Answer:
Explanation: because it develops a thin oxide layer on the surface when the metal comes in contact with oxygen. The oxide layer protect the aluminum against corrosion and if damaged it will immediately regenerate in presence of
A vibrating guitar string makes very little sound if it is not mounted on the guitar body. Why does the sound have greater intensity if the string is attached to the guitar body? (a) The string vibrates with more energy. (b) The energy leaves the guitar at a greater rate. (c) The sound power is spread over a larger area at the listener's position. (d) The sound power is concentrated over a smaller area at the listener's position. (e) The speed of sound is higher in the material of the guitar body. (f) None of these answers is correct
The sound has greater intensity if the string is attached to the guitar body as the sound power is spread over a larger area at the listener's position.
A sound wave is basically delivered by a vibrating object. As a guitar string vibrates, it sets encompassing air particles into vibrational movement. The frequency at which these air particles vibrate is rise to the frequency of vibration of the guitar string. The back and forward vibrations of the surrounding air particles make a pressure wave that voyages outward from its source. This pressure wave comprises compressions and rarefactions. The compressions are regions of high pressure, where the air particles are compressed into a little region of space. The rarefactions are districts of low pressure, where the air particles are spread and separated. This substituting design of compressions and rarefactions is known as a sound wave. A guitar string vibrating by itself does not deliver a really loud sound. The string itself disturbs exceptionally small air since its little surface zone makes exceptionally small contact with encompassing air particles. In any case, in case the guitar string is joined to a bigger object, such as a wooden sound box, at that point more air is aggravated. The guitar string forces the sound box to start vibrating at the same frequency as the string. The sound box in turn powers surrounding air particles into vibrational movement. Since of the huge surface range of the sound box, more discuss particles are set into vibrational movement. This produces a more capability of hearing a sound.
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water (2990 g ) is heated until it just begins to boil. if the water absorbs 5.11×105 j of heat in the process, what was the initial temperature of the water?
According to the given statement the initial temperature of the water is 54.171°C
What is unit of temperature?The SI unit of temperature is Kelvin, which is represented by the letter K. Kelvin is part of the International System of Units.
Briefing:Mass of water
= 2290 g
= 2.29 Kg
Heat absorbed (Q) = 5.11 x 10⁵ J = 511 KJ
Water is boiling, final temperature of water
= 100°C = 373 K
When water is getting warmed, the amount of heat absorbed to increase the temperature of water by 1°C is given by heat capacity.
Specific heat capacity of water
= 4.87 KJ/Kg
Mathematically,
Q = mCΔT
where
Q = Heat absorbed
m= mass of the water
C = specific heat capacity of water
ΔT = Temperature change
= Final temperature - initial temperature
Putting numerical values
511 = 2.29 x 4.87 x ΔT
⇒ΔT = 45.829
⇒Final temperature - Initial temperature = 45.829°C
⇒100°C - Initial temperature = 45.829°C
⇒ Initial temperature = 100 - 45.829 = 54.171°C
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Answer explanation !!!!!!!!!!
Answer:
65 meters for 5 seconds at a time
Explanation:
1. A car begins at a speed of 3m/s and accelerates at 2m/s² over a distance of 40m,
calculate the final speed of the car.
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: v = 13 \:\: m/s[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex] \texttt{Initial speed of the car (u) = 3 m/s} [/tex][tex] \texttt{final speed of the car (v) = ??} [/tex][tex] \texttt{acceleration of the car (a)= 2 m/s²} [/tex][tex] \texttt{distance covered in that time (s) = 40 m} [/tex]By third equation of motion :
[tex]\qquad \tt \rightarrow \: {v}^{2} = {u}^{2} + 2as[/tex]
[tex]\qquad \tt \rightarrow \: {v}^{2} = (3) {}^{2} + 2(2)(40) [/tex]
[tex]\qquad \tt \rightarrow \: {v}^{2} = 9 + 160[/tex]
[tex]\qquad \tt \rightarrow \: {v}^{2} = 169[/tex]
[tex]\qquad \tt \rightarrow \: v = 169[/tex]
[tex]\qquad \tt \rightarrow \: v = 13[/tex]
so, speed of the car after that time is : 13 m/s
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
superman throws a 1400 nn boulder at an adversary. what horizontal force must superman apply to the boulder to give it a horizontal acceleration of 15.0 m/s2m/s2 ?
The horizontal force superman apply to the boulder is F = 2142.9 N.
