Place the following cell types in the order they are shown to appeared on earth

Answer:

isolation is a significant factor in adaptation and speciation

Explanation:

In the theory of evolution by natural selection proposed by Darwin, adaptation refers to the adjustment of organisms to their environments in order to increase their chances of survival in that environment. In the Galapagos Islands, Darwin observed that finches had different types of beaks adapted to the type of food they ate. From this observation, Darwin proposed that finches evolved to eat different food sources. In this case, the islands lead to an adjustment (evolutionary) process by which geographically isolated individuals accumulate genetic differences in order to adapt them to the environmental conditions in the islands, which then may also prevent breeding between individuals from different islands when they are reunited (i.e., it may also lead to speciation).

Answer:

Because of the garden that the dude made on mars.

Explanation:

The dude grew plants from his crew's poop and made a little tent with airtight seals, and as he said, once you grow something, you colonize it.

Answer:

Virgo

Explanation:

Have a great day :)

Answer:

libra, cancer, aries, scorpio, leo, pisces, saggitarius, aqurious, capicorn, tarous, and gemini

Explanation:

Virgo

The zodiac sign for September  is Virgo.

This zodiac symbol is considered to influence those born August 23 - September 22, under the Virgo zodiac sign

Answer:

All of the choices are correct

Explanation:

The respiratory syncytial virus (RSV) is an enveloped, negative-strand RNA virus (Paramyxoviridae family) capable of infecting ciliated cells of the airways by using its surface glycoproteins G and F for attachment and fusion during viral entry in target cells. RSV can affect the lungs and parts of the respiratory system (e.g., nasopharynx). Although RSV generally causes mild, cold-like symptoms, this virus may also lead to severe infection in babies (12 months) and infants, being one of the most common types of respiratory infections in children, older adults, and immunocompromised patients. Some common symptoms in individuals with RSV pneumonia include fever, nonproductive cough, dyspnea, wheezes, rales, rhonchi, etc.

Answer:

The answer is the first one, i hope it helps

Explanation:

Answer:

The soil could kill the plants in the area and the consumers will lose there food and the organisms will die off or go extinct.

Explanation:

Answer:

[tex]\huge\mathcal\red{Answer...} \\ \\ \huge\mathsf\purple{photosynthesis \: } \\ \\ \huge\mathfrak\orange{hope \: it \: helps..}[/tex]

Answer:

(ﾉ≧∇≦)ﾉ

Our Respiratory system gets rid of Carbon Dioxide as a waste product. Carbon Dioxide is then taken in by plants for the process of

[tex]photosynthesis[/tex]

I hope it helps

have a nice day

#Captainpower

Answer:

answer 3

Explanation:

because john said so

Answer:

Orchids, Queen’s Tears, Lilies, Poinciana, Torch Ginger, Heliconia and Bromeliads. Orchids. This type of rainforest flowers grows in humid environments such is the Amazon rainforest. This type of rainforest flower is most frequently found rainforest flower in tropical rainforests.

Explanation:

respiration

photosynthesis

Answer:

sample

Mass

Starting

temp.

Answer:

A. Wind

wind is a renewable resource because there is unlimited supply of it.

Explanation:

Answer:

Chains of amino acids make proteins. They can fold into many different complex shapes.

Answer:

will you msg me in I.nstagram

11. The balanced chemical reaction is:

2 B(IO₃)₃ + 3 Fe₃P → 2 BF₃ + 3 Fe(IO₃)₂

12.  In this case, the limiting reagent is the Iron (II) phosphide.

13. The amount of Iron (II) iodate produced is 1.825 moles.

14. The amount of excess Boron iodate remaining after the reaction is 0.265 moles.

15. The actual yield of the reaction is 132.1 g.

11. To write the balanced chemical reaction, we need to first determine the correct coefficients for each reactant and product. We can do this by balancing the number of atoms of each element on both sides of the equation.

