Omar buys eggs and lemons at the store.
He pays a total of $26.10.
He pays a total of $6.30 for the eggs.
• He buys 6 bags of lemons that each cost the same amount.
How much does each bag of lemons cost?

Answers

Answer 1

Answer:

Each bag of lemons cost $3.30

Step-by-step explanation:

The equation will be

6x = 26.10 - 6.306x=26.10−6.30

Solve for x to get,

6x = 19.86x=19.8

x = 3.3x=3.3

Answer 2

Answer:

$3.30 for each bag of lemons

Step-by-step explanation:


We know that Omar only bought both lemons and eggs. We also know that the total amount of money he spent on groceries is $26.30 and that the eggs are worth $6.30 out of the total.


So, if we can subtract the cost of the eggs from his total cost of groceries to find how much the lemons cost. After that we can divide the cost of all the lemons, which is $19.80, by the number of bags, which is 6, to find how much each bag costs.

(26.10 - 6.30) / 6 = ?

19.8/6 = 3.30



Related Questions

15. The area of a triangle is given by
A = 1/2bh, where b is the base and h is the height of the triangle. In the triangle PQR above, PR=6, PQ=7, QR=12, and PH=3. If PH is perpendicular to QR, what is the area of the triangle PQR?
(A) 12
(B) 18
(C) 36
(D) 42

Answers

The answer is (B) 18.

In order to calculate the area of a triangle we must use the equation 1/2·base·height.

In this case, the base of the triangle would be QR, which is 12. The height would be PH, which is 3.

Using the formula above, we can do 1/2·12·3 which equals 18. This is the area of triangle PQR and our final answer.

Hope this helps.

(1/8) raised to -x ppwer= 64 raised to x powerI'll upload a picture

Answers

x = 0

Explanation:[tex](\frac{1}{8})^{-x}=64^x[/tex][tex]\begin{gathered} \frac{1}{8\text{ }}\text{ = }\frac{1}{2^3}\text{ } \\ \text{Rule: }\frac{1}{a^b}=a^{-b} \\ so,\text{ }\frac{1}{2^3}=2^{-3} \\ (\frac{1}{8\text{ }})^{-x}=(\frac{1}{2^3})^{-x}\text{ = }(2^{-3})^{-x} \\ =2^{3x} \end{gathered}[/tex][tex]\begin{gathered} 64=2^6 \\ 64^x=(2^6)^x=2^{6x} \\ (\frac{1}{8})^{-x}=64^x \\ 2^{3x}\text{ = }2^{6x} \\ \text{base cancels out:} \\ 3x\text{ = 6x} \end{gathered}[/tex][tex]\begin{gathered} 3x\text{ - }6x\text{ = 0 } \\ -3x\text{ = 0} \\ \text{divide both sides by -3:} \\ \frac{-3x}{-3}\text{ = }\frac{0}{-3} \\ x\text{ = 0} \end{gathered}[/tex]

Please show work THANK YOU

Answers

The net force  acting on the object is 12.44 N.

In this problem, we are dealing with the magnitude of a vector, where A vector is an object that has both a magnitude and a direction. Geometrically, able to picture a vector as a directed line segment, whose length is the magnitude of the vector, and with an arrow showing the direction. A vector's magnitude  is the length of the vector. The magnitude of the vector a is signified as ∥a∥. Since we are provided with magnitudes of the three forces acting on the object which are (-8,5), (0,1), and (4, -7) So  we can represent them in terms of vectors which are :

F₁= -8i+5j

F₂= j

F₃ = 4i-7j

The magnitude of a vector is basically to add the individual horizontal and vertical components to get the horizontal and vertical components of the resultant force, then sum up the square of the  vertical components and horizontal of the resultant force and take the square root of the result.

