Magnesium is added to dilute hydrochloric acid. This makes bubbles of hydrogen and a colorless solution of magnesium chloride. Write down the name of one of the products of this reaction.

Answer:

A

not sure of answer ndhfhfjfjcjfjfj

The equation for the average, also known as the arithmetic mean, is:

D. Average = (sum of all data values) / (total number of data values)

The average is calculated by adding up all the data values and then dividing the sum by the total number of data values. This equation provides a measure of central tendency that represents the typical value or the "average" value of a set of data.

Option A, (total number of data values) / (sum of all data values), does not represent the correct equation for calculating the average. Dividing the total number of data values by the sum of all data values does not yield the average. This equation would result in a value that is not representative of the data set.

Option B, (sum of target data values) / (sum of all data values), is not the correct equation for calculating the average. This equation suggests finding the average of specific "target" data values rather than considering the entire data set.

Option C, (sum of target data values) / (total number of data values), is also not the correct equation for calculating the average. Similar to option B, this equation suggests finding the average of specific "target" data values rather than considering the entire data set.

Therefore, the correct equation for calculating the average is D. Average = (sum of all data values) / (total number of data values). This equation provides the most accurate representation of the average value of a given data set.

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Answer:

divergence of continental crust

Explanation:

Answer:

on image

Explanation:

Answer:

≈ 2.74 mol [tex]AlCl_{3}[/tex]

(I rounded to 3 sig figs because the starting amount has 3 sig figs.)

Explanation:

[tex]\frac{365g AlCl_{3}}{1}*\frac{1 mol AlCl_{3}}{133.34g AlCl_{3}} =[/tex] 2.73736313184 mol [tex]AlCl_{3}[/tex] ≈ 2.74 mol [tex]AlCl_{3}[/tex]

Hope this helps!

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Answer:

Option A.

Explanation:

1 mol of anything contains 6.02×10²³ particles.

We know that 1 mol of oxygen gas contains 2 moles of O.

1 mol of oxygen weighs 16 g/mol, the mass for 1 molecule of O.

By the way, the mass for 1 mol of O₂ may be:

Option A  →  16 g/mol . 2 mol

32 g

Oyxgen is a dyatomic molecule, that's why we have 2 moles of O.

Another example can be:

1 mol of water (H₂O) contains 2 moles of H and 1 mol of O.

Answer:

neom, sodium bicarbonate

Answer:

See explanation

Explanation:

Electro negativity refers to the ability of an atom in a molecule to attract the shared pair of electrons of a bond closer to itself.

In a molecule, the polarity of bonds is determined by the relative electro negativity of the bonding atoms. If the difference in electro negativity between the atoms in a bond is significant, such a bond is polar in nature e.g H-Cl, H-Br, C-F, etc.

However, the occurrence of polar bonds in a molecule alone does not guarantee the polarity of the molecule. The polarity of a molecule also depends on the shape of the molecule since dipole moment is a vector quantity.

A molecule is polar when the resultant dipole moment which is determined by the shape of the molecule is non zero.

For instance, CO2 contains two polar C-O bonds but the molecule is non polar because the two dipole moments cancel out. Also, symmetrical molecules are nonpolar irrespective of the presence of polar bonds in the molecule.

Answer:

acceleration

inversly

opposite

directly

mass

Answer: hello your question has some missing data attached below is the missing data

answer:

i) volumetric flow rate = 168 m^3/h = 5932.86 ft^3/h

ii) n = 582.4 Ib mole/hr

Explanation:

Given that the volumetric flow rate is a Linear function of R

V = ∝R + β

where; R1 = 15 , V1 = 40 m/h , R2 = 50, V2 = 96 m/h  input values into equation above

40 = 15∝ + β ----- ( 1 )

96 = 50∝ + β ----- ( 2 )

resolve equations 1 and 2 simultaneously

56 = 35∝ + 0

∴ ∝ = 56 / 35 = 1.6

back to equation 1:  40 = 15(1.6) + β    ∴ β = 40 - 24 = 16

hence ; V = 1.6(95) + 16 = 168 m^3/h = 5932.86 ft^3/h

lets assume room temperature

density of water = 62.4 Ib/ft^3

molecular weight of water = 18

therefore n = ( 62.4 / 18 ) * 168

                  = 582.4 Ib mole/hr

Answer:

C-HOC6H12OH and HOOCCH.COOH

hexane-1,6-diol and propane-1,3-dioic acid

Answer:

I am sure it is D or C. have a nice day

Answer:

80.7 °C

Explanation:

Step 1: Given and required data

Step 2: Calculate the final temperature of the water

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = Q / c × m + T₁

T₂ = -1,200 J / (4.184 J/g.°C) × 20.0 g + 95.0 °C = 80.7 °C

Answer:

81 C

Explanation:

Mass and volume are two factors that affect that density of matter!

Answer:

40.7g

Explanation:

so mass = moles × mr( 6.94+16+1)

=1.7 × 23.94

= 40.698

so 3 S.F = 40.7 g

hope this helps :)

Answer:

the amount of trials in an experiment

Answer:

23, 51

Explanation:

Edmentum/plato

As per the balanced reaction, 2 moles of aluminum metal and 3 moles of copper nitrate gives 2 moles of aluminum nitrate and 3 moles of copper metal.  10 g  of Al and 25g of copper nitrate gives 0.08 moles of aluminum nitrate and 0.13 moles of copper.

