Oxalic acid is a diprotic acid with a first dissociation constant Ka1 = 0.0537 and a second dissociation constant Ka2 = 5.42×10-5. Consider all the species in equilibrium with each other in a 0.45 M solution. Note that the first acid dissociation constant is pretty large. This acid is almost a strong acid.

Part 1:
What is the concentration of undissociated oxalic acid in the 0.45 M oxalic acid solution?

Part 2:
What is the concentration of hydrogen oxalate?

Part 3:
What is the concentration of oxalate?

Part 4:
What is the concentration of hydronium?

Part 5:
What is the concentration of hydroxide?

Part 6:
What is the pH of the solution?

Answers

Answer 1

Answer:

50 points for this easy question


Related Questions

Calculate the moles of calcium oxalate formed from 5 grams of potassium oxalate (molar mass 184.24 g/mol) the mole mole ratio from the balanced equation is 2.1 potassium oxalate to calcium oxalate

Answers

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).

We can calculate the moles of CaC₂O₄ obtained considering the following relationships.

The molar mass of K₂C₂O₄ is 184.24 g/mol.The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

[tex]5 g K_2C_2O_4 \times \frac{1molK_2C_2O_4}{184.24gK_2C_2O_4} \times \frac{1molCaC_2O_4}{2molK_2C_2O_4} = 0.03molCaC_2O_4[/tex]

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

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The ancient Egyptians planted crops and raised
animals for food as early as?
100 AD.
2000 BCE.
5200 BCE.
2560 BCE.

Answers

2560 BC) , some Egyptologists have claimed that the ancient Egyptians used an approximation of π as 22/7 from as early as the Old Kingdom.

Is a compound a mixture or a pure substance

Answers

Answer:

A compound is a pure substance.

a compound is a pure substance

22. What is the mass in grams of each of the following?
a. 3.011 x 1023 atoms F
b. 1.50 x 1023 atoms Mg
c. 4.50 x 1012 atoms Cl
d. 8.42 x 1018 atoms Br
e. 25 atoms W
f. 1 atom Au

Answers

The mass in grams of 3.011 x 10²³ atoms of F is 9.5 g.

The mass in grams of  1.50 x 10²³ atoms of Mg is 5.98 g.

The mass in grams of  4.50 x 10¹² atoms of Cl is 2.65 x 10⁻¹⁰ g.

The mass in grams of  8.42 x 10¹⁸ atoms of Br is 1.12 x 10⁻³ g.

The mass in grams of  25 atoms of W is 3.1 x 10⁻²¹ g.

The mass in grams of  1 atom of Au is 3.27 x 10⁻²² g.

What is the mass in grams of 3.011 x 10²³ atoms F?

The mass in grams of 3.011 x 10²³ atoms of F is calculated as follows;

6.023 x 10²³ atoms = 19 g of F

3.011 x 10²³ atoms F  = ?

= (3.011 x 10²³ x 19 g)/(6.023 x 10²³)

= 9.5 g

The mass in grams of  1.50 x 10²³ atoms of Mg is calculated as follows;

6.023 x 10²³ atoms = 24g of Mg

1.5 x 10²³ atoms F  = ?

= (1.5 x 10²³ x 24 g)/(6.023 x 10²³)

= 5.98 g

The mass in grams of  4.50 x 10¹² atoms of Cl is calculated as follows;

6.023 x 10²³ atoms = 35.5 g of Cl

4.5 x 10²³ atoms Cl  = ?

= (4.5 x 10¹² x 35.5 g)/(6.023 x 10²³)

= 2.65 x 10⁻¹⁰ g

The mass in grams of  8.42 x 10¹⁸ atoms of Br is calculated as follows;

6.023 x 10²³ atoms = 80 g of Br

8.42 x 10¹⁸ atoms Br = ?

= (8.42 x 10¹⁸  x 80 g)/(6.023 x 10²³)

= 1.12 x 10⁻³ g

The mass in grams of  25 atoms of W is calculated as follows;

6.023 x 10²³ atoms = 74 g of W

25 atoms W = ?