Equation :The boulder has a weight of
W = 1400 N
The weight of an object is the product between its mass m and the gravitational acceleration g:
W = mg
Rearrange the equation, we can calculate the mass of the boulder:
m = W / g
m = 1400 N / 9.8 m/s
m = 142.86 kg
As we know that Superman applies a horizontal force to this object, and as a result, the acceleration of the boulder is
a = 15 m/s²
We can find the force applied by using Newton's second law of motion:
F = ma
As, now we have m that is 142.86 kg and a is 15 m/s²
So, putting these values in formula we have,
F = 142.86 kg x 15 m/s²
F = 2,142.9 N
Hence, the horizontal force superman apply to the boulder is F = 2142.9 N.
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A bicyclist steadily speeds up from rest to 18.0m/s during a 4.40s time interval. Determine all unknowns and answer the following questions.
1. What is the magnitude of the bicyclist's acceleration?
2. How far did the bicyclist travel during this time?
1. The magnitude of the bicyclist's acceleration is 4.09 m/s²
2. The distance travelled by the bicyclist during the time is 39.6 m
1. How to determine the acceleration
We can obtain the acceleration of the bicyclist as illustrated below:
Initial velocity (u) = 0 m/sFinal velocity (v) = 18 m/sTime (t) = 4.40 sAcceleration (a) =?a = (v – u) / t
a = (18 – 0) / 4.40
a = 18 / 4.40
a = 4.09 m/s²
Thus, the acceleration of the bicyclist is 4.09 m/s²
2. How to determine the distance travelled
The distance travelled by the bicyclist can be obtained as follow:
Initial velocity (u) = 367 m/sFinal velocity (v) = 0 m/s (at maximum height)Acceleration(a) = 4.09 m/s²Distance (s) =?v² = u² + 2as
18² = 0² + (2 × 4.09 × s)
324 = 0 + 8.18s
324 = 8.18s
Divide both side by 8.18
s = 324 / 8.18
s = 39.6 m
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an exceptional standing jump would raise a person 0.80 m off the ground. to do this, what force must a 68-kg person exert against the ground? assume the person crouches a distance of 0.20 m prior to jumping, and thus the upward force has this distance to act over before he leaves the ground.
The force applied by the person is 2587.5N. The energy approach is by far and away the easiest. Earlier work equals potential energy (after).
Most issues involving forces and velocities can be solved using energy formulas like Ek = EP or W = Ep or W = Ek.
Always consider using an energy formula first; they frequently work and prevent the need for many steps to solve for one thing before moving on to another. It would take a while to find a solution if you approached it the way you did since you would have to tackle several problems as you went along. You must determine the initial takeoff speed using F = ma the way you did since you would have to tackle several problems as you went along. You must determine the initial takeoff speed using F = ma before utilizing V2f=V2i + 2ad then, given that Vf is zero, get Vi. You would then factor that into the same equation using that as your takeoff speed V2f = V2i + 2ad but this time it would be Vf. Vi would be 0, therefore the answer to the equation would be "a." The energy approach is by far and away the easiest.
Earlier work equals potential energy (after)
Fd = mghF = mgh/dF = (66)(9.81)(0.8)/0.2F= 2587.5N
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find the difference between the moon’s gravitational force on a 1 kg mass on the side of the earth facing the moon and an identical mass on the side of the earth opposite the moon (this difference is called the tidal force).
The tidal force is a gravitational phenomenon that, as a result of a gradient in the gravitational field from the other body, stretches a body along a line towards the center of mass of another body.
The surface gravity of the Moon is around 1/6th as strong, or 1.6 meters per second every second. Because the Moon is significantly less massive than Earth, its surface gravity is weaker. The surface gravity of a body is inversely related to the square of its radius but directly proportional to its mass.
The Earth is forced to orbit around the Earth-Moon center of mass, which is situated roughly 1600 km beneath the surface of the planet along a line connecting it to the Moon. It is possible to think of the tidal force as the difference between the force at the Earth's center and all other locations.
At sea level, where we can see the ocean tides, this distinction is evident. (Remember that the tidal forces' impact on sea level is measured relative to the baseline sea level.
As we previously observed, the rotation of the Earth causes a significant bulge along its equator. Here, we merely take into account the much smaller tidal bulge measured from that baseline sea level, which establishes the baseline sea level.)
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The time it takes to
wake up. Time interval or a time instant? (Please give me the right answer)
Answer:
Time interval
Explanation:
The amount of time it takes to wake up is a time interval because it has a start and stop time. For example, if someone's alarm goes off at 7AM and they fully wake up at 7:15AM, then the period from 7AM-7:15AM is a time interval.