A limiting reactant is the reacting species which is not sufficient in amount to complete the reaction. Hence, the limiting reactant determines the yield of the reaction.

The given reaction is written as:

[tex]\rm 3Cu(NO_{3})_{2} + 2Al \rightarrow 2 Al(NO_{3})_{3} + 3Cu[/tex]

2 moles of Al and 3 moles of copper nitrate gives 2 moles of aluminum nitrate and 3 moles of Cu.

Molar mass of copper nitrate = 187.5 g/mol

atomic mass of aluminum = 27 g/mol

then, number of moles in 10 g of Al = 10 g/27 g/mol = 0.37 moles.

number of moles in 25 g of copper nitrate = 25 g/187.5 g/mol = 0.13 moles.

0.37 moles of Al needs 0.5 moles of copper nitrate to react with. Hence, copper nitrate is the limiting reactant.

3 moles of copper nitrate gives 2 moles of aluminum nitrate. Then 0.13 moles will give 2/3rd of 0.13 i e., 0.08 moles of aluminum nitrate. Similarly 0.13 moles copper nitrate gives 0.13 moles of copper metal.

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Your question is incomplete. But your complete question probably was:

10 g of aluminum metal reacts with 25 g of copper nitrate. Use the periodic table to determine the amount of copper and aluminum nitrate formed in the reaction.

In the reaction,

moles of Cu and

moles of Al(NO3)3 are formed.

Answer:

a lot but im pretty sure if u just take avogadros number and multiply it by 9.8 u get the answer

Explanation:

There are 5.89 × 10²⁴ atoms in 9.8 moles on NaCl. Details about number of atoms can be found below.

The number of atoms of a compound can be calculated by multiplying the number of moles of the substance by Avogadro's number.

no of atoms = no of moles × 6.02 × 10²³

According to this question, there are 9.8 moles of NaCl.

no of atoms = 9.8 × 6.02 × 10²³

no of atoms = 5.896 × 10²⁴

Therefore, there are 5.89 × 10²⁴ atoms in 9.8 moles on NaCl.

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Answer:

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Answer:

A. Sodium (Na)

Explanation:

The total number of electrons in the outermost principal energy level of an element is called the valence electrons of that element.

Na (11)---→1s2 2s2 2p6 3s1

There 1 electron in the outermost principal energy level of Sodium. So, the number of valence electron of Sodium is 11.

Answer:

Na

Explanation:

I was learning about it recently, that dude's right, it's Sodium

Answer:

ΔH = 283kJ/mol

Explanation:

Using Hess's law, the ΔH of a reaction is equal to the sum of ΔH° of products times its coefficient subtracting the sum of ΔH° of reactants times its coefficient. Replacing, for the reaction:

ΔH = 2ΔH°C + 2ΔH°D - (2ΔH°A+ΔH°B)

ΔH = 2*193kJ/mol + 2*-493kJ/mol - (2*-235kJ/mol+ (-413kJ/mol)

c) because rays contain electrons

OPTION C is the correct answer.

Answer:

-3169

Explanation:

trust the process

-3169 kJ/mol is the enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex] completely reacts with oxygen.

Explanation:

Given:

The reaction of combustion of [tex]C_6H_6(g)[/tex] along with enthalpies of formation of the compounds.

To find:

The enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex]  completely reacts with oxygen.

Solution:

[tex]2C_6H_6(g) + 15O_2(g) \rightarrow 12CO_2(g) + 6H_2O(g)[/tex]

Enthalpy of the reaction:

[tex]\Delta H^o_{rxn}=\sum [\Delta H^o_{f,products}]-\sum [\Delta H^o_{f,reactants}]\\=[12mol\times \Delta H^o_{f.CO_2(g)}+6mol\times \Delta H^o_{f,H_2O(g)}]-[2 mol\times \Delta H^o_{f.C_6H_6(g)}+15\times \Delta H^o_{f,O_2(g)}]\\=[12mol\times (-393.50 kJ/mol)+6mol\times (-241.82 kJ/mol)]-[2mol\times 82.90kJ/mol+15mol\times 0 kJ/mol]\\=-6338.72 kJ[/tex]

[tex]2C_6H_6(g) + 15O_2(g) \rightarrow 12CO_2(g) + 6H_2O(g).\Delta H^o_{rxn}=-6338.72 kJ[/tex]

When 1 mole of [tex]C_6H_6(g)[/tex]  reacts with oxygen gas:

[tex]=\frac{\Delta H^o_{rxn}}{\text{2 mol of } C_6H_6}\\=\frac{-6338.72 kJ}{2 mol}\\=-3169.36 kJ/mol\approx -3169 kJ/mol[/tex]

-3169 kJ/mol is the enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex] completely reacts with oxygen.

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Answer:

The answer will be Number C that is positively and part of the nucleus

Answer:

Part C best describes a proton, as it is positively charged and part on the nucleus