Need ASAP!! Please solve the equation and include steps if you're able to :). Best answer with steps gets Branliest

The average speed during the two seconds in which the runner moved from 15 meters from the finish line to 3 meters past the finish line is 9 m/s

The average speed of the runner can be determined by using the following formula;

speed = distance ÷ time

As she moved from 15 meters from the finish line to 3 meters past the finish line in 2 seconds, the total distance covered in these 2 seconds by her can be calculated as follows;

distance = 15 meters + 3 meters

distance = 18 meters

Now substituting the values for distance and time in the formula;

speed = 18 / 2

speed = 9 m/s

Hence the average speed of the runner during the two seconds is calculated to be 9 m/s.

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The probability a randomly selected worker primarily drives a car or takes public transportation to work is 0.915

Here's the complete question:

According to the U.S. census bureau, the probability a randomly selected worker primarily drives a car to work is 0.76. the probability a randomly selected worker primarily takes public transportation to work is 0.05. what is the probability a randomly selected worker primarily drives a car or takes public transportation to work?

Given that according to the U.S. Census Bureau:

The probability that a randomly selected worker primarily drives a car to work  is 0.867

The probability that a randomly selected worker primarily takes public transportation to work is 0.048

The probability that a randomly selected worker primarily drives a car or takes public transportation to work is

= 0.867 +0.048 = 0.915

(since these two are disjoint sets)

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Answer:

y=-2x+5

Step-by-step explanation:

This is my last one for today hahaha. Good luck on the rest.

Answer:

+ 9

Step-by-step explanation:

x² + 6x

to complete the square

add ( half the coefficient of the x- term )² to x² + 6x

x² + 2(3)x + 3²

= x² + 2(3)x + 9

= (x + 3)² ← a perfect square

Let's begin by listing out the information given to us:

Cost (c) = $1500, interest (r) = 8% /annum

The equation for this is given by:

11. The exponential function is given by: y = c * 1.08^z

12. The artwork is worth $3238.39

central angle Θ  of the circle is equal to =  3.6633333 radian

While a radian is another unit of measurement that is used to measure angles, a degree is a unit of measurement that is used to measure circles, spheres, and angles. The radian, or one pi radian, is only half the diameter of a circle, which has 360 degrees, or its entire area.

central angle of the circle is equal to = (14 * 3.14 )/12

                                                              = 3.6633333 radian
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Answer:

E. 4x - 1

Explanation:

An equation that represents the table satisfies that when we replace each value of x in the table, we get its respective value of y in the table.

So, the answer is:

y = 4x - 1

Because:

For x = -2, we get:

y = 4(-2) - 1

y = -8 - 1

y = -9

For x = -1, we get:

y = 4(-1) - 1

y = -4 - 1

y = -5

For x = 1:

y = 4(1) - 1

y = 4 - 1

y = 3

For x = 2:

y = 4(2) - 1

y = 8 - 1

y = 7

Since the diagonal is less than the circle's diameter, the Pythagorean theorem reveals that the square may fit within the circle without touching its edge.

Since squares are made up of two right triangles of equal length, the Pythagorean theorem is used to calculate the length of the hypotenuse of right triangles, which corresponds to the diagonals in squares.

The diagonal (L) of the square must be less than the diameter of the circle if it can fit within the circle without touching the edge (d). Therefore, we continue to establish this connection:

[tex]L=\sqrt{2}.5cm[/tex]

L ≈ 7.071 cm

Because the diagonal is less than the circle's diameter, the Pythagorean theorem reveals that the square may fit within the circle without touching its edge.

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Answer:

A (3; 4)

B (5; 2)

C (4; 0)

D (-6; -2)

E (-2; -5)

I hope this helps!

Answer: it would be either: 1 or 0 or 62

Step-by-step explanation:

ok

Answer: Your fourth point is going to be (-3,4). Hope this helps!

Step-by-step explanation:

The equation obtained for Kim will be t = x/2

Equation obtained for Jake will be t = (x - 6)/1.5

As for the problem, Kim and Jake are competing in the big race. And the values of their speed are given below.

Kim moves at a 2-meter-per-second running pace.

Jake moves at a 1.5 meter per second running pace (3 meters per 2 seconds)

Jake gets 6 meters ahead of Kim.

To get equations for the same case to both persons we should get it as,

Let x be the complete race distance and t be either Kim's or Jake's total race time.

Time = Speed/Distance

Kim's time equation is t = x/ 2.

The time equation that Jake uses is t = (x - 6)/1.5.

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The option that describes the sample you would ask is A. twenty students from one elementary class in your town.

