Answer:
(a) W = 882 N
(b) m = 90 kg
(c) Wm = 342 N
Explanation:
(a)
The weight of n object on the surface of earth is given as:
W = mg
where,
W = Weight of Astronaut on Earth = ?
m = mass of astronaut = 90 kg
g = acceleration due to gravity on surface of earth = 9.8 m/s²
Therefore,
W = (90 kg)(9.8 m/s²)
W = 882 N
(b)
Mass of a body is a universal constant. The mass of the body remains same any where in the universe. Therefore, on mars the mass of astronaut will be:
m = 90 kg
(c)
The weight of an object on the surface of Mars is given as:
Wm = m(gm)
where,
Wm = Weight of Astronaut on Mars = ?
m = mass of astronaut = 90 kg
gm = acceleration due to gravity on surface of Mars = 3.8 m/s²
Therefore,
Wm = (90 kg)(3.8 m/s²)
Wm = 342 N
To exercise, a man attaches a 4.0 kg weight to the heel of his foot. When his leg is stretched out before him, what is the torque exerted by the weight about his knee, 40 cm away from the weight? Use g = 10 m/s2. A. 160 Nâm B. 16 Nâm C. 1600 Nâm D. 1.6 Nâm
Answer:
B. τ = 16 Nm
Explanation:
In order to find the torque exerted by the weight attached to the heel of man's foot, when his leg is stretched out. We use following formula:
τ = Fd
here,
τ = Torque = ?
F = Force exerted by the weight = Weight = mg
F = mg = (4 kg)(10 m/s²) = 40 N
d = distance from knee to weight = 40 cm = 0.4 m
Therefore,
τ = (40 N)(0.4 m)
B. τ = 16 Nm
The torque exerted by the weight about his knee, 40 cm away from the weight is: D. 1.6 Nm
Given the following data:
Mass = 4.0 kgDistance = 40 cm to m = 0.04 metersAcceleration due to gravity (g) = 10 [tex]m/s^2[/tex].To determine the torque exerted by the weight about his knee, 40 cm away from the weight:
First of all, we would calculate the force being exerted by the weight on his heel.
[tex]Force = mg\\\\Force = 4 \times 10[/tex]
Force = 40 Newton
Mathematically, torque is given by the formula:
[tex]Torque = force \times distance[/tex]
Substituting the given parameters into the formula, we have;
[tex]Torque = 40 \times 0.04[/tex]
Torque = 1.6 Nm
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if it took 3.7 seconds for the sound to reach john how far away was the firework shell when it exploded in kilometers assume that the speed of sound in air is 1,236 km/h
Answer:
1.2703 km
Explanation:
The speed can be calculated using the formula;
Speed (m/s) = distance (m) ÷ time (s)
Based on the information in this question, it took 3.7 seconds for a sound with speed of 1236 km/h to reach John. The distance will be:
Distance = speed × time
However, we need to convert the time in seconds (s) to hour (hr).
1 second = 0.000277778 hour
3.7 seconds = 0.00102778 hours.
Hence,
distance = 1236 × 0.00102778
Distance = 1.2703 km
Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?
Fp, Ff, and Fg
Fp and FN
Fp, Fg, and Ff
Fp and Fg
Answer:
Answer is D: D.Fp and Fg
Explanation:
I did the quiz some time ago and rember it hope it helps.
Answer:
i just finish its d
Explanation:
A volume of air increases 0.227 m^3 at a net pressure of 2.07 x 10^7 Pa. How much work is done on the air?
Answer:
The work done on the air is 4.699 x 10⁶ Joules
Explanation:
Given;
increase in air volume, ΔV = 0.227 m³
net pressure of the air, P = 2.07 x 10⁷ Pa
The work done on the air is given by;
W = PΔV
Where;
W is the work done on the air
P is the net pressure
ΔV is the increase in air volume
Substitute the given values and solve for work done;
W = (2.07 x 10⁷ Pa) (0.227 m³)
W = 4.699 x 10⁶ Joules
Therefore, the work done on the air is 4.699 x 10⁶ Joules
7.
