PLEASE ANSWER ASAP
A random sample of n50 ASU students shows that they spend an average of $3.17 on coffee/tea each day with standard error of about $1.11. FIND and INTERPRET a 95% confidence interval for the mean amount spent on coffee/tea by an ASU student Note: you do not have to show work on how you found your interval, but you do need to be thorough with your interpretation of the found interval.

The option that is NOT a requirement for a density​ curve is option

A. The graph is centered around 0.

A graph that displays probability is known as a density curve. All probability are represented by 100% of the curve's area under the curve.

Note that you can alternatively state that the area is equal to 1 because 100% is a decimal, which is how we typically express probabilities. Those are some characteristics of a density curve. One particular category of density curves is the normal density curve. They are bell-shaped, symmetric, and unimodal.

Therefore, To view the distribution of a variable in a dataset, utilize density graphs. The graph is plotted across a continuous range of time. Another name for this is a kernel density plot. Histograms are modified into density charts. An idealized representation of a distribution is a density curve, and there is no centered graph at point zero.

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Which of the following is NOT a requirement for a density​ curve?

Choose the correct answer below.

A.

The graph is centered around 0.

B.

The curve cannot fall below the horizontal axis.

C.

The total area under the curve must equal 1.

D.

Every point on the curve must have a vertical height that is 0 or greater.

The regulatory requirements for continuing professional development for Certificate of Registration holders in real estate differ from location to location. Here is an example of what obtains in the US.

According to MCKissock Learning, the Real Estate Professional must complete the following:

It is to be noted that Continuing education classes allow you to expand your knowledge and abilities in a certain field. Local school districts, colleges, and universities provide continuing education classes to individuals in the community. Courses in anything from digital design to philosophy to visual literacy are available.

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Answer:

x = 4.2

Explanation:

log 11 = log(x - 2) + log(5)

log 11 = log(5x - 10)

Taking antilog,

11 = 5x - 10

5x = 21

x = 4.2

Answer:

Explanation:

We know that Julian's profit per download is 0.75x dollars. Let's start by setting up an equation for his total profit, given the number of downloads:

Total profit = (profit per download) x (number of downloads)

We also know that the number of downloads Julian will sell is given by the equation:

Number of downloads = -4x + 160

So we can substitute this expression for the number of downloads into the equation for total profit:

Total profit = (profit per download) x (-4x + 160)

Simplifying this expression:

Total profit = -3x(4x - 160)

Total profit = -12x^2 + 480x

To earn exactly $900 in profit, we set the total profit equal to 900 and solve for x:

-12x^2 + 480x = 900

Dividing both sides by -12:

x^2 - 40x + 75 = 0

We can solve this quadratic equation using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

Plugging in a = 1, b = -40, and c = 75:

x = (-(-40) ± sqrt((-40)^2 - 4(1)(75))) / 2(1)

x = (40 ± sqrt(400)) / 2

x = 20 ± 10

So the two prices Julian can charge per download to earn exactly $900 in profit in his first year are $10 and $30.

To verify, we can calculate Julian's profit for each price:

At $10 per download, Julian will sell -4(10) + 160 = 120 downloads. His profit per download is 0.75(10) = $7.50, so his total profit will be 120 x 7.50 = $900.

At $30 per download, Julian will sell -4(30) + 160 = 40 downloads. His profit per download is 0.75(30) = $22.50, so his total profit will be 40 x 22.50 = $900.

Explanation:

Density, colour, hardness, melting and boiling points, and electrical conductivity are all examples of physical properties.

Answer:

Information is obtained from knowledge because you can utilize your current knowledge to learn new information.

Using the graphical methods [online graph calculator], the domain of (fx) = (x-3)/7x is given as All real numbers except 0. (Option B)

A relation's domain and range are defined as the sets of all the x-coordinates and all the y-coordinates of ordered pairs, respectively.

Graphs may also be used to determine the domain and range of functions. The domain of a graph consists of all the input values represented on the x-axis since the domain refers to the set of potential input values. The range is the collection of potential output values represented on the y-axis.

Notice as indicated in the graph that the coordinates or ordered pairs plotted DO NOT go through the origin which is zero. Also notice that the curved lines, extend to all real numbers on the grapy to infinity.

