Mary pushes a crate by applying force of 18 newtons. unable to push it alone, she gets help from her friend, anne. together they apply a force of 43 newtons, and the crate just starts moving. if the coefficient of static friction is 0.11, what is the value of the normal force? a. 2.0 × 102 newtons b. 2.6 × 102 newtons c. 3.9 × 102 newtons d. 4.0 × 102 newtons e. 4.3 × 102 newtons

B. The pairs of vectors equal in direction only are one short and one long arrow going in the same direction.

The direction of a vector  can be defined as the measure of the angle it makes with a horizontal line.

The direction of a vector can also be described as the measure of the exact position on the x and y coordinate where a vector can be found.

When we describe the direction of vectors, we don't consider their size or magnitude, rather we focus on the angle of inclination of the vectors above the horizontal.

The magnitude of a vector is defined as the size of the vector.

Vectors pointing or going in the same direction have equal directions despite their size.

Vectors with equal size have the same magnitude despite their directions.

Thus, we can conclude that two vectors going in the same direction will have equal direction.

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As she starts to move upward, the student pushes down on the surface with a force that is greater than her weight. This will cause her net force to be directed upwards, thus, alternative B.

Net force is the vectoral sum or the resolution of all the forces acting on a body. Although, more than one force may be acting on a body at the same time, only the resultant force or the net force will have a significant effect on the body. If the net force is equal to zero, the body is said to be in a state of equilibrium, and according to Newton's first law of motion, the body will remain in its state of rest or will continue to move in uniform speed.

As for the student in the question, her net force isn't equal to zero, so she will move in the direction of her net force, which is upwards. Newton's third law of motion states that "to every action, there is an equal but opposite reaction".

When she pushed downwards on the surface of the ground with a force greater than her weight, the ground surface will also produce a force in opposite direction to and equal to the force she used on the ground called a normal force, according to Newton's third law of motion. The normal force is also greater than the weight of the girl, hence, her net force will not be zero, and it will move in an upward direction, causing her to jump off the ground.

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Complete question:

As she starts to move upward, the student pushes down on the surface with a force that is greater than her weight. What can you say about the net force on her?

A. The net force is zero.

B. The net force is directed upward.

C. The net force is directed downward

The change in momentum of the ball travelling along a straight path, perpendicular to a wall, after bouncing off the wall as observed by the ground observer is 0

Δp = [tex]p_{f}[/tex] - [tex]p_{i}[/tex]

Δp = Change in momentum

[tex]p_{f}[/tex] = Final momentum

[tex]p_{i}[/tex] = Initial momentum

p = m v

m = Mass

v = Velocity

Since, [tex]p_{f}[/tex] = [tex]p_{i}[/tex]

Δp = 0

Momentum can be simply defined as a mass in motion. So if an object with mass moves, it will have momentum. It is a vector quantity.

Therefore, the change in momentum as observed by the ground observer is 0

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The change created by melting is known to be called a physical change.

A physical change happens when a given  substance's physical characteristics alters without undergoing a kind of chemical composition.

Note that Melting, changes in size, as well as in volume, color, also density, and crystal shape are said to be an examples of common physical changes.

Physical changes, like melting or the act of boiling, are usually simple to undo even though the final result might not always look exactly the same as the original. Aside from gaining or losing energy, particles do not change during physical changes and no new materials are created.

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The speed of the ball is "50.4 m/s"

The structure is 130 meters high.

64 meters across the horizontal

Gravity causes an acceleration of 9.8 m/s.

Using the equation of motion s = ut + (0.5at2) and presuming that air resistance is not taken into account, we first calculate how long it takes for the object to strike the ground.

where s = distance (height of the building)

initial speed is u. (which is 0 in this case )

Time t equals (130/4.9) where an is the gravitational acceleration (0 x t) + (0.5 x 9.8 x t2) = 130 4.9 x t2.

5.15 seconds = t

We now apply the equation Vy = Uy + at to get the speed before it touches the ground (0 in this case)

Vy = 0 + (9.8 x 5.15) (9.8 x 5.15) (9.8 x 5.15)

Vy = 50.4 m/s

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The car B will experience greater acceleration than car A.

According to the Newton's second law, the acceleration of an object is depends on the net force acting upon the object and the mass of the object. The mathematical form of the law is given below.

