Make the FG perpendicular bisector. Then draw the square using the perpendicular bisector's points of intersection with the circle, as well as points F and G is the correct procedure. Option C is correct.
What is the procedure for constructing a square inscribed in the circle?The procedure is as follows:
1. A circle's diameter is drawn.
2. Using the approach given in the perpendicular bisector of a segment, draw a perpendicular bisector of the diameter. This is also the circle's diameter.
3. The vertices of the inscribed square are the four points on the circle that result.
The summary describes the basic process for constructing a square inscribed in the circle is to create the perpendicular bisector of FG. Then use the points of intersection of the perpendicular bisector with the circle, along with points F and G, to draw the square.
Hence,option C is correct.
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Answer: C
Step-by-step explanation:
C.
Create the perpendicular bisector of FG. Then use the points of intersection of the perpendicular bisector with the circle, along with points F and G, to draw the square.
A certain ore contains 9 percent gold. How much ore (in tons) is needed to obtain 126 tons of gold
Answer:
251,991 tons of ore are need to obtain 126 tons of gold.
Step-by-step explanation:
When are two triangles similar? Select all that apply.
All three of their corresponding angles have the same measure.
Two of their corresponding angles are the same angle measure.
Only one of their angles match.
All ratios of corresponding sides are proportional.
Two of their corresponding sides are in the same ratio.
Two triangles are said to be similar when; two of their corresponding angles are the same angle measure.
What is a triangle?A triangle is a polygon with three sides and three angles.
Types of triangles
Equilateral triangleScalene triangleIsosceles triangleTwo triangles are said to be similar if two pairs of their corresponding angles are congruent. This is because if two pairs of angle are the equal, then the third pair must also be equal.
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PLSSS HELP ME WITH MATH
Step-by-step explanation:
always remember, equations and inequalities are like a scale with 2 pans (left and right).
a variable is like a placeholder, an empty spot on the pans. and the expressions on both sides are kind of the conditions for the things to put in these empty spots so that the status of the scale stays unchanged.
for an equation the scale has to stay balanced all the time.
and in an inequality one side is heavier that the other (it normally does not matter how much heavier) with "<" or ">" signs, or the scale can be also balanced with "<=" or ">=" signs. just the other side must never be heavier.
A
so, in our case here
2x - 5 = 3
yes, the solution (the ONLY solution, actually) is x = 4. no other value of x allows the scale to be balanced.
2x - 5 >= 3
well, since it is a ">=" sign, we can be lazy and treat it like the equation above, and x = 4 is therefore a valid solution for the inequality too.
but so is every other value of x that makes the left side "heavier". what about e.g. 5 ?
2×5 - 5 >= 3
10 - 5 >= 3
5 >= 3
true, great ! so, e.g. x = 5 is also a valid solution.
what else ?
let's simplify the inequality
2x - 5 >= 3
2x >= 8
x >= 4
so, really every value of x that is greater or equal to 4 is a valid solution for the inequality.
B
-2x - 5 = 3
yes, the solution (the ONLY solution, actually) is x = -4. no other value of x allows the scale to be balanced.
-2x - 5 >= 3
well, since it is a ">=" sign, we can be lazy and treat it like the equation above, and x = -4 is therefore a valid solution for the inequality too.
but so is every other value of x that makes the left side "heavier". what about e.g. -5 ?
-2×-5 - 5 >= 3
remember, -×- = +
10 - 5 >= 3
5 >= 3
true, great ! so, e.g. x = -5 is also a valid solution.
what else ?
let's simplify the inequality
-2x - 5 >= 3
-2x >= 8
x <= -4
a multiplication or division by a negative value flips the inequality sign, because such an operation makes a light weight heavy and a heavy weight light.
so, really every value of x that is less or equal to -4 is a valid solution for the inequality.
subtract the quotient of 15 divided by 3 from the sum of 33 and 7
Answer:
(33+7)-(15/3) = 35
Step-by-step explanation:
35
Step-by-step explanation:
fancy way of saying (33+7) - (15/3)
33 + 7 = 40
15 / 3 = 5
40 - 5 = 35
If two supplementary angles are in the ratio of 7: 8 ,find them.
