Answer: $1,800
Step-by-step explanation:
600x3=1,800
Answer:
1800 is the cost.
Step-by-step explanation:
Each hoop costs 600 dollars and their are 3 hoops so multiply 600 times 3 or you can do 6 times 3 and add the zeros at the end which is 1800 dollars and btw you got this!!! don't give up. I believe in you :)
What’s the website in this image called?
The G.M and H.M between two number are respectively 9 & 5.4. Find the numbers.
Answer:
The numbers are 3 and 27.
Step-by-step explanation:
The explanation is attached below.
Help pls I’m on a time limit. Please and thank you <33
Answer: the answer is 3/10
Step-by-step explanation: because its 3/10
Answer:
es
3/ 10
Step-by-st
Compute r''(t) and r'''(t) for the following function. r(t) = (9t² +6,t + 5,6) Find r'(t). r(t) = 0.00
The derivatives of the vector function are r'(t) = (18 · t, 1, 0), r''(t) = (18, 0, 0) and r'''(t) = (0, 0, 0).
How to determine the first three derivatives in a vector functionIn this question we find the definition of a vector function in terms of time, whose first, second and third derivatives must be found. This can be done by using derivative rules several times. First, define the vector function:
r(t) = (9 · t² + 6, t + 5, 6)
Second, find the first derivative:
r'(t) = (18 · t, 1, 0)
Third, find the second derivative:
r''(t) = (18, 0, 0)
Fourth, find the third derivative:
r'''(t) = (0, 0, 0)
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Simplify.
+6 - 4 =
please help ..........
Answer:
2
Step-by-step explanation:
it's literally 6-4 = 2
Answer: 2
Step-by-step explanation: +6 is simply 6 and 6-4 is 2.
Use the following diagram to answer question 4 and 5
Exterior Angle Theorem
8.6 points
The measure of ZA is
Given the following diagram, find the measures of
LA and ZB
Type your answer...
B (2x + 4)
5
8.6 points
The measure of ZB is
Type your answer...
(3x - 13)
116°
А
Answer:
3x-13+2x+4=116( the sum of two interior angle is epual to the sum of exterior angle )
5x =116-9
5x=107
x=21.4 degree
then
angle a= 3*21.4-13
a=51.2degree
angle b=2*21.4+2
b =44.8degree
Step-by-step explanation:
plz make me brainliest
Mario tiene 4 pantalones de diferente color (azul, café, negro y blanco) y 6 camisas también de diferente color (blanca, negra, azul, café, gris y verde). Si Mario escoge una combinación al azar, ¿cuál es la probabilidad de que se vista con pantalón azul y camisa blanca?
Write an expression in factored form to represent the area of each shaded region. Include the area formula and full steps and write your answer in simplified form. 3x a) (3 marks) 3x + y 2x +y 3x b) 3y (3 marks) B 2x 2x
a. The area of the shaded region = (3x)(5x + 2y).
b. The area of shaded region = 2x(2xπ - 3x).
Given that,
We have to write an expression in factored form to represent the area of each shaded region.
We know that,
a. In the picture we can see that the shaded region.
The area of the shaded region is area of rectangle with vertical + area of rectangle Horizontal
The area of rectangle is length × width.
The area of the shaded region = (3x)(3x + y) + (2x + y)(3x)
The area of the shaded region = (3x)(3x + y + 2x + y)
The area of the shaded region = (3x)(5x + 2y)
Therefore, The area of the shaded region = (3x)(5x + 2y)
b. In the picture we can see that circle with shaded region,
The area of shaded region is area of the circle - area of the rectangle
The area of the circle is πr² and area of rectangle is length × width.
The area of shaded region = πr² - (l×w)
The area of shaded region = π(2x)² - (2x × 3x)
The area of shaded region = 4x²π - 6x²
The area of shaded region = 2x(2xπ - 3x)
Therefore, The area of shaded region = 2x(2xπ - 3x).