12. The limiting reagent is the reactant that is used up first. In this case, the limiting reagent is the Iron (II) phosphide. This is because 112.0 g of Iron (II) phosphide is equivalent to 0.560 moles, which is less than the 1.825 moles of Boron iodate.

13. To calculate the amount of Iron (II) iodate produced, we need to multiply the number of moles of Boron iodate by the molar ratio between Boron iodate and Iron (II) iodate.

14. The amount of excess Boron iodate remaining after the reaction is 0.265 moles. This is because 1.825 moles of Boron iodate minus 0.560 moles of Iron (II) phosphide is equal to 0.265 moles.

The amount of excess Iron (II) phosphide remaining after the reaction is 56.0 g. This is because 0.560 moles of Iron (II) phosphide is equal to 56.0 g.

15. To calculate the actual yield of the reaction, we need to multiply the theoretical yield by the percentage yield.

The actual yield of the reaction is 132.1 g. This is because 1.825 moles of Boron iodate is equivalent to 132.1 g and the percentage yield is 72.659.

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Answer:

the yard did not have enough nutrients to support all 10 trees that were planted

Explanation:

Answer:

A nebula is a giant cloud of dust and gas in space. Some nebulae (more than one nebula) come from the gas and dust thrown out by the explosion of a dying star, such as a supernova. Other nebulae are regions where new stars are beginning to form. For this reason, some nebulae are called "star nurseries."

Explanation:

Answer:

True

Explanation:

A mutation is any alteration in the genetic sequence of the genome of a particular organism. Mutations in the germline (i.e., gametes) can pass to the next generation, thereby these mutations can increase their frequency in the population if they are beneficial or 'adaptive' for the organism in the environment in which the organism lives (in this case, an insect/bug). The mutation rate can be defined as the probability of mutations in a single gene/locus/organism over time. Mutation rates are highly variable and they depend on the organism/cell that suffers the mutation (e.g., prokaryotic cells are more prone to suffer mutations compared to eukaryotic cells), type of mutations (e.g., point mutations, fragment deletions, etc), type of genetic sequence (e.g., mitochondrial DNA sequences are more prone to suffer mutations compared to nuclear DNA), type of cell (multicellular organisms), stage of development, etc. Thus, the mutation rate is the frequency by which a genetic sequence changes from the wild-type to a 'mutant' variant, which is often indicated as the number of mutations per round of replication, per gamete, per cell division, etc. In a single gene sequence, the mutation rate can be estimated as the number of de novo mutations per nucleotide per generation. For example, in humans, the mutation rate ranges from 10⁻⁴ to 10⁻⁶ per gene per generation.

Answer:

A. They regulate the development of body parts

Explanation:

I just did it on Savvas (Pearson)

The statement which is true about HOX genes is they regulate the development of body parts.

HOX genes may be defined as components of the homeotic transcription factor family that play a key part in controlling the body plan.

HOX genes play two important roles, which are given below:

Therefore, the statement which is true about HOX genes is they regulate the development of body parts.

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Answer:

meander

Explanation:

A meander is a series of regular sinuous curves in the channel of a stream/river/watercourse, thereby forming a rounded or "S"-shaped bend curve. Meanders are common in alluvial areas that have low gradients, where they are formed by the dynamics of the watercourse. The meander belt is the zone within which a meandering watercourse occupies on its floodplain. The sinuosity is a measure to calculate the degree of meandering in the channel of a watercourse.

Answer:

THE ANSWER IS B I THINK

Explanation:

RJEBEJRHRHRRHRH

Answer:

The answer is "PK1 activates PK2"

Explanation:

All enzymes were required again for the transmission of a signal. If Pk1 is continuously active, pk2 will no longer be required, as per my theory, can trigger pk1, therefore the cells were if they amplify the message even when they're not active. But since both enzymes require regular copies together for transduction, pk2 is simple and pk1 requires to also be activated.