F(net) =[tex]\sqrt{}[/tex]( F₁²+ F₂²+ F₃²)

  =[tex]\sqrt{}[/tex] ((-8)²+(0)²+(4)²) +((5)²+ (1)²+(-7)²)

 =[tex]\sqrt{}[/tex](64+16)+(25+1+49)

= 12.44  N

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Need help with this one

Answers

Answer: The answer should be 10^2  or C

Step-by-step explanation: 65.108 if you move the six to left 2 times you will get 6,510.8

40% of the airplanes were hydroplanes. If 660 were hydroplanes, how many were not hydropons?

Answers

40% of the airplanes were hydroplanes.

If 660 were hydroplanes, how many were not hydroplanes?​

SOLUTION

If 40% of the airplanes were hydroplanes.

Let x represents the total number of Hydroplanes.

So that 40 % of X = 660

40/ 100 x X = 660

2 / 5 x X = 660

2X / 5 = 660

cross- multiply, we have:

2X = 660 X 5

2 X = 3300

Divide oth sides by 2 , we have :

X = 3300 / 2

X = 1650

Total number of Hydrophones = 1650

Those that are Hydrophones = 660

Those that are not Hydrophones = 1650 - 660

= 990

solve. -6 4/9 - 3 2/9 - 8 2/9

Answers

Answer:

the answer is -17 8/9

Step-by-step explanation:

when "subtracting" negative numbers you actually add all of them together and attach the negative sign

Select all the equations that represent lines perpendicular to Y= 3x+4.A. Y= -1/3xB. 6x-2y=4C. 3y= -x+7D. X+3y=4E. y=3x-10

Answers

if two lines are perpendicular it is true that:

[tex]m1\cdot m2=-1[/tex]

For the line:

[tex]\begin{gathered} y=3x+4 \\ m1=3 \end{gathered}[/tex]

Let's check every line:

[tex]\begin{gathered} y=-\frac{1}{3}x \\ m2=-\frac{1}{3} \\ m1\cdot m2 \\ 3\cdot-\frac{1}{3}=-1=-1 \end{gathered}[/tex]

So, A is a correct choice

[tex]\begin{gathered} 6x-2y=4 \\ y=3x-2 \\ m2=3 \\ m1\cdot m2 \\ 3\cdot3=9\ne-1 \end{gathered}[/tex]

B is not a correct choice

[tex]\begin{gathered} 3y=-x+7 \\ y=-\frac{1}{3}x+\frac{7}{3} \\ m2=-\frac{1}{3} \\ m1\cdot m2 \\ 3\cdot-\frac{1}{3}=-1=-1 \end{gathered}[/tex]

C is a correct choice

[tex]\begin{gathered} x+3y=4 \\ y=-\frac{1}{3}x+\frac{4}{3} \\ m2=-\frac{1}{3} \\ m1\cdot m2 \\ 3\cdot-\frac{1}{3}=-1=-1 \end{gathered}[/tex]

D is a correct choice

[tex]\begin{gathered} y=3x-10 \\ m2=3 \\ m1\cdot m2 \\ 3\cdot3=9\ne-1 \end{gathered}[/tex]

E is not a correct choice

Use a table of trigonometric values to find the angle θ in the right triangle in the following problem. Round to the nearest degree, if necessary.
sin θ = 0.7071 O = 5 H = ?

Answers

By applying sine trigonometry, the angle θ in this right angled triangle is approximately equal to 50 degrees.

What is the law of sines?

In Trigonometry, the law of sines is also referred to as sine law or sine rule and it can be defined as an equation that relates the side lengths of a triangle to the sines of its angles.

How to apply basic trigonometry?

In order to determine the value of H, we would apply basic trigonometry. From the information provided about this right angled triangle, we can logically deduce the following parameters:

sinθ = 0.7071Opposite (Opp) = 5Hypotenuse (Hyp) = H.

Therefore, we would use the sine trigonometry to determine the value of H as follows:

Sinθ = Opp/Hyp

0.7071 = 5/H

H = 5/0.7071

H = 7.0711.