1. Two particles are placed in a line 90.0 cm apart. One particle, q1, has a charge of 1.0 μC and the
other, q2, 3.0 μC. How far from q1 should a third charge of 2.0 μC be placed, so that the forces
acting on it are equal? HELPP
a movable bracket is held at rest by a cable attached at e and by frictionless rollers. knowing that the width of post fg is slightly less than the distance between the rollers, determine the force exerted on the post by each roller when α
The force exerted on the post by the roller,
A = D = 0B = 868 N ; C = 126.1 NThe equilibrium for bracket,
∑ [tex]F_{y}[/tex] = 0
T sin 20° - 270 = 0
T = 789.43 N
[tex]T_{x}[/tex] = ( 789.43 ) cos 20°
[tex]T_{x}[/tex] = 741.82 N
[tex]T_{y}[/tex] = ( 789.43 ) sin 20°
[tex]T_{y}[/tex] = 270 N
The 270 N force and [tex]T_{y}[/tex] forms a couple
τ = ( 270 ) 0.25
τ = 67.5 N m Clockwise
∑ [tex]M_{B}[/tex] = 0
( 741.82 * 0.125 ) - 67.5 + [tex]F_{CD}[/tex] ( 0.2 ) = 0
[tex]F_{CD}[/tex] = - 126.138 N
∑ [tex]F_{y}[/tex] = 0
[tex]F_{AB}[/tex] - 126.138 - 741.82 = 0
[tex]F_{AB}[/tex] = 867.96 N
The direction of force [tex]F_{CD}[/tex] is towards left and the direction of force [tex]F_{AB}[/tex] is towards right. The force [tex]F_{CD}[/tex] is exerted by roller B and the force [tex]F_{AB}[/tex] is exerted by roller C. Rollers A and D exert no force. The force exerted by the rollers exert oppositely on the post. So the force exerted by roller C is 126.1 N and the force exerted by roller B is 867.96 N.
Therefore, the force exerted on the post by the roller,
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a baseball mass 220.00 g approaches a bat horizontally at a speed of 32.20 m/s and is hit straight back at a speed of 54.50 m/s . if the ball is in contact with the bat for a time of 1.50 ms, what is the average force exerted on the ball by the bat? neglect the weight of the ball, since it is so much less than the force of the bat. choose the direction of the incoming ball as the positive direction.
According to the given statement F = -12716 N is the average force exerted on the ball by the bat.
What does "average force" mean?The average force is the force applied by an object traveling over a specific period of time at a given rate of speed, or velocity. This velocity is not immediate or precisely calculated, even as word "average" implies.
Briefing:m = 220 g = 0.22 kg
v[tex]_1[/tex] = 32.20m/s
v[tex]_2[/tex] = -54.50 m.s
t = 1.5 ms = 1.5 * 10⁻³
To find the average force exerted on the ball.
If we use the impulse-momentum theorem,
F = mv[tex]_2[/tex] - mv[tex]_1[/tex]/t
Now, we have to substitute values in equation 11:
[tex]$F=\frac{0.22 \mathrm{~kg} \cdot\left(-54.5 \frac{\mathrm{m}}{\mathrm{s}}\right)-0.22 \mathrm{~kg} \cdot\left(32.2 \frac{\mathrm{m}}{\mathrm{s}}\right)}{1.5 \cdot 10^{-3} \mathrm{~s}}$[/tex]
F = -12716 N
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If u move 50 meters in 10 sec, what is yor speed?
Which equation shows that mass is conserved in the chemical
reaction?
a 3N₂ + H₂ → 2NH3
b N₂ + H₂ → NH3
c N₂ + 2H2 → 3NH3
d N₂ + 3H2 → 2NH3
d N₂ + 3H2 → 2NH3 equation shows that mass is conserved in the chemical reaction
What is the law of mass conservation?According to the rule of conservation of mass, mass is neither generated nor destroyed during a chemical process. For instance, when coal is burnt, the carbon atom in it transforms into carbon dioxide.
According to the law of conservation of mass, a chemical reaction will not cause a change in the mass of a closed system. Mass just moves; it is neither generated nor destroyed.
Understanding and producing different chemical reactions depend heavily on this rule. Researchers might anticipate how much the result would be if they knew the names and amounts of the reactants for each reaction.
