.45 m/s

Answer:

Yes

Explanation:

Answer:

Explanation:

Remember that all solids, liquids, and gases are made up of atoms, molecules, and / or ions. ( Also remember that the answer "maybe" most likely won't be the answer in most quizzes. )

Which answers your question, gases are made up of particles.

Hope this helps! <3

Answer:

E.

Explanation:

In a galvanic cell, electrons flow from the anothe to the cathode.

I hope you got the answer

Answer:

pretty sure its kinetic

Explanation:

Answer:

Kinetic

Explanation:

The stored chemical potential energy of a battery converts to electrical kinetic energy to transport electricity to a light bulb, which radiates thermal kinetic energy.

Answer:

W = 3934 N ,     m = 401.43 kg

Explanation:

This problem can be solved using the rotational equilibrium relation, where we place the reference system at the pivot point and assume that the counterclockwise turns are positive.

     ∑τ = 0

     F 7 - W 1 = 0

    W = F 7/1

     W = 562 7

     W = 3934 N

W = mg

     m = W / g

     m = 3934 / 9.8

     m = 401.43 kg

Answer:

If a player is fouled while shooting a three-point shot and makes it anyway, he is awarded one free throw. Thus, he could score four points on the play. Inbounds- If fouled while not shooting, the ball is given to the team the foul was committed upon.

Explanation:

Niels Bohr improved Rutherford's model. Using mathematical ideas, he showed that electrons occupy shells or energy levels around the nucleus. The Dalton model has changed over time because of the discovery of subatomic particles .

Explanation:

We need to find the index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum.

The wavelength in any medium is given by :

[tex]\lambda_m=\dfrac{\lambda}{n}[/tex]

Where, [tex]\lambda[/tex] is wavelength in vacuum and n is refractive index of the medium.

[tex]n=\dfrac{\lambda}{\lambda_m}\\\\n=\dfrac{\lambda}{0.671\lambda}\\\\=\dfrac{1}{0.671}\\\\=1.49[/tex]

So, the medium can be PMMA (acrylic, plexiglas, lucite, perspex) which have a refractive index of 1.49.

The index of refraction of the material for which the wavelength of light is 0.671 times, the value of it in a vacuum is 1.49.

The index of refraction of a material is the ratio of wavelength of the wave in vacuum to the wavelength of the wave in the given medium.

The index of refraction is inversely proportional to the wavelength. It can be find out using the following formula.

[tex]n=\dfrac{\lambda}{\lambda_m}[/tex]

Here, (λ) is the wavelength in vacuum and (λm) is the wavelength in a medium.

The index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum (0.671×λ).

Plug in the values in the above formula,

[tex]n=\dfrac{\lambda}{0.671\times\lambda}\\n=1.49[/tex]

Thus, the index of refraction of the material for which the wavelength of light is 0.671 times, the value of it in a vacuum is 1.49.

Learn more about the index of refraction here;

https://brainly.com/question/10729741

Answer:

20.8 ft³

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 80 psi

Initial volume (V1) = 13 ft³

Final pressure (P2) = 50 psi

Final volume (V2) =?

The new volume of the gas can be obtained by using the Boyle's law equation as shown below:

P1V1 = P2V2

80 × 13 = 50 × V2

1040 = 50 × V2

Divide both side by 50

V2 = 1040 / 50

V2 = 20.8 ft³

Thus, the volume of the gas at a pressure of 50 psi is 20.8 ft³

Answer:

total sum of all numbers/ number of items in the set

Explanation:

Answer: Calendar

Explanation: I'm pretty sure it is calendar.