As the distance from the Sun increases the time to orbit the Sun
a. Increases
b. Decreases
c. Stays the same
As the distance from the Sun increases the time to orbit the Sun increases. (a)
Examples:
-- Nearest planet to the sun: Mercury. Time to orbit the sun: 88 days
-- 3rd planet from the sun: Earth. Time to orbit the sun: 1 year
-- 5th planet from the sun: Jupiter. Time to orbit the sun: 12 years
-- 9th closest object to the sun: Pluto. Time to orbit the sun: 248 years
Another pair of examples:
-- Object in a near Earth orbit: International Space Station
Time to orbit the Earth: 90 minutes
-- Object in a far Earth orbit: the Moon
Time to orbit the Earth: 27.3 days
The reason for all of this is: Two things about orbits.
1). The larger the orbit is, the farther the object has to travel around it.
2). The farther out the object is, the slower it travels in its orbit.
This is simply the way gravity works.
Jeff was riding in a car with a textbook sitting on the seat beside him. When would the textbook demonstrate the GREATEST effect of inertia?
А
When the car makes a sudden stop,
B
When the car changes into another lane.
С
When the car slows down gradually.
D
When the car runs out of gas and rolls to a stop
The pharyngeal tonsil is found in the __________________________ .
Answer:
The pharyngeal tonsils are located near the opening of the nasal cavity into the pharynx. When these tonsils become enlarged they may interfere with breathing and are called adenoids.
A tennis rackets delivers 500 N on impact with a tennis ball. What is the force of the tennis ball on the racket?
A: this cannot be determined without knowing the mass of the tennis ball
B: the force on the tennis racket is more than 500 N
C: the force on the tennis racket is 500 N
D: the force on the tennis racket is less than 500 N
Answer:
the a.
Explanation:
because if you compute you can't know the distance
A 20.0 cm wrench is used to generate a torque at a bolt. A force of 50 N is applied at the end of the wrench at an angle of 60.0 degrees to the wrench. The torque generated at the bolt is A. 4.9 N•m. B. 5.7 N•m. C. 6.0 N•m. D. 7.5 N•m. E. 8.7 N•m.
Answer:
The correct option is E
Explanation:
From the question we are told that
The length of the wrench which is also the radius of the circle made by the wrench is [tex]l =r = 20.0 \ cm = 0.2 \ m[/tex]
The force is [tex]F = 50 \ N[/tex]
The angle is [tex]\theta = 60^o[/tex]
Generally the torque generated by the bolt is mathematically represented as
[tex]\tau = F * sin (\theta ) * r[/tex]
=> [tex]\tau = 50 * sin (60 ) * 0.2[/tex]
=> [tex]\tau = 8.7 \ N \cdot m[/tex]
Find the magnitude of the buoyant force on the block. The acceleration of gravity is 9.8 m/s 2 . Answer in units of N.
All of the following are categories used to classify problems except problems of
A. arrangement
B. inducing structure
C. transformation
D. schematic completion
Answer:D. schematic completion
Explanation:The rest are actual categoroes
Answer:
schematic completion
Explanation:
got it right on edge
Most generation of electricity involves turning turbines to spin coils of metal. However some do not. Give a type of energy that does not involve spinning coils of metal. How does it generate electricity?
Answer:
Photovoltaic Energy
Explanation:
There are other forms of energy that do not involve spinning of metals to generate electricity, one of many such is the Solar Photovoltaic Energy.
Photovoltaic is a form of energy in which sunlight Is directly into electricity. This type of energy is often used to power devices such as small wrist watches, rechargeable lamps, and others. They are connected together to panels that are joined together in arrays to power people or heavy power plants. Photovoltaic power plants are happening to be one of the fastest growing sources of electricity generation around the world.
HELP!!
You are traveling at a speed of 70 miles per hour. How long did it take you to travel 2400 miles?
Answer:
So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3
Consider an underwater spherical air bubble (you can assume the index of refraction of air is 1 and water is 1.33) with radius R. This bubble can act as a lens. What is its focal length?
