Math the words in the box with the sentences below.

Answer:

Solubility in gasses and liquids increase as pressure increases. This is due to colligative properties. The nitrogen gas levels would increase the farther the diver dives due to the increase of pressure causing the solubility of the nitrogen to increase, thus increasing the amount of it as you go deeper in the ocean.

Explanation:

As they plummet down, the driver would be in more risk. The solubility of gases and liquids increases as pressure increases. This is due to the existence of colligative properties. The nitrogen gas levels grow when the diver descends further into the water due to increased pressure, which causes the nitrogen's solubility to rise, increasing the amount of nitrogen present.

Answer:

question 1 is centripetal acceleration question 2 is 4

Explanation:

centripetal acceleration basically is acceleration that only changes velocity but not speed, while for question 2, you divide 10 by 2.5

Exerted force is called Pressure.

From,

Pressure = Force/Area

P = 500N/10m²

P = 50N/m²

The force exerted is 50N/m²

The unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.

The given parameter;

The equations that model the motion of the ball is given as follows;

[tex]h = v_0_y + \frac{1}{2} gt^2[/tex]

[tex]v_f = v_0_y + gt[/tex]

All the unknown variables in the equations include;

The vertical distance traveled by the ball is calculated as follows;

[tex]h = \frac{1}{2} gt^2\\\\h = 0.5 \times 9.8 \times 2.55^2\\\\h = 31.86 \ m[/tex]

The final velocity of the ball is calculated as follows;

[tex]v_f = 0 + 9.8(2.55)\\\\v_f = 25 \ m/s[/tex]

Thus, the unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.

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Answer:

1 st question: Control variable

2nd question: random variable

3rd question: if the two objects are dropped from the same height they will hit the ground at the same time

Answer:

it IS the control variable

Explanation:

Answer:

wall,ceiling or other permanent surfaces

Answer:

resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.

Explanation:

assume that the ship started moving from A to B (north at 50km/hr for 2 hours) so the covered distance will be: 50*2 = 100 km

then it moves from B to C so the covered distance will be: 3*60 = 180 km

using Pythagoras, we get the resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.

Answer:

Answer:

The use of a telescope is to see distant objects

Explanation:

For example: you can look through a telescope to see constellations and stars. Hope this helps <3

Answer: (Sorry, but I don't know how to calculate mass)

1. 15 N

2. 0.4921 [tex]\frac{ft}{s^2}[/tex] (feet per second squared)

4. 150 N

5. 8.202 feet per second squared

Answer:

Interest groups help democracy because they represent the interests of such large numbers of people and encourage political participation by many groups. The stable, cooperative relationship often develops among a congressional committee, an administrative agency, and one or more supportive interest groups.

Interest groups try to influence the government to adopt legislation that would benefit them. Email, letter, faxes, phone calls, providing research and information (to bring about change by proving your cause with facts by funded research).

Answer:

about 16.5 by-

wait DO UR OWN MATH lol

Explanation:

We have that for the Question "A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that  the minimum force that must be applied on the book is

From the question we are told

A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal

Generally the equation for the  Force  is mathematically given as

[tex]F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\[/tex]

F=44N

Therefore

the minimum force that must be applied on the book is

F=44N

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The truck applies the same force to the car that the car applies to the truck. The truck applies the same force to the car that the car applies to the truck. According to Newton's third law, action and reaction have the same magnitude and move in the opposite direction.

Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.

The direction of the force is the point where force is applied, and the application of force is the point where force is applied.

The concept of force is commonly explained in terms of Isaac Newton's three laws of motion, which are laid out in his Principia Mathematica.

The truck exerts the very same force on the car as the car exerts on the truck. The truck exerts this very same force on the car as the car exerts on the truck.

Action and reaction have the same amplitude and move in the opposite direction, according to Newton's third law.

Thus, this can be the comparison in the given scenario.

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Your question seems incomplete, the complete question is:

Consider the collision between a car and a

light truck whose weights are equal (M = m). If they are moving at the same speed when they collide, compare the size (or magnitude) of the forces between the car and the truck. Friction is so small that it can be ignored.

Compare the forces if the light truck is standing

still when the car hits it.

Answer:

i dont understand sorry

Explanation:

I don't understand this question

could you please explain

Explanation:

Well ball on ramp .Which factors are affected?

So if we put the ball right above the centre of mass it can be best stabled

Answer:

v2^2 - v1^2 = 2 g s        fundamental formula

v2 = v1 + 2 g    = v1 + 19.8         increase in velocity in 2 sec

v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76

v1 = (2412.76 - 392) / 39.6 = 51.03

v2 = 51.03 + 19.6 = 70.63

T = 70.63 / .8 = 7.207 sec     time to fall height of tower

S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m

(Note  v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m

2385 / (2 * 9.8) = 122 m (close to 123.1    as was given

Answer:

To show that magnets repel, you must place the strong and weak magnets to another magnet with their poles being both south or both north facing eachother.

To show they attract, place opposite poles near eachother.

Explanation:

It obeys the inverse square law.

It is always attractive in nature.

It is a long range force. ...

The graviton is the field particle of gravitational force.

Answer:

Gravitational force−Properties:

(1) It is a universal attractive force. It is directly proportional to the product of the masses of the two bodies.

(2) It obey inverse square law.

(3) It is the weakest force known in nature.

Answer:C

Explanation:

For parallel connection

For series connection

Net resistance

Answer:

For example, one method for estimating the length of time it takes something to occur is to time it once using a stopwatch. You can reduce the uncertainty in this estimate by repeating the measurement and taking the average.

There are a lot of way to reduce the uncertainty however with real life sciences like quantum mechanics it will reveal more about the world and life if we have better measuring tools. Being precise is essential to understanding many parts of life.

Hope this helped! Have a great day!!!

Answer:

-2.68m/s²

Explanation:

To find acceleration use the formula:

acceleration = change in velocity ÷ time

Substitute in the values:

acceleration = -8.3 ÷ 3.1

acceleration = -2.67741.. ≈ -2.68m/s²

Hope this helps!

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Displacement is equal to ~

See the attachment for solution ~

Answer:

It is 24000meter per second

Answer:

William Cullen Bryant, Henry Wadsworth Longfellow, John Greenleaf Whittier, Oliver Wendell Holmes, and James Russell Lowell. These five men made up a group of poets known as the Fireside Poets or the Schoolroom Poets.They were hugely popular in the second half of the 19th century, like the pop stars of their time.

Explanation:

hope this helps if not let me know