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A 5 meter ladder is leaning against a house when its base starts to slide away. By the time the base is 3 meter from the house, the base is moving at the rate of 2 m/sec. (a) How fast is the top of the ladder sliding down the wall then? (b) At what rate is the angle between the ladder and the ground changing then?
(a) The top of the ladder is sliding down the wall at a rate of 3/2 m/sec.
(b) The angle between the ladder and the ground is changing at a rate of 1/2 rad/sec.
To solve this problem, we can use related rates, considering the ladder as a right triangle formed by the ladder itself, the wall, and the ground.
Let's denote:
x: the distance from the base of the ladder to the house (in meters)
y: the height of the ladder on the wall (in meters)
θ: the angle between the ladder and the ground (in radians)
Given:
dx/dt = -2 m/sec (the rate at which the base of the ladder is moving away from the house)
Using the Pythagorean theorem, we have:
x^2 + y^2 = 5^2 (since the ladder has a length of 5 meters)
Taking the derivative of both sides with respect to time (t), we get:
2x(dx/dt) + 2y(dy/dt) = 0
(a) To find dy/dt:
We can solve the equation above for dy/dt:
2x(dx/dt) + 2y(dy/dt) = 0
2(3)(-2) + 2y(dy/dt) = 0 (substituting x = 3 and dx/dt = -2)
-12 + 2y(dy/dt) = 0
2y(dy/dt) = 12
dy/dt = 12/(2y)
dy/dt = 6/y
Now, we need to find y. Using the Pythagorean theorem again:
x^2 + y^2 = 5^2
3^2 + y^2 = 5^2
9 + y^2 = 25
y^2 = 25 - 9
y^2 = 16
y = 4 (taking the positive value as y represents a length)
Substituting y = 4 into dy/dt = 6/y:
dy/dt = 6/4
dy/dt = 3/2 m/sec
Therefore, the top of the ladder is sliding down the wall at a rate of 3/2 m/sec.
(b) To find dθ/dt:
We can use trigonometry to relate θ, x, and y:
tan(θ) = y/x
Differentiating both sides with respect to time (t), we get:
sec^2(θ)dθ/dt = (x(dy/dt) - y(dx/dt))/x^2
Substituting the given values:
sec^2(θ)dθ/dt = (3(3/2) - 4(-2))/3^2
sec^2(θ)dθ/dt = (9/2 + 8)/9
sec^2(θ)dθ/dt = (25/2)/9
sec^2(θ)dθ/dt = 25/18
Since sec^2(θ) is equal to 1 + tan^2(θ) and tan(θ) = y/x:
sec^2(θ) = 1 + (y/x)^2
sec^2(θ) = 1 + (4/3)^2
sec^2(θ) = 1 + 16/9
sec^2(θ) = (9 + 16)/9
sec^2(θ) = 25/9
Substituting sec^2(θ) = 25/9 into the equation:
(25/9)dθ/dt = 25/18
Simplifying and solving for dθ/dt:
dθ/dt = (25/18) * (9/25)
dθ/dt = 1/2 rad/sec
Therefore, (b) the angle between the ladder and the ground is changing at a rate of 1/2 rad/sec.
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What is the probability of 4 consecutive 2-sided coin tosses all coming up heads?
The probability of getting four consecutive heads in four 2-sided coin tosses is 1/16 or 0.0625 or 6.25%.
The Probability is defined as a measure of the likelihood or chance that an event will occur, expressed as a value between 0 and 1, where 0 represents impossibility and 1 represents certainty.
To calculate the probability of getting four consecutive heads in a row, we multiply the probabilities of each individual toss.
The Probability of heads (H) is = 1/2,
So, The Probability of four consecutive heads (HHHH) is :
= (1/2) × (1/2) × (1/2) × (1/2) = (1/2)⁴ = 1/16,
Therefore, the required probability is 1/16 or 6.25%.
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There are 40 batteries in 10 packs.