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5. How long would it take a truck to increase its speed from 10 m/s to 30 m/s if it does so
with uniform acceleration over a distance of 80 m ?
a) 8.0 s
b) 5.0 s
c) 4.0 s
d) 2.0 s
Answer:
C
Explanation:
Average velocity = (10+30) / 2 = 20 m/s
80 m / 20 m/s = 4 seconds
It would take a truck to increase its speed from 10 m/s to 30 m/s in 2.0 s. Option D is the correct answer.
To determine how long it would take for the truck to increase its speed from 10 m/s to 30 m/s, we can use the equations of motion. Option D is the correct answer.
The first equation we will use is: v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given:
Initial velocity, u = 10 m/s
Final velocity, v = 30 m/s
We need to find the time, t. Since the truck is accelerating uniformly, we can assume a constant acceleration. Next, we use another equation of motion: v² = u² + 2as, where s is the distance traveled.
Given:
Distance, s = 80 m
Initial velocity, u = 10 m/s
Final velocity, v = 30 m/s
Rearranging the equation, we get: s = (v² - u²) ÷ (2a)
Substituting the given values, we have: 80 = (30² - 10²) ÷ (2a)
Simplifying the equation, we find:
80 = (900 - 100) / (2a)
80 = 800 / (2a)
2a = 800 / 80
a = 10 m/s²
Now, we can go back to the first equation: v = u + at
Substituting the known values: 30 = 10 + 10t
Simplifying, we find: 10t = 20
t = 2 seconds
Therefore, it would take the truck 2.0 seconds to increase its speed from 10 m/s to 30 m/s.
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A car starts from rest and accelerates to it’s top speed of 50 m/s. If it accelerates at a uniform rate of 3 m/s2, then how long will it take to reach its’ top speed?
a battery with voltage v is connected to a chain of three capacitors in series each with a capacitance of , after a long time has passed each capacitor has a charge of q
A capacitor acts as a low-pass filter to increase damping and temporarily store energy, much like a spring-loaded shock absorber, to reduce vibrations when driving on washboard roads.
A battery with voltage v is connected to a chain of three capacitors in series each with a capacitance of , after a long time has passed each capacitor has a charge of q
Since there is only one channel for the charging current (iC) to take when capacitors are connected in series, the charging current (iC) going through all capacitors is the SAME.
Then, as iT = i1 = i2 = i3 etc., all capacitors connected in series have the same current flowing through them. As a result, regardless of capacitance, each capacitor will store the same quantity of electrical charge, Q, on its plates.
As we know,
Q = C*V
Applying Kirchhoff’s Voltage Law,
V = Qt/C1 + Qt/C2 + Qt/C3
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describe the techniques that industries can use to conserve water.
I have to get it done right now
Answer:
reducing water use, recycling water, install basic water-efficient technologies, and reusing water.
John rode 3,150 m at an average speed of 350 m/min. if he had ridden at average of 375 m/min instead, how many seconds fewer would the ride have taken him to complete?
John will take 0.6 min or 36 seconds more faster during uniform motion than before.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
s = v . t
where v is velocity, t is time and s is displacement.
From the question above, we know that
v1 = 350 m/min
v2 = 375 m/min
s = 3150 m
Find the initial time
s = v1 . t
3150 = 350 . t
t = 9 min
Find second time
s = v2 . t
3150 = 375 .t
t = 8.4 min
John will take 0.6 min or 36 seconds more faster than before
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Which statement best describes the difference between a physical change and a chemical change?.
A. A physical change produces a new element, and a chemical change results in a bond breaking between atoms.
B. A physical change is a change from one state of matter to another; a chemical change results in a new substance formed.
C. A chemical change does not result in a new substance being formed, whereas a physical change does.
D. A chemical change results in a new element being formed, and a physical change results in a new compound being formed
Work out the specific heat capacity of a substance if it takes 5,200J of energy to heat 2kg of it from 42°C to 47°C.
Answer:
specific heat capacity = 5 J/kg °C
Explanation:
To calculate the specific heat capacity of a substance, we can use the following formula:
[tex]\boxed{c= \frac{Q}{m \Delta T}}[/tex],
where:
• c = specific heat capacity
• Q = heat energy
• m = mass of substance
• ΔT = change in temperature
We know from the question that Q = 5200J, m = 2kg, and ΔT = 47 - 42 = 5°C.
