Answer -2x^4 - 2x^3 + 22x^2 - 30x + 12Here's your solution => (2x^2 - 4x + 2) - (x^2 + 3x - 6) => (2x^2 - 4x + 2) -x^2 - 3x + 6 => firstly multiple whole with -x^2 => -x^2(2x^2 - 4x + 2) = -2x^4 + 4x^3 - 2x^2 => now with -3x => -3x(2x^2 - 4x + 2) = -6x^3 +12x^2 -6x => with 6=> 6(2x^2 - 4x + 2) = 12x^2 - 24x + 12 => now add all terms => -2x^4 - 2x^3 + 22x^2 - 30x + 12 hope it helps and your day will be full of happiness ^_^

Mathematics High School

Multiply polynomials

Answers

Answer 1

Answer -2x^4 - 2x^3 + 22x^2 - 30x + 12

Here's your solution

=> (2x^2 - 4x + 2) - (x^2 + 3x - 6)

=> (2x^2 - 4x + 2) -x^2 - 3x + 6

=> firstly multiple whole with -x^2

=> -x^2(2x^2 - 4x + 2) = -2x^4 + 4x^3 - 2x^2

=> now with -3x

=> -3x(2x^2 - 4x + 2) = -6x^3 +12x^2 -6x

=> with 6

=> 6(2x^2 - 4x + 2) = 12x^2 - 24x + 12

=> now add all terms

=> -2x^4 - 2x^3 + 22x^2 - 30x + 12

hope it helps and your day will be full of happiness ^_^

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