= (25  x 74 g)/(6.023 x 10²³)

= 3.1 x 10⁻²¹ g

The mass in grams of  1 atom of Au is calculated as follows;

6.023 x 10²³ atoms = 197 g of Au

1 atom of Au = ?

= (1  x 197 g)/(6.023 x 10²³)

= 3.27 x 10⁻²² g

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Where is groundwater stored?


Answers

Answer:

Answer Below! : )

Explanation:

Groundwater is stored in the tiny open spaces between rock and sand, soil, and gravel. How well loosely arranged rock (such as sand and gravel) holds water depends on the size of the rock particles.

Hope this helps! : )

Answer:

Underground  brainliest plz

Explanation:

Hi. Please tell me When you test starch with Barfoed’s reagent, what would be the answer, positive or negative? Explain the answer by giving reasons and structures.

Answers

by adding the positive the answer would be above b so that’s answer would be d

How many milligrams are in 2.89 x 1024 CO2 molecules?

Answers

Answer:

2,959.36

Explanation:

There are 2959.36 milligrams present in 2.89 x [tex]10^{24}[/tex]  CO2 molecules.

What is molecule?

The smallest component of a substance which possesses both its chemical as well as physical characteristics. One or even more atoms make up molecules.

What is milligrams?

Such a measure of mass as well as weight that weighs 0.0154 grains or one-thousandth of a gram.

Calculation of milligram in CO2 molecule.

Mass = No. of molecule / molar mass.

Molar mass = 44.02 g/mol.

Mass = 2.89 x [tex]10^{24}[/tex]  /[tex]6.023 * 10^{23}[/tex]× 44.02 g/mol.

Mass = 2959.36 milligrams

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b. How does government funding affect scientific progress? (1 point)

Answers

Answer:

29 percent of federal R&D money goes to universities, 29 percent goes to industry, and another 29 percent goes to researchers who work directly for federal agencies. About 10 percent goes to federally funded labs operated by private contractors.

Answer:

Explanation:

Funding from the government greatly affects the scientific research as a research can take number of years to complete. During this time period lot of financial support is required as there might be lot of expensive chemicals or substance that the scientist requires for his research.

The water in a fishery became polluted when toxic waste was dumped into its pond, causing the fish population to substantially decline. The percents of fish that survived are recorded in the table.
Day 1 2 3 4 5
% Survival 79 55 38 31 19


a) What is the order of the reaction live fish ------> dead fish?

b) What is the rate constant?

c) If the fish continue to die at this rate, how many fish will be alive after 10 days?

Answers

In the pond, the percentage of fish left after ten days is 4%.

Given that;

N(t) = Noe^-kt

Where;

N(t) = percentage of fish at time t

No = Initial percentage of fish

k = rate constant

t = time taken

Given that we had 100% fish population at the beginning, we can see that this reaction is first order.

The rate constant is obtained from;

When t = 5

19 = 100e^-5k

19/100 =e^-5k

0.19 = e^-5k

ln 0.19 = -5k

k = ln (0.19)/-5

k = 0.33

In ten days;

N(10) = 100e^-0.33(10)

N(10) = 4%

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THIS IS MY LAST WUESTION FOR MY TEST I ONLY HAVE 30 MINS LEFT TO ASNWER HELP.

Tiffany decided to make a salad for her lunch. She combined Lettuce, croutons, bacon,
cucumbers, cheese, ham and salad dressing into her bowl. As she was adding each different
ingredient, she tasted each one to make sure that she like it. When she was done, she ate her
salad. She noticed while she was eating the salad, that it had a different flavor than each of the
original ingredients. What type of change occurred?
Homogenous change
A solution change
A chemical change
A physical change

Answers

The answer is A Physical Change. A physical change is a change that does not involve a change in composition

highlight main approaches that could be used to investigate the waterer Quality.​

Answers

Answer:

Seven methods were used to assess water quality in the river system. These methods included single-factor assessment, water quality grading, comprehensive pollution index, the Nemerow pollution index, principle component analysis, fuzzy comprehensive evaluation, and comprehensive water quality identification index.