Answer:
-2R
Explanation:
The focal length can be calculated using this formula
1/f = (n1/n2-1)(1/r1-1/r2)
1/f = (1/1.33-1)(1/r + 1/r)
= -0.133/1.33(2/R)
F = -2R
The focal length is this
A 4 kilogram box is at rest on a frictionless floor. A net force of 12 newtons acts on it. What is the acceleration of the box?
Answer:
3 m/s^2Explanation:
Step one:
given
Mass m= 4kg
Force F= 12N
Required
Acceleration the relation between force, acceleration, and mass is Newton's first equation of motion, which says a body will continue to be at rest or uniform motion unless acted upon by an external force
F=ma
a=F/m
a=12/4
a=3 m/s^2
help asap
How does the scientist know that the substance goes through a change of state during the time period labeled B on the graph?
a.the temperature remains the same
b.the temperature increases gradually
c.the particles start slowing down
d.the particles start moving faster
Answer:
The answer is A. The temperature remains the same.
A rock is thrown with an initial vertical velocity 50 m/s at an angle of 40 degrees.
a. What is the horizontal component of the velocity?
b. What is the vertical component of the velocity?
c. What is the hang timel?
d. What is the peak height?
e. What is the range?
Answer:
[tex]38.3\ \text{m/s}[/tex]
[tex]32.14\ \text{m/s}[/tex]
6.55 seconds
[tex]52.65\ \text{m}[/tex]
[tex]254.84\ \text{m}[/tex]
Explanation:
u = Initial velocity of rock = 50 m/s
[tex]\theta[/tex] = Angle of throw = [tex]40^{\circ}[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Horizontal component is given by
[tex]u_x=u\cos\theta\\\Rightarrow u_x=50\times \cos40^{\circ}\\\Rightarrow u_x=38.3\ \text{m/s}[/tex]
The horizontal component of the velocity is [tex]38.3\ \text{m/s}[/tex]
Vertical component is given by
[tex]u_y=u\sin\theta\\\Rightarrow u_y=50\times \sin40^{\circ}\\\Rightarrow u_y=32.14\ \text{m/s}[/tex]
The horizontal component of the velocity is [tex]32.14\ \text{m/s}[/tex]
Time of flight is given by
[tex]t=\dfrac{2u\sin\theta}{g}\\\Rightarrow t=\dfrac{2\times 50\sin40^{\circ}}{9.81}\\\Rightarrow t=6.55\ \text{s}[/tex]
The hang time of the rock is 6.55 seconds
Maximum height is given by
[tex]h=\dfrac{u^2\sin^2\theta}{2g}\\\Rightarrow h=\dfrac{50^2\sin^240^{\circ}}{2\times 9.81}\\\Rightarrow h=52.65\ \text{m}[/tex]
Maximum height is [tex]52.65\ \text{m}[/tex]
Range is given by
[tex]d=\dfrac{u^2\sin2\theta}{g}\\\Rightarrow d=\dfrac{50^2\sin(2\times40)^{\circ}}{9.81}\\\Rightarrow d=254.84\ \text{m}[/tex]
The range is [tex]254.84\ \text{m}[/tex]
A 5 kg ball is moving at a velocity of +2 m/s when it
speeds up to +5 m/s in 7 seconds.
Calculate the acceleration.
Heya!!
For calculate aceleration, lets applicate formula:
[tex]\boxed{a=\frac{V-V_o}{t} }[/tex]
Δ Being Δ
V = Final Velocity = 5 m/s
Vo = Initial Velocity = 2 m/s
a = Aceleration = ? m/s²
t = Time = 7 s
⇒ Let's replace according the formula:
[tex]\boxed{a=\frac{5\ m/s - 2 \ m/s}{7\ s} }[/tex]
⇒ Resolving
[tex]\boxed{ a=0,428\ m/s^{2}}[/tex]
Result:
The aceleration of the object is 0,428 m/s²
Good Luck!!
Answer:
Ksasdasd
Explanation:
A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 G to 1.60 M in 0.99 s. What is the resulting induced current if the loop has a resistance of 1.20 Ω?