Now, we can determine the angle θ in this right angled triangle as follows:

Sinθ = Opp/Hyp

Angle, θ = sin⁻¹(Opp/Hyp)

Angle, θ = sin⁻¹(5/7.0711)

Angle, θ = sin⁻¹(0.7071)

Angle, θ = 44.999 ≈ 50°.

Angle, θ = 50 degrees.

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For the following exercise graph the given ellipse, noting center, vertices, and foci #41

Answers

Given the equation of an ellipse: #41

[tex]x^2+8x+4y^2-40y+112=0[/tex]

To find the center and the vertices, we will complete the square of (x) and (y):

[tex]\begin{gathered} x^2+8x+4(y^2-10y)=-112 \\ (x^2+8x+16)+4(y^2-10y+25)=-112+16+100 \end{gathered}[/tex]

Factor for (x) and (y) then simplify:

[tex]\begin{gathered} (x+4)^2+4(y-5)^2=4\rightarrow(\div4) \\ \\ \frac{(x+4)^2}{4}+\frac{(y-5)^2}{1}=1 \end{gathered}[/tex]

The general form of the ellipse will be:

[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]

Comparing the equation with the form:

[tex]\begin{gathered} (h,k)=(-4,5) \\ a=\sqrt[]{4}=2 \\ b=\sqrt[]{1}=1 \\ c=\pm\sqrt[]{a^2-b^2}=\pm\sqrt[]{4-1}=\pm\sqrt[]{3} \end{gathered}[/tex]

The graph of the ellipse will be as shown in the following picture:

As shown in the figure:

The center C = (h,k) = (-4 , 5)

The vertices denoted by V = (-6, 5) and (-2, 5)

Foci denoted by F =

[tex](-4+\sqrt[]{3},5),(-4-\sqrt[]{3},5)[/tex]

Event A, Event B, and Event C are provided. Event A and Event B aremutually exclusive. Event A and Event C are not mutually exclusive.P(A) = 0.45P(B) = 0.30P(C) = 0.25What is the probability of the complement of Event A [Find P(A')] ?Be sure to show your work and/or explain your reasoning.

Answers

If two events are mutually exclusive this means they cannot occur at the same time and do not over lap

If two events are mutually inclusive this means they can occur at the same time and they over lap

Event A and Event B are mutually exclusive

Event A and event C are not mutually exclusive

To find the complement of event A (A'), which is the part of the universal set of events not in A

We use the formula

[tex]1\text{ - P(A)}=P(A^{\prime})[/tex]

P(A) = 0.45

substituting this into the equation yields

[tex]\begin{gathered} 1-\text{ 0.45 = P(A')} \\ P(A^{\prime})\text{ = 0.55} \end{gathered}[/tex]

P(A') = 0.55

Consider the transformation shown.
6
8
Pre-image
Intro
10
3
5
Image
Use the drop-down menus to complete the sentence.
The transformation is
because the
preserved.
Done

Answers

The transformation is non rigid

What transformations ?

Transformations involve the rotation, reflection, or translation of forms on a coordinate plane. Transformational geometry is a fresh viewpoint on geometry that Felix Klein suggested in the 19th century. The majority of geometric proofs rely on the transformations of objects. Any image in a coordinate plane can be changed using transformations. Applying the transformational laws will help you better understand the graphics in video games. Learn to recognize transformations, comprehend function transformation principles, and investigate the various forms of transformations.

What is non rigid transformations ?

Non-Rigid Transformations actually alter the original object's structure. Scaling, for instance, allows us to make our object larger or smaller. Alternatively, shearing can be used to "push" it up or to the side. In essence, non-rigid transformations allow an object's size to change.

because the size became small as compare to pre image it is non rigid transformation

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Find an equation for the graph sketched below.

