Please can anybody help me with this:
Show that (x − 9)(x − 1) ≡ x^2 − 10x + 9

Answer:

................

Step-by-step explanation:

Answer:

[tex]0 < x < 6[/tex]

Step-by-step explanation:

This question asks to solve an inequality which can be written as:

[tex]\sqrt{x^2-6x+9} < 3[/tex]

Solve for x:

[tex]\sqrt{x^2-6x+9} < 3\\x^2-6x+9 < 9\\x^2-6x < 0\\x(x-6) < 0[/tex]

From here we can deduce that the inequality is [tex]0[/tex] when:

[tex]x = 0[/tex] or [tex]x = 6[/tex]

We can write the solution as:

[tex]0 < x < 6[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 3x - 3x+ 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{}(x - 3) - 3(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3)(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: { (x - 3) {}^{} } [/tex]

Now, we have been given that value of x :

[tex]\qquad \sf  \dashrightarrow \:x < 3[/tex]

So, let's plug the value of x as 3 in the given expression ~

[tex]\qquad \sf  \dashrightarrow \:3 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

Therefore, we can conclude that :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } < 0[/tex]

Value of the expression should be less than 0

Step-by-step explanation

Here ...I'm not too sure about the question as you have written

P = 2 ( 1 + 6 ) and ask to solve for L ...

.So I guess the question you have written is wrong .. ...and I guess there should be L in the place of 1.

...So let me correct the question....

P = 2 ( l + 6 )

P = 2l + 12

P - 2l = 12

- 2l = 12 - P

- 2l = - P + 12

Change the sign of both side of the equation...

2l = P + 12

divide both side by the same number...

L = ( P + 12 ) ÷ 2

[tex]l = \frac{1}{2} p - 12 \times \frac{1}{2} \\ [/tex]

Calculate the product of rational numbers...

[tex]l = \frac{1}{2} p - 6 \\ [/tex]

Answer:

x/3+3=x/8+1/11

x+9/3=11x+8/88

88(x+9)=3(11x+8)

88x+729=33x+24

88x-33x=729-24

55x=705

x=705/55

x=12.80

Answer:

You infer that mean weight of catfusf in the lake is close to 2.2lbs

Step-by-step explanation:

Because it's a random sample of 50.

See below for the proof of the equation 4h² - 4dh + x² = 0 using the Pythagoras theorem

The Pythagoras theorem states that:

Hypotenuse² = Opposite² + Adjacent²

The question is incomplete, as the figure is not given.

So, I will complete the proof using the following parameters:

Substitute the above values in the following equation

Hypotenuse² = Opposite² + Adjacent²

So, we have:

(2√dh)² = x² + (2h)²

Evaluate the exponents

4dh = x² + 4h²

Subtract 4dh from both sides

0 = x² + 4h² - 4dh

Rewrite as:

4h² - 4dh + x² = 0

Hence, the equation has been proved

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#34.

If one's price be d

#35

So old area=150(100)=15000

New area increase

New area

Option C

#36

Prime numbers inbetween

#37

#38

1hr additional=1.5(2)=3$

Equation is

So

Option A

Answer:

here i have tried 2 question hope it help u

Answer:

[tex]2x - 2y = 24 \\ 2(x - y) = 24 \\ x = 12 + y......eq(1) \\ 4x + 7y = - 40......eq(2) \\ substituting \: the \: value \: of \: x \: in \: eq(2) \\ 4(12 + y) + 7y = - 40 \\ 48 + 4y + 7y = - 40 \\ 11y = - 40 - 48 \\ y = \frac{ - 88}{11} \\ y = - 8 \\ putting \: the \: value \: of \: y \: im \: eq(1) \\ x = 12 - 8 \\ = 4[/tex]

Step-by-step explanation:

3x-2y=24......eqi

x+2y=48........eqii

now solving eq i&ii

4x=72

x=72/4

x=18

now putting the value of x in eqii

18+2y=48

2y=48-18

y=30/2

y=15

Answer:

135 cubes

Step-by-step explanation:

Volume of cuboid :

Volume of a small cube :

Number of cubes :

You should plot the total distance traveled from the base camp on the x-coordinate while the elevation should be plotted on the y-coordinate.

A graph simply refers to a type of chart which is commonly used to graphically represent data on both the vertical and horizontal lines of a cartesian coordinate (x-coordinate and y-coordinate).

In this scenario, you would plot the total distance traveled from the base camp on the x-coordinate while the elevation of the camps would be plotted on the y-coordinate as shown in the image attached below.

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Answer:

180-108=72   72/2=36 degrees

Step-by-step explanation:

Please ad brainliest

Answer:

4/19

Step-by-step explanation:

Jar a: 3/8

Jar b: 1/11

8+11 = 19

3+1= 4

4/19

Answer:

a line segment

Step-by-step explanation:

Answer:

A line segment is part of a line that has two endpoints and is finite in length. A ray is a line segment that extends indefinitely in one direction.