Using this information as well as the formula above, we can calculate the specific heat capacity of the substance:
c = [tex]\frac{5200\ \mathrm{J}}{2\ \mathrm{kg} \times 5^{\circ}\mathrm{C}}[/tex]
= 5 J/kg °C
Therefore the specific heat capacity of the substance is 5 J/kg °C.
Answer: 520 J
Explanation:
What does it mean when the wave
crests of a transverse wave move
closer together?
A. The amplitude is getting bigger.
B. The amplitude is getting smaller.
C. The wavelength is getting smaller.
D. The wavelength is getting bigger.
When the wave crests of a transverse wave move closer together it means the wavelength is getting smaller.
Briefing :The wavelength of a transverse wave is the distance from one peak to the next or from one dip to the next. The wavelength gets shorter as the crests or troughs get closer together. The wavelength increases as the distance between the crests and troughs increases.
How wavelength affect a transverse wave?One way to gauge the size of waves is by their wavelength. It is the separation of two matching waves' neighboring points. In a transverse wave, the medium's particles vibrate up and down perpendicular to the wave's path of propagation. A longitudinal wave's wavelength can be calculated as its length. A crest and a trough make up a transversal. The largest upward displacement is at the crest, while the maximum downward displacement is at the dip.
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Answer:
C. The wavelength is getting smaller.
Explanation:
A cliff that is known to be 20 m high has a river that is 30 m wide, that runs below the cliff. With what minimum speed should you drive over the cliff so that the car crosses the river?
The minimum speed you should drive over the cliff so that the car can cross the river is 15 m/s
How to determin the minimum speedwe'll begin by obtainig the time taken for the car to cross the river. This can be obtained as follow:
Height (h) = 20 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) = ?h = ½gt²
20 = ½ × 9.8 × t²
20 = 4.9 × t²
Divide both side by 4.9
t² = 20 / 4.9
Take the square root of both side
t = √(20/ 4.9)
t = 2 s
Finally, we shall determine the minimum speed as follow:
Horizontal distance (s) = 30 mTime (t) = 2 sMinimum speed (u) = ?s = ut
30 = u × 2
Divide both sides by 2
u = 30 / 2
u = 15 m/s
Thus, we can conclude that the minimum speed needed is 15 m/s
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The minimum speed should be 15 m/s to drive over the cliff so that the car will cross the river.
What is Speed?The speed of an item, which is a scalar quantity in everyday usage and kinematics, can be defined as the size of the change in position per unit of time or the size of the change in position over time for an object.
The given values in the question are :
Height of the cliff, h = 20 m
The acceleration due to gravity, g = 9.8 m/s².
Use the formula,
h = 1/2gt²
20 = 1/2(9.8)t²
20 = 4.9 t²
t = 2 seconds.
Now, calculate the minimum speed,
s = ut
30 = u × 2
u = 30/2
u = 15 m/s.
Hence, the minimum speed required by the car to cross the river is 15 m/s.
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consider a parallel plate capacitor having plates of area 1.7 cm2 that are separated by 0.022 mm of neoprene rubber. you may assume the rubber has a dielectric constant κ
The simplest type of capacitor is the parallel plate capacitor. The capacitance value in Farads is fixed by the surface area of the conductive plates and the space between them, and it can be built using two metal or metallized foil plates placed parallel to one another at a distance.
Chloroprene is polymerized to create the family of synthetic rubbers known as neoprene. Good chemical stability and flexibility are displayed by neoprene over a broad temperature range.
A parallel-plate capacitor's capacitance is calculated by multiplying the dielectric constant by the permittivity of free space, the area of the plates, and the distance between them.
The generalised formula for a parallel plate capacitor's capacitance is given as C = ε(A/d), where stands for the absolute permittivity of the material being utilised as the dielectric. The value of the dielectric constant, commonly referred to as the "permittivity of open space," is 8.854 x 10-12 Farads per metre.
Therefore, Capacitance = ε x (area of plates / thickness of rubber)
= 8.854 x 10^-12 *(1700 / 0.022)
= 68.4173 farads
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explain and justify what would happen to the work done by the cable and magnitude of tension force as the crate was lifted the same height h but with a longer ramp.
Friction comes in two flavors: kinetic and static. Static friction affects a system or an object at rest, whereas kinetic friction affects an object in motion.
Typically, the maximal static friction between the objects is greater than the kinetic friction. Consider attempting to move a large crate across a concrete floor. The crate might not budge no matter how much you push on it. In other words, the static friction reacts to your actions by increasing to match and move in the opposite direction of your push.