Gavin wants to know how many batteries are in 1 pack.
Kylie wants to know how many batteries are in 5 packs.
Drag an expression to answer each question.
Help me Please I would appreciate your help!
:-):-):-):-):-)
Step-by-step explanation:
1) 40÷10
2) 40÷2
You invest $32,000 in an account that earns 5.75% interest compounded yearly. What is
the total amount of money you will have in the account after 20 years if you never
deposit any additional funds?
Answer:
$97,894.33.
Step-by-step explanation
A rectangular prism has a base perimeter of 28 inches and a height of 6 inches. What is the lateral surface area of the prism?
Answer:
uhuhuhuhuhuhuhuhuhuhuh oh yeah
Step-by-step explanation:
find the area of this polygon
Answer:
answer is 65 in²
hope this helps
Let be an equivalence relation on a set S, and let a, b e S. Show that two equivalence classes under ~ are either equal or disjoint, i.e. either [a] = [b] or [a] n [b] = 0.
Given, an equivalence relation ~ on a set S. Let a and b be two elements in the set S. Assuming that [a] and [b] are two equivalence classes under the equivalence relation ~. Now we need to prove that either [a] = [b] or [a] ∩ [b] = ∅ (disjoint).
Proof:If [a] and [b] are not equal, then there must be some element c in the intersection of the equivalence classes [a] and [b]. i.e, c belongs to [a] and c belongs to [b].Thus, [a] ∩ [b] is not empty.
Let x be an element in [a], then x~a, and a~c (since c belongs to [a]) and hence x~c. So, x belongs to [c] which implies that [a] is a subset of [c].Now, let y be an element in [b], then y~b, and b~c (since c belongs to [b]) and hence y~c. So, y belongs to [c] which implies that [b] is a subset of [c].Thus, both [a] and [b] are subsets of [c].
Therefore, if [a] and [b] are not equal, then [a] and [b] are both subsets of [c] and hence the intersection of [a] and [b] is not empty. Thus, [a] and [b] are not disjoint. Hence, the proof by contradiction.
Conversely, if [a] and [b] are disjoint, then [a] ∩ [b] = ∅. And thus, [a] is not equal to [b].Therefore, two equivalence classes under the equivalence relation ~ are either equal or disjoint.
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Make r the subject of x=e+r/d
Answer:
r = dx - de
Step-by-step explanation:
x = e + r/d
x - e = r/d
d (x - e) = r
dx- de = r
r = dx - de
I NEEED HELP match the equation with the term it belongs to. 3.14 *r *r. 2* 3.14 *r
Answer:
3.14 * r * r = area of circle, 2 * 3.14 * r = circumference
Step-by-step explanation:
Remember these formulas, very important.
Please help me, GodBless.
Answer:
Rate of change is 1
Step-by-step explanation:
Well rate of change in a function is basically slope
theres 1 rise and.1 run
1/1=1
So rate of change is 1
What is the smallest solution to the equation 3x2 - 16 = 131?
Answer:
7,-7 are the solutions
Step-by-step explanation:
Not a perfect square so its
+-7
I would go with -7 since its the lowest amount
Answer:
-7
Step-by-step explanation:
Find the measurements of DBC
Answer:
72 degrees
Step-by-step explanation:
To determine the value of DBC, we first have to determine the value of q
Angle on a straight line = 180 degrees
7q - 46 + 3q + 6 = 180
10q - 40 = 180
collect like terms
10q = 180 + 40
10q = 220
q = 22
Substitute for q in angle dbc
3(22) + 6 = 72 degrees
Use Strong Induction to prove that: If p + 1/p E N, then Pn+1/Pn EN for all nEN.
We prove with the help of Strong Induction.
Let P(n) be the statement that Pn+1/Pn E N.
In order to prove this statement, we will utilize strong induction.So we are given that p + 1/p E N. We will show that P(n) is true for all n >= 1.