F = m*a

Where F = force, m = mass and a = acceleration.

The equation in terms of acceleration is,

a = F/m

From the formula, we can see that the acceleration is directly proportional to force and indirectly proportional to mass. The net force on the car A is greater than car B. But the mass of the car A is larger than almost three times of the mass of car B. Hence the car A will have lower acceleration compared to car B. The larger net force will not increase the acceleration very much. So, the car B will experience greater acceleration than car A.

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In order for the electrons to emit photons and leave the ground state, the heat produced by the electricity must be present.

The electron is a subatomic particle with a negative one elementary charge electric charge. Due to their lack of components or substructure, electrons, which are part of the lepton particle family's first generation, are typically thought to be elementary particles.

The electromagnetic force is carried by a photon, an elementary particle that is a quantum of the electromagnetic field and includes electromagnetic radiation like light and radio waves. Since photons have no mass, they always move at the 299792458 m/s speed of light in a vacuum.

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In a feedback loop, the stimulus Creates an set point that impacts the original event.

A system component known as a feedback loop is one in which all or a portion of the output is used as input for subsequent operations. A minimum of four stages comprise each feedback loop.

Input is produced in the initial phase. Input is recorded and stored in the subsequent stage. Input is examined in the third stage, and during the fourth, decisions are made using the knowledge from the examination.

Both negative and positive feedback loops are possible. Insofar as they stay within predetermined bounds, negative feedback loops are self-regulating and helpful for maintaining an ideal state. One of the most well-known examples of a self-regulating negative feedback loop is an old-fashioned home thermostat that turns on or off a furnace using bang-bang control.

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The change in the velocity of the rocket after 220 meters is 80.42 m/s.

The change in the velocity of the rocket at the given time of motion is calculated as follows;

Apply the following kinematic equation to determine the velocity of the rocket.

v² = u² + 2as

where;

v² = 2as

v = √2as

v = √(2 x 14.7 x 220)

v = 80.42 m/s

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The component of the gravitational force acting down the inclined plane has a magnitude of 209.98 N

Eventhough the box is at an inclined plane which makes 36° with the horizontal, the gravitational force will still act straight down perpendicular to the horizontal. Resolving the force due to gravity into its horizontal and vertical components. The vertical component makes 36° with the gravitational force and is at right angles with the horizontal component.

The component of the gravitational force acting down the inclined plane is the horizontal component.

W = 355.9 N

In a right angled triangle,

sin θ = Opposite side / Hypotenuse

sin 36° = [tex]W_{x}[/tex] / W

[tex]W_{x}[/tex] = 355.9 * 0.59

[tex]W_{x}[/tex] = 209.98 N

Therefore, the component of the gravitational force acting down the inclined plane is the horizontal component with a magnitude of 209.98 N

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Since the chute is semicircular, the ball's velocity shortly before free fall at the top would be horizontal. Given that, starting velocity u=0 As a result, 2R is the distance from the chute's bottom.

We must first determine the speed at which the ball is moving at the top of the shop. Therefore, let's accelerate. Two G are equal to the centripetal acceleration.

In contrast, acceleration is equal to two B squared. Because of this, the speed is equal to two square. The square root of two G is the Rudolph centripetal acceleration times. It's calculated, that. Yeah. So now, mm hmm, mm hmm, we must calculate it.

Approximately 14 m/s and quite close to checkpoint 1 in meters per second. By dividing the object's velocity by the amount of time it takes to go from one location to another, the acceleration velocity can be calculated. Acceleration results from changes in the magnitude of velocity or direction.

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Given the fact that the arrow is in motion, it the follows that the arrow possesses kinetic energy.

The kinetic energy is the energy that is possessed by a body by virtue of its motion. This is different form the potential energy of the body which is the energy that the body possesses as a result of the fact that the object is located at a particular position. These are actually the two kinds of mechanical energy that we have in the study of physics.

If we consider this matter closely, we would see that the arrow as shown is in motion. The arrow does posses a velocity and such the arrow is in motion. As long as we can see that the arrow is in motion, it the follows that the arrow as we can see does and in fact possesses the kinetic energy.

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Answer:

See below

Explanation:

Use pythag theorem

r^2 = 3^2 + 5^2

r = sqrt (34)  = 5.83

          angle    = arctan (3/5) = 31 degrees   north of east

The mass of the chocolate from the table that we can find in the question is 11 grams.