Answers

The equation for the graph sketched below is given as y = -3(3)^x

Exponential equation

The standard form of an exponential equation is given as y = ab^x

Using the coordinate points on the graph (-1, 1) and (0, -3)

The equivalent equations are;

1 = ab^-1

-3 = ab^0

From equation2;

a= -3

Substitute into equation 1;

1 = ab^-1

1 = 3b^-1

1 =3/b

b =3

Determine the equation

y = ab^x

y = -3(3)^x

This gives the required exponential equation

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2. Let f(x) = 5x² - 2x - 7.
(a) find f(0)
(b) find f(-3)
(c) find x if f(x) = 0

Answers

(A) f(0) = 5*0 - 2*0 - 7 = -7
(B) Same calcul with -3 f(-3) = 25
(C) delta = b^2 - 4ac
= -2^2 - 4*5*(-7)
= 4 + 140
= 144 so delta>0 2 solutions
X1 = -10/10 = -1
X2 = 14/10 = 7/5

Answer:

A) f(0) = -7

B) f(-3) = 44

C) x = -1, (7/5)

Step-by-step explanation:

2. Let f(x) = 5x² - 2x - 7.

(a) find f(0)

f(x) = 5x² - 2x - 7

f(0) = 5(0)² - 2(0) - 7

f(0) = -7

(b) find f(-3)

f(x) = 5x² - 2x - 7

f(-3) = 5(-3)² - 2(-3) - 7

f(-3) = 5(9) - 2(-3) - 7

f(-3) = 45 + 6 - 7

f(-3) = 45 + 6 - 7

f(-3) = 44

(c) find x if f(x) = 0

f(x) = 5x² - 2x - 7

f(x) = 5x² - 2x - 7 = 0

(5x² + 5x)(-7x - 7)

5x(x + 1) -7(x + 1)

(5x - 7)(x + 1)

5x - 7 = 0,  x + 1 = 0

    +7   +7       -1    -1

---------------  ---------------

5x = 7             x = -1

÷5   ÷5

------------

x = (7/5)

5(-1)² - 2(-1) - 7 = 0

5(7/5)² - 2(7/5) - 7 = 0

----------------------------------------------------------------------------------------------------------

I hope this helps!

Find S7 of the sum of the geometric series. a1 = 729, a? = 1, r = 1

Answers

Let's write out the formula for the sum of geometric series,

[tex]S_n=\frac{a(1-r^n)}{1-r}[/tex][tex]\begin{gathered} \text{where a=first term=729} \\ r=\text{common ratio=}\frac{1}{-3} \\ S_7=?,\text{ where n= number of terms=7} \end{gathered}[/tex]

Let's solve for the sum of seven geometric series,

[tex]\begin{gathered} S_7=\frac{729(1-(-\frac{1}{3})^7)}{1-(-\frac{1}{3})} \\ =\frac{729(1-(-\frac{1}{2187}))}{1+\frac{1}{3}} \\ =\frac{729(1+\frac{1}{2187})}{\frac{4}{3}} \end{gathered}[/tex]

[tex]\begin{gathered} S_7=\frac{729(1\frac{1}{2187})}{\frac{4}{3}} \\ =\frac{729(\frac{2188}{2187})}{\frac{4}{3}}=\frac{\frac{2188}{3}}{\frac{4}{3}} \\ =\frac{2188}{3}\frac{\text{.}}{.}\frac{4}{3} \\ =\frac{2188}{3}\times\frac{3}{4}=547 \end{gathered}[/tex]

Hence,

[tex]S_7=547[/tex]

Therefore, option 5 is the correct answer.

Option 5 is none of these are correct.

Whats the correct answer answer asap for brainlist

Answers

Answer:

It is A how the body responds to a change

Pls help will rate 5 stars and maybe also brainliest. Pls help anyways tysm

Answers

Answer:

1. Decimal: 0.1 Fraction: 1/10

2. Decimal: 0.8 Fraction: 8/10

3. Decimal: 0.4 Fraction: 4/10

4. Decimal: 0.6 Fraction: 6/10

5. Decimal: 0.7 Fraction: 7/10

Explaination:

brainliest me if it helps!