However, if you exert enough force, the crate eventually looks to slip and begin to move. The kinetic friction force is lower than the static friction force, making it simpler to maintain motion once it is underway.
You would have to push more harder to initiate and maintain motion if you added mass to the crate (by, say, stacking a box on top of it). On the other hand, if you greased the concrete, it would be simpler to start and maintain the box.
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pls answer the 15a answer i cant understand it
Materials required for the experiment of limiting force borne by string:-
String balanceweightslight stringsweight hanger pan for spring balanceSandSteps of procedure for for the experiment of limiting force borne by string:-
First we have to tie a light string to the fixed support and then tie the other end with the weight hanger consists of weight.Add additional weight to the hanger again and again. And continue the same until the string is broken.Note down the weight (x) where the string is broken.Suspend spring balance to a support.Tie the light string at the end of the balance and at the other end suspend the pan for spring balance.Now place the weights (x-100 grams) in pan.Observe the reading in the spring balance.Add a small amount of sand in the pan by observing the readings.same is to be done till the string is broken.Learn more about limiting force here:- https://brainly.com/question/11371672
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a snowboarder glides down a 60-mm-long, 15∘∘ hill. she then glides horizontally for 10 mm before reaching a 26 ∘∘ upward slope. assume the snow is frictionless.
v ^2f-v^2i= 2a Replace the known values,
0-16^2=2 (-4.2)S, S= 256/8.4, S= 30.4m. The maximum distance a snowboarder could travel on a 25o slope was 30.4 meters.
The snowboarder travels a distance of H=50 meters on the hill. The hill slopes at a 15 degree slant. snowboarder's horizontal distance traveled after passing a slope, S=10m Crossing a horizontal distance, there is a 25-degree rising slope.
The snowboarder's initial speed at location A is u = 0 m/s. Let v be the representation of the final velocity. G = 10m/s2 is the acceleration caused by gravity. The snowboarder's acceleration at the incline is = a = 10 sin (15 degree)
The snowboarder moved 10 meters horizontally after reaching the bottom of the hill. Before she reaches the steep slope, as depicted in the illustration, her pace is unchanged. Now, at the top of the hill, where she could go the farthest, S
Vf = 0 m/sec would be the final speed.
To calculate the furthest she could go, write the equation of motion,
v ^2f-v^2i= 2a Replace the known values,
0-16^2=2 (-4.2)S, S= 256/8.4, S= 30.4m. The maximum distance a snowboarder could travel on a 25o slope was 30.4 meters.
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Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of what?.
The gravitational force between them will change by a factor 1/9.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
R2 = 3R1
By substituting the following parameters, we get
F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²
F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²
F2/F1 = 1/9
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an object accelerates from rest to a velocity of 4.0 m/s in 8 seconds. what
was its acceleration
Answer:
Acceleration (a) = 0.5 mp[tex]s^{2}[/tex]
Explanation:
Given,
Object starts from rest, hence the initial velocity of the object is said to be 0
Velocity in the next 8 seconds is 4.0 m/s
u = 0 m/s
v = 4 m/s
t = 8 secs
We know,
a = (v-u)/t
=> a = (4-0)/8
=> a = 4/8 = 0.5 m/[tex]s^{2}[/tex]
1. A scientist wants to test the sleeping effects of a mild animal tranquilizer on two of his pet rats. He decides that he will put them in two cages of the same size and shape and place them in the same area of his lab for 24 hrs. He decides that he is going to turn the lights on at 5am and turn the lights of at 8pm each day. He feeds both rats lunch each day at noon and chops up 5mg of animal tranquilizer into their food. He notes that at about 5pm both rats fall asleep and wake up at about 5am the following day. He continues this procedure for 15 days and notes the same pattern each day. He concludes that his study shows that the animal tranquilizer will cause all animals to fall asleep at 5pm for a total of 12 hrs.
Did this experiment give accurate results? Why or why not?
Since both rats get the tranquilizer and there is no control condition, the experiment is not accurate.
An experiment is what?An experiment would be carried out by a scientist in search of data and knowledge. We are aware that in an experiment, the impact of the independent variable on the dependent variable must be determined.
In this instance, the dosage of the medication is the independent variable, and the duration of sleep time for the pet rats is the dependent variable.
Let's notice that a controlled setting is required for every experiment.
What would be used to validate the experiment as we now understand it is the control setting of the experiment?We can observe that this experiment lacks a controlled environment, proving that it is not reliable.
A control setting should be introduced, and this experiment would need to be evaluated.
To learn more about the experiment.
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