It should be noted that a simple random sampling simply means a form of sampling whereby everybody has an equal chance of being selected.

In this case, it should be noted that the person wanted to take a simple random sample for a study on screen time in elementary school students in the town. Therefore, twenty students can be chosen to illustrate this.

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Answer:

x=15

Step-by-step explanation:

You can set up the equation like this

60 =3x+15

Get x by itself

45=3x

Divide both sides by 3

x=15

A maximum of 105 number of 120 kilograms can be loaded in the container.

What is Inequality?

A relation by which we can compare two or more mathematical expression is called an inequality.

Given that;

Weight of each crate = 120 kg

The greatest weight loaded in the container = 27500 kg

Weight already loaded in the container = 14900 kg

Now,

Since, Weight already loaded = 14900 kg

Let number of 120 kilograms loaded in the container = x.

Hence, Weight of x = 120 kg

So, After combined we get;

Weight nor be greater than the capacity of the container.

Hence, we can formulate;

14900 + 120x ≤ 27500

Subtract 14900 we get;

120x ≤ 27500 - 14900

120x ≤ 12600

x ≤ 12600 ÷ 120

x ≤ 105

Thus, A maximum of 105 number of 120 kilograms can be loaded in the container.

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The solution to the system is 6 and 11.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides. We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value of an unknown variable that represents an unknown quantity, equations can be solved. A statement is not an equation if it has no "equal to" sign.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" symbol and terms on both sides must always be present when writing an equation.

Given equation:

y=2x-1 .....(1)

y=x+5....(2)

Now solving equation 1 and 2, we get

2x -1 = x + 5

2x - x= 5 +1

x = 6

and, y= 2x-1

y= 2(6)-1

y= 12 -1

y= 11

Hence, the value of x is 6 and y is 11.

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Answer:

Step-by-step explanation:

Given isosceles trapezoid MNFD with short base NF = 6 cm, diagonal ND perpendicular to leg MN, and triangle MND median NX = 5 cm, you want ...

MD is the hypotenuse of right triangle MND. The median from the right angle of a right triangle is half the length of the hypotenuse, so ...

  MD = 2·NX = 2·(5 cm)

  MD = 10 cm

In the attached diagram, we see that right triangle XYN has side XY = 3 (half of NF), and hypotenuse NX = 5 (given). These are two sides of a 3-4-5 right triangle, so the remaining side, altitude h, is 4.

  h = 4 cm

The attache diagram shows congruent side lengths MN and FD are the hypotenuse of a right triangle with sides YM = 2 and YN = 4. The Pythagorean theorem tells us the length of side MN is ...

  MN² = MY² +NY²

  MN² = 2² +4² = 4 +16 = 20

  MN = √20

  MN = FD = 2√5 ≈ 4.47

Triangle MND has a base length MD = 10 and a height h = 4. Triangle NFD has a base length NF = 6 and a height h = 4. The ratio of the areas of these two triangles is ...

  [tex]\dfrac{A_{MND}}{A_{NFD}}=\dfrac{\frac{1}{2}\cdot10\cdot4}{\frac{1}{2}\cdot6\cdot4}=\dfrac{10}{6}=\boxed{\dfrac{5}{3}}[/tex]

The ratio between the areas is 5 : 3.

__

Additional comment

We are also given the area of the trapezoid as 32 cm². That can be used to find the longer base and/or the altitude, or to check the answers we have for those values. It is redundant information.

The midpoint X of MD is the center of the circumscribing circle of the trapezoid and right triangles MND and MFD. The midpoint of the hypotenuse of a right triangle is always the circumcenter, so knowing the length NX tells us the radius of that circle, hence MX and XD.

The common denominators and the equivalent fractions are discussed below.

A fraction represents a part of the whole or group of objects.

Given are the pair of fractions.

1 -  1/8 and 1/2

The common denominator will be - 16

(1 x 2)/(8 x 2) = 2/16

(1 x 8)/(2 x 8) = 8/16

2 -  1/8 and 9/5

The common denominator will be - 40

(1 x 5)/(8 x 5) = 5/40

(9 x 8)/(5 x 8) = 72/40

3 - 1/8 and 11/6

The common denominator will be - 48

(1 x 6)/(8 x 6) = 6/48

(11 x 8)/(6 x 8) = 88/48

Therefore, the common denominators and the equivalent fractions are discussed above.

