Answer:
-8.9×10-14=-89-14=-103°C
25°C=2km
-103°C=? Less
=-103/25×2km
=-8.24km
I need help in question 7, a and b.
Answer:
The graph for 7a is shown in the attachment. For question 7b she walks a distance of 16 meters. (m)
Explanation:
31. TRUE or FALSE A cheese puff must contain C since CO2 was produced when it was burned,
I
Answer:
True
Explanation:
What is the scientific name for a push or a pull?
Answer:
thats a force
Explanation:
Answer:
force
Explanation:
the definition of a push or pull is force
How to find density of a gas.
Answer:
Subtract the mass of the cylinder from the mass of the cylinder when it contains gasoline. This is the mass of the gasoline. Divide this figure by the volume, 100 ml, to get the density.
Emma travels at a speed of 23 miles per hour for 3.5 hours. How far has she travelled?
Answer: 80.5 miles
Explanation:
3.5 x 23 = 80.5
Why are saturn's rings so noticeable?.
Answer:
Why are Saturn's rings so noticeable? They are made of lots of fresh, bright icy particles from a recent breakup.
Explanation:
BEFORE COLLISION
MASS = 4200 kg
MASS = 990 kg
V = 10 m/s
AFTER COLLISION
V = ?
V = 2 m/s
What is the velocity after the crash?
Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.
Analyze the effects on a passenger riding in a car traveling at
50 km/h that collides head-on with a solid object.
Without:
The passenger will get seriously injuredColliding with the windshield at 50km/hCould result in deathWith safety:
The seatbelt holds tge passengers body back so they dont collide with anythingTheir head is cushioned by the airbagThe passenger might get minor injuries but nothing serious will happenA 800N mountain climber scales a 140m cliff. How much work is done by the mountain climber?
Answer:
112 [kJ]
Explanation:
1) related formula is: A=F*S, where A - required work [J], F - force [N], S - distance [m].
2) according to the formula above: A=140*800=112000[J]=112 [kJ]
Answer:
112000 J
Explanation:
800N x 140m
¿Cuál es la densidad de un metal si una muestra tiene una masa de 63.5 g cuando se mide en el aire y una masa aparente de 55.4 g cuando está sumergida en agua?. Considere la densidad del agua como 1000 kg/m3.
La densidad del metal como se requiere en la pregunta es 7.8 * 10 ^ 3 Kg / m ^ 3.
Sabemos que ese empuje hacia arriba = peso en aire - peso en líquido
Peso en el aire = 63,5 * 10 ^ -3 Kg * 10 m / s ^ 2 = 0,635 N
Peso en líquido = 55,4 * 10 ^ -3 Kg * 10m / s ^ 2 = 0,554 N
Empuje hacia arriba = 0,635 N - 0,554 N = 0,081 N
Pero ;
Empuje hacia arriba = Volumen * densidad del fluido * aceleración debido a la gratitud
volumen = empuje hacia arriba / densidad del fluido * aceleración debido a la gratitud
volumen = 0.081 N / 1000 * 10
Volumen = 8.1 * 10 ^ -6 m ^ 3
Densidad = masa / volumen
Densidad = 63,5 * 10 ^ -3 Kg / 8,1 * 10 ^ -6 m ^ 3
= 7,8 * 10 ^ 3 kg / m ^ 3
Más información: https://brainly.com/question/12108425
(50 POINTS!!) 3. Make a model that shows the forces acting on two blocks on a flat, frictionless surface:
a. A 1 N block at rest
b. A 1 N block with 2 N of force applied in one horizontal direction
Include arrows to represent the forces and labels to indicate the magnitude of each force. Use your model to compare and explain the motion of each block.
The change in position of an object is known as motion. Force is external that causes a body to change its position
For a body is to be at rest, the sum of all the forces acting on the object must be zeroFor a 1N block to be at rest, the normal force acting opposite to the weight must also be 1N.For 1 N block with 2 N of force applied in one horizontal direction, the image of the body is as shown in the attachmentLearn more about force here: https://brainly.com/question/20955770
Answer:
In short terms. the 1N block at rest will stay still and the 1N block with 2N applied will move forward.
How fast should a girl of 35 kg run so that her kinetic energy becomes 700J
of?
Answer:
√40m/sec
Explanation:
As we know Kinetic energy = 1/2 mv^2
700 = 1/2 x 35 x v^2
1400/35 = v^2
√40 = v
So v, √40m/sec
Hope this helps you.
If your neighbor leaves his house, walks 2 miles south, then turns around and walks home, what is his displacement?
Answer:
0
Explanation:
The neighbors displacement is 0 as displacement is how far the person is from their starting location. If they walk 2 miles away and then head back those 2 miles back to their house; 2-2=0
How to use bernoulli's equation.
Answer:
Answer is below ….
Explanation:
The Bernoulli equation is a crucial statement that connects a fluid's pressure, height, and velocity at a single point in its flow. In an idealised system, the connection between these fluid conditions along a streamline always equals the same constant along that streamline.
Water from a reservoir runs through enormous tubes called penstocks before reaching a turbine at the end of a hydroelectric dam. The gravitational potential energy drops as the water flows down the pipe according to Bernoulli's equation, yet in many configurations, the water departs at the same speed.
Bernoulli's equation is a more broad and mathematical version of Bernoulli's principle that includes variations in gravitational potential energy. We'll derive this equation in the following part, but first, let's look at Bernoulli's equation to get a sense of what it says and how one may use it.
