Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms did each of them pick?

Answers

Answer 1

Answer and Step-by-step explanation: Let \displaystyle xx be the amount Peter picked. Then Mary and Lucy picked \displaystyle 2x2x and \displaystyle x+2x+2, respectively. So

\displaystyle x+2x+x+2=26x+2x+x+2=26

\displaystyle 4x=244x=24

\displaystyle x=6x=6

Therefore, Peter, Mary, and Lucy picked 6, 12, and 8 kg, respectively.

Answer 2

Peter picked 6 kilograms of chestnuts.

Mary picked 12 kilograms of chestnuts.

Lucy picked 8 kilograms of chestnuts.

What are Arithmetic operations?

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.

Let Peter pick x kilograms of chestnuts.

Given that Mary picked twice as many chestnuts as Peter

So, Mary picks 2x kilograms of chestnuts.

And Lucy picks  x + 2 kilograms of chestnuts

Together the three of them picked 26 kg of chestnuts

So, x + 2x + x + 2 = 26

4x + 2= 26

4x= 26-2

4x= 24

4x/4= 24/4

x= 6

Thus, Peter picked 6 kilograms of chestnuts.

⇒ 2x

⇒ 2 (6)

⇒ 12

Thus, Mary picked 12 kilograms of chestnuts.

⇒ x + 2

⇒ 6 + 2

⇒ 8

Thus, Lucy picked 8 kilograms of chestnuts.

Learn more about Arithmetic operations here:

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The shadow of a 60 foot pole is a 100 feet long. What is the angle of evaluation from the end of the shadow to the top of the pole?

Answers

Answer:

The angle is approximately [tex]31^{o}[/tex].

Step-by-step explanation:

The description i the given question can be represented with the sides of a right angled triangle.

Applying the appropriate trigonometric function, we have;

Tan θ = [tex]\frac{opposite}{adjacent}[/tex]

In the question, opposite side = 60 feet, and adjacent side = 100 feet.

Tan θ = [tex]\frac{60}{100}[/tex]

         = 0.6

θ = [tex]Tan^{-1}[/tex] 0.6

  = [tex]30.964^{o}[/tex]

θ = [tex]31^{o}[/tex]

The angle of elevation from the end of the shadow to the top of the pole is [tex]31^{o}[/tex].

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Answers

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Answer:

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Step-by-step explanation:

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