Which layer is thin, brittle, solid, and composed primarily of silica?

the crust

the mantle

the outer core

the inner core

Answers

The crust.

You can immediately cross out the inner and outer core. And the mantle is the layer between the crust and the cores.


A solution is prepared by diluting 6.0 mL of a 7.6 x 10-4 g/mL solution to a total volume
of 10.0 mL. Calculate the concentration of the dilute solution.

Answers

Answer:

4.56 X 10^ -4 g/mL

Explanation:

A solution is  prepared by diluting 6.0 mL of a 7.6 x 10-4 g/mL solution to a total volume of 10.0 mL. Calculate the concentration of the dilute solution.

(7.6 X10^-4  gm/m L) x( 6.0 m L ) = 45.6 X 10^-4 g

this is dissolved )in 10 m L=45.6 X 10^-4  g/ 10

4.56 X 10^ -4 g/mL

check

6/10 =0.6

4.56/7.6 = o.,6

When a sample of iron ore of mass 2.016 g is treated with 50.0 mL of hydrochloric acid, the iron dissolves in the acid to form a solution of . The solution is diluted to 100.0 mL and the concentration of ions is determined by spectrometry to be . What is the mass percentage of iron in the ore

Answers

The mass percentage of iron in the ores is 0.05036 g Fe2+

Please for real help me, show work !

Answers

Answer:

27)

a. Silver nitrate

b. Lead chromate

c. Anhydrous magnesium acetate

d. Copper nitrate

28) a. KNo3

Which has more calories: table sugar or aspartame?

Answers

Answer:

Aspartame produces 4 kilocalories of energy per gram when metabolized, sucrose (table sugar) produces 3.9 kilocalories. However, aspartame is approximately 200 times sweeter than sucrose, so it is consumed in much smaller doses.

Explanation:

Answer is Aspartame.

Select the correct answer.
What are the products in the following chemical reaction?
Pb(NO3)2 + KCl

Answers

Lead (II) chloride+ potassium nitrate
PbCI2+KNO3(B)

Phản ứng phân hủy dinitơ pentaoxide N2O5 là một phản ứng bậc 1 có giá trị hằng số tốc độ
K = 5,1.10-4
s
-1
tại 45oC.
2N2O5(k) → 4NO2(k) + O2(k)
a. Biết nồng độ ban đầu của N2O5 là 0,25M, hỏi sau 3,2 phút nồng độ của nó là bao nhiêu?
b. Sau bao lâu nồng độ N2O5 giảm từ 0,25M thành 0,15M?
c. Sau bao lâu chuyển hóa hết 62% N2O5?

Answers

When converted to a household measurement, 9 kilograms is approximately equal to a

Aluminium sulphate is organic or inorganic compound​

Answers

Answer:

Aluminium sulphate is an inorganic compound.

What physical and chemical properties would an antique dealer use to determine the substance that makes up a
piece of jewelry?

Answers

Answer:

Characteristics such as melting point, boiling point, density, solubility, color, odor, etc. are physical properties. Properties that describe how a substance changes identity to produce a new substance are chemical properties. ... Physical and chemical properties can be used to classify a substance as ionic or molecular.

Sometimes people have to cry out all their tears, to make room for a heart full of smiles.​

Answers

True. I am always sad but my heart is always happy cuz it knows there are good things ahead

15.3 Determine the mass of the following: 15.3.1. 2 mol calcium atoms
15.3.2. 0,3 mol nitrogen molecules
15.3.3. 0,5 mol table salt
15.3.4. 0,2 mol hydrochloric acid
15.3.5. 0,08 mol sodium carbonate (Na2CO3)
15.3.6. 0,25 mol ammonium sulphate (NH4)2SO4​

Answers

Answer:

htyiu

Explanation:

[EASY][50pt] Temperature vs Time Graph
5. In what state of matter does this substance exist at the 22 minute mark?