A company is reviewing a batch of 26 products to determine if any are defective. On average, 3.6% of products are defective.What is the probability that the company will find 2 or fewer defective products in this batch?What is the probability that 4 or more defective products are found in this batch?If the company finds 5 defective products in this batch, should the company stop production?

Answers

The experiment has a binomial distribution just because the product could be or not defective. In this case you have n=26 the number of product that the company will check and you also know that the probability to get a defective one is 3.6%. Now we will proceed as follows, to find the probability of getting 2 or fewer defective products is exactly the same that

[tex]\begin{gathered} P(X\leq2)=P(X=0)+P(X=1)+P(X=2)\text{ } \\ \text{ where }X\text{ is a random variable that measures the number of defective products} \end{gathered}[/tex]

We also should notice that

[tex]P(X=k)=(n;k)p^k(1-p)^{(n-k)};\text{ where }(n;k)=\frac{n!}{k!(n-k)!}[/tex]

Now,

[tex]P(X=0)=(26;0)(0.036)^0(1-0.036)^{26-0}=(1-0.036)^{26}\approx0.3855[/tex][tex]P(X=1)=(26;1)(0.036)(1-0.036)^{26-1}=26(0.036)(1-0.036)^{25}\approx0.3743[/tex][tex]P(X=2)=(26;2)(0.036)²(1-0.036)^{26-2}=325(0.001296)(1-0.036)^{24}\approx0.1747[/tex]

Then the probability that the company takes 2 or fewer defective products in this batch is

[tex]P(X\leq2)=P(X=0)+P(X=1)+P(X=2)=0.3855+0.3743+0.1747=0.9345[/tex]

Now, to get the probability that the company find 4 or more defective products we proceed as follows. Since

[tex]P(X\ge4)+P(X<4)=1,\text{ }[/tex]

then

[tex]P(X\ge4)=1-P(X<4)=1-(\text{ }P(X=0)+P(X=1)+P(X=2)+P(X=3)).[/tex]

Notice that we only need to find one of these probabilities to get the answer.

[tex]P(X=3)=(26;3)(0.036)³(1-0.036)^{26-3}=\frac{23!(24)(25)(26)}{3!23!}(0.036)³(1-0.036)^{23}=0.05219[/tex]

Then the probability to get more than 4 defective products is

[tex]\begin{gathered} P(X\ge4)=1-(P(X=0)+P(X=1)+P(X=2)+P(X=3))= \\ =1-(0.9345+0.05219)=0.01331 \\ \\ P(X\ge4)=0.01331 \end{gathered}[/tex]

So if the company finds 5 defective products in this batch the company should stop the production because the probability to get more than 4 defective products is around 1.3%. It means that if you get 5 defective products even with this small probability then we could say that is really probable to get more defective products that those who were expected.

URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS

Answers

A - Reflection over y-axisB - Translation 3 rightC - Translation 4 downD - Reflection over x-axis.What is termed as reflection of figures?A reflection is just a transformation that represents a figure flip. Figures can be reflected in the form of a point, a line, or even a plane. When a figure is reflected in a line or a point, the image would be congruent to a preimage.Every point on a figure is mapped to an image by a reflection along a fixed line. The fixed line is referred to as the line of reflection.

For the given question,

Figure A and D are the cases of reflection over y and x axis respectively.

What is termed as Translation?In mathematics, a translation is the movement of a shape to the left or right and/or upward or downward. The translated shapes appear to be the same size as that of the original shape, and thus the shapes are congruent. They were simply shifted in one or even more directions.

For the given question,

Figure B and C are the cases of translation 3 right and 4 down respectively.

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f(x) = -x +2^x+8
Find f(-2)

Answers

Value of f(-2) is 12.25.

What is equation?

Equation, also known as a statement of equivalence between two expressions with variable- and/or number-based components. In essence, equations are questions, and efforts to discover a method for answering them have fueled the growth of mathematics.