Step-by-step explanation:

hope this helps

Yes

Step-by-step explanation:

[tex] \cos( \alpha ) = \frac{base}{hypoteneuse} [/tex]

Its just correct..

Answer:

9 / 2 = 4.5

4.5 - 4 = 0.5

Answer:

10

Step-by-step explanation:

32 - 12 (because C is 12 years younger) = 20

20 / 2 (because twice Anna's age, so we do the inverse) = 10

Anna is 10 years old.

Hope this helps!

Answer:44

Step-by-step explanation:

Answer:Angle BCE

Step-by-step explanation:

look across from point C

Check the picture below.

Answer:

  3 1/2 square units

Step-by-step explanation:

For this small triangle whose vertices are on grid points, the use of Pick's theorem will give the area with the least work.

__

Pick's theorem says that the area is ...

  A = i +b/2 -1

where i is the number of grid points inside the boundary, and b is the number of grid points on the boundary.

Here, only the given coordinates are boundary points that are on grid points. (b = 3)

The figure shows us three grid intersections inside the boundary of the triangle. (i = 3)

That means the area is ...

  A = 3 +3/2 -1 = 3 1/2 . . . . square units

_____

Alternate solution

The triangle is bounded by a square 3 units on a side. From that, we can subtract a 2×3 triangle at upper left, a 1×2 triangle at upper right, and a 3×1 triangle at the bottom. That leave a figure area of ...

  A = 3² -1/2(2×3) -1/2(1×2) -1/2(3×1) = 9 -3 -1 -3/2 = 3 1/2 . . . . square units

(The area of a triangle is 1/2bh, where b and h are the base and height of the triangle.)

__

Another alternate solution can be had by using a formula with the vertex coordinates:

  A = 1/2|(x1)(y2 -y3) +(x2)(y3 -y1) +(x3)(y1 -y2)|

  = 1/2|(-8)(3 -5) +(-5)(5 -2) +(-6)(2 -3)| = 1/2|16 -15 +6| = 3 1/2 . . . square units

The expression (7+ y) ∙9 is described by its factors and terms as; lt is has two factors and the factor (7+ y) has two terms.

(7 + y) × 9

63 + 9y

The factors are 7 and y and the two terms are 63 + 9y.

Therefore, the correct answer is; lt is has two factors and the factor (7+ y) has two terms.

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To solve this problem, we must consider all the trigonometric equations:

 ⇒ (see image below)

Let's examine the diagram:

Thus we can use:

 [tex]cos(A)=\frac{35}{53} \\A= cos^{-1}(\frac{35}{53})\\ A = 48.67[/tex]

Answer: 49 degrees (as rounded)

Hope that helps!

Answers:

===========================================================

Explanation:

Think of a hexagonal room with n = 6 walls, i.e. the floor is a hexagon with n = 6 sides. The floor and ceiling are parallel to each other, and congruent hexagons. That's 2 faces so far. Then we have another 6 faces to account for the walls. This gives 2+6 = 8 faces of a hexagonal prism.

In more general terms, a prism with a base of n sides will have 2 parallel and congruent base faces, and n walls or lateral faces. This gives n+2 total faces.

------------------------

Let's go back to the hexagonal prism. The floor has 6 sides to it, and so does the ceiling. We have 6+6 = 12 edges so far. Then we have another 6 edges where each of the rectangular walls meet up. That gives 12+6 = 18 edges total of this hexagonal prism room.

For any more general case, each base has n sides. That gives 2n sides so far for just the bases. Then add on another n for the lateral edges and we get 3n total edges.

--------------------------

Once again lets revisit the room with the hexagonal floor and ceiling. The floor has 6 vertices and the ceiling has the same vertex count. Therefore, this prism has 6+6 = 12 vertices.

For the general case, each base has n vertices. There are 2 such identical bases giving 2n vertices total.

---------------------------

One way to check the answer:

We could use Euler's Polyhedron Formula which is

F+V-E = 2

where,

For the hexagonal prism we found

Then notice how

F+V-E = 2

8+12-18 = 2

20-18 = 2

2 = 2

This confirms the formula works for a hexagonal prism.

Now let's check it for the more general case

We found earlier that,

So,

F+V-E = 2

n+2+2n-3n = 2

3n-3n+2 = 2

0n+2 = 2

0+2 = 2

2 = 2

This helps confirm the answer for any prism with the base of n sides.

Answer:

Hope the picture will help you.....................

Answer:

[tex]2[/tex]

Step-by-step explanation:

[tex] {16}^{ \frac{1}{4} } \: is \: the \: same \: as \\ \\ \sqrt[4]{16} = \sqrt[4]{ {4}^{2} } [/tex]

Note we broke down the 16 into 4 squared*. This is because 4 squared is the same as 16. The four and the two would cancel each other leaving:

[tex] \sqrt[2]{4} \;\\ or \\ \: \sqrt [2]{{2}^{2}} [/tex]

Like before the two and the two would cancel each other out leaving:

[tex]2[/tex]

Answer:

C. 2

Step-by-step explanation:

edge

Answer:

32π cm^3.

