Part g
consider the melting points of sugar and salt, as well as the states of sugar, salt, and oil
at room temperature. what can you conclude about the attractive forces between
particles in the three substances?

Answer:

x²+6x+5=0

On comparing with the equation

ax² + bx + c = 0

a=1, b = 6 and c = 5

Now

b²– 4ac = 6² – 4 x 1 x 5 = 36 - 20 = 16

[tex]x = \frac{ - b \:± \: \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ x = \frac{ - 6\:± \: \sqrt{16 } }{2 \times 1} \\ \\ x = \frac{ - 6± {4} }{2} \\ \\ x = \frac{ - 6 + {4} }{2} \: \: or \: \: x = \frac{ - 6 - {4} }{2} \\ \\ \implies \: x = \frac{ \cancel-2 }{ \cancel2}^{-1 }\: \: or \: \: x = \frac{ \cancel-10 }{ \cancel2}^{-5}\\ \\ \implies \: { \blue{\fbox{ \: x = - 1 \: \: \: or \: \: \:x = - 5}}}[/tex]

[tex] {x}^{2} + 6x + 5 = 0 \\ \\ {x}^{2} + 5x + x + 5 = 0 \\ \\ x(x + 5) + 1(x + 5) = 0 \\ \\ (x + 1)(x + 5) = 0.[/tex]

[tex]x = - 1 \\ x = - 5.[/tex]

The IUPAC nomenclature system is a set of logical rules devised and used by organic chemists to circumvent problems caused by arbitrary nomenclature.

The 1-ethyl-3-propylcyclopentane molecule contains a total of 30 bond(s) There are 10 non-H bond(s), 3 rotatable bond(s) and 1 five-membered ring(s).

The 1,2-dimethylcyclopentene molecule contains two methyl groups and one double bond in the ring.

The 1,3,5-Triethylbenzene molecule contains three ethyl groups and a benzene ring.

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Answer:

14

Explanation:

sun normal persentage is 14

Answer: 0.84 M

[tex]M_{A}V_{A}=M_{B}V_{B}\\(20)M_{B}=10(1.67)\\M_{B}=\frac{10(1.67)}{20} \approx \boxed{0.84 \text{ M}}[/tex]

Answer:

0.5 M

Explanation:

molarity = (moles of solute)/(liters of solution)

molarity = 2.00/4 = 0.5 M

The amount of the magnesium in the sample in ppm is 497 ppm.

The term parts per million refers to one of the manners in which concentration is expressed. It is common in oceanography and analytical chemistry.

Given that;

Mass of Mg= 0.0549 g

Mass of the sample = 110.52 g

Amount in PPM = 0.0549 g/110.52 g * 10^6

= 497 ppm

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Hence, 5.1 * 10^-11 alpha particles is being emitted each second by the sample.

The term half life is the time taken for only half of the original  amount of radioactive nuclides to remain.

Thus, we have that the half life is 432.2 years or 1.36 * 10^10 s.

k = 0.693/ 1.36 * 10^10 s

k = 5.1 * 10^-11 alpha particles per second.

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The volume of the gas in a sealed container would be decreased at constant pressure: C. by raising the temperature.

Charles law states that when the pressure of an ideal gas is kept constant, the volume of a gas is directly proportional to the absolute temperature of the gas.

This ultimately implies that, the volume of a gas decreases at constant pressure when its temperature is decreased and vice-versa.

In conclusion, we can infer and logically deduce that the volume of the gas in a sealed container would be decreased at constant pressure by raising the temperature in accordance with Charles law.

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1 mol of every gas weighs 22.4L at STP

So

Moles of oxygen

1 mol Nitrogen required for 2 mol O_2

0.5 mol N_2 required for 1 mol O_2

Moles of Nitrogen

Volume

Consider the reaction is taking place at standard temperature and pressure. Then 22.4 L reacts with 44.8 L of oxygen. Thus, 33.6 L of oxygen needs 16.8 L of nitrogen.

The condition of STP is the standard temperature and pressure. The temperature of 298 K and  pressure of 1 atm is called the standard condition.

At STP the volume of every substance is 22.4 L. The reaction of  nitrogen and oxygen forming nitrogen dioxide is given below:

[tex]\rm N_{2} + 2O _{2} \rightarrow 2 NO_{2}[/tex]

As per this reaction, 22.4 L of nitrogen reacts with  (2 × 22.4) = 44.8 L of oxygen. Hence, the volume of nitrogen required by 33.6 L of oxygen is calculated as follows:

(33.6 L × 22.4 L) / 44.8 L = 16.8 L

Therefore, the volume of nitrogen required to react with 33.6 L  of oxygen is 16.8 L.