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Answer:

434

Step-by-step explanation:

Steps:

156.24 ÷ 36% = 156.24 ÷ 0.36 = 434

The function is f(x) = 1/3(27)ˣ, the key aspects are domain: -oo < x < oo and range: y ≥ 1/3

From the question, the equation of the function is given as

f (x) = one-third (81) Superscript StartFraction 3 x Over 4 EndFraction

Rewrite the equation properly

So, we have

f(x) = 1/3(81)³/⁴ˣ

Express 81 as 3 exponent 4

So, we have the following equation

f(x) = 1/3(3⁴)³/⁴ˣ

Evaluate the exponents

f(x) = 1/3(3)³ˣ

Further, evaluate the exponents

f(x) = 1/3(27)ˣ

Next, we calculate the key aspects i.e. the domain and the range

The above function is an exponential function.

The domain of an exponent is the set of all real values

Set the radicand to 1, to calculate the range

So, we have

y = 1/3 * 1

Evaluate

y = 1/3

Since the coefficient, this value is a minimum

So, the range is

y ≥ 1/3

Hence, the simplified function is f(x) = 1/3(27)ˣ

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Answer:

1/3

27

all real numbers

y > 0

or B. C. D. B.

Step-by-step explanation:

hope I could help

At the end of the sixth second, the coin will have fallen 176 feet in Arithmetic Progression.

What is Arithmetic Progression (AP)?

16, 48, 80, ?

Use  The sum up to nth terms of an AP is given as :-

S(n) = (n/2)[2a + (n - 1)d]

In this arithmetic sequence, each term is 32 more than the one immediately before it.

So,

16, 48, 80, 112, 144,  176

At the end of the sixth second, the coin will have fallen 176 feet.

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The solution is Option A.

The value of the 13th number from the equation A = ( -2/3 ) ( n - 1 ) is A = -8

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

A = ( -2/3 ) ( n - 1 )   be equation (1)

On simplifying the equation , we get

The thirteenth number in the list is n = 13

So , when n = 13

A = ( -2/3 ) ( n - 1 )

A = ( -2/3 ) ( 13 - 1 )

On further simplification , we get

A = ( -2/3 ) ( 12 )

A = ( -2 ) x 4

So , the value of A = -8

Hence , the thirteenth number in the list is A = -8

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1. The θ lies in the 2nd quadrant of the graph.

2. The θ lies in the 1st quadrant of the graph.

3. The θ lies in the 3rd quadrant of the graph.

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Henry can write 13 pages in 8 hours, at this rate.

This is a problem from the unitary method. We can solve this question following a few steps.

Here if Henry can write 5 pages of his novel in 3 hours. We have to find the number of pages that Henry can write within 1 hour.

The number of pages Henry can write within 1 hour is 5/3 pages.

[Number of pages within a unit hour = number of total pages/ total hour]

Therefore, Henry writes in 8 hours is, ( 5/3 × 8 ) = 40/3 = 13.33 ≈ 13 pages

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Answer:

80

Step-by-step explanation:

→ Work out how many rabbits after 60 days

20 rabbits

→ Work out how many rabbits after 90 days

40 rabbits

→ Work out how many rabbits after 120 days

80 rabbits

Answer:

-49 and then -63

Step-by-step explanation:

it is going by -14s

Answer:

2880 seats

Step-by-step explanation:

r1 r2 r3 r36

20 + 20+4 + 20+4+4 + ···+20+4×35

total seats = ((20 + 20+4×35)÷2)×36= 2880

198, 714

a. What digit is in the ten thousands place? - 9

b. Which place is used to decide which way to round the ten thousands place? - thousands place

c. What is the digit in this place? - 8

d. Should you round the number in the ten thousands place up or down? - UP

e. What happens when you round up a 9? - It becomes 10.

f. What do you do when the value of a place is 10 or more? - The number becomes 0 and we add 1 to the next place to the right.

g. What is the value of the ten thousands place when the number is rounded to the nearest ten thousand? 100,000

h. What is 198,714 rounded to the nearest ten thousand? - 200,000

i. What is 302,895 rounded to the nearest thousand? - 303, 000

j. What is 7,142 rounded to the nearest ten? - 7, 140

k. Round 24,793 to the nearest hundred? - 24, 800



Answer: When x=3 y=-3

Step-by-step explanation:

The relation given can be classified as a function as every single input corresponds to a single output value.

The difference between a relation and a function lies in the fact that a relation can have many outputs for a single input, but a function has a single input for a single output. The statement above is the distinctive property between a relation and a function.

The relation given in the task content is a function as every single input has a single output as evident in the function.

Hence, the domain of the function is; {x | x : 0, 2, 3} while the range is; {y | y : 0, 22, 33}.

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