Step-by-step explanation:

The volume of a cone is 1/3 of the volume of a cylinder with the same base area and height.

So the empty space = 2/3 * 48π

= 32π cm^3.

✒️ Equation

••••••••••••••••••••••••••••••••••••••

A. To find the x - intercept, let y = 0.

[tex]\tt \: \: \large \tt \: \begin{array}{|c|} \hline \tt \: 4x \: - \: 3y \: = \: \tt\underline{\green{ 12 }} \\ \tt 4x \: - \: 3(0) \: = \: \tt\underline{\blue{ 12 }} \\ \tt4x \: - \: 0 \: = \: \tt\underline{\pink{ 12 }} \\ \tt \tt\underline{\red{ \: x \: = \: 3 }} \\ \\ \tt \: x ↬\: the \: intercept\\ \tt\\ \hline\end{array} \: \\ [/tex]

[tex] \\ [/tex]

To find the y - intercept, let x = 0

[tex]\large \tt \: \begin{array}{|c|} \hline \tt 4x \: - \: 3y \: = \: \tt\underline{\green{ 12 }} \\ \tt 4(0) \: - \: 3y \: = \: \tt\underline{\blue{ 12 }} \\ \tt \: 0 \: - \: 3y \: = \: \tt\underline{\pink{ 12 }} \\ \tt \tt\underline{\red{ y \: = \: - 4 }} \\ \\ \tt \: x ↬\: the \: intercept \\ \ \\ \hline\end{array} \: [/tex]

[tex] \\ [/tex]

B. Replace x with 0 and solve for y. Then replace y with 0 and solve for x.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt y \: - \: intercept: \: y \: = \: \frac{1}{3}(0) \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \tt = \tt\underline{\red{ 0 }} \\ \\ \tt \: x \: and \: y ↬ intercepts: (0,0)\\ \\ \tt \: x \: ↬ \: intercepts: \: 0 = \: \frac{1}{3} x \\ \quad\quad \quad \quad\quad\quad\quad\quad\quad \: \tt \tt\underline{\red{ \: 0 \: = \: x }} \ \\ \\ \hline\end{array} \\ [/tex]

[tex] \\ [/tex]

The equation in b is a linear equation in the form y = mx, where m is any real number. the graph of any equation in the form y = mx is always a line that passes through the origin, which means that both the x - and - y - intercepts are (0,0).

[tex]\large \tt \: \begin{array}{|c|} \hline \tt intercept \: for \: m \: of \: y \: = \: \tt\underline{\red{ mx }} \\ \hline\end{array}[/tex]

[tex] \\ [/tex]

C. Replace y with 0, then solve for the x.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt x ↬ \: intercept : \: 0 \: = \: 2x \: \ + 5 \\ \\ \tt - 5 \: = \: 2x\\ \\ \tt \: \frac{ - 5}{2} \: = \: x\\ \\ \tt \: x \: ↬ \: intercept \ \\ \hline\end{array}[/tex]

Now, replace x with 0, and then solve for y.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt y ↬ \: intercept: \: y \: = \: 2(0) \: + \: 5 \\ \\ \tt \: y \: = \: 0 \: + \: 5 \\ \\ \tt \: y \: = \: 5 \\ \\ \tt y ↬ \: intercept \ \\ \\ \hline\end{array}[/tex]

The equation in 11c is written in the form y = mx + b. note than in the form, when x is replaced by 0 to find the y↬intercept. you are left with the constant b.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt \: the \: y ↬ intercept \: of \: y \: = \: mx \: + \: b \\ \hline\end{array}[/tex]

If the equation is in the form y = mx + b, where m and b are real numbers, then the y ↬intercept is b.

[tex] \\ [/tex]

D. Remember that the graph of y = 6 is horizontally line parallel to the x axis that passes through the y axis at (0,6). since the line is parallel to x axis, it will not incest tha x-axis. Hence, there is no x ↬ intercept.

[tex] \\ \\ \\ [/tex]

[tex]\pmb{(ノ‥)ノ}\qquad\qquad\qquad\qquad\boxed{\tt{[05-12-2022]}} \\ \qquad\qquad\qquad\qquad\qquad\qquad\boxed{\tt{[03:11 \: am]}}[/tex]

Answer:

if this is 4.88/16 then the answer is 0.305.

There are 258 ways to color the octagon such that no two adjacent vertices are the same color

The given parameters are:

Since no two adjacent vertices are the same color, we use the following  chromatic polynomial of an octagon equation

Ways = (r - 1)⁸ + (r -1)

Substitute 3 for r

Ways = (3 - 1)⁸ + (3 -1)

Evaluate

Ways = 258

Hence, there are 258 ways to color the octagon

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