Answer:
84° and 96°Step-by-step explanation :
Given :
Two supplementary angles are in the ratio of 7: 8To Find :
The two anglesSolution :
Let the angles be 7x and 8x respectively
As We know that, Sum of supplementary angles is always 180°
So, Adding Both the angles,
→ 7x + 8x = 180°
→ 15x = 180°
→ x = 180/15
→ x = 12
Hence,
7x = 7(12) = 84° 8x = 8(12) = 96°Therefore,
The required angles are 84° and 96°Please help me its a math problem !! please see image
Answer:
y ≤ 4
Step-by-step explanation:
Solving :
Highest y-value is 4The other y-values are less than 4Hence, the range is : y ≤ 4Somebody please explain how to solve this by formula or theorem
[tex]\text{It is an equilateral triangle, so all angles are equal to}~ 60^{\circ}\\\\~~~~~~m\angle 2 = x+72\\\\\implies 60 = x+72\\\\\implies x = 60-72\\\\\implies x = -12[/tex]
A sector whose central angle measures 72º has an area of 16.211 square feet. What is the radius of the circle?
Answer:
81.055 ft²
Step-by-step explanation:
A full circle has a central angle of 360°.
A sector with a central angle is 72° is 72/360 = 1/5 of a circle.
A full circle has 5 times the area of a sector with a 72° central angle.
A = 5 × 16.211 ft²
A = 81.055 ft²
what is the circumference of a circle that has a diameter of 12 feet
Answer:
i think it's 37.7
Step-by-step explanation:
Solve This please!
Divide twice the variable x by the summation of z and y.
Answer:
2x/z+y
Step-by-step explanation:
Construct a confidence interval using a sample of size 15, with a sample standard deviation of 1.45, a sample mean of 5.3, and a confidence level of 90%. Write your answer EXACTLY as is given by Excel. Do not round.
A confidence interval is the mean of the estimate plus and minus the variation in that estimate.
How to depict the confidence interval?
From the excel, Confidence.T(0.10,1.45,15)
Margin of error = 0.659414066
Lower limit will be;
= mean-0.659414066
= 5.3 - 0.659414066
= 4.640585934
Upper limit will be:
= mean+0.659414066
= 5.3+0.659414066
= 5.959414066
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Renting Cars Floppy Jalopy Rent-a-Car has 25 cars available for
rental-20 big bombs and 5 midsize cars. If two cars are selected at
random, what is the probability that both are big bombs?
The probability that both are big bombs is 19/30 or 0.63 if the renting Car's Floppy Jalopy Rent-a-Car has 25 cars available for rental-20 big bombs and 5 midsize cars. If two cars are selected at random.
What is probability?It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
Renting Cars Floppy Jalopy Rent-a-Car has 25 cars available for rental-20 big bombs and 5 midsize cars. If two cars are selected at random.
Total number of outcomes = C(25, 2) = 300
Total number of favorable outcomes = C(20, 2) = 190
Probability = 190/300 = 19/30 or
= 0.63
Thus, the probability that both are big bombs is 19/30 or 0.63 if the renting Car's Floppy Jalopy Rent-a-Car has 25 cars available for rental-20 big bombs and 5 midsize cars. If two cars are selected at random.
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Pls solve 3c for me.will mark branliest a
.
Step-by-step explanation:
if you could solve 3a and 3b, you can also solve 3c. it is the same principle.
x-intercepts means y = 0.
remember, a square root has always 2 results : a positive and a negative one.