Answer:

The correct option is  D

Explanation:

From the question we are told that

  The maximum electric field strength is  [tex]E = 1.0 *10^{11} \ V/m[/tex]

   The  area is  [tex]A = 5.0 \ mm^2 = 5.0 *10^{-6} \ m^2[/tex]

Generally the force the laser applies is mathematically represented as

       [tex]F = \epsilon_o * E ^2 * A[/tex]

Here  [tex]\epsilon_o = 8.85*10^{-12} C/(V \cdot m)[/tex]

      [tex]F = 8.85*10^{-12} * (1.0 *10^{11}) ^2 * 5.00*10^{-6 }[/tex]

=>   [tex]F = 4.43 *10^{5} \ N[/tex]

Answer:

Speed of the spacecraft right before the collision: [tex]\displaystyle \sqrt{\frac{2\, G\cdot M_\text{e}}{R\text{e}}}[/tex].

Assumption: the earth is exactly spherical with a uniform density.

Explanation:

This question could be solved using the conservation of energy.

The mechanical energy of this spacecraft is the sum of:

Let [tex]m[/tex] denote the mass of this spacecraft. At a distance of [tex]R[/tex] from the center of the earth (with mass [tex]M_\text{e}[/tex]), the gravitational potential energy ([tex]\mathrm{GPE}[/tex]) of this spacecraft would be:

[tex]\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R}[/tex].

Initially, [tex]R[/tex] (the denominator of this fraction) is infinitely large. Therefore, the initial value of [tex]\mathrm{GPE}[/tex] will be infinitely close to zero.

On the other hand, the question states that the initial kinetic energy ([tex]\rm KE[/tex]) of this spacecraft is also zero. Therefore, the initial mechanical energy of this spacecraft would be zero.

Right before the collision, the spacecraft would be very close to the surface of the earth. The distance [tex]R[/tex] between the spacecraft and the center of the earth would be approximately equal to [tex]R_\text{e}[/tex], the radius of the earth.

The [tex]\mathrm{GPE}[/tex] of the spacecraft at that moment would be:

[tex]\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}[/tex].

Subtract this value from zero to find the loss in the [tex]\rm GPE[/tex] of this spacecraft:

[tex]\begin{aligned}\text{GPE change} &= \text{Initial GPE} - \text{Final GPE} \\ &= 0 - \left(-\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\right) = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \end{aligned}[/tex]

Assume that gravitational pull is the only force on the spacecraft. The size of the loss in the [tex]\rm GPE[/tex] of this spacecraft would be equal to the size of the gain in its [tex]\rm KE[/tex].

Therefore, right before collision, the [tex]\rm KE[/tex] of this spacecraft would be:

[tex]\begin{aligned}& \text{Initial KE} + \text{KE change} \\ &= \text{Initial KE} + (-\text{GPE change}) \\ &= 0 + \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \\ &= \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\end{aligned}[/tex].

On the other hand, let [tex]v[/tex] denote the speed of this spacecraft. The following equation that relates [tex]v\![/tex] and [tex]m[/tex] to [tex]\rm KE[/tex]:

[tex]\displaystyle \text{KE} = \frac{1}{2}\, m \cdot v^2[/tex].

Rearrange this equation to find an equation for [tex]v[/tex]:

[tex]\displaystyle v = \sqrt{\frac{2\, \text{KE}}{m}}[/tex].

It is already found that right before the collision, [tex]\displaystyle \text{KE} = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}[/tex]. Make use of this equation to find [tex]v[/tex] at that moment:

[tex]\begin{aligned}v &= \sqrt{\frac{2\, \text{KE}}{m}} \\ &= \sqrt{\frac{2\, G\cdot M_\text{e} \cdot m}{R_\text{e}\cdot m}} = \sqrt{\frac{2\, G\cdot M_\text{e}}{R_\text{e}}}\end{aligned}[/tex].

Answer:

Explanation:

the formula for calculating the linear velocity is expressed as;

v = wr

w is the angular velocity

r is the radius

r = d/2 = 18/2

r = 9 m

Given that 1rev/min = 0.10472rad/s

4.9 rev/min = x

x = 4.9 * 0.10472

x = 0.513128 rad/s

Substitute into the given formula;

v = 9 * 0.513128

V = 4.61m/s

Hence the velocity of the child in m/s is 4.6m/s