Complete Question
A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of [tex]1.20 \ \Omega[/tex]
Answer:
The current is [tex]I = 0.0007 41 \ A[/tex]
Explanation:
From the question we are told that
The area is [tex]A = 8.00 \ cm^2 = 8.0 *10^{-4} \ m^2[/tex]
The initial magnetic field at [tex]t_o = 0 \ seconds[/tex] is [tex]B_i = 0.500 \ T[/tex]
The magnetic field at [tex]t_1 = 0.99 \ seconds[/tex] is [tex]B_f = 1.60 \ T[/tex]
The resistance is [tex]R = 1.20 \ \Omega[/tex]
Generally the induced emf is mathematically represented as
[tex]\epsilon = A * \frac{B_f - B_i }{ t_f - t_o }[/tex]
=> [tex]\epsilon = 8.0 *10^{-4} * \frac{1.60 - 0.500 }{ 0.99- 0 }[/tex]
=> [tex]\epsilon = 0.000889 \ V[/tex]
Generally the current induced is mathematically represented as
[tex]I = \frac{\epsilon}{R }[/tex]
=> [tex]I = \frac{0.000889}{ 1.20 }[/tex]
=> [tex]I = 0.0007 41 \ A[/tex]
Three polarizing filters are shown in the figure below. The alignment of each filterâs transmission axis is shown, as measured from the vertical. Show calculations to justify all of your answers.Angles: 0, 70, and 90a. Unpolarized light, with an intensity I0 passes through the three filters. What is the intensity of the transmitted light?b. Vertically polarized light, with an intensity I0 passes through the three filters. What is the intensity of the transmitted light?c. Is it possible to remove a polarizer from this collection of filters so that unpolarized light transmitted from the left is not transmitted at all? If so, which filter?
Answer: B.
Explanation:
Hope help :p
A) The intensity of the transmitted light will depend on the angle between the polarization direction of the incident light and the transmission axis of each filter.
B) The intensity of the transmitted light will be equal to the initial intensity, I0.
C) The filter that blocks light vibrating perpendicular to its transmission axis is typically called a "crossed" polarizer.
Polarizing filters are optical devices that allow light waves vibrating in a specific direction to pass through while blocking or attenuating light waves vibrating in other directions. The alignment of a polarizing filter's transmission axis refers to the direction in which it allows light to pass through with maximum intensity.
a. Unpolarized light passing through a polarizing filter will have its intensity reduced by a factor called the transmittance, which depends on the angle between the polarization direction of the incident light and the transmission axis of the filter. If the incident light is unpolarized, it contains an equal distribution of light waves vibrating in all possible directions.
As a result, when unpolarized light passes through a polarizing filter, only the component of light vibrating parallel to the transmission axis will be transmitted, while the perpendicular components will be blocked. Therefore, the intensity of the transmitted light will depend on the angle between the polarization direction of the incident light and the transmission axis of each filter.
b. Vertically polarized light has its electric field oscillating only in the vertical direction. When vertically polarized light passes through a polarizing filter whose transmission axis is aligned with the vertical direction, it will pass through with maximum intensity. Therefore, the intensity of the transmitted light will be equal to the initial intensity, I0.
c. In general, if you have a collection of polarizing filters with different transmission axes, it is possible to remove a polarizer so that unpolarized light transmitted from the left is not transmitted at all. This can be achieved by removing the filter whose transmission axis is perpendicular to the direction of polarization of the incident light. The filter that blocks light vibrating perpendicular to its transmission axis is typically called a "crossed" polarizer.
Specific calculations and analysis of the figure you provided would require more detailed information, such as the transmittance characteristics of each filter at different angles. Without the figure or additional data, it is not possible to provide precise calculations or identify the exact filter that should be removed to block unpolarized light.
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What changes occurred when you heated sugar ?
Please help
Test
Integrated Concepts A lightning bolt strikes a tree, moving 20.0 C of charge through a potential difference of 1.00×102 MV . (a) What energy was dissipated? (b) What mass of water could be raised from 15ºC to the boiling point and then boiled by this energy? (c) Discuss the damage that could be caused to the tree by the expansion of the boiling steam.