3c
0 = -(x - 3)² + 25
(x - 3)² = 25
x - 3 = ±5
x1 = +5 + 3 = 8
x2 = -5 + 3 = -2
3a
0 = (x + 1)² - 4
4 = (x + 1)²
±2 = x + 1
x1 = +2 - 1 = 1
x2 = -2 - 1 = -3
3b
0 = (x + 2)² - 9
9 = (x + 2)²
±3 = x + 2
x1 = +3 - 2 = 1
x2 = -3 - 2 = -5
Find the coordinates of the midpoint of the line segment with endpoints at ( 6, -7) and (-3,5)
Answer:
Coordinates of the midpoint are ( 9/2 , -6 )
Determine why the triangles are congruent. Choose from SSS, SAS, ASA, AAS, and HL. If the
triangles are not congruent type NC. (Use all capitals in your answer)
Answer:
Step-by-step explanation:
please slove question 5
Answer:
2,160 mm³
Step-by-step explanation:
Q5
V = 1/2 × lwhV = 1/2 × 24 × 10 × 18V = 12 x 10 x 18V = 216 x 10V = 2,160 mm³A water tank measures 1.4m by 8cm by 60cm. Find the capacity of the tank in litres
Answer:
672 litres.
Step-by-step explanation:
Convert the measurements to cm:
14 m = 1400 cm
The capacity = 1400 * 8 * 60
= 672,00 cm^3
There are 1000 cm^3 in 1 litre so the answer is
672 litres.
please answer this!!!
Step-by-step explanation:
sin60 =opp/hyp
0.86=y/20
y=17.2
cos60=adj/hyp
0.5=x/20
x=10
sin57=y/15
0.83=y/15
y=12.45
#88 will give brainliest to the best response!
Answer:
Mean: 80
Mode: 81
Median:81
Step-by-step explanation:
First, let's get the set of numbers from this Stem-and-Leaf plot:
[60,61,73,75,79,81,81,81,92,96,98]. From here we can solve for the mean by adding all the numbers up and dividing it by the number of terms that we have: [tex]\frac{60+61+73+75+79+81+81+81+92+96+98}{11} = 80[/tex] when rounded to the nearest whole number. The median is the middle number of the set when arranged from least to greatest, in this case, the median is 81.
Hope this helps! :)
A car starts from an office building, which is 5 miles east and 2 miles south of the town center. The car travels 6 miles north, makes a left turn and then travels 8 miles. What is the car’s final position? What single translation vector moves the car from its starting position to its final position?
Answer:
[tex]\displaystyle \binom{-8}{6}[/tex]
Step-by-step explanation:
The car's starting position is 2 miles south of the town center. If it travels 6 miles north, then it will be 4 miles north of the town center.
The car's starting position is 5 miles east of the town center. If it travels 8 miles west, it will be 3 miles west of the town center.
Therefore, its final position is 4 miles north and 3 miles west of the town center.
If the car travels 6 miles north from it's starting position, the y-value of the vector will be 6, as the car is moving in a positive direction along the y-axis.
If the car travels 8 miles left, the x-value of the vector will be -8, as the car is moving in a negative direction along the x-axis.
Therefore, the single translation vector that moves the car from its starting position to its final position is:
[tex]\displaystyle \binom{x}{y}=\binom{-8}{6}[/tex]
the distance lesley walks from home to school is 120 meters and 80 meters when he goes to church from home. gusion estimates that the distance lesley walks when he goes directly to church. coming frim school is 180 meters. guinevere's estimation is 210 meters which etimation is feasible? make a map of lesley ways from home to school and church justify.
triple the sum of x and 5
Answer:
The expression becomes 3(x+5) = 3x+15
Robert climbed 125 steps in five minutes at this rate how many steps did he average per minute
The solution is 62. We have to multiply the mixed number by the whole number. 12 1/2 is 25/2 so we now multiply by flipping the 25/2 to 2/25 and when you multiply you get 1550/25, which is 62
I need help with part 2 on this question (Screenshot)
What is the eighth term of the sequence below?