Hence stated as a mathematical expression, the domain would be:

(-∞, 0) ∪ (0,∞)

{x|x≠0}

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A z-score of 3.4 equates to a height of 92.23

We have to find the height of the player given the figures that we have in he question

We have the formula for the height as

z = x - u / sd

where z is the z score of the player = 3.4

x is the average which is not given here. This would be the height

u is = mean which is the value of 79 inches

while the standard deviation is given by sd = 3.89

We have to put these values in the formula that we have here. Such that we would have

3.4 = x - 79 / 3.89

we have to cross multiply

3. 89 * 3.4 = x - 79

13.226 = x - 79

x = 79 + 13.226

x = 92.23

From the value that we have here, we can see that the height of the player that was reported is given as 92. 23.

This is not believable because it would mean that the height is far greater than the height of all of the players which is 79 inches.

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7) Choose the word that is most nearly similar in meaning to the word MITIGATE.

A/ Exacerbate

B/ Worsen

D/ Escalate

The probability that it would take 6 minutes in order to get a parking space has been calculated to be 0.2524

The question requires us to find the probability that it would take at least 6 minutes in order to find the parking space

The mean u = 4 minutes

The standard deviation sd = 3 minutes

The formula that is to be used for the normal distribution that we have here would be

z = x - u / sd

where P(X < 6)

xu = 4

sd = 3

When we put in these values in the equation we would have

z = 6 - 4 / 3

= 2 / 3

z = 0.6667

we are to find P(X < 0.6667) in the standard normal table

p-value ≈ 0.747518

= P(X > = 6) = (1 - P(X < 6)

= 1 - 0.747518

= 0.2524

0.2524 is the probability it would take 6 minutes in order to find the parking space.

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In comparison to last year's class, this year there are [tex]15[/tex]‰ more students. That means there were [tex]60[/tex] students in the class.

Someone who is enrolled in school or another type of educational facility is called a student. A "student" is someone who attends secondary school or above in the United Kingdom and the majority of commonwealth nations; "pupils" are those who attend primary or elementary schools.

A student is a person who attends school in order to learn. In addition to being people who attend school, such as children, teenagers, or adults, students can also be those who are learning elsewhere, such as in a college or university. A younger student is frequently referred to as a pupil.

Required calculations are,

Let the number of students in last year's class be [tex]x[/tex].

Increase in number of students by [tex]15[/tex]% or [tex]0.15.[/tex]

This year’s strength is [tex]69[/tex].

[tex]1x + 0.15 x = 69[/tex]

[tex]1.15 x = 69\\x = 69/1.15\\x=60[/tex]

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1. The mean for each of these two data sets is 0.058.

2. The standard deviation for each of these two data sets is 0.465.

3. It should be noted that the mean of the days set II is 3 less than the data set of I.

1. From the information, the value of the second data set is obtained by subtracting 3 from the corresponding value of the first data set. In order to calculate the mean for each of these two data sets, this will be:

P(X > 7) = P[(X - U/SD > (7 - 5.9)/0.7]

where sd = standard deviation

= P(Z > 1.57)

= 0.058 (Checking the distribution table)

2. The standard deviation for each of these two data sets will be:

P(52.55 < x < 56.15)

= P[(52.55 - 54.2)/2.9 < x - u/sd < (56.15 - 54.2)/2.9]

= P(-0.57 < z < 0.67)

= 0.749 - 0.284

= 0.465

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Using the z-distribution, the 95% confidence interval for the proportion of critical strikes out of all attacks is given by:

0.3752 < p < 0.4542

A confidence interval of proportions is given by the following rule:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which the parameters are described as follows:

The character has 248 critical strikes out of 598 attacks, hence the values of the parameters are given as follows:

[tex]n = 598, \pi = \frac{248}{598} = 0.4147[/tex]

The confidence level is of 95%, hence the critical value z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.

The lower bound of the interval is given as follows:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4147 - 1.96\sqrt{\frac{0.4147(0.5853)}{598}} = 0.3752[/tex]

The upper bound of the interval is given as follows:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4147 + 1.96\sqrt{\frac{0.4147(0.5853)}{598}} = 0.4542[/tex]

The problem asks for the 95% confidence interval for the proportion of critical strikes out of all attacks.

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