Answer:
a) 2*10^9 J
b) 764.8 kg
Explanation:
Given that
Energy of charge, q = 20 C
Potential difference, ΔV = 1*10^2 MV = 1*10^2 * 10^6 V = 1*10^8 V
a)
To find the energy dissipated, we use the formula
ΔU = qΔV
ΔU = 20 * 1*10^8
ΔU = 2*10^9 J
b)
Change in temperature, ΔT = 100 - 15°
ΔT = 85° C
Change in energy, ΔU = 2*10^9 J
Specific heat of water, C = 4180 j./Kg.K
Latent heat of vaporization, L(v) = 2.26*10^6 J/Kg
Q1 = mcΔT
Q2 = mL(v)
Net energy needed, U = Q1 + Q2
U = mcΔT + mL(v)
U = m (cΔT + L(v))
m = U /[cΔT + L(v)]
Being that we have all the values, we then substitute
m = 2*10^9 / [(4180 * 85) + 2.26*10^6]
m = 2*10^9 / (3.553*10^5 + 2.26*10^6]
m = 2*10^9 / 2.615*10^6
m = 764.8 kg
c)
Having 765 kg of steam at the temperature would have extreme effect on the tree, damaging it permanently. Possibly even blowing it to pieces
At what final position would you be if you began at initial position of 4m and drove at 30m/s for 20 seconds?
Answer:
604m
Explanation:
30 * 20=600
600 + 4 = 604m
Calculate the wavelengths of a 1530 kHz AM radio signal, a 105.1 MHz FM radio signal, and a 1.90 GHz cell phone signal.
Answer:
196.07 m, 2.85 m and 0.15 m
Explanation:
Frequency of AM radio signal, f₁ = 1530 kHz
Its wavelength can be given by :
[tex]\lambda_1=\dfrac{c}{f_1}\\\\=\dfrac{3\times 10^8}{1530\times 10^3}\\\\=196.07\ m[/tex]
Frequency of FM radio signal, f₂ = 105.1 MHz
Its wavelength can be given by :
[tex]\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{105.1\times 10^6}\\\\=2.85\ m[/tex]
Frequency of cell phone signal, f₃ = 1.9 GHz
Its wavelength can be given by :
[tex]\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{1.9\times 10^9}\\\\=0.15\ m[/tex]
Hence, the required wavelengths are 196.07 m, 2.85 m and 0.15 m respectively.
Rain drops are formed when water vapor _____.
condenses on grass
evaporates
condenses on dust
freezes
Answer:
Condenses on dust
Explanation:
Pls brainiest
Answer:
condenses on dust
Explanation:
What is energy?
A. A change that appears in an object when forced is applied.
B. The property of a body that gives it mess.
C. The amount of heat produced by the body.
D. The ability of an object to undergo change.
E. The ability of a body to move.
Answer:
A
Explanation:
Answer: a or e
Explanation:
if you double the magnitude of a vector, does it follow that the magnitude of the components double? Give example.
Answer:
The magnitude of the vector clearly doubles if each of its components is doubled.
Explanation:
When the rate of the forward reaction equals the rate of the backward reaction, the system is said to be in
Answer:
equilibrium
Explanation:
bcoz forward reaction equals backward reaction
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Remember: cal=m*deltaT
(WRITE THE WORK!/Give explanation.)
Answer:
Q = 12540 J
Explanation:
It is given that,
Mass of water, m = 50 mL = 50 g
It is heated from 0 degrees Celsius to 60 degrees Celsius.
We need to find the energy required to heat the water. The formula use to find it as follows :
[tex]Q=mc\Delta T[/tex]
Where c is the specific heat of water, c = 4.18 J/g°C
Put all the values,
[tex]Q=50\times 4.18\times (60-0)\\Q=12540\ J[/tex]
So, 12540 J of energy is used to heat the water.
How are all paths that have a displacement of zero similar?
Answer:
Any situation that has a path that stops at the same position that it started from has a displacement of zero
Explanation:
hope it helps