Let's consider the base case
P(1):P2/P1 = (p + 1/p)^2 - 2 = (p^2 + 2 + 1/p^2) - 2p/p = (p^2 + 1/p^2) - (2p - 2/p)
Since p + 1/p E N, both p and 1/p must be integers.
Hence, p^2 and 1/p^2 are also integers. This implies that (p^2 + 1/p^2) is an integer.
It only remains to show that (2p - 2/p) is an integer. This is equivalent to showing that 2p^2 - 2 E 0 mod p. But this is clearly true, since 2p^2 - 2 = 2(p^2 - 1) and p^2 - 1 is divisible by p.
Let's assume that P(k) is true for all k such that 1 <= k <= n. We need to prove that P(n+1) is true as well.
Now we need to prove that P(n+1) is true. In other words, we need to show that P(n+2)/P(n+1) E N, assuming that P(n+1)/P(n) E N and P(n)/P(n-1) E N.
Using the definition of P(n), we have:P(n+1)/P(n) E N and P(n)/P(n-1) E N imply that P(n+1) = aP(n) and P(n) = bP(n-1) for some integers a and b. Then:P(n+2)/P(n+1) = (P(n+2)/P(n+1)) * (P(n)/P(n)) = (P(n+2)P(n))/(P(n+1)P(n)) = (aP(n+1)P(n))/(bP(n)P(n+1)) = a/bIf we can show that a/b E N, then P(n+2)/P(n+1) E N, and P(n+1) satisfies the inductive hypothesis.
But this follows from the fact that a and b are integers and the product of two integers is always an integer.
Hence, P(n+1) is true for all n >= 1, by strong induction.Therefore, by strong induction, we have proved that if p + 1/p E N, then Pn+1/Pn EN for all nEN.
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Tina drew a triangle with side lengths 6, 8, and 14. She claims it is a right triangle. Is she correct?
Answer:
No such a triangle can not exist.
plz help fast!!!!!!!!!!!!!!!!!!!!!
Answer:
D) 156/100 = n/70
Step-by-step explanation:
n = 156% of 70
% indicates a fraction over 100.
"of" indicates multiplication.
n = 156/100 • 70
Let's divide both sides by 70 to have one fraction one each side.
n/70 = 156/100
This is equal to D) [tex](\frac{156}{100}) = (\frac{n}{70})[/tex]
what is the volume of a right triangular prism whose height is 20 units and whose base is a right triangle with side lengths of 3,4, and 5?
Wiseman Video plans to make four annual deposits of $2,000 each to a special building fund. The fund’s assets will be invested in mortgage instruments expected to pay interest at 12% on the fund’s balance. (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided.)
Using the appropriate annuity table, determine how much will be accumulated in the fund on December 31, 2019, under each of the following situations.
1. The first deposit is made on December 31, 2016, and interest is compounded annually.
Table or calculator function: FVA of $1
Payment: $2,000
n = 4
i = 12%
Fund balance 12/31/2019: $9,559
2. The first deposit is made on December 31, 2015, and interest is compounded annually.
Table or calculator function: FVAD of $1
Payment: $2,000
n = 4
i = 12%
Fund balance 12/31/2019: $10,706
3. The first deposit is made on December 31, 2015, and interest is compounded quarterly.
Using the FV of $1 chart, calculate the fund balance:
Deposit Date i = n = Deposit Fund Balance 12/31/2019
12/31/2015 3% 16 $2,000 $3,209
12/31/2016 3% 12 2,000 2,852
12/31/2017 3% 8 2,000 2,534
12/31/2018 3% 4 2,000 2,251
$10,846
4. The first deposit is made on December 31, 2015, interest is compounded annually, and interest earned is withdrawn at the end of each year.
Deposit Amount No. of Payments Interest left in Fund Fund Balance 12/31/2019
$2,000 $8,000
The fund balance at the end of 2019 will be $8,000.
The given problem has four different parts, where we are supposed to calculate the accumulation of funds at the end of 2019 in different scenarios.