6.At what temperature does condensation occur?

7.What phase change occurs at 70C

Answers

#5

At 22min the temperature is at 40°C

So the matter is at solid state.

#6

Graph ended at 20°C so condetion occured at 20°C

#7

After 70°C the matter got melted do its at liquid state

calculate the mass in grams of two cubic inches (2.00 in³)" of gold. density of gold =19.3 g cm-.³​

Answers

Taking into account the definition of density,  the mass of two cubic inches (2.00 in³) of gold is 632.54 grams.

But first you must know the definition of density. Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words,  density is a scalar quantity referring to the amount of mass in a given volume of a substance, that is, it shows the relationship between the weight (mass) of a substance and the volume it occupies.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density=\frac{mass}{volume}[/tex]

In this case, you know that:

Density= 19.3 g/cm³ Volume= 2 in³= 32.7741 cm³ (being 1 in³= 16.3871 cm³)

Replacing in the definition of density:

[tex]19.3\frac{g}{cm^{3} } =\frac{mass}{32.7741 cm^{3} }[/tex]

Solving:

mass= 19.3 [tex]\frac{g}{cm^{3} }[/tex]× 32.7741 cm³

mass= 632.54 g

In summary, the mass of two cubic inches (2.00 in³) of gold is 632.54 grams.

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How many mL of 1.76 M sodium hydroxide solution (strong base) must be added to 0.75
Macetic acid to make 683 mLa pH 49 buffer? (pka of acetic acid is 4.76)

Answers

Answer: Special care is required to prepare a solution of sodium hydroxide or NaOH in water because considerable heat is liberated by the exothermic reaction. The solution may splatter or boil. Here is how to make a sodium hydroxide solution safely, along with recipes for several common concentrations of NaOH solution.

Explanation:

Hope this helps!

Determine the molar solubility for Cr(OH)3 Ksp = 6.3x10^-31 ....

a) Set up the ICE table Cr(OH)3 (s) <-> Cr^3+ (aq) + 3OH^- (aq)

b) Ksp expression

c) Determine molar solubility

Answers

The equilibrium constant shows the extent of dissolution of a substance in solution. The molar solubility of the compound here is 1.2 * 10^-8 M.

What is solubility product?

The solubility product is the equilibrium constant that shows the extent to which a substnace is dissolved in soution.

Now let us set up the ICE table as shown;

               Cr(OH)3 (s) <-> Cr^3+ (aq) + 3OH^- (aq)

I                                           0                 0

C                                          +x               +3x

E                                          x                   3x

Ksp = [Cr^3+] [OH^- ]^3

6.3x10^-31 = [x] [3x]^3

6.3x10^-31 = 27x^4

x = 4√6.3x10^-31 /27

x = 1.2 * 10^-8 M

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Please answer question (e)

Answers

Answer:

here is no question (e).............

Radar images storms by

Answers

Weather radar consists of a rotating dish protected by a large white dome; this dish sends pulses of energy (the radar beam) into the atmosphere to

state why vulcanologist make predications about when a volcano will erupt

Answers

Answer:

They want to know how long it has been since it last erupted.

Explanation:

Scientists study a volcano's history to try to predict when it will next erupt.  They also want to know the time span between its previous eruptions

Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical
formula in the last column.
solution A
solution B
Does a
precipitate form
when A and B
are mixed?
Oyes no
empirical
formula of
precipitate
х
X
x
5
?
copper(II) chloride
sodium sulfide
potassium sulfate
O yes no
lead(II) nitrate
ammonium bromide
sodium hydroxide
O yes no
Que

Answers

The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.

The solubility of a substance in water is in accordance with the solubility rules.  It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.

Now, we will consider each reaction individually to decode whether or not a precipitate is possible.

In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formedIn the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g)  + NaBr(aq) + H2O(l), a precipitate is not formed here.

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