We can see that the table as it have been shown gives us both the total number of the  trail mix that Alex has brought to the school as well as the various individual components of the  trail mix that he has. Looking at this over view would be of a lot of help as we are trying to find out now the number of the mass of the chocolate that Alex ate.

We have the following information;

Mass of nuts = 24 grams

Mass of raisins = 10 grams

Mass of chocolate = unknown grams

We can now have;

Total mass = Mass of nuts + Mass of raisins + Mass of chocolate

Mass of chocolate = Total mass - (Mass of nuts + Mass of raisins)

Mass of chocolate = 45 - (10 + 24)

Mass of chocolate = 11 grams

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Answer:

mass is measured in kilograms

The force varies in magnitude is 1350 N.

We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by

P = m . v

where P is momentum, m is mass and v is velocity.

Momentum depends on the Impulse, where

ΔP = I

m (v2 - v1) = F . t

where I is impulse, F is force and t is time

From the question above, we know that:

m = 0.5 kg

t = 24 ms = 0.024 s

v1 = 16 m/s

I = 32.4 Ns

Find the force applied

I = F . t

32.4 = F . 0.024

F = 1350 N

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The final displacement vector for Max's golf ball is d. 246 m, 29.1 degrees north of east.

displacement 1 = 235 m  15.9° west of north.

displacement2 = 29.5  meters 41.1° east of north.

resultant vector = [tex]\sqrt{235{^{2} + 29.5^{2} }[/tex]

                          = 246.84 m, 29.1 degrees north of east

A vector is an object that has both importance and direction. Geometrically, we are able to image a vector as a directed line section, whose duration is the importance of the vector, and with an arrow indicating the direction. The direction of the displacement vector is from its tail to its head.

Vector is a term that refers colloquially to a few quantities that can not be expressed via an unmarried variety, or to elements of a few vector spaces. Vectors are geometrical or physical portions that own both value and direction wherein the item is moving. The importance of a vector shows the length of the vector. it's far normally represented by means of an arrow pointing within the course of the vector.

Disclaimer:- your question is incomplete, please see below for the complete question.

Max is golfing and he hits a ball 235 meters 15.9° west of north. From that location, he hits the ball 29.5 meters 41.1° east of north. What is the final displacement vector for Max's golf ball?​

a. 246 m, 29.1 degrees east of north

b. 252 m, 10.3 degrees west of north

c. 252 m, 10.3 degrees north of west

d. 246 m, 29.1 degrees north of east

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The radius of a planet that has the same mass as earth but on which the free-fall acceleration is 4.90 m/s² is 9 M m

g = G M / R²

g = Acceleration due to gravity

G = Gravitational constant

M = Mass

R = Radius

g = 4.9 m / s²

G = 6.67 * [tex]10^{-11}[/tex] m³ / kg s²

M = 5.97 * [tex]10^{24}[/tex] kg

R² = ( 6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] ) / 4.9

R² = 81.3 * [tex]10^{12}[/tex].

R = 9 * [tex]10^{6}[/tex] m

R = 9 M m

Acceleration due to gravity is the acceleration produced by a planet. If an object is falling, it will gain some acceleration due to gravitational force.

Therefore, the radius of a planet is 9 M m

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The hanging mass that would produce an extension of 3.0cm is 4.5kg (option A).

The spring constant denoted by K is a measure of the stiffness of the spring. It is different for different springs and materials.

The larger the spring constant, the stiffer the spring and the more difficult it is to stretch.

The spring constant can be calculated using the following formula:

k = F/e

Where;

F = 15 × 3 = 45N

Since Force = mass × acceleration (10m/s²), the mass can be calculated as follows:

m = 45N ÷ 10m/s² = 4.5kg

Therefore, 4.5kg is the mass of the spring.

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Answer:

✨Hello mark as branlist Identify the physical principles involved by listing the givens and the quantities to be calculated

Explanation:

The volume of the bubble of gas when it reaches the surface is 1 cm³.

Boyle's law states that the pressure of a given mass of a gas is inversely proportional to its  volume provided that the temperature of the gas is constant.

Mathematically, Boyle's law is given as;

P₁V₁ = P₂V₂

where;

When the pressure at the bottom is double the pressure at the surface, then the pressure at the surface is half the pressure at the bottom.