Scenario 1In the first scenario, the first deposit is made on December 31, 2016, and interest is compounded annually.
Using the FVA of $1 table; Payment: $2,000n = 4i = 12%
Fund balance 12/31/2019: $9,559
Hence, the fund balance at the end of 2019 will be $9,559.Scenario 2In the second scenario, the first deposit is made on December 31, 2015, and interest is compounded annually.
Using the FVAD of $1 table;Payment: $2,000n = 4i = 12%
Fund balance 12/31/2019: $10,706 Therefore, the fund balance at the end of 2019 will be $10,706.Scenario 3In the third scenario, the first deposit is made on December 31, 2015, and interest is compounded quarterly. Using the FV of the $1 chart, we get the following calculation:
Deposit Date i = n = Deposit Fund Balance 12/31/2015 3% 16 $2,000 $3,20912/31/2016 3% 12 $2,000 $2,85212/31/2017 3% 8 $2,000 $2,53412/31/2018 3% 4 $2,000 $2,251
The interest rate is 3%, and the payment is $2,000. Hence, the fund balance at the end of 2019 will be $10,846.Scenario 4In the fourth scenario, the first deposit is made on December 31, 2015, interest is compounded annually, and interest earned is withdrawn at the end of each year.
Deposit Amount No. of Payments Interest left in Fund Fund Balance 12/31/2019$2,000 $8,000 Hence, the fund balance at the end of 2019 will be $8,000.
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How many real solutions exist for this system of equations? Y = -x + 1 y = -x2 + 4x − 2 A. Zero B. One C. Two D. Infinite
Answer:
Two solutions
Step-by-step explanation:
Given the functions Y = -x + 1 y = -x² + 4x − 2
Since they are both y values, we will equate them to have:
-x+1 = -x² + 4x − 2
Equate to zero
x²-x-4x+1+2=0
x²-5x+3 = 0
Since the resulting equation is quadratic (highest degree being 2), hence there will be two solutions to the equation
What’s the opposite of -5/8
Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be . Saul asks Jasmine to check his work. Saul copies the data in numerical order from least to greatest for Jasmine.
The question is incomplete. The compete question is :
Saul decides to use the IQR to measure the spread of data. Saul calculates the IQR of the data set to be 27. Saul asks Jasmine to check his work. Saul copies the data in numerical order from least to greatest for Jasmine. 25, 30, 50, 50, 50, 50, 56, n, 250. What is the value of n that will make the IQR of the data set equal to 27?
Solution :
The inter quartile range is being measured as : 3rd quartile - 1st quartile
The 1st quartile = 25% mark
The 3rd quartile = 75% mark
The data set as given in the question is :
25, 30, 50, 50, 50, 50, 56, n, 250
Therefore, the total number of the sample = 9
And the median is = 50
The median separates the given data sets into two equal halves-- that is the upper half and the lower half.
Let the middle of a lower half is the 1st quartile be [tex]$Q_1$[/tex]
And the middle of a 2nd half is the 3rd quartile be [tex]$Q_3$[/tex]
∴ [tex]$Q_1=\frac{30+50}{2}$[/tex]
[tex]$=40$[/tex]
[tex]$Q_3=\frac{56+n}{2}$[/tex]
Now for the IQR of the data set to be equal to [tex]$27$[/tex],
[tex]$\frac{56+n}{2}-40=27$[/tex]
[tex]$\frac{56+n}{2}=27+40$[/tex]
[tex]$\frac{56+n}{2}=67$[/tex]
[tex]$56 +n=134$[/tex]
[tex]$n=134-56$[/tex]
[tex]$n=78$[/tex]
HELP PWEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Answer:
rap music
Step-by-step explanation:
^
Answer:
i’m not sure if these are right or not but
Step-by-step explanation:
the first one is no
i think the second one is no
i think the third one is yes
i think the fourth one is yes
i am not sure and i’m REALLY sorry if its wrong
Simplify this expression