5, 9, 13, 17, …
A. 33
B. 30
C. 29
D. 34
Answer:
A. 33
Step-by-step explanation:
Add 4 to each number
1. 5 is your first number
2. 5+4= 9 is your second number
3. 9+4= 13 is your third number
4. 13+4= 17 ...
5. 17+4= 21 ...
6. 21+4= 25 ...
7.25+4= 29 ...
8.29+ 4= 33 is your eight number
VW has a midpoint at M(12, 0.5). Point V is at (10, -18). Find the coordinates of point W. Write the coordinates as decimals or integers.
[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ V(\stackrel{x_1}{10}~,~\stackrel{y_1}{-18})\qquad W(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ x +10}{2}~~~ ,~~~ \cfrac{ y -18}{2} \right)~~ = ~~\stackrel{M}{(12~~,~~0.5)} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{ x +10}{2}=12\implies x+10=24\implies \boxed{x=14} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{ y -18}{2}=0.5\implies y-18=1\implies \boxed{y=19}[/tex]
In the past month, Joe rented 5 video games and 4 DVDs. The rental price for each video game was $2.60. The rental price for each DVD was $3.30. What is
the total amount that Joe spent on video game and DVD rentals in the past month?
Answer:
$26.2
Step-by-step explanation:
5*2.50 is 13 for video games
4*3.30 is 13.2 for DVD
Sum them up and you get 26.2
Enter the values for the highlighted variables that show how to subtract the rational expressions correctly: startfraction 2 over x squared minus 36 endfraction minus startfraction 1 over x squared 6 x endfraction = startfraction 2 over (x 6) (x minus 6) endfraction minus startfraction 1 over x (x a) endfraction. = startfraction b x over (x 6) (x minus 6) x endfraction minus startfraction x minus c over (x 6) (x minus 6) x endfraction. = startfraction d x minus x e over (x 6) (x minus 6) x endfraction. = startfraction x f over (x 6) (x minus 6) x endfraction. = startfraction g over x (x minus 6) endfraction a = b = c = d = e = f = g =
The values for the highlighted variables that show how to subtract the rational expressions correctly are a = 6, x^2 + 6x is equal to x(x+6), and b=2.
How to explain rational expressions?From the informaation, the denominator and numerator of the first term are multiplied by x.
The second term is multiplied by (x-6)/(x-6).
Now that they have the same denominator, the two terms are combined. 2 is the coefficient of the first term. In the same way as d is carried over from b, e is carried over from c.
We factor out the (x+6) from the numerator and denominator.
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A goat race is 325 meters long. An ant race is 75 centimeters long.
How much longer is the goat race than the ant race in meters?
Step 1: To compare the distances, they must both be in meters or both be in centimeters. Change 75 centimeters to meters.
Question 2
Step 2: Determine how much longer the goat race is than the ant race in meters.
The goat race is 324.25 meters longer than the ant race .
How to find the distance differences?
The goat race is 325 meters long. The ant race is 75 centimetres long.
The goat race is in meters while the ant race is in centimetres.
Let's convert the ant race to meters.
Hence,
1 cm = 0.01 m
75 = ?
cross multiply
Ant race = 0.75 meters
Therefore, let's find the difference between the goat race and the ant race.
325 - 0.75 = 324.25 meters.
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Answer: Step 1: To compare the distances, they must both be in meters or both be in centimeters. Change 75 centimeters to meters.
So=75 cm ÷ 100 = 0.75 m
Step-by-step explanation:
Step 2: Determine how much longer the goat race is than the ant race in meters.
o get the correct answer, subtract the length of the ant race in meters from the length of the goat race.
Remember to line up the decimal points and add zeros as plac
eholders. The difference of 325 and 0.75 is 324.25.
The goat race is 324.25 meters longer than the ant race.
y
12
11
10
9
7
NWO0065
4
-12-11-10-9-8
-65
-3-2-1
1
2 3 4 5 6
8 9 10 11 12
-2
-9
-10
-11
-12
Answer:
y12111097
Step-by-step explanation:
because I know the answer