V₂ = P₁V₁/P₂

Let the pressure at the surface = P

V₂ = (2PV₁)/P

V₂ = 2V₁

V₂ = 2(0.5 cm³)

V₂ = 1 cm³

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The complete question is below:

A bubble of gas is released from the mud at the bottom of the pond. It’s initial volume is 0.5cm^3. Ignoring any temperature differences in the water calculate the volume of the bubble as it reaches the surface if the pressure at the bottom is twice the pressure at the surface.

Both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.

Instantaneous velocity is the rate of differential change of displacement with respect differential change in time. Mathematically -

v = dx/dt

Given is the acceleration of a school bus over a given time interval as zero.

For acceleration over a given time interval to be zero, it must be ensured that the the velocity of the object should remain constant. Mathematically-

a = (v - u)/(t₂ - t₁)

For acceleration [a] = 0, v = u. Therefore -

a = 0

The instantaneous velocity for zero acceleration between the time interval t₁ to t₂ will be equal to initial velocity only -

dx/dt = u          

This will be the instantaneous velocity and is equal to (u) at any instant.

Now -

dx = u dt

Integrating both sides, we get -

∫dx = ∫u dt

x = ut

Therefore, the average velocity will be =

v(avg) = x/Δt = ut/Δt

Now -

t = Δt for any specific time interval. Therefore -

v(avg) = ut/t = u

This is the average velocity and it is equal to (u).

Therefore, both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.

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The radius of curve that a car goes around that is banked at an angle of 32.6° is 69 m

R = v² / g tan θ

R = Radius of the curve

v = Velocity

g = Acceleration due to gravity

θ = Banked angle

R = 20.8² / ( 9.8 * tan 32.6° )

R = 432.64 / ( 9.8 * 0.64 )

R = 432.64 / 6.27

R = 69 m

A banked surface is a surface that is sloped upwards on the outer side of a curve. In race car tracks, the banked angle is usually 12° to 36°.

Therefore, the radius of curve that a car goes around that is banked at an angle of 32.6° is 69 m

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Answer:

I believe that it is A) they're more spread out

Answer:

The relative density of mercury is 13.6, this means that mercury is 13.6 times as heavy as an equal volume of water.

Answer: 100km/20s=5km/s

Explanation:because velocity is equal to distance ovet time

Answer:

0.2

Explanation:

0.5 - 0.3 = 0.2

A. The time spent by the ball in the air is 14.7 s

B. The ball will land at 1060.47 m as it hits the net.

C. The maximum height reached by the ball is 265.12 m

A. How to determine the time

The time spent by the ball in the air can be obtained as follow:

T = 2uSineθ / g

T = [2 × 101.944 × Sine 45] / 9.8

T = 14.7 s

B. How to determin the distance

R = u²Sine(2θ) / g

R = (101.944)² × Sine (2×45) / 9.8

R = 1060.47 m

C. How to determine the maximum height

The maximum height reached by the ball can be obtained as follow:

H = u²Sine²θ / 2g

H = [(101.944)² × (Sine 45)²] / (2 × 9.8)

H = 265.12 m

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The center of mass of the three mass system is at 83cm

A position relative to an object or set of objects is known as the center of mass. It is the system's average location, weighted by the mass of each component.

Given the mass of the meter stick is:

M = 0.5kg.

Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.

Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.

Now a mass m2 = 1kg is attached at 50cm mark.

So the distance of m2 from 0cm is x2 = 50cm = 0.5m.

Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.

Now the position of the three mass system from 0cm is given by,

[tex]X_{CM}=\frac{Mx_{1}+m_{2}x_{2}+m_{3}x_{3}}{M+m_{2}+m_{3}}X_{CM}=\frac{0.5\times 0.5+1\times 0.5+3\times 1}{0.5+1+3}=\frac{3.75}{4.5}=0.83m = 83cm[/tex]

So the center of mass of the three mass system is at 83cm.

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The resultant speed of the airplane is 150 km/h, and this is the speed relative to the ground.

The resultant speed of the airplane is the single speed of the airplane that will produce same effect as the two speeds acting together.

To convince your classmate about the ground speed of the airplane we need to calculate the resultant speed of the airplane.

R² = Vp² + Vw²

where;

R² = Vp² + Vw²

R = √[Vp² + Vw²]

R = √[120² + 90²]

R = 150 km/h

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