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated by the symbol "equal."

Given Data

Expression

f(x) = -x +2ˣ+8

f(-2)

Equating -2 in the place of x

= -(-2) + 2⁻² + 8

= 4 + 8 +[tex]\frac{1}{4}[/tex]

= [tex]\frac{16+32+1}{4}[/tex]

= [tex]\frac{49}{4}[/tex]

= 12.25

Value of f(-2) is 12.25.

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If Thiyo traveled 420 miles at the same rate, how many hours did he drive?Enter your answer as a decimal into the box. h

Answers

Solution:

Speed is expressed as

[tex]\text{speed = }\frac{dis\tan ce\text{ covered}}{time\text{ taken}}[/tex]

Given that Thiyo traveled 420 miles at 56 mi/h, let t represent the number of hour he drove.

Thus,

[tex]56\text{ mi/h = }\frac{420\text{ miles}}{t}[/tex]

Make t the subject of the formula.

[tex]\begin{gathered} 56\text{ mi/h = }\frac{420\text{ miles}}{t} \\ \text{Multiply through by t} \\ t(56\text{ mi/h) = t(}\frac{420\text{ miles}}{t}) \\ 56t=420 \\ \text{divide both sides by the coefficient of t, which is 56.} \\ \text{thus, } \\ \frac{56t}{56}=\frac{420}{56} \\ \Rightarrow t=7.5\text{ hours} \end{gathered}[/tex]

Hence, Thiyo drives for 7.5 hours.

If it laptop computer right now because $1549 and is on sale for $1149 what percentage discount is being given round your answer to the nearest hundredth when necessary

Answers

Okay, here we have this:

Considering the following equation:

Sale Price=Original Price*(100%-Percentage discount)

Replacing we obtain:

$1149=$1549*(100%-Percentage discount)

$1149/$1549=(100%-Percentage discount)

0.7417=100%-Percentage discount

Percentage Discount=100%-0.7417

Percentage Discount=1-0.7417

Percentage Discount=0.2583

Percentage Discount=25.83%

Finally we obtain that the discount percentage is 25.83%.

Chris and Beth Micelli made a $235,000 offer for the purchase of a new home, which was accepted. They made a 30% down payment and financed the rest. Using the closing cost table below, find the mortgage total if they include the closing costs in the mortgage amount.

Answers

The amount of mortgage will be the remaining amount after they made a downpayment.

Since the downpayment is 30%, the mortgage will be 70% of the purchased amount

So mortage will be :

mortgage = 0.70 x $235,000 = $164,500

From the closing cost table :

There are charges related to the mortgage (Points, Document stamp and Processing fee)

Adding these charges will be :

=2% + 0.30% + 1.10% = 3.4% of the mortgage

So this will give us :

= 0.034 x $164,500 = $5,593

Now to find the total mortgage, add the values in the closing cost table including the mortgage itself.

Total mortgage = 164500 + 5,593 + 252 + 65 + 325 + 212 + 410 + 350 + 450

Answer :

Total mortgage = $172,157

Point M is the midpoint of AB¯¯¯¯¯. AM=2x+9, and AB=8x−50.

What is the length of AM¯¯¯¯¯¯?

Answers

Answer:

43

Step-by-step explanation:

→ Set up an equation

2x + 9 = 0.5 ( 8x - 50 )

→ Simplify

2x + 9 = 4x - 25

→ Minus 4x from both sides

-2x + 9 = -25

→ Minus 9 from both sides

-2x = - 34

→ Divide both sides by -2

x = 17

→ Substitute into AM

2 × 17 + 9 = 34 + 9 = 43

What is 80% of 45?
WITH EXPLINATION PLS!!