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The volume of ethane gas, C₂H₆ in cm³ that will react to produce 40 cm³ of CO₂ is 20 cm³

2C₂H₆ + 7O₂ —> 4CO₂ + 6H₂O

From the balanced equation above,

4 cm³ of CO₂ were obtained from 2 cm³ of C₂H₆

From the balanced equation above,

4 cm³ of CO₂ were obtained from 2 cm³ of C₂H₆

Therefore,

40 cm³ of CO₂ will be obtain from = (40 × 2) / 4 = 20 cm³ of C₂H₆

Thus, 20 cm³ of C₂H₆ are required for the reaction.

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Answer:

heres your answer 50gms

Answer: [tex]\text{N}_{5}\text{O}_{10}[/tex]

Explanation:

This means the molecular mass of nitrogen dioxide is [tex]14.0067+2(15.9994)=46.0055[/tex] g/mol.

Dividing this molecular mass of the compound we need to find, we get that

[tex]\frac{230.05}{46.0055} \approx 5[/tex].

So, the final answer is [tex]\boxed{\text{N}_{5}\text{O}_{10}}[/tex]

Extinct species be saved by increasing their population numbers and is denoted as option B.

This is defined as the total number of organisms in a particular area at a given period of time.

Extinct species can be saved by increasing their population through conservation and public awareness.

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The average reaction rate during that time period is 0.0025 mol/l.

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Given data:

[tex]t_1[/tex] = 10 seconds

[tex]t_2[/tex] = 20 seconds

[tex]C_1[/tex] = 0.210 mol/L

[tex]C_2[/tex] = 0.185 mol/L

∆C = |[tex]C_2[/tex]–[tex]C_1[/tex]| = |0.185-0.21| = 0.025 mol/l

∆t = [tex]t_2[/tex]– [tex]t_1[/tex] = 20 - 10 = 10 sec

∆C — is the concentration change

∆t — is the time change

V — reaction rate

V=  [tex]\frac{\Delta C}{\Delta t}[/tex] = [tex]\frac {0.025}{10}[/tex]= 0.0025 mol/l•sec

Hence, 0.0025 mol/l is the average reaction rate during that time period.

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The correct answers are Potential and Kinetic energy.

An object can store energy as a result of its position. For example, the heavy ball of a demolition machine is storing energy when it is held at an elevated position. This stored energy of position is referred to as potential energy. Similarly, a drawn bow is able to store energy as a result of its position.

Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

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In this case, among the list of components given, the abiotic factors are water, rock, soil, and sun.

An abiotic factor is a non-living part of an ecosystem that shapes its environment.

Biotic and abiotic factors make up a community via interaction.

Biotic factors are considered living things (having "life") while abiotic factors are simply non-living things.

Hence, in this case, among the list of components given, the abiotic factors are water, rock, soil, sun

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Decanting, filtration, sublimation and distillation are the separation techniques.

Decanting is a process in which a liquid is carefully poured out, leaving the solid behind in the container.

A solid is caught on paper or a membrane while the liquid passes through, this process is called Filtration.

Sublimation is a process in which a solid mixture is heated in which one component transitions directly between solid and gas.

A solvent is added to dissolve only one mixture component and then the liquids are separated, this process is known as distillation.

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The physical separation techniques used are :

Physical Separation techniques are procedures applied for the separation of a mixture of two different states pf matter based on their physical properties. usually solid and liquid mixtures. When a mixture of liquid and solid is separated by carefully pouring out the liquid while leaving the solid behind that separation technique is known as decanting.

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Answer:

its particles slow down and come closer together.

The 6.023 * 10²³  molecule means  384.7 grams of Vitamin D.

A mole is a universal unit used to measure large number of atoms , molecules of an element.

one mole is equal to the Avogadro's Constant.

Mole is equal to the ratio of the mass of a compound to its molecular weight

It is given that Vitamin D is present

no. of molecule = 6.023 * 10²³

6.023 * 10²³ molecule constitutes of 1 mol

1 mole  is equal to the molar mass of a compound/ element

Therefore 1 mole = 384.7grams of Vitamin D

and hence 6.023 * 10²³  molecule means 384.7 grams of Vitamin D.

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The number of molecules of oxygen in the cylinder is 6.02×1023 molecules

Data obtained from the question

Number of mole of oxygen = 1 mole

Number of molecule of oxygen =?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×1023 molecules. This implies that 1 mole of oxygen contains 6.02×1023 molecules.

Since the cylinder contains 1 mole of oxygen, then the number of molecules of oxygen present in the cylinder is 6.02×1023 molecules.

answer:

is Well-Known Member. For a 35" you should be in the 28-32 range on road.

Explanation:

your welcome make brainlist

Answer:

Right if you think it is.

Answer:

The correct answer is Au, H

(Took the exam)

The exercise requires you to complete the sentences using the drop down. The complete sentences are given below.

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The next step in the engineering design process is to identify the criteria and constraints of the process.

The process of engineering design has to do with the fabrication of new materials or the reworking of existing materials to fit into certain pre-specified objectives.

In this case, the next step in the engineering design process is to identify the criteria and constraints of the process.

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Answer:

3.1 x 10^10

Explanation:

there are 9 zeroes, so the quick way is too just add a one to the 9 and you get 10, so that is your power.