________________________________________________________
(hope this helps can I pls have brainlist (crown)☺️)
3. Would prudent to do an observatory M 82 for this class?
Answer: Yes,
If you need any other thing let me know, I'll still be on
Explanation:
A) infrared energy
B) microwave energy
C) radio wave energy
Answer:
Infrared energy
Explanation:
Answer:
A) infrared energy
Explanation:
what are the characteristics of a " team " in hit in volleyball ?
Answer:
A team may contact the ball a total of three (3) times before it is sent over the net.
Help plz????????? Giving out Brainly
Answer:
Answer should be (B)
Explanation:
If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: a stationary object stays still. a moving object continues to move at the same speed and in the same direction.
ALSO: forces acting upon an object are balanced, then the object will maintain its state of motion. To maintain the state of motion is to keep the current speed and direction. But if the forces are not balanced, the object will change its state of motion.
You push a 24.7 kg toy wagon at a speed of 9.7. What is the momentum of the wagon?
Answer:
Momentum = 239.59 kg·m/s
Explanation:
Mass x Velocity = Momentum
Two towers of height 40 m and 30 m respectively support a transmission line conductor at water crossing. The horizontal distance between the towers is 300 m. If the tension in the conductor is 1590 kg, find the clearance of the conductor at a point mid-way between the supports. Weight of conductor is 0·8 kg/m. Bases of the towers can be considered to be at the water level.
The sag in the tensioned cable depends on the weight of the cable and
the applied tension.
The clearance midway between the support is approximately 29.34 metersReasons:
The given parameters are;
Height of the towers are; h₁ = 40 m and h₂ = 30 m
Horizontal distance between the towers, l = 300 m
The tension in the conductor, T = 1,590 kg
Weight of the conductor, w = 0.8 kg/m
Required:
The clearance space of the conductor mid-way between the support
Solution:
The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;
[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]
Where;
h = h₂ - h₁ = 40 m - 30 m = 10 m
Which gives;
[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]
The sag at the lowest point is give by the formula;
[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]
Therefore;
[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]
The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m
The distance of the midpoint from the lowest point, x, is therefore;
[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]
Which gives;
[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]
The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34
The clearance midway between the support ≈ 29.34 m
Learn more about overhead lines sag calculations here:
https://brainly.com/question/14210921
is there any difference in upthrust of water at b and c
Answer:
no picture attached
Explanation:
Plz help ⭐..................
Answer:
where in the world is the image????..
What is the force on a 2kg object that is moving right at 6 m/s2?
0 3.0N
Ο ΟΝ
.33N
12.0N
Answer:
12N
Explanation:
By Newton second law force is the product of the mass of the object times it's acceleration. That makes it [tex]2\cdot 6 kg \cdot m/s^2 = 12 N[/tex]
The first hill of a roller coaster is 42.0 meters high. The bottom of the first hill is 4.2 meters off the ground.The roller coaster cart has a mass of 4500 kg.
Calculate its potential energy at the top of the first hill.
Calculate its potential energy at the bottom of the first hill.
Challenge- What is the velocity of the cart at the bottom of the first hill?
Answer:
1.89*10⁶J
Explanation:
because 4500kg * 42m*10m/s² is 1890000J
What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod
Answer:
C) 5ML^2
Explanation:
2 Spheres of mass M
Bug's mass 3M
Rod length 2L, radius L
Find Rotational Inertia I
I=Σmr^2
I=(3M+M+M)L^2
I=5ML^2
The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Rotational inertia of the systemThe rotational inertia of the system is determined by summing all the masses together and multiply with the radius.
I(t) = Σmr²
Where;
m is the massr is the radiusI(t) = Inertia of the 2 spheres + inertia of the bug
I(t) = (M + M)L² + (3M)L²
I(t) = 2ML² + 3ML²
I(t) = 5ML²
Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Complete question is below:
There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.
Learn more about rotational inertia here: https://brainly.com/question/14001220
During a ______ Moon phase, the side of the Moon facing Earth isn't reflecting any sunlight from the Sun.
A: Full
B: New
Answer:
B) New
During a new Moon phase, the side of the Moon facing Earth isn't reflecting any sunlight from the Sun.
if the magntidude of the sum and difference of two non zero vectors A and B is equal. what can we say about the two vectors
Answer:
A + B = B - A
The above equation must hold for the sum and difference to be zero.
How can one of the vectors not be zero?????
A 2kg water balloon is flying at a rate of 4m/s^2. With what force will it hit its target?
Explanation:
F=m×a
m=2kg
a=4m/s^2
F=2kg×4m/s^2
F=8N
A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.
What is force?A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is body with some mass than there is force.
Given in the question mass and acceleration of balloon, force is given as
F = m*a
m = 2 kg
a = 4 m/s²
F = 2 kg×4 m/s²
F = 8 N
A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.
To learn more about force refer to the link:
brainly.com/question/13191643
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How are typhoons formed?
Need help!
Answer:
typhoon forms when winds blow into areas of the ocean where the water is warm. These winds collect moisture and rise, while colder air moves in below. This creates pressure, which causes the winds to move very quickly. The winds rotate, or spin, around a center called an eye.
A 2kg body is moving a long a horizontal circular path of radius 2m with constant speed of 6m/s . what is the magnitude of the force acting on the body ?