Answers

Answer: The 80% of 45 is 36

Step-by-step explanation:

Write 80% as

80

100

Since finding the fraction of a number is the same as multiplying the fraction with the number, we have

80

100

of 45 =

80

100

× 45

Therefore, the answer is 36

If you are using a calculator, simply enter 80÷100×45 which will give you 36 as the answer. Hope it helps!

x = -CD/CD2-40 DC8x2 + 8x = -2Write the quadratic equation in standard form:( a )x2 + ( b )x+ C) = 0Identify the values of a, b, and c.b =Substitute these values into the quadratic formula and simplify:2( )a =C=

Answers

So the initial equation is:

[tex]8x^2+8x=-2[/tex]

To writte the equation in the standard form we have to make it equal to 0, so we can add 2 in bout sides of the equation:

[tex]\begin{gathered} 8x^2+8x+2=-2+2 \\ 8x^2+8x+2=0 \end{gathered}[/tex]

now, (a) is the number thas goes with the x^2, (b) is the number that goes with the x and (c) is the number that is alon, so:

[tex]\begin{gathered} a=8 \\ b=8 \\ c=2 \end{gathered}[/tex]

Now we can substitute this numbers in the quadratic equation:

[tex]\begin{gathered} \frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \frac{-8\pm\sqrt[]{8^2-4(8)(2)}}{2(8)} \end{gathered}[/tex]

and finally we can simplify the equation:

[tex]\begin{gathered} \frac{-8\pm\sqrt[]{64-64}}{16} \\ \frac{-8}{16}=\frac{-4}{8}=\frac{-2}{4}=-\frac{1}{2} \end{gathered}[/tex]

SO GUYSS I NEED THIS TODAY if it not to much to ask for.....
how does simple interest show proportional reasoning and relate to the percent equation

Answers

Answer: Use cross-product to determine if the two ratios form a proportion.

The relationship between proportion and percentage is when a proportion is multiplied by 100 it gives the percentage of parts taken i.e.(Parts /whole) × 100 = percent. Similarly, when a percent is multiplied by total it gives the number of parts taken i.e. Parts = percent × whole.


Multiplying Binomials with Fractional Coefficients
Express the product of (2x + 3) and (x − 3) as a trinomial in simplest form

Answers

[tex] = (2x + 3)(x - 3) \\ = 2x(x - 3) +3 (x - 3) \\ = 2 {x}^{2} - 6x + 3x - 9 \\ = 2 {x}^{2} - 3x - 9[/tex]

ATTACHED IS THE SOLUTION

When a number is added to 20 and 5 is subtracted from the number, their product is 150. Find the two possible numbers

Answers

Answer:

--15 and --10 respectively

Step-by-step explanation:

Let the first no be a and second no be b

From the interpretation of the question

a + 20 (added) -- 5 (subtracted) = 0

a + 20 -- 5 = 0

a + 15 = 0

a = --15

Product = 150

a×b = 150

(--15) × b = 150

b = --150/15

b = --10

#AllonGod

i need help i doint think i did it right

Answers

Memory of the phones = 32 gigabytes

Now,

[tex]1\text{ gigabyte = }1073741824\text{ bytes}[/tex]

Therefore ,

[tex]32\text{ gigabytes = }34359738368\text{ bytes}[/tex]

Also ,

[tex]1\text{ byte = 8 bits}[/tex]

Therefore,

[tex]34359738368\text{ bytes = }274877906944\text{ bits}[/tex]

Thus the memory of the phone in bits is ,

[tex]274877906944\text{ bits}[/tex]


Please help me I was sick today and missed out on class and I don’t understand this question

Answers

i.

it is an corresponding angles

ii.

the realtion we have is that the angles are equal

iii.

4+10x=11x-1

or 4+1=11x-10x

5=x

iv

4+10x=4+10×5

=54

11x-1=11×5-1=54

Answer:

A)Corresponding angles (When two lines are crossed by another line (which is called the Transversal), the angles in matching corners are called corresponding angles

B)They are congruent to each other

C) 4+10x=11x-1

4=x-1

5=x

( we put them equal to each other because they are the same)

D)4+10(5)=

4+50=54

D